समीकरण (14x+7y=35) को (y=mx+c) रूप में लिखने पर ढाल और (y)-अवरोध क्या होंगे?
When (14x+7y=35) is written in (y=mx+c) form, what are the slope and (y)-intercept?
#standard_form
#slope_intercept
#rearrange
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A ढाल (-2), (y)-अवरोध (5) / Slope (-2), (y)-intercept (5)
B ढाल (2), (y)-अवरोध (5) / Slope (2), (y)-intercept (5)
C ढाल (-14), (y)-अवरोध (7) / Slope (-14), (y)-intercept (7)
D ढाल (14), (y)-अवरोध (-7) / Slope (14), (y)-intercept (-7)
Explanation opens after your attempt
Correct Answer
A. ढाल (-2), (y)-अवरोध (5) / Slope (-2), (y)-intercept (5)
Step 1
Concept
From (7y=-14x+35), we get (y=-2x+5). The coefficient is slope and the constant term is the (y)-intercept.
Step 2
Why this answer is correct
The correct answer is A. ढाल (-2), (y)-अवरोध (5) / Slope (-2), (y)-intercept (5). From (7y=-14x+35), we get (y=-2x+5). The coefficient is slope and the constant term is the (y)-intercept.
Step 3
Exam Tip
(7y=-14x+35) से (y=-2x+5) मिलता है। गुणांक ढाल और स्थिर पद (y)-अवरोध होता है।
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यदि रेखा (y=(3k-4)x+2) की ढाल (17) है, तो (k) क्या है?
If the line (y=(3k-4)x+2) has slope (17), what is (k)?
#parameter_slope
#linear_expression
#solve
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A (5)
B (6)
C (8)
D (7)
Explanation opens after your attempt
Step 1
Concept
The slope is (3k-4). From (3k-4=17), (k=7).
Step 2
Why this answer is correct
The correct answer is D. (7). The slope is (3k-4). From (3k-4=17), (k=7).
Step 3
Exam Tip
ढाल (3k-4) है। (3k-4=17) से (k=7) मिलता है।
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समीकरण (6y=18x-54) का (y)-अवरोध क्या है?
What is the (y)-intercept of (6y=18x-54)?
#y_intercept
#rearrange_equation
#constant_term
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A (18)
B (-9)
C (6)
D (-54)
Explanation opens after your attempt
Step 1
Concept
Dividing by (6) gives (y=3x-9). The constant term (-9) is the (y)-intercept.
Step 2
Why this answer is correct
The correct answer is B. (-9). Dividing by (6) gives (y=3x-9). The constant term (-9) is the (y)-intercept.
Step 3
Exam Tip
(6) से भाग देने पर (y=3x-9) मिलता है। स्थिर पद (-9) (y)-अवरोध है।
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रेखा (y=-6x+c) बिंदु ((5,-18)) से गुजरती है। इसका (y)-अवरोध क्या है?
The line (y=-6x+c) passes through ((5,-18)). What is its (y)-intercept?
#find_intercept
#point_given
#negative_slope
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A (10)
B (11)
C (13)
D (12)
Explanation opens after your attempt
Step 1
Concept
Substituting the point gives (-18=-6(5)+c). Therefore (c=12).
Step 2
Why this answer is correct
The correct answer is D. (12). Substituting the point gives (-18=-6(5)+c). Therefore (c=12).
Step 3
Exam Tip
बिंदु रखने पर (-18=-6(5)+c) मिलता है। इसलिए (c=12) है।
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रेखा (y=mx-11) बिंदु ((-4,9)) से गुजरती है। इसकी ढाल क्या है?
The line (y=mx-11) passes through ((-4,9)). What is its slope?
#find_slope
#point_given
#parameter
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A (5)
B (-5)
C (4)
D (-4)
Explanation opens after your attempt
Step 1
Concept
Substituting the point gives (9=-4m-11). Thus (-4m=20) and (m=-5).
Step 2
Why this answer is correct
The correct answer is B. (-5). Substituting the point gives (9=-4m-11). Thus (-4m=20) and (m=-5).
Step 3
Exam Tip
बिंदु रखने पर (9=-4m-11) मिलता है। इससे (-4m=20) और (m=-5) है।
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समीकरण (9x-4y=28) की ढाल क्या है?
What is the slope of (9x-4y=28)?
#standard_form
#fraction_slope
#rearrange
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A \(\frac{9}{4}\)
B \(-\frac{9}{4}\)
C (4)
D (28)
Explanation opens after your attempt
Correct Answer
A. \(\frac{9}{4}\)
Step 1
Concept
From (9x-4y=28), we get \(y=\frac{9}{4}x-7\). Therefore the slope is \(\frac{9}{4}\).
Step 2
Why this answer is correct
The correct answer is A. \(\frac{9}{4}\). From (9x-4y=28), we get \(y=\frac{9}{4}x-7\). Therefore the slope is \(\frac{9}{4}\).
Step 3
Exam Tip
(9x-4y=28) से \(y=\frac{9}{4}x-7\) मिलता है। इसलिए ढाल \(\frac{9}{4}\) है।
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यदि (ay=36x-60) की ढाल (6) है, तो (a) का मान क्या है?
If (ay=36x-60) has slope (6), what is the value of (a)?
#parameter_slope
#rearrange_equation
#expert
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A (4)
B (6)
C (8)
D (10)
Explanation opens after your attempt
Step 1
Concept
\(y=\frac{36}{a}x-\frac{60}{a}\). From \(\frac{36}{a}=6\), (a=6).
Step 2
Why this answer is correct
The correct answer is B. (6). \(y=\frac{36}{a}x-\frac{60}{a}\). From \(\frac{36}{a}=6\), (a=6).
Step 3
Exam Tip
\(y=\frac{36}{a}x-\frac{60}{a}\) होगा। \(\frac{36}{a}=6\) से (a=6) है।
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यदि (ky=30x-90) का (y)-अवरोध (-15) है, तो (k) क्या है?
If (ky=30x-90) has (y)-intercept (-15), what is (k)?
#parameter_intercept
#rearrange_equation
#expert
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A (3)
B (5)
C (9)
D (6)
Explanation opens after your attempt
Step 1
Concept
\(y=\frac{30}{k}x-\frac{90}{k}\). From \(-\frac{90}{k}=-15\), (k=6).
Step 2
Why this answer is correct
The correct answer is D. (6). \(y=\frac{30}{k}x-\frac{90}{k}\). From \(-\frac{90}{k}=-15\), (k=6).
Step 3
Exam Tip
\(y=\frac{30}{k}x-\frac{90}{k}\) होगा। \(-\frac{90}{k}=-15\) से (k=6) है।
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रेखा (y=(4p-3)x-5) की ढाल (25) है। (p) क्या होगा?
The line (y=(4p-3)x-5) has slope (25). What will (p) be?
#parameter_slope
#linear_polynomial
#solve
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A (5)
B (6)
C (8)
D (7)
Explanation opens after your attempt
Step 1
Concept
The slope is (4p-3). From (4p-3=25), (p=7).
Step 2
Why this answer is correct
The correct answer is D. (7). The slope is (4p-3). From (4p-3=25), (p=7).
Step 3
Exam Tip
ढाल (4p-3) है। (4p-3=25) से (p=7) मिलता है।
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यदि (y=(r+8)x+(r-4)) मूल बिंदु से गुजरती है, तो इसकी ढाल क्या होगी?
If (y=(r+8)x+(r-4)) passes through the origin, what will be its slope?
#origin
#parameter
#find_slope
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A (4)
B (8)
C (12)
D (16)
Explanation opens after your attempt
Step 1
Concept
To pass through the origin, (r-4=0). Thus (r=4) and the slope is (12).
Step 2
Why this answer is correct
The correct answer is C. (12). To pass through the origin, (r-4=0). Thus (r=4) and the slope is (12).
Step 3
Exam Tip
मूल बिंदु से गुजरने के लिए (r-4=0) होगा। इसलिए (r=4) और ढाल (12) है।
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समीकरण (18x+6y-72=0) में ढाल और (y)-अवरोध क्या हैं?
What are the slope and (y)-intercept in (18x+6y-72=0)?
#general_form
#slope_intercept
#rearrange
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A ढाल (-3), (y)-अवरोध (12) / Slope (-3), (y)-intercept (12)
B ढाल (3), (y)-अवरोध (12) / Slope (3), (y)-intercept (12)
C ढाल (-18), (y)-अवरोध (6) / Slope (-18), (y)-intercept (6)
D ढाल (18), (y)-अवरोध (-6) / Slope (18), (y)-intercept (-6)
Explanation opens after your attempt
Correct Answer
A. ढाल (-3), (y)-अवरोध (12) / Slope (-3), (y)-intercept (12)
Step 1
Concept
From (6y=-18x+72), (y=-3x+12). So the slope is (-3) and the (y)-intercept is (12).
Step 2
Why this answer is correct
The correct answer is A. ढाल (-3), (y)-अवरोध (12) / Slope (-3), (y)-intercept (12). From (6y=-18x+72), (y=-3x+12). So the slope is (-3) and the (y)-intercept is (12).
Step 3
Exam Tip
(6y=-18x+72) से (y=-3x+12) मिलता है। इसलिए ढाल (-3) और (y)-अवरोध (12) है।
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समीकरण (10x-5y+25=0) का (y)-अवरोध क्या है?
What is the (y)-intercept of (10x-5y+25=0)?
#general_form
#y_intercept
#substitution
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A (5)
B (-5)
C (10)
D (25)
Explanation opens after your attempt
Step 1
Concept
Putting (x=0) gives (-5y+25=0). Thus (y=5).
Step 2
Why this answer is correct
The correct answer is A. (5). Putting (x=0) gives (-5y+25=0). Thus (y=5).
Step 3
Exam Tip
(x=0) रखने पर (-5y+25=0) मिलता है। इससे (y=5) है।
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यदि दो रेखाएं (y=(q-6)x+9) और (y=10x-4) समान ढाल रखती हैं, तो (q) क्या है?
If the two lines (y=(q-6)x+9) and (y=10x-4) have the same slope, what is (q)?
#compare_slopes
#parameter
#parallel_lines
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A (14)
B (15)
C (18)
D (16)
Explanation opens after your attempt
Step 1
Concept
For equal slopes, (q-6=10). This gives (q=16).
Step 2
Why this answer is correct
The correct answer is D. (16). For equal slopes, (q-6=10). This gives (q=16).
Step 3
Exam Tip
समान ढाल के लिए (q-6=10) होना चाहिए। इससे (q=16) मिलता है।
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यदि (y=-9x+s) और (y=6x-17) का (y)-अवरोध समान है, तो (s) क्या होगा?
If (y=-9x+s) and (y=6x-17) have the same (y)-intercept, what will (s) be?
#compare_intercepts
#parameter
#constant_term
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A (-17)
B (-9)
C (6)
D (17)
Explanation opens after your attempt
Step 1
Concept
The first line has (y)-intercept (s) and the second has (-17). If equal, (s=-17).
Step 2
Why this answer is correct
The correct answer is A. (-17). The first line has (y)-intercept (s) and the second has (-17). If equal, (s=-17).
Step 3
Exam Tip
पहली रेखा का (y)-अवरोध (s) और दूसरी का (-17) है। समान होने पर (s=-17) होगा।
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यदि (y=(a-7)x+a) में ढाल और (y)-अवरोध का अंतर (-7) है, तो कौन सा कथन सही है?
If in (y=(a-7)x+a), the difference between slope and (y)-intercept is (-7), which statement is correct?
#parameter_condition
#slope_intercept
#identity
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A यह हर (a) के लिए सही है / It is true for every (a)
B केवल (a=7) के लिए सही है / It is true only for (a=7)
C कोई (a) संभव नहीं / No (a) is possible
D केवल (a=0) के लिए सही है / It is true only for (a=0)
Explanation opens after your attempt
Correct Answer
A. यह हर (a) के लिए सही है / It is true for every (a)
Step 1
Concept
The slope is (a-7) and the (y)-intercept is (a). The difference ((a-7)-a=-7) holds for every (a).
Step 2
Why this answer is correct
The correct answer is A. यह हर (a) के लिए सही है / It is true for every (a). The slope is (a-7) and the (y)-intercept is (a). The difference ((a-7)-a=-7) holds for every (a).
Step 3
Exam Tip
ढाल (a-7) और (y)-अवरोध (a) है। अंतर ((a-7)-a=-7) हर (a) के लिए है।
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रेखा (y=6x+b) बिंदुओं ((2,19)) और ((5,37)) से गुजरती है। (b) क्या है?
The line (y=6x+b) passes through ((2,19)) and ((5,37)). What is (b)?
#two_points
#intercept_given_slope
#verify
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A (5)
B (7)
C (9)
D (11)
Explanation opens after your attempt
Step 1
Concept
From the first point, (19=6(2)+b). So (b=7) and the second point also fits.
Step 2
Why this answer is correct
The correct answer is B. (7). From the first point, (19=6(2)+b). So (b=7) and the second point also fits.
Step 3
Exam Tip
पहले बिंदु से (19=6(2)+b) मिलता है। इसलिए (b=7) है और दूसरा बिंदु भी सही है।
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रेखा (y=mx+3) बिंदुओं ((4,27)) और ((7,45)) से गुजरती है। (m) क्या है?
The line (y=mx+3) passes through ((4,27)) and ((7,45)). What is (m)?
#two_points
#slope
#linear_form
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A (4)
B (5)
C (6)
D (7)
Explanation opens after your attempt
Step 1
Concept
The slope from the two points is \(\frac{45-27}{7-4}=6\). Therefore (m=6).
Step 2
Why this answer is correct
The correct answer is C. (6). The slope from the two points is \(\frac{45-27}{7-4}=6\). Therefore (m=6).
Step 3
Exam Tip
दोनों बिंदुओं से ढाल \(\frac{45-27}{7-4}=6\) है। इसलिए (m=6) है।
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यदि (y=(k-8)x+11) और (y=5x+(k-2)) की ढालें समान हैं, तो (k) क्या है?
If (y=(k-8)x+11) and (y=5x+(k-2)) have equal slopes, what is (k)?
#compare_slopes
#parameter
#hard
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A (11)
B (12)
C (14)
D (13)
Explanation opens after your attempt
Step 1
Concept
For equal slopes, (k-8=5). This gives (k=13).
Step 2
Why this answer is correct
The correct answer is D. (13). For equal slopes, (k-8=5). This gives (k=13).
Step 3
Exam Tip
समान ढाल के लिए (k-8=5) होगा। इससे (k=13) मिलता है।
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यदि (y=(m+2)x-8) और (y=9x+(m-12 )) का (y)-अवरोध समान है, तो (m) क्या है?
If (y=(m+2)x-8) and (y=9x+(m-12 )) have the same (y)-intercept, what is (m)?
#compare_intercepts
#parameter
#hard
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A (2)
B (3)
C (5)
D (4)
Explanation opens after your attempt
Step 1
Concept
For equal (y)-intercepts, (-8=m-12 ). This gives (m=4).
Step 2
Why this answer is correct
The correct answer is D. (4). For equal (y)-intercepts, (-8=m-12 ). This gives (m=4).
Step 3
Exam Tip
समान (y)-अवरोध के लिए (-8=m-12 ) होगा। इससे (m=4) मिलता है।
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रेखा (y=-7x+24) में (x) कितने बढ़ाने पर (y) (56) घटेगा?
In the line (y=-7x+24), by how much must (x) increase for (y) to decrease by (56)?
#negative_slope
#change_in_x
#total_change
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A (6)
B (7)
C (9)
D (8)
Explanation opens after your attempt
Step 1
Concept
The slope is (-7), so the decrease is \(7\Delta x\). From \(7\Delta x=56\), \(\Delta x=8\).
Step 2
Why this answer is correct
The correct answer is D. (8). The slope is (-7), so the decrease is \(7\Delta x\). From \(7\Delta x=56\), \(\Delta x=8\).
Step 3
Exam Tip
ढाल (-7) है, इसलिए कमी \(7\Delta x\) होगी। \(7\Delta x=56\) से \(\Delta x=8\) है।
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रेखा \(y=\frac{7}{5}x-12\) में (y) को (28) बढ़ाने के लिए (x) कितना बढ़ना चाहिए?
In the line \(y=\frac{7}{5}x-12\), how much should (x) increase to increase (y) by (28)?
#fraction_slope
#change_in_x
#rate
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A (16)
B (18)
C (20)
D (25)
Explanation opens after your attempt
Step 1
Concept
The change is \(\frac{7}{5}\Delta x=28\). This gives \(\Delta x=20\).
Step 2
Why this answer is correct
The correct answer is C. (20). The change is \(\frac{7}{5}\Delta x=28\). This gives \(\Delta x=20\).
Step 3
Exam Tip
परिवर्तन \(\frac{7}{5}\Delta x=28\) होगा। इससे \(\Delta x=20\) मिलता है।
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यदि (y=px+q) में (p=-8) और (q=11), तो सही कथन कौन सा है?
If (p=-8) and (q=11) in (y=px+q), which statement is correct?
#sign_analysis
#graph_behavior
#slope_intercept
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A रेखा बढ़ती है और (y)-अवरोध ऋणात्मक है / The line increases and the (y)-intercept is negative
B रेखा घटती है और (y)-अवरोध धनात्मक है / The line decreases and the (y)-intercept is positive
C रेखा क्षैतिज है और मूल से गुजरती है / The line is horizontal and passes through origin
D रेखा बढ़ती है और मूल से गुजरती है / The line increases and passes through origin
Explanation opens after your attempt
Correct Answer
B. रेखा घटती है और (y)-अवरोध धनात्मक है / The line decreases and the (y)-intercept is positive
Step 1
Concept
(p=-8) gives a negative slope and (q=11) gives a positive (y)-intercept. So the line decreases.
Step 2
Why this answer is correct
The correct answer is B. रेखा घटती है और (y)-अवरोध धनात्मक है / The line decreases and the (y)-intercept is positive. (p=-8) gives a negative slope and (q=11) gives a positive (y)-intercept. So the line decreases.
Step 3
Exam Tip
(p=-8) ऋणात्मक ढाल देता है और (q=11) धनात्मक (y)-अवरोध देता है। इसलिए रेखा घटती है।
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यदि (5x+ay=45) का (y)-अवरोध (9) है, तो (a) क्या है?
If (5x+ay=45) has (y)-intercept (9), what is (a)?
#parameter_intercept
#standard_form
#substitution
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A (3)
B (4)
C (9)
D (5)
Explanation opens after your attempt
Step 1
Concept
Putting (x=0) gives (ay=45) and \(y=\frac{45}{a}\). From \(\frac{45}{a}=9\), (a=5).
Step 2
Why this answer is correct
The correct answer is D. (5). Putting (x=0) gives (ay=45) and \(y=\frac{45}{a}\). From \(\frac{45}{a}=9\), (a=5).
Step 3
Exam Tip
(x=0) रखने पर (ay=45) और \(y=\frac{45}{a}\) मिलता है। \(\frac{45}{a}=9\) से (a=5) है।
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यदि (bx+10y=70) की ढाल (-3) है, तो (b) क्या है?
If (bx+10y=70) has slope (-3), what is (b)?
#parameter_slope
#standard_form
#hard
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A (20)
B (25)
C (35)
D (30)
Explanation opens after your attempt
Step 1
Concept
From (10y=-bx+70), the slope is \(-\frac{b}{10}\). From \(-\frac{b}{10}=-3\), (b=30).
Step 2
Why this answer is correct
The correct answer is D. (30). From (10y=-bx+70), the slope is \(-\frac{b}{10}\). From \(-\frac{b}{10}=-3\), (b=30).
Step 3
Exam Tip
(10y=-bx+70) से ढाल \(-\frac{b}{10}\) है। \(-\frac{b}{10}=-3\) से (b=30) है।
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रेखा (y=(n-7)x+(4n-5)) का (y)-अवरोध (23) है। इसकी ढाल क्या है?
The line (y=(n-7)x+(4n-5)) has (y)-intercept (23). What is its slope?
#parameter_intercept
#find_slope
#zero_slope
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A (0)
B (1)
C (2)
D (3)
Explanation opens after your attempt
Step 1
Concept
From (4n-5=23), (n=7). The slope is (n-7=0).
Step 2
Why this answer is correct
The correct answer is A. (0). From (4n-5=23), (n=7). The slope is (n-7=0).
Step 3
Exam Tip
(4n-5=23) से (n=7) मिलता है। ढाल (n-7=0) है।
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रेखा (y=(t-10)x+(3t-1)) की ढाल (5) है। इसका (y)-अवरोध क्या है?
The line (y=(t-10)x+(3t-1)) has slope (5). What is its (y)-intercept?
#parameter_slope
#find_intercept
#hard
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A (41)
B (44)
C (43)
D (42)
Explanation opens after your attempt
Step 1
Concept
From (t-10=5), (t=15). The (y)-intercept is (3t-1=44).
Step 2
Why this answer is correct
The correct answer is B. (44). From (t-10=5), (t=15). The (y)-intercept is (3t-1=44).
Step 3
Exam Tip
(t-10=5) से (t=15) मिलता है। (y)-अवरोध (3t-1=44) है।
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कौन सी रेखा ((0,-14)) पर (y)-अक्ष काटती है और (x) के (6) बढ़ने पर (y) (54) बढ़ाती है?
Which line cuts the (y)-axis at ((0,-14)) and increases (y) by (54) when (x) increases by (6)?
#equation_from_rate
#intercept
#hard
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A (y=9x-14)
B (y=54x-14)
C (y=-9x-14)
D (y=9x+14)
Explanation opens after your attempt
Correct Answer
A. (y=9x-14)
Step 1
Concept
The slope is \(\frac{54}{6}=9\) and the (y)-intercept is (-14). So the line is (y=9x-14).
Step 2
Why this answer is correct
The correct answer is A. (y=9x-14). The slope is \(\frac{54}{6}=9\) and the (y)-intercept is (-14). So the line is (y=9x-14).
Step 3
Exam Tip
ढाल \(\frac{54}{6}=9\) है और (y)-अवरोध (-14) है। इसलिए रेखा (y=9x-14) है।
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कौन सी रेखा ((0,18)) पर (y)-अक्ष काटती है और (x) के (7) बढ़ने पर (y) (49) घटाती है?
Which line cuts the (y)-axis at ((0,18)) and decreases (y) by (49) when (x) increases by (7)?
#equation_from_rate
#negative_slope
#intercept
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A (y=7x+18)
B (y=-7x+18)
C (y=-49x+18)
D (y=-7x-18)
Explanation opens after your attempt
Correct Answer
B. (y=-7x+18)
Step 1
Concept
The slope is \(-\frac{49}{7}=-7\) and the (y)-intercept is (18). So (y=-7x+18) is correct.
Step 2
Why this answer is correct
The correct answer is B. (y=-7x+18). The slope is \(-\frac{49}{7}=-7\) and the (y)-intercept is (18). So (y=-7x+18) is correct.
Step 3
Exam Tip
ढाल \(-\frac{49}{7}=-7\) है और (y)-अवरोध (18) है। इसलिए (y=-7x+18) सही है।
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यदि (y=(a+9)x+(a-15)) मूल बिंदु से गुजरती है, तो इसकी ढाल क्या होगी?
If (y=(a+9)x+(a-15)) passes through the origin, what will be its slope?
#origin
#parameter
#find_slope
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A (22)
B (23)
C (24)
D (25)
Explanation opens after your attempt
Step 1
Concept
To pass through the origin, (a-15=0). Thus (a=15) and the slope is (24).
Step 2
Why this answer is correct
The correct answer is C. (24). To pass through the origin, (a-15=0). Thus (a=15) and the slope is (24).
Step 3
Exam Tip
मूल बिंदु से गुजरने के लिए (a-15=0) होगा। इसलिए (a=15) और ढाल (24) है।
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यदि (y=(3u-2)x+(u+6)) का (y)-अवरोध (16) है, तो ढाल क्या है?
If (y=(3u-2)x+(u+6)) has (y)-intercept (16), what is the slope?
#parameter_intercept
#find_slope
#linear_form
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A (26)
B (28)
C (30)
D (32)
Explanation opens after your attempt
Step 1
Concept
From (u+6=16), (u=10). The slope is (3u-2=28).
Step 2
Why this answer is correct
The correct answer is B. (28). From (u+6=16), (u=10). The slope is (3u-2=28).
Step 3
Exam Tip
(u+6=16) से (u=10) मिलता है। ढाल (3u-2=28) है।
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समीकरण (10x+4y-44=0) में (y)-अवरोध और ढाल कौन से हैं?
What are the (y)-intercept and slope in (10x+4y-44=0)?
#general_form
#fraction_slope
#y_intercept
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A (y)-अवरोध (11), ढाल \(-\frac{5}{2}\) / (y)-intercept (11), slope \(-\frac{5}{2}\)
B (y)-अवरोध (-11), ढाल \(\frac{5}{2}\) / (y)-intercept (-11), slope \(\frac{5}{2}\)
C (y)-अवरोध (44), ढाल (-10) / (y)-intercept (44), slope (-10)
D (y)-अवरोध (10), ढाल (4) / (y)-intercept (10), slope (4)
Explanation opens after your attempt
Correct Answer
A. (y)-अवरोध (11), ढाल \(-\frac{5}{2}\) / (y)-intercept (11), slope \(-\frac{5}{2}\)
Step 1
Concept
From (4y=-10x+44), \(y=-\frac{5}{2}x+11\). So the (y)-intercept is (11) and slope is \(-\frac{5}{2}\).
Step 2
Why this answer is correct
The correct answer is A. (y)-अवरोध (11), ढाल \(-\frac{5}{2}\) / (y)-intercept (11), slope \(-\frac{5}{2}\). From (4y=-10x+44), \(y=-\frac{5}{2}x+11\). So the (y)-intercept is (11) and slope is \(-\frac{5}{2}\).
Step 3
Exam Tip
(4y=-10x+44) से \(y=-\frac{5}{2}x+11\) मिलता है। इसलिए (y)-अवरोध (11) और ढाल \(-\frac{5}{2}\) है।
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यदि (y=8x+b) और (y=-6x+13) (y)-अक्ष पर एक ही बिंदु काटती हैं, तो (b) क्या है?
If (y=8x+b) and (y=-6x+13) cut the (y)-axis at the same point, what is (b)?
#same_y_intercept
#parameter
#comparison
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A (6)
B (8)
C (21)
D (13)
Explanation opens after your attempt
Step 1
Concept
The same (y)-axis point means equal (y)-intercepts. Therefore (b=13).
Step 2
Why this answer is correct
The correct answer is D. (13). The same (y)-axis point means equal (y)-intercepts. Therefore (b=13).
Step 3
Exam Tip
एक ही (y)-अक्ष बिंदु का अर्थ समान (y)-अवरोध है। इसलिए (b=13) है।
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यदि (y=ax-12) और (y=10x+5) की ढालें समान हैं, तो (x=3) पर पहली रेखा का (y) क्या होगा?
If (y=ax-12) and (y=10x+5) have equal slopes, what is (y) on the first line at (x=3)?
#compare_slopes
#evaluate_line
#parameter
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A (16)
B (18)
C (20)
D (22)
Explanation opens after your attempt
Step 1
Concept
Equal slopes give (a=10). Putting (x=3), (y=10(3)-12=18).
Step 2
Why this answer is correct
The correct answer is B. (18). Equal slopes give (a=10). Putting (x=3), (y=10(3)-12=18).
Step 3
Exam Tip
समान ढाल से (a=10) है। (x=3) रखने पर (y=10(3)-12=18) है।
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रेखा (y=-11x+c) का (y)-अवरोध (7) है। (x=-3) पर (y) क्या होगा?
The line (y=-11x+c) has (y)-intercept (7). What will (y) be at (x=-3)?
#evaluate_line
#negative_x
#intercept_given
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A (33)
B (37)
C (44)
D (40)
Explanation opens after your attempt
Step 1
Concept
The (y)-intercept (7) gives (c=7). Putting (x=-3), (y=-11(-3)+7=40).
Step 2
Why this answer is correct
The correct answer is D. (40). The (y)-intercept (7) gives (c=7). Putting (x=-3), (y=-11(-3)+7=40).
Step 3
Exam Tip
(y)-अवरोध (7) से (c=7) है। (x=-3) रखने पर (y=-11(-3)+7=40) है।
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यदि रेखा (y=(k-5)x+4) (x) के (8) बढ़ने पर (y) (72) बढ़ाती है, तो (k) क्या है?
If the line (y=(k-5)x+4) increases (y) by (72) when (x) increases by (8), what is (k)?
#parameter_slope
#total_change
#hard
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A (12)
B (13)
C (15)
D (14)
Explanation opens after your attempt
Step 1
Concept
The slope is (k-5) and (8(k-5)=72). Therefore (k-5=9) and (k=14).
Step 2
Why this answer is correct
The correct answer is D. (14). The slope is (k-5) and (8(k-5)=72). Therefore (k-5=9) and (k=14).
Step 3
Exam Tip
ढाल (k-5) है और (8(k-5)=72)। इसलिए (k-5=9) और (k=14) है।
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यदि रेखा (y=-(p+4)x+20) (x) के (5) बढ़ने पर (y) (55) घटाती है, तो (p) क्या है?
If the line (y=-(p+4)x+20) decreases (y) by (55) when (x) increases by (5), what is (p)?
#parameter_slope
#negative_slope
#total_change
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A (5)
B (6)
C (7)
D (8)
Explanation opens after your attempt
Step 1
Concept
The slope is (-(p+4)) and the decrease is (5(p+4)=55). So (p+4=11) and (p=7).
Step 2
Why this answer is correct
The correct answer is C. (7). The slope is (-(p+4)) and the decrease is (5(p+4)=55). So (p+4=11) and (p=7).
Step 3
Exam Tip
ढाल (-(p+4)) है और कमी (5(p+4)=55) होगी। इसलिए (p+4=11) और (p=7) है।
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समीकरण (9y-7x=45) में (x=0) पर (y) का मान और ढाल क्या हैं?
In (9y-7x=45), what are the value of (y) at (x=0) and the slope?
#rearrange_equation
#value_at_zero
#slope
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A (y=5), ढाल \(\frac{7}{9}\) / (y=5), slope \(\frac{7}{9}\)
B (y=-5), ढाल \(-\frac{7}{9}\) / (y=-5), slope \(-\frac{7}{9}\)
C (y=45), ढाल (7) / (y=45), slope (7)
D (y=9), ढाल (-7) / (y=9), slope (-7)
Explanation opens after your attempt
Correct Answer
A. (y=5), ढाल \(\frac{7}{9}\) / (y=5), slope \(\frac{7}{9}\)
Step 1
Concept
From (9y=7x+45), \(y=\frac{7}{9}x+5\). So at (x=0), (y=5) and the slope is \(\frac{7}{9}\).
Step 2
Why this answer is correct
The correct answer is A. (y=5), ढाल \(\frac{7}{9}\) / (y=5), slope \(\frac{7}{9}\). From (9y=7x+45), \(y=\frac{7}{9}x+5\). So at (x=0), (y=5) and the slope is \(\frac{7}{9}\).
Step 3
Exam Tip
(9y=7x+45) से \(y=\frac{7}{9}x+5\) मिलता है। इसलिए (x=0) पर (y=5) और ढाल \(\frac{7}{9}\) है।
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यदि (y=mx+c) में (m+c=21) और (c=8), तो ढाल क्या है?
If (m+c=21) and (c=8) in (y=mx+c), what is the slope?
#slope_intercept_relation
#parameter
#hard
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A (8)
B (11)
C (13)
D (21)
Explanation opens after your attempt
Step 1
Concept
Putting (c=8) gives (m+8=21). Therefore (m=13).
Step 2
Why this answer is correct
The correct answer is C. (13). Putting (c=8) gives (m+8=21). Therefore (m=13).
Step 3
Exam Tip
(c=8) रखने पर (m+8=21) मिलता है। इसलिए (m=13) है।
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यदि (y=mx+c) में ढाल (-7) है और (m+c=5), तो (y)-अवरोध क्या है?
If the slope is (-7) and (m+c=5) in (y=mx+c), what is the (y)-intercept?
#slope_intercept_relation
#find_intercept
#hard
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A (7)
B (10)
C (12)
D (-12)
Explanation opens after your attempt
Step 1
Concept
Slope (-7) gives (m=-7). From (-7+c=5), (c=12).
Step 2
Why this answer is correct
The correct answer is C. (12). Slope (-7) gives (m=-7). From (-7+c=5), (c=12).
Step 3
Exam Tip
ढाल (-7) से (m=-7) है। (-7+c=5) से (c=12) है।
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रेखा \(y=\frac{5}{6}x+c\) बिंदु ((12,19)) से गुजरती है। (c) क्या है?
The line \(y=\frac{5}{6}x+c\) passes through ((12,19)). What is (c)?
#fraction_slope
#find_intercept
#point_given
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A (7)
B (9)
C (8)
D (10)
Explanation opens after your attempt
Step 1
Concept
Substituting the point gives (19=\frac{5}{6}(12)+c). So (19=10+c) and (c=9).
Step 2
Why this answer is correct
The correct answer is B. (9). Substituting the point gives (19=\frac{5}{6}(12)+c). So (19=10+c) and (c=9).
Step 3
Exam Tip
बिंदु रखने पर (19=\frac{5}{6}(12)+c) मिलता है। इसलिए (19=10+c) और (c=9) है।
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रेखा (y=mx-7) बिंदु ((14,0)) से गुजरती है। (m) क्या है?
The line (y=mx-7) passes through ((14,0)). What is (m)?
#find_slope
#point_given
#fraction_slope
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A \(\frac{1}{2}\)
B \(\frac{1}{3}\)
C \(\frac{7}{14}\)
D \(\frac{2}{7}\)
Explanation opens after your attempt
Correct Answer
A. \(\frac{1}{2}\)
Step 1
Concept
Substituting the point gives (0=14m-7). Thus (14m=7) and \(m=\frac{1}{2}\).
Step 2
Why this answer is correct
The correct answer is A. \(\frac{1}{2}\). Substituting the point gives (0=14m-7). Thus (14m=7) and \(m=\frac{1}{2}\).
Step 3
Exam Tip
बिंदु रखने पर (0=14m-7) मिलता है। इससे (14m=7) और \(m=\frac{1}{2}\) है।
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यदि (y=(6a-5)x+(a+4)) का (y)-अवरोध (13) है, तो ढाल क्या है?
If (y=(6a-5)x+(a+4)) has (y)-intercept (13), what is the slope?
#parameter_intercept
#find_slope
#linear_form
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A (49)
B (50)
C (51)
D (52)
Explanation opens after your attempt
Step 1
Concept
From (a+4=13), (a=9). The slope is (6a-5=49).
Step 2
Why this answer is correct
The correct answer is A. (49). From (a+4=13), (a=9). The slope is (6a-5=49).
Step 3
Exam Tip
(a+4=13) से (a=9) मिलता है। ढाल (6a-5=49) है।
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यदि (y=(b-13)x+(3b+1)) की ढाल (4) है, तो (y)-अवरोध क्या है?
If (y=(b-13)x+(3b+1)) has slope (4), what is the (y)-intercept?
#parameter_slope
#find_intercept
#linear_form
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A (49)
B (52)
C (51)
D (50)
Explanation opens after your attempt
Step 1
Concept
From (b-13=4), (b=17). The (y)-intercept is (3b+1=52).
Step 2
Why this answer is correct
The correct answer is B. (52). From (b-13=4), (b=17). The (y)-intercept is (3b+1=52).
Step 3
Exam Tip
(b-13=4) से (b=17) मिलता है। (y)-अवरोध (3b+1=52) है।
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समीकरण (7x-8y+24=0) की ढाल और (y)-अवरोध क्या हैं?
What are the slope and (y)-intercept of (7x-8y+24=0)?
#general_form
#fraction_slope
#rearrange
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A ढाल \(\frac{7}{8}\), (y)-अवरोध (3) / Slope \(\frac{7}{8}\), (y)-intercept (3)
B ढाल \(-\frac{7}{8}\), (y)-अवरोध (-3) / Slope \(-\frac{7}{8}\), (y)-intercept (-3)
C ढाल (8), (y)-अवरोध \(\frac{7}{8}\) / Slope (8), (y)-intercept \(\frac{7}{8}\)
D ढाल (7), (y)-अवरोध (-24) / Slope (7), (y)-intercept (-24)
Explanation opens after your attempt
Correct Answer
A. ढाल \(\frac{7}{8}\), (y)-अवरोध (3) / Slope \(\frac{7}{8}\), (y)-intercept (3)
Step 1
Concept
From (-8y=-7x-24), \(y=\frac{7}{8}x+3\). So the slope is \(\frac{7}{8}\) and the (y)-intercept is (3).
Step 2
Why this answer is correct
The correct answer is A. ढाल \(\frac{7}{8}\), (y)-अवरोध (3) / Slope \(\frac{7}{8}\), (y)-intercept (3). From (-8y=-7x-24), \(y=\frac{7}{8}x+3\). So the slope is \(\frac{7}{8}\) and the (y)-intercept is (3).
Step 3
Exam Tip
(-8y=-7x-24) से \(y=\frac{7}{8}x+3\) मिलता है। इसलिए ढाल \(\frac{7}{8}\) और (y)-अवरोध (3) है।
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यदि (y=(t+5)x-9) और (y=14x+(2t-7)) की ढालें समान हैं, तो दूसरी रेखा का (y)-अवरोध क्या है?
If (y=(t+5)x-9) and (y=14x+(2t-7)) have equal slopes, what is the (y)-intercept of the second line?
#compare_slopes
#find_intercept
#parameter
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A (9)
B (11)
C (13)
D (15)
Explanation opens after your attempt
Step 1
Concept
Equal slopes give (t+5=14) and (t=9). The second line's (y)-intercept is (2t-7=11).
Step 2
Why this answer is correct
The correct answer is B. (11). Equal slopes give (t+5=14) and (t=9). The second line's (y)-intercept is (2t-7=11).
Step 3
Exam Tip
समान ढाल से (t+5=14) और (t=9) है। दूसरी रेखा का (y)-अवरोध (2t-7=11) है।
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यदि (y=5x+(v-9)) और (y=(v+4)x+8) का (y)-अवरोध समान है, तो दूसरी रेखा की ढाल क्या है?
If (y=5x+(v-9)) and (y=(v+4)x+8) have the same (y)-intercept, what is the slope of the second line?
#compare_intercepts
#find_slope
#parameter
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A (19)
B (20)
C (21)
D (22)
Explanation opens after your attempt
Step 1
Concept
Equal (y)-intercepts give (v-9=8) and (v=17). The slope of the second line is (v+4=21).
Step 2
Why this answer is correct
The correct answer is C. (21). Equal (y)-intercepts give (v-9=8) and (v=17). The slope of the second line is (v+4=21).
Step 3
Exam Tip
समान (y)-अवरोध से (v-9=8) और (v=17) है। दूसरी रेखा की ढाल (v+4=21) है।
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रेखा \(y=-\frac{7}{4}x+18\) में (y) को (42) घटाने के लिए (x) कितना बढ़ना चाहिए?
In the line \(y=-\frac{7}{4}x+18\), how much should (x) increase to decrease (y) by (42)?
#negative_fraction_slope
#change_in_x
#rate
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A (20)
B (22)
C (24)
D (28)
Explanation opens after your attempt
Step 1
Concept
The decrease is \(\frac{7}{4}\Delta x\). From \(\frac{7}{4}\Delta x=42\), \(\Delta x=24\).
Step 2
Why this answer is correct
The correct answer is C. (24). The decrease is \(\frac{7}{4}\Delta x\). From \(\frac{7}{4}\Delta x=42\), \(\Delta x=24\).
Step 3
Exam Tip
कमी \(\frac{7}{4}\Delta x\) होगी। \(\frac{7}{4}\Delta x=42\) से \(\Delta x=24\) मिलता है।
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यदि (y=(k+7)x+2) (x) के (5) बढ़ने पर (y) (75) बढ़ाती है, तो (k) क्या है?
If (y=(k+7)x+2) increases (y) by (75) when (x) increases by (5), what is (k)?
#parameter_slope
#total_change
#solve
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A (6)
B (7)
C (8)
D (9)
Explanation opens after your attempt
Step 1
Concept
The slope is (k+7) and (5(k+7)=75). Therefore (k+7=15) and (k=8).
Step 2
Why this answer is correct
The correct answer is C. (8). The slope is (k+7) and (5(k+7)=75). Therefore (k+7=15) and (k=8).
Step 3
Exam Tip
ढाल (k+7) है और (5(k+7)=75)। इसलिए (k+7=15) और (k=8) है।
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यदि (y=mx+c) में (c=-15) और (m-c=26), तो ढाल क्या है?
If (c=-15) and (m-c=26) in (y=mx+c), what is the slope?
#slope_intercept_relation
#parameter
#hard
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A (9)
B (10)
C (11)
D (12)
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Step 1
Concept
Putting (c=-15) gives (m-(-15)=26). Therefore (m=11).
Step 2
Why this answer is correct
The correct answer is C. (11). Putting (c=-15) gives (m-(-15)=26). Therefore (m=11).
Step 3
Exam Tip
(c=-15) रखने पर (m-(-15)=26) मिलता है। इसलिए (m=11) है।
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यदि (y=mx+c) में (m=-5) और (3c+m=31), तो (y)-अवरोध क्या है?
If (m=-5) and (3c+m=31) in (y=mx+c), what is the (y)-intercept?
#slope_intercept_relation
#find_intercept
#hard
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A (10)
B (11)
C (12)
D (13)
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Step 1
Concept
Putting (m=-5) gives (3c-5=31). Thus (3c=36) and (c=12).
Step 2
Why this answer is correct
The correct answer is C. (12). Putting (m=-5) gives (3c-5=31). Thus (3c=36) and (c=12).
Step 3
Exam Tip
(m=-5) रखने पर (3c-5=31) मिलता है। इससे (3c=36) और (c=12) है।
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