\(6x^2+x-2=0\) में मध्य पद का सही विभाजन कौनसा है?
What is the correct splitting of the middle term in \(6x^2+x-2=0\)?
Explanation opens after your attempt
A. \(6x^2+4x-3x-2=0\)
Concept
(ac=-12) and (4+(-3)=1), so (x) is split as (4x-3x). In exams, check the sign of (ac) carefully.
Why this answer is correct
The correct answer is A. \(6x^2+4x-3x-2=0\). (ac=-12) and (4+(-3)=1), so (x) is split as (4x-3x). In exams, check the sign of (ac) carefully.
Exam Tip
(ac=-12) और (4+(-3)=1), इसलिए (x) को (4x-3x) में तोड़ते हैं। परीक्षा में (ac) का संकेत ध्यान से देखें।
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