Concept-wise Practice

ac-method MCQ Questions for Class 10

ac-method se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

14 questions tagged with ac-method.

\(30x^2-61x+30=0\) में मध्य पद का सही विभाजन कौनसा है?

What is the correct splitting of the middle term in \(30x^2-61x+30=0\)?

Explanation opens after your attempt
Correct Answer

A. \(30x^2-36x-25x+30=0\)

Step 1

Concept

Here (ac=900) and (-36+(-25)=-61), so the correct split is (-36x-25x). In exams, even for large (ac), match both sum and product.

Step 2

Why this answer is correct

The correct answer is A. \(30x^2-36x-25x+30=0\). Here (ac=900) and (-36+(-25)=-61), so the correct split is (-36x-25x). In exams, even for large (ac), match both sum and product.

Step 3

Exam Tip

यहां (ac=900) और (-36+(-25)=-61), इसलिए सही विभाजन (-36x-25x) है। परीक्षा में बड़ा (ac) हो तो भी योग और गुणनफल दोनों मिलाएं।

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\(24x^2-50x+25=0\) में मध्य पद का सही विभाजन कौनसा है?

What is the correct splitting of the middle term in \(24x^2-50x+25=0\)?

Explanation opens after your attempt
Correct Answer

A. \(24x^2-30x-20x+25=0\)

Step 1

Concept

Here (ac=600) and (-30+(-20)=-50), so the correct split is (-30x-20x). In exams, even for large (ac), match both sum and product.

Step 2

Why this answer is correct

The correct answer is A. \(24x^2-30x-20x+25=0\). Here (ac=600) and (-30+(-20)=-50), so the correct split is (-30x-20x). In exams, even for large (ac), match both sum and product.

Step 3

Exam Tip

यहां (ac=600) और (-30+(-20)=-50), इसलिए सही विभाजन (-30x-20x) है। परीक्षा में बड़ा (ac) हो तो भी योग और गुणनफल दोनों मिलाएं।

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\(20x^2-43x+21=0\) में मध्य पद का सही विभाजन कौनसा है?

What is the correct splitting of the middle term in \(20x^2-43x+21=0\)?

Explanation opens after your attempt
Correct Answer

A. \(20x^2-28x-15x+21=0\)

Step 1

Concept

Here (ac=420) and (-28+(-15)=-43), so the correct split is (-28x-15x). In exams, even when (ac) is large, match both sum and product.

Step 2

Why this answer is correct

The correct answer is A. \(20x^2-28x-15x+21=0\). Here (ac=420) and (-28+(-15)=-43), so the correct split is (-28x-15x). In exams, even when (ac) is large, match both sum and product.

Step 3

Exam Tip

यहां (ac=420) और (-28+(-15)=-43), इसलिए सही विभाजन (-28x-15x) है। परीक्षा में (ac) बड़ा हो तो भी योग और गुणनफल दोनों मिलाएं।

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\(18x^2-27x+10=0\) में मध्य पद का सही विभाजन कौनसा है?

What is the correct splitting of the middle term in \(18x^2-27x+10=0\)?

Explanation opens after your attempt
Correct Answer

A. \(18x^2-15x-12x+10=0\)

Step 1

Concept

Here (ac=180) and (-15+(-12)=-27), so the correct split is (-15x-12x). In exams, match both sum (b) and product (ac).

Step 2

Why this answer is correct

The correct answer is A. \(18x^2-15x-12x+10=0\). Here (ac=180) and (-15+(-12)=-27), so the correct split is (-15x-12x). In exams, match both sum (b) and product (ac).

Step 3

Exam Tip

यहां (ac=180) और (-15+(-12)=-27), इसलिए सही विभाजन (-15x-12x) है। परीक्षा में योग (b) और गुणनफल (ac) दोनों मिलाएं।

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\(15x^2+16x+4=0\) में मध्य पद का सही विभाजन कौनसा है?

What is the correct splitting of the middle term in \(15x^2+16x+4=0\)?

Explanation opens after your attempt
Correct Answer

A. \(15x^2+10x+6x+4=0\)

Step 1

Concept

Here (ac=60) and (10+6=16), so (16x) is split as (10x+6x). In exams, check both sum (b) and product (ac).

Step 2

Why this answer is correct

The correct answer is A. \(15x^2+10x+6x+4=0\). Here (ac=60) and (10+6=16), so (16x) is split as (10x+6x). In exams, check both sum (b) and product (ac).

Step 3

Exam Tip

यहां (ac=60) और (10+6=16), इसलिए (16x) को (10x+6x) में तोड़ते हैं। परीक्षा में योग (b) और गुणनफल (ac) दोनों जांचें।

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\(8x^2-2x-3=0\) में मध्य पद का सही विभाजन कौनसा है?

What is the correct splitting of the middle term in \(8x^2-2x-3=0\)?

Explanation opens after your attempt
Correct Answer

A. \(8x^2+4x-6x-3=0\)

Step 1

Concept

(ac=-24) and (4+(-6)=-2), so (-2x) is split as (4x-6x). In exams, check the sign of (ac) carefully.

Step 2

Why this answer is correct

The correct answer is A. \(8x^2+4x-6x-3=0\). (ac=-24) and (4+(-6)=-2), so (-2x) is split as (4x-6x). In exams, check the sign of (ac) carefully.

Step 3

Exam Tip

(ac=-24) और (4+(-6)=-2), इसलिए (-2x) को (4x-6x) में तोड़ते हैं। परीक्षा में (ac) का संकेत ध्यान से देखें।

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\(10x^2-17x+3=0\) में मध्य पद का सही विभाजन कौनसा है?

What is the correct splitting of the middle term in \(10x^2-17x+3=0\)?

Explanation opens after your attempt
Correct Answer

A. \(10x^2-15x-2x+3=0\)

Step 1

Concept

Here (ac=30) and (-15+(-2)=-17), so the middle term is (-15x-2x). In exams, check both sum and product.

Step 2

Why this answer is correct

The correct answer is A. \(10x^2-15x-2x+3=0\). Here (ac=30) and (-15+(-2)=-17), so the middle term is (-15x-2x). In exams, check both sum and product.

Step 3

Exam Tip

यहां (ac=30) और (-15+(-2)=-17), इसलिए मध्य पद (-15x-2x) होगा। परीक्षा में योग और गुणनफल दोनों जांचें।

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\(6x^2+x-2=0\) में मध्य पद का सही विभाजन कौनसा है?

What is the correct splitting of the middle term in \(6x^2+x-2=0\)?

Explanation opens after your attempt
Correct Answer

A. \(6x^2+4x-3x-2=0\)

Step 1

Concept

(ac=-12) and (4+(-3)=1), so (x) is split as (4x-3x). In exams, check the sign of (ac) carefully.

Step 2

Why this answer is correct

The correct answer is A. \(6x^2+4x-3x-2=0\). (ac=-12) and (4+(-3)=1), so (x) is split as (4x-3x). In exams, check the sign of (ac) carefully.

Step 3

Exam Tip

(ac=-12) और (4+(-3)=1), इसलिए (x) को (4x-3x) में तोड़ते हैं। परीक्षा में (ac) का संकेत ध्यान से देखें।

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\(8x^2+14x+3=0\) में मध्य पद का सही विभाजन कौनसा है?

What is the correct splitting of the middle term in \(8x^2+14x+3=0\)?

Explanation opens after your attempt
Correct Answer

A. \(8x^2+12x+2x+3=0\)

Step 1

Concept

Here (ac=24) and (12+2=14), so (14x) is split as (12x+2x). In exams, find (ac) first.

Step 2

Why this answer is correct

The correct answer is A. \(8x^2+12x+2x+3=0\). Here (ac=24) and (12+2=14), so (14x) is split as (12x+2x). In exams, find (ac) first.

Step 3

Exam Tip

यहां (ac=24) और (12+2=14), इसलिए (14x) को (12x+2x) में तोड़ते हैं। परीक्षा में पहले (ac) निकालें।

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\(2x^2+x-6=0\) में मध्य पद का सही विभाजन कौनसा है?

What is the correct splitting of the middle term in \(2x^2+x-6=0\)?

Explanation opens after your attempt
Correct Answer

A. \(2x^2+4x-3x-6=0\)

Step 1

Concept

(ac=-12) and (4+(-3)=1), so (x) is split as (4x-3x). In exams, check the sign of (ac) carefully.

Step 2

Why this answer is correct

The correct answer is A. \(2x^2+4x-3x-6=0\). (ac=-12) and (4+(-3)=1), so (x) is split as (4x-3x). In exams, check the sign of (ac) carefully.

Step 3

Exam Tip

(ac=-12) और (4+(-3)=1), इसलिए (x) को (4x-3x) में तोड़ते हैं। परीक्षा में (ac) का संकेत ध्यान से देखें।

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\(6x^2+11x+3=0\) में मध्य पद का सही विभाजन कौनसा है?

What is the correct splitting of the middle term in \(6x^2+11x+3=0\)?

Explanation opens after your attempt
Correct Answer

A. \(6x^2+9x+2x+3=0\)

Step 1

Concept

Here (ac=18) and (9+2=11), so (11x) is split as (9x+2x). In exams, check both sum (b) and product (ac).

Step 2

Why this answer is correct

The correct answer is A. \(6x^2+9x+2x+3=0\). Here (ac=18) and (9+2=11), so (11x) is split as (9x+2x). In exams, check both sum (b) and product (ac).

Step 3

Exam Tip

यहां (ac=18) और (9+2=11), इसलिए (11x) को (9x+2x) में तोड़ते हैं। परीक्षा में योग (b) और गुणनफल (ac) दोनों जांचें।

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मध्य पद विभाजन में \(4x^2+13x+3=0\) के लिए (ac) का मान क्या है?

In middle term splitting for \(4x^2+13x+3=0\), what is the value of (ac)?

Explanation opens after your attempt
Correct Answer

A. (12)

Step 1

Concept

Here (a=4) and (c=3), so (ac=12). In exams, finding (ac) first helps.

Step 2

Why this answer is correct

The correct answer is A. (12). Here (a=4) and (c=3), so (ac=12). In exams, finding (ac) first helps.

Step 3

Exam Tip

यहां (a=4) और (c=3), इसलिए (ac=12) है। परीक्षा में पहले (ac) निकालना मदद करता है।

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मध्य पद विभाजन में \(3x^2+10x+3=0\) के लिए (ac) का मान क्या है?

In middle term splitting for \(3x^2+10x+3=0\), what is the value of (ac)?

Explanation opens after your attempt
Correct Answer

A. (9)

Step 1

Concept

Here (a=3) and (c=3), so (ac=9). In exams, finding (ac) first helps.

Step 2

Why this answer is correct

The correct answer is A. (9). Here (a=3) and (c=3), so (ac=9). In exams, finding (ac) first helps.

Step 3

Exam Tip

यहां (a=3) और (c=3), इसलिए (ac=9) है। परीक्षा में पहले (ac) निकालना मदद करता है।

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मध्य पद विभाजन विधि में \(2x^2+7x+3=0\) के लिए (ac) का मान क्या है?

In middle term splitting method for \(2x^2+7x+3=0\), what is the value of (ac)?

Explanation opens after your attempt
Correct Answer

A. (6)

Step 1

Concept

Here (a=2) and (c=3), so (ac=6). In exams, finding (ac) makes middle term splitting easier.

Step 2

Why this answer is correct

The correct answer is A. (6). Here (a=2) and (c=3), so (ac=6). In exams, finding (ac) makes middle term splitting easier.

Step 3

Exam Tip

यहां (a=2) और (c=3), इसलिए (ac=6) है। परीक्षा में (ac) निकालकर मध्य पद तोड़ना आसान होता है।

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