\(2x^2-5x+3=0\) में मध्य पद का सही विभाजन क्या है?
What is the correct splitting of the middle term in \(2x^2-5x+3=0\)?
Explanation opens after your attempt
A. \(2x^2-2x-3x+3=0\)
Concept
((-2)+(-3)=-5) and ((-2)(-3)=6=ac), so the correct split is (-2x-3x). In exams, the product of the two numbers must be (ac).
Why this answer is correct
The correct answer is A. \(2x^2-2x-3x+3=0\). ((-2)+(-3)=-5) and ((-2)(-3)=6=ac), so the correct split is (-2x-3x). In exams, the product of the two numbers must be (ac).
Exam Tip
((-2)+(-3)=-5) और ((-2)(-3)=6=ac), इसलिए सही विभाजन (-2x-3x) है। परीक्षा में दोनों संख्याओं का गुणनफल (ac) होना चाहिए।
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