\(6x^2+x-2=0\) में मध्य पद का सही विभाजन कौनसा है?

What is the correct splitting of the middle term in \(6x^2+x-2=0\)?

Explanation opens after your attempt
Correct Answer

A. \(6x^2+4x-3x-2=0\)

Step 1

Concept

(ac=-12) and (4+(-3)=1), so (x) is split as (4x-3x). In exams, check the sign of (ac) carefully.

Step 2

Why this answer is correct

The correct answer is A. \(6x^2+4x-3x-2=0\). (ac=-12) and (4+(-3)=1), so (x) is split as (4x-3x). In exams, check the sign of (ac) carefully.

Step 3

Exam Tip

(ac=-12) और (4+(-3)=1), इसलिए (x) को (4x-3x) में तोड़ते हैं। परीक्षा में (ac) का संकेत ध्यान से देखें।

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Mathematics Answer, Explanation and Revision Hints

\(6x^2+x-2=0\) में मध्य पद का सही विभाजन कौनसा है? / What is the correct splitting of the middle term in \(6x^2+x-2=0\)?

Correct Answer: A. \(6x^2+4x-3x-2=0\). Explanation: (ac=-12) और (4+(-3)=1), इसलिए (x) को (4x-3x) में तोड़ते हैं। परीक्षा में (ac) का संकेत ध्यान से देखें। / (ac=-12) and (4+(-3)=1), so (x) is split as (4x-3x). In exams, check the sign of (ac) carefully.

Which concept should I revise for this Mathematics MCQ?

(ac=-12) and (4+(-3)=1), so (x) is split as (4x-3x). In exams, check the sign of (ac) carefully.

What exam hint can help solve this Mathematics question?

(ac=-12) और (4+(-3)=1), इसलिए (x) को (4x-3x) में तोड़ते हैं। परीक्षा में (ac) का संकेत ध्यान से देखें।