\(3x^2-11x+6=0\) में मध्य पद का सही विभाजन क्या है?
What is the correct splitting of the middle term in \(3x^2-11x+6=0\)?
Explanation opens after your attempt
A. \(3x^2-9x-2x+6=0\)
Concept
((-9)+(-2)=-11) and ((-9)(-2)=18=ac), so (-9x-2x) is correct. In exams, split the middle term by checking (ac).
Why this answer is correct
The correct answer is A. \(3x^2-9x-2x+6=0\). ((-9)+(-2)=-11) and ((-9)(-2)=18=ac), so (-9x-2x) is correct. In exams, split the middle term by checking (ac).
Exam Tip
((-9)+(-2)=-11) और ((-9)(-2)=18=ac), इसलिए (-9x-2x) सही है। परीक्षा में (ac) देखकर मध्य पद तोड़ें।
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