\(8x^2-2x-3=0\) में मध्य पद का सही विभाजन कौनसा है?
What is the correct splitting of the middle term in \(8x^2-2x-3=0\)?
Explanation opens after your attempt
A. \(8x^2+4x-6x-3=0\)
Concept
(ac=-24) and (4+(-6)=-2), so (-2x) is split as (4x-6x). In exams, check the sign of (ac) carefully.
Why this answer is correct
The correct answer is A. \(8x^2+4x-6x-3=0\). (ac=-24) and (4+(-6)=-2), so (-2x) is split as (4x-6x). In exams, check the sign of (ac) carefully.
Exam Tip
(ac=-24) और (4+(-6)=-2), इसलिए (-2x) को (4x-6x) में तोड़ते हैं। परीक्षा में (ac) का संकेत ध्यान से देखें।
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