रेखा \(y=-\frac{7}{4}x+18\) में (y) को (42) घटाने के लिए (x) कितना बढ़ना चाहिए?

In the line \(y=-\frac{7}{4}x+18\), how much should (x) increase to decrease (y) by (42)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

C. (24)

Step 1

Concept

The decrease is \(\frac{7}{4}\Delta x\). From \(\frac{7}{4}\Delta x=42\), \(\Delta x=24\).

Step 2

Why this answer is correct

The correct answer is C. (24). The decrease is \(\frac{7}{4}\Delta x\). From \(\frac{7}{4}\Delta x=42\), \(\Delta x=24\).

Step 3

Exam Tip

कमी \(\frac{7}{4}\Delta x\) होगी। \(\frac{7}{4}\Delta x=42\) से \(\Delta x=24\) मिलता है।

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Mathematics Answer, Explanation and Revision Hints

रेखा \(y=-\frac{7}{4}x+18\) में (y) को (42) घटाने के लिए (x) कितना बढ़ना चाहिए? / In the line \(y=-\frac{7}{4}x+18\), how much should (x) increase to decrease (y) by (42)?

Correct Answer: C. (24). Explanation: कमी \(\frac{7}{4}\Delta x\) होगी। \(\frac{7}{4}\Delta x=42\) से \(\Delta x=24\) मिलता है। / The decrease is \(\frac{7}{4}\Delta x\). From \(\frac{7}{4}\Delta x=42\), \(\Delta x=24\).

Which concept should I revise for this Mathematics MCQ?

The decrease is \(\frac{7}{4}\Delta x\). From \(\frac{7}{4}\Delta x=42\), \(\Delta x=24\).

What exam hint can help solve this Mathematics question?

कमी \(\frac{7}{4}\Delta x\) होगी। \(\frac{7}{4}\Delta x=42\) से \(\Delta x=24\) मिलता है।