समीकरण \(x^2-6x-7=0\) के मूलों का अंतर कितना है?
What is the difference between the roots of \(x^2-6x-7=0\)?
#roots
#difference_of_roots
#factorisation
A (8)
B (6)
C (7)
D (1)
Explanation opens after your attempt
Step 1
Concept
(x-2 -6x-7=(x-7)(x+1)). The roots are (7) and (-1), so the difference is (8).
Step 2
Why this answer is correct
The correct answer is A. (8). (x-2 -6x-7=(x-7)(x+1)). The roots are (7) and (-1), so the difference is (8).
Step 3
Exam Tip
(x-2 -6x-7=(x-7)(x+1)) है। मूल (7) और (-1) हैं इसलिए अंतर (8) है।
Login to save your score, XP, coins and progress. Login
समीकरण \(x^2-5x-24=0\) का धनात्मक मूल कौन सा है?
What is the positive root of \(x^2-5x-24=0\)?
#roots
#positive_root
#factorisation
A (8)
B (-3)
C (3)
D (-8)
Explanation opens after your attempt
Step 1
Concept
(x-2 -5x-24=(x-8)(x+3)). Therefore the roots are (8) and (-3), and the positive root is (8).
Step 2
Why this answer is correct
The correct answer is A. (8). (x-2 -5x-24=(x-8)(x+3)). Therefore the roots are (8) and (-3), and the positive root is (8).
Step 3
Exam Tip
(x-2 -5x-24=(x-8)(x+3)) है। इसलिए मूल (8) और (-3) हैं तथा धनात्मक मूल (8) है।
Login to save your score, XP, coins and progress. Login
समीकरण \(3x^2+2x-8=0\) के मूल कौन से हैं?
What are the roots of \(3x^2+2x-8=0\)?
#roots
#factorisation
#medium
A \(\frac{4}{3}\) और (-2) / \(\frac{4}{3}\) and (-2)
B -\(\frac{4}{3}\) और (2) / \(-\frac{4}{3}\) and (2)
C (4) और (-2) / (4) and (-2)
D (2) और (-4) / (2) and (-4)
Explanation opens after your attempt
Correct Answer
A. \(\frac{4}{3}\) और (-2) / \(\frac{4}{3}\) and (-2)
Step 1
Concept
(3x-2 +2x-8=(3x-4)(x+2)). Therefore the roots are \(\frac{4}{3}\) and (-2).
Step 2
Why this answer is correct
The correct answer is A. \(\frac{4}{3}\) और (-2) / \(\frac{4}{3}\) and (-2). (3x-2 +2x-8=(3x-4)(x+2)). Therefore the roots are \(\frac{4}{3}\) and (-2).
Step 3
Exam Tip
(3x-2 +2x-8=(3x-4)(x+2)) है। इसलिए मूल \(\frac{4}{3}\) और (-2) हैं।
Login to save your score, XP, coins and progress. Login
समीकरण \(x^2+x-20=0\) के मूल कौन से हैं?
What are the roots of \(x^2+x-20=0\)?
#roots
#factorisation
#mixed_signs
A (4) और (-5) / (4) and (-5)
B (5) और (-4) / (5) and (-4)
C (4) और (5) / (4) and (5)
D (-4) और (-5) / (-4) and (-5)
Explanation opens after your attempt
Correct Answer
A. (4) और (-5) / (4) and (-5)
Step 1
Concept
(x-2 +x-20=(x+5)(x-4)). Therefore the roots are (-5) and (4).
Step 2
Why this answer is correct
The correct answer is A. (4) और (-5) / (4) and (-5). (x-2 +x-20=(x+5)(x-4)). Therefore the roots are (-5) and (4).
Step 3
Exam Tip
(x-2 +x-20=(x+5)(x-4)) है। इसलिए मूल (-5) और (4) हैं।
Login to save your score, XP, coins and progress. Login
समीकरण \(2x^2+9x+4=0\) के मूल कौन से हैं?
What are the roots of \(2x^2+9x+4=0\)?
#roots
#factorisation
#negative_fraction
A (-4) और \(-\frac{1}{2}\) / (-4) and \(-\frac{1}{2}\)
B (4) और \(\frac{1}{2}\) / (4) and \(\frac{1}{2}\)
C (-2) और (-4) / (-2) and (-4)
D (2) और (4) / (2) and (4)
Explanation opens after your attempt
Correct Answer
A. (-4) और \(-\frac{1}{2}\) / (-4) and \(-\frac{1}{2}\)
Step 1
Concept
(2x-2 +9x+4=(2x+1)(x+4)). Therefore the roots are \(-\frac{1}{2}\) and (-4).
Step 2
Why this answer is correct
The correct answer is A. (-4) और \(-\frac{1}{2}\) / (-4) and \(-\frac{1}{2}\). (2x-2 +9x+4=(2x+1)(x+4)). Therefore the roots are \(-\frac{1}{2}\) and (-4).
Step 3
Exam Tip
(2x-2 +9x+4=(2x+1)(x+4)) है। इसलिए मूल \(-\frac{1}{2}\) और (-4) हैं।
Login to save your score, XP, coins and progress. Login
समीकरण \(3x^2-13x+4=0\) के मूल कौन से हैं?
What are the roots of \(3x^2-13x+4=0\)?
#roots
#factorisation
#fraction_root
A (4) और \(\frac{1}{3}\) / (4) and \(\frac{1}{3}\)
B (-4) और \(-\frac{1}{3}\) / (-4) and \(-\frac{1}{3}\)
C (3) और (4) / (3) and (4)
D \(\frac{4}{3}\) और (1) / \(\frac{4}{3}\) and (1)
Explanation opens after your attempt
Correct Answer
A. (4) और \(\frac{1}{3}\) / (4) and \(\frac{1}{3}\)
Step 1
Concept
(3x-2 -13x+4=(3x-1)(x-4)). Therefore the roots are \(\frac{1}{3}\) and (4).
Step 2
Why this answer is correct
The correct answer is A. (4) और \(\frac{1}{3}\) / (4) and \(\frac{1}{3}\). (3x-2 -13x+4=(3x-1)(x-4)). Therefore the roots are \(\frac{1}{3}\) and (4).
Step 3
Exam Tip
(3x-2 -13x+4=(3x-1)(x-4)) है। इसलिए मूल \(\frac{1}{3}\) और (4) हैं।
Login to save your score, XP, coins and progress. Login
समीकरण \(x^2-12x+35=0\) के मूल कौन से हैं?
What are the roots of \(x^2-12x+35=0\)?
#roots
#factorisation
#numerical
A (5) और (7) / (5) and (7)
B (1) और (35) / (1) and (35)
C (-5) और (-7) / (-5) and (-7)
D (0) और (12) / (0) and (12)
Explanation opens after your attempt
Correct Answer
A. (5) और (7) / (5) and (7)
Step 1
Concept
(x-2 -12x+35=(x-5)(x-7)). Therefore the roots are (5) and (7).
Step 2
Why this answer is correct
The correct answer is A. (5) और (7) / (5) and (7). (x-2 -12x+35=(x-5)(x-7)). Therefore the roots are (5) and (7).
Step 3
Exam Tip
(x-2 -12x+35=(x-5)(x-7)) है। इसलिए मूल (5) और (7) हैं।
Login to save your score, XP, coins and progress. Login
समीकरण \(6x^2-7x+2=0\) के मूल कौन से हैं?
What are the roots of \(6x^2-7x+2=0\)?
#roots
#factorisation
#fraction_roots
A \(\frac{1}{2}\) और \(\frac{2}{3}\) / \(\frac{1}{2}\) and \(\frac{2}{3}\)
B -\(\frac{1}{2}\) और \(-\frac{2}{3}\) / \(-\frac{1}{2}\) and \(-\frac{2}{3}\)
C (2) और (3) / (2) and (3)
D \(\frac{3}{2}\) और \(\frac{1}{3}\) / \(\frac{3}{2}\) and \(\frac{1}{3}\)
Explanation opens after your attempt
Correct Answer
A. \(\frac{1}{2}\) और \(\frac{2}{3}\) / \(\frac{1}{2}\) and \(\frac{2}{3}\)
Step 1
Concept
(6x-2 -7x+2=(3x-2)(2x-1)). Therefore the roots are \(\frac{2}{3}\) and \(\frac{1}{2}\).
Step 2
Why this answer is correct
The correct answer is A. \(\frac{1}{2}\) और \(\frac{2}{3}\) / \(\frac{1}{2}\) and \(\frac{2}{3}\). (6x-2 -7x+2=(3x-2)(2x-1)). Therefore the roots are \(\frac{2}{3}\) and \(\frac{1}{2}\).
Step 3
Exam Tip
(6x-2 -7x+2=(3x-2)(2x-1)) है। इसलिए मूल \(\frac{2}{3}\) और \(\frac{1}{2}\) हैं।
Login to save your score, XP, coins and progress. Login
समीकरण \(x^2-4x-5=0\) के मूलों का अंतर कितना है?
What is the difference between the roots of \(x^2-4x-5=0\)?
#roots
#difference_of_roots
#factorisation
A (6)
B (4)
C (5)
D (1)
Explanation opens after your attempt
Step 1
Concept
(x-2 -4x-5=(x-5)(x+1)). The roots are (5) and (-1), so the difference is (6).
Step 2
Why this answer is correct
The correct answer is A. (6). (x-2 -4x-5=(x-5)(x+1)). The roots are (5) and (-1), so the difference is (6).
Step 3
Exam Tip
(x-2 -4x-5=(x-5)(x+1)) है। मूल (5) और (-1) हैं इसलिए अंतर (6) है।
Login to save your score, XP, coins and progress. Login
समीकरण \(x^2-3x-18=0\) का धनात्मक मूल कौन सा है?
What is the positive root of \(x^2-3x-18=0\)?
#roots
#positive_root
#factorisation
A (6)
B (-3)
C (3)
D (-6)
Explanation opens after your attempt
Step 1
Concept
(x-2 -3x-18=(x-6)(x+3)). Therefore the roots are (6) and (-3), and the positive root is (6).
Step 2
Why this answer is correct
The correct answer is A. (6). (x-2 -3x-18=(x-6)(x+3)). Therefore the roots are (6) and (-3), and the positive root is (6).
Step 3
Exam Tip
(x-2 -3x-18=(x-6)(x+3)) है। इसलिए मूल (6) और (-3) हैं तथा धनात्मक मूल (6) है।
Login to save your score, XP, coins and progress. Login
समीकरण \(2x^2+x-6=0\) के मूल कौन से हैं?
What are the roots of \(2x^2+x-6=0\)?
#roots
#factorisation
#medium
A \(\frac{3}{2}\) और (-2) / \(\frac{3}{2}\) and (-2)
B \(-\frac{3}{2}\) और (2) / \(-\frac{3}{2}\) and (2)
C (3) और (-2) / (3) and (-2)
D (2) और (-3) / (2) and (-3)
Explanation opens after your attempt
Correct Answer
A. \(\frac{3}{2}\) और (-2) / \(\frac{3}{2}\) and (-2)
Step 1
Concept
(2x-2 +x-6=(2x-3)(x+2)). Therefore the roots are \(\frac{3}{2}\) and (-2).
Step 2
Why this answer is correct
The correct answer is A. \(\frac{3}{2}\) और (-2) / \(\frac{3}{2}\) and (-2). (2x-2 +x-6=(2x-3)(x+2)). Therefore the roots are \(\frac{3}{2}\) and (-2).
Step 3
Exam Tip
(2x-2 +x-6=(2x-3)(x+2)) है। इसलिए मूल \(\frac{3}{2}\) और (-2) हैं।
Login to save your score, XP, coins and progress. Login
समीकरण \(x^2-2x-15=0\) के मूल कौन से हैं?
What are the roots of \(x^2-2x-15=0\)?
#roots
#factorisation
#mixed_signs
A (5) और (-3) / (5) and (-3)
B (3) और (-5) / (3) and (-5)
C (5) और (3) / (5) and (3)
D (-5) और (-3) / (-5) and (-3)
Explanation opens after your attempt
Correct Answer
A. (5) और (-3) / (5) and (-3)
Step 1
Concept
(x-2 -2x-15=(x-5)(x+3)). Therefore the roots are (5) and (-3).
Step 2
Why this answer is correct
The correct answer is A. (5) और (-3) / (5) and (-3). (x-2 -2x-15=(x-5)(x+3)). Therefore the roots are (5) and (-3).
Step 3
Exam Tip
(x-2 -2x-15=(x-5)(x+3)) है। इसलिए मूल (5) और (-3) हैं।
Login to save your score, XP, coins and progress. Login
समीकरण \(3x^2+10x+3=0\) के मूल कौन से हैं?
What are the roots of \(3x^2+10x+3=0\)?
#roots
#factorisation
#negative_fraction
A (-3) और \(-\frac{1}{3}\) / (-3) and \(-\frac{1}{3}\)
B (3) और \(\frac{1}{3}\) / (3) and \(\frac{1}{3}\)
C (-1) और (-3) / (-1) and (-3)
D (1) और (3) / (1) and (3)
Explanation opens after your attempt
Correct Answer
A. (-3) और \(-\frac{1}{3}\) / (-3) and \(-\frac{1}{3}\)
Step 1
Concept
(3x-2 +10x+3=(3x+1)(x+3)). Therefore the roots are \(-\frac{1}{3}\) and (-3).
Step 2
Why this answer is correct
The correct answer is A. (-3) और \(-\frac{1}{3}\) / (-3) and \(-\frac{1}{3}\). (3x-2 +10x+3=(3x+1)(x+3)). Therefore the roots are \(-\frac{1}{3}\) and (-3).
Step 3
Exam Tip
(3x-2 +10x+3=(3x+1)(x+3)) है। इसलिए मूल \(-\frac{1}{3}\) और (-3) हैं।
Login to save your score, XP, coins and progress. Login
समीकरण \(2x^2-7x+3=0\) के मूल कौन से हैं?
What are the roots of \(2x^2-7x+3=0\)?
#roots
#factorisation
#fraction_root
A (3) और \(\frac{1}{2}\) / (3) and \(\frac{1}{2}\)
B (-3) और \(-\frac{1}{2}\) / (-3) and \(-\frac{1}{2}\)
C (2) और (3) / (2) and (3)
D \(\frac{3}{2}\) और (1) / \(\frac{3}{2}\) and (1)
Explanation opens after your attempt
Correct Answer
A. (3) और \(\frac{1}{2}\) / (3) and \(\frac{1}{2}\)
Step 1
Concept
(2x-2 -7x+3=(2x-1)(x-3)). Therefore the roots are \(\frac{1}{2}\) and (3).
Step 2
Why this answer is correct
The correct answer is A. (3) और \(\frac{1}{2}\) / (3) and \(\frac{1}{2}\). (2x-2 -7x+3=(2x-1)(x-3)). Therefore the roots are \(\frac{1}{2}\) and (3).
Step 3
Exam Tip
(2x-2 -7x+3=(2x-1)(x-3)) है। इसलिए मूल \(\frac{1}{2}\) और (3) हैं।
Login to save your score, XP, coins and progress. Login
समीकरण \(x^2-11x+28=0\) के मूल कौन से हैं?
What are the roots of \(x^2-11x+28=0\)?
#roots
#factorisation
#numerical
A (4) और (7) / (4) and (7)
B (2) और (14) / (2) and (14)
C (-4) और (-7) / (-4) and (-7)
D (1) और (28) / (1) and (28)
Explanation opens after your attempt
Correct Answer
A. (4) और (7) / (4) and (7)
Step 1
Concept
(x-2 -11x+28=(x-4)(x-7)). Therefore the roots are (4) and (7).
Step 2
Why this answer is correct
The correct answer is A. (4) और (7) / (4) and (7). (x-2 -11x+28=(x-4)(x-7)). Therefore the roots are (4) and (7).
Step 3
Exam Tip
(x-2 -11x+28=(x-4)(x-7)) है। इसलिए मूल (4) और (7) हैं।
Login to save your score, XP, coins and progress. Login
समीकरण \(4x^2-12x+9=0\) के मूल कौन से हैं?
What are the roots of \(4x^2-12x+9=0\)?
#roots
#factorisation
#fraction_root
A \( \frac{3}{2} \) और \( \frac{3}{2} \) / \( \frac{3}{2} \) and \( \frac{3}{2} \)
B \(-\frac{3}{2}\) और \(-\frac{3}{2}\) / \(-\frac{3}{2}\) and \(-\frac{3}{2}\)
C (2) और (3) / (2) and (3)
D \(\frac{2}{3}\) और \(\frac{2}{3}\) / \(\frac{2}{3}\) and \(\frac{2}{3}\)
Explanation opens after your attempt
Correct Answer
A. \( \frac{3}{2} \) और \( \frac{3}{2} \) / \( \frac{3}{2} \) and \( \frac{3}{2} \)
Step 1
Concept
(4x-2 -12x+9=(2x-3)2 ). Therefore the repeated root is \(\frac{3}{2}\).
Step 2
Why this answer is correct
The correct answer is A. \( \frac{3}{2} \) और \( \frac{3}{2} \) / \( \frac{3}{2} \) and \( \frac{3}{2} \). (4x-2 -12x+9=(2x-3)2 ). Therefore the repeated root is \(\frac{3}{2}\).
Step 3
Exam Tip
(4x-2 -12x+9=(2x-3)2 ) है। इसलिए दोहराया मूल \(\frac{3}{2}\) है।
Login to save your score, XP, coins and progress. Login
समीकरण \(x^2+x-12=0\) के मूल कौन से हैं?
What are the roots of \(x^2+x-12=0\)?
#roots
#factorisation
#mixed_signs
A (3) और (-4) / (3) and (-4)
B (4) और (-3) / (4) and (-3)
C (-3) और (-4) / (-3) and (-4)
D (3) और (4) / (3) and (4)
Explanation opens after your attempt
Correct Answer
A. (3) और (-4) / (3) and (-4)
Step 1
Concept
(x-2 +x-12=(x+4)(x-3)). Therefore the roots are (-4) and (3).
Step 2
Why this answer is correct
The correct answer is A. (3) और (-4) / (3) and (-4). (x-2 +x-12=(x+4)(x-3)). Therefore the roots are (-4) and (3).
Step 3
Exam Tip
(x-2 +x-12=(x+4)(x-3)) है। इसलिए मूल (-4) और (3) हैं।
Login to save your score, XP, coins and progress. Login
समीकरण \(x^2-6x+9=0\) के मूल कौन से हैं?
What are the roots of \(x^2-6x+9=0\)?
#roots
#factorisation
#basic
A (3) और (3) / (3) and (3)
B (-3) और (-3) / (-3) and (-3)
C (0) और (9) / (0) and (9)
D (6) और (9) / (6) and (9)
Explanation opens after your attempt
Correct Answer
A. (3) और (3) / (3) and (3)
Step 1
Concept
(x-2 -6x+9=(x-3)2 ). Therefore both roots are (3).
Step 2
Why this answer is correct
The correct answer is A. (3) और (3) / (3) and (3). (x-2 -6x+9=(x-3)2 ). Therefore both roots are (3).
Step 3
Exam Tip
(x-2 -6x+9=(x-3)2 ) है। इसलिए दोनों मूल (3) हैं।
Login to save your score, XP, coins and progress. Login
समीकरण \(4x^2-20x=0\) के मूल कौन से हैं?
What are the roots of \(4x^2-20x=0\)?
#roots
#common_factor
#factorisation
A (0) और (5) / (0) and (5)
B (4) और (5) / (4) and (5)
C (-5) और (0) / (-5) and (0)
D (0) और (20) / (0) and (20)
Explanation opens after your attempt
Correct Answer
A. (0) और (5) / (0) and (5)
Step 1
Concept
(4x-2 -20x=4x(x-5)). Therefore the roots are (0) and (5).
Step 2
Why this answer is correct
The correct answer is A. (0) और (5) / (0) and (5). (4x-2 -20x=4x(x-5)). Therefore the roots are (0) and (5).
Step 3
Exam Tip
(4x-2 -20x=4x(x-5)) है। इसलिए मूल (0) और (5) हैं।
Login to save your score, XP, coins and progress. Login
समीकरण \(x^2-11x+30=0\) का एक मूल (5) है तो दूसरा मूल क्या है?
If one root of \(x^2-11x+30=0\) is (5), what is the other root?
#roots
#other_root
#factorisation
A (5)
B (6)
C (11)
D (30)
Explanation opens after your attempt
Step 1
Concept
(x-2 -11x+30=(x-5)(x-6)). Therefore the other root is (6).
Step 2
Why this answer is correct
The correct answer is B. (6). (x-2 -11x+30=(x-5)(x-6)). Therefore the other root is (6).
Step 3
Exam Tip
(x-2 -11x+30=(x-5)(x-6)) है। इसलिए दूसरा मूल (6) है।
Login to save your score, XP, coins and progress. Login
समीकरण \(x^2=4x\) के मूल कौन से हैं?
What are the roots of \(x^2=4x\)?
#roots
#standard_form
#factorisation
A (0) और (4) / (0) and (4)
B (1) और (4) / (1) and (4)
C (0) और (-4) / (0) and (-4)
D (2) और (4) / (2) and (4)
Explanation opens after your attempt
Correct Answer
A. (0) और (4) / (0) and (4)
Step 1
Concept
Write \(x^2=4x\) as \(x^2-4x=0\). Then (x(x-4)=0) gives roots (0) and (4).
Step 2
Why this answer is correct
The correct answer is A. (0) और (4) / (0) and (4). Write \(x^2=4x\) as \(x^2-4x=0\). Then (x(x-4)=0) gives roots (0) and (4).
Step 3
Exam Tip
\(x^2=4x\) को \(x^2-4x=0\) लिखें। फिर (x(x-4)=0) से मूल (0) और (4) मिलते हैं।
Login to save your score, XP, coins and progress. Login
समीकरण \(x^2+10x+21=0\) के मूल कौन से हैं?
What are the roots of \(x^2+10x+21=0\)?
#roots
#factorisation
#signs
A (-3) और (-7) / (-3) and (-7)
B (3) और (7) / (3) and (7)
C (-1) और (-21) / (-1) and (-21)
D (1) और (21) / (1) and (21)
Explanation opens after your attempt
Correct Answer
A. (-3) और (-7) / (-3) and (-7)
Step 1
Concept
(x-2 +10x+21=(x+3)(x+7)). Therefore the roots are (-3) and (-7).
Step 2
Why this answer is correct
The correct answer is A. (-3) और (-7) / (-3) and (-7). (x-2 +10x+21=(x+3)(x+7)). Therefore the roots are (-3) and (-7).
Step 3
Exam Tip
(x-2 +10x+21=(x+3)(x+7)) है। इसलिए मूल (-3) और (-7) हैं।
Login to save your score, XP, coins and progress. Login
समीकरण \(x^2-8x+15=0\) के मूल कौन से हैं?
What are the roots of \(x^2-8x+15=0\)?
#roots
#factorisation
#numerical
A (3) और (5) / (3) and (5)
B (-3) और (-5) / (-3) and (-5)
C (1) और (15) / (1) and (15)
D (0) और (8) / (0) and (8)
Explanation opens after your attempt
Correct Answer
A. (3) और (5) / (3) and (5)
Step 1
Concept
(x-2 -8x+15=(x-3)(x-5)). Therefore the roots are (3) and (5).
Step 2
Why this answer is correct
The correct answer is A. (3) और (5) / (3) and (5). (x-2 -8x+15=(x-3)(x-5)). Therefore the roots are (3) and (5).
Step 3
Exam Tip
(x-2 -8x+15=(x-3)(x-5)) है। इसलिए मूल (3) और (5) हैं।
Login to save your score, XP, coins and progress. Login
समीकरण \(x^2-36=0\) के मूल कौन से हैं?
What are the roots of \(x^2-36=0\)?
#roots
#difference_of_squares
#factorisation
A (6) और (-6) / (6) and (-6)
B (36) और (-36) / (36) and (-36)
C (0) और (6) / (0) and (6)
D केवल (6) / Only (6)
Explanation opens after your attempt
Correct Answer
A. (6) और (-6) / (6) and (-6)
Step 1
Concept
(x-2 -36=(x-6)(x+6)). Therefore the roots are (6) and (-6).
Step 2
Why this answer is correct
The correct answer is A. (6) और (-6) / (6) and (-6). (x-2 -36=(x-6)(x+6)). Therefore the roots are (6) and (-6).
Step 3
Exam Tip
(x-2 -36=(x-6)(x+6)) है। इसलिए मूल (6) और (-6) हैं।
Login to save your score, XP, coins and progress. Login
समीकरण \(3x^2-10x+3=0\) के मूल कौन से हैं?
What are the roots of \(3x^2-10x+3=0\)?
#roots
#factorisation
#fraction_root
A (3) और \(\frac{1}{3}\) / (3) and \(\frac{1}{3}\)
B (1) और (3) / (1) and (3)
C (-3) और \(-\frac{1}{3}\) / (-3) and \(-\frac{1}{3}\)
D \(\frac{3}{2}\) और (2) / \(\frac{3}{2}\) and (2)
Explanation opens after your attempt
Correct Answer
A. (3) और \(\frac{1}{3}\) / (3) and \(\frac{1}{3}\)
Step 1
Concept
(3x-2 -10x+3=(3x-1)(x-3)). Therefore the roots are \(\frac{1}{3}\) and (3).
Step 2
Why this answer is correct
The correct answer is A. (3) और \(\frac{1}{3}\) / (3) and \(\frac{1}{3}\). (3x-2 -10x+3=(3x-1)(x-3)). Therefore the roots are \(\frac{1}{3}\) and (3).
Step 3
Exam Tip
(3x-2 -10x+3=(3x-1)(x-3)) है। इसलिए मूल \(\frac{1}{3}\) और (3) हैं।
Login to save your score, XP, coins and progress. Login
समीकरण \(x^2-3x-10=0\) के मूल कौन से हैं?
What are the roots of \(x^2-3x-10=0\)?
#roots
#factorisation
#mixed_signs
A (5) और (-2) / (5) and (-2)
B (2) और (-5) / (2) and (-5)
C (-5) और (-2) / (-5) and (-2)
D (5) और (2) / (5) and (2)
Explanation opens after your attempt
Correct Answer
A. (5) और (-2) / (5) and (-2)
Step 1
Concept
(x-2 -3x-10=(x-5)(x+2)). Therefore the roots are (5) and (-2).
Step 2
Why this answer is correct
The correct answer is A. (5) और (-2) / (5) and (-2). (x-2 -3x-10=(x-5)(x+2)). Therefore the roots are (5) and (-2).
Step 3
Exam Tip
(x-2 -3x-10=(x-5)(x+2)) है। इसलिए मूल (5) और (-2) हैं।
Login to save your score, XP, coins and progress. Login
समीकरण \(x^2-5x+6=0\) के मूल कौन से हैं?
What are the roots of \(x^2-5x+6=0\)?
#roots
#factorisation
#basic
A (2) और (3) / (2) and (3)
B (-2) और (-3) / (-2) and (-3)
C (1) और (6) / (1) and (6)
D (0) और (6) / (0) and (6)
Explanation opens after your attempt
Correct Answer
A. (2) और (3) / (2) and (3)
Step 1
Concept
(x-2 -5x+6=(x-2)(x-3)). Therefore the roots are (2) and (3).
Step 2
Why this answer is correct
The correct answer is A. (2) और (3) / (2) and (3). (x-2 -5x+6=(x-2)(x-3)). Therefore the roots are (2) and (3).
Step 3
Exam Tip
(x-2 -5x+6=(x-2)(x-3)) है। इसलिए मूल (2) और (3) हैं।
Login to save your score, XP, coins and progress. Login
समीकरण \(2x^2-10x=0\) के मूल कौन से हैं?
What are the roots of \(2x^2-10x=0\)?
#roots
#common_factor
#factorisation
A (0) और (5) / (0) and (5)
B (2) और (5) / (2) and (5)
C (-5) और (0) / (-5) and (0)
D (0) और (10) / (0) and (10)
Explanation opens after your attempt
Correct Answer
A. (0) और (5) / (0) and (5)
Step 1
Concept
(2x-2 -10x=2x(x-5)). Therefore the roots are (0) and (5).
Step 2
Why this answer is correct
The correct answer is A. (0) और (5) / (0) and (5). (2x-2 -10x=2x(x-5)). Therefore the roots are (0) and (5).
Step 3
Exam Tip
(2x-2 -10x=2x(x-5)) है। इसलिए मूल (0) और (5) हैं।
Login to save your score, XP, coins and progress. Login
समीकरण \(x^2-9x+18=0\) का एक मूल (3) है तो दूसरा मूल क्या है?
If one root of \(x^2-9x+18=0\) is (3), what is the other root?
#roots
#other_root
#factorisation
A (3)
B (6)
C (9)
D (18)
Explanation opens after your attempt
Step 1
Concept
(x-2 -9x+18=(x-3)(x-6)). Therefore the other root is (6).
Step 2
Why this answer is correct
The correct answer is B. (6). (x-2 -9x+18=(x-3)(x-6)). Therefore the other root is (6).
Step 3
Exam Tip
(x-2 -9x+18=(x-3)(x-6)) है। इसलिए दूसरा मूल (6) है।
Login to save your score, XP, coins and progress. Login
समीकरण \(x^2=9x\) के मूल कौन से हैं?
What are the roots of \(x^2=9x\)?
#roots
#standard_form
#factorisation
A (0) और (9) / (0) and (9)
B (1) और (9) / (1) and (9)
C (0) और (-9) / (0) and (-9)
D (3) और (9) / (3) and (9)
Explanation opens after your attempt
Correct Answer
A. (0) और (9) / (0) and (9)
Step 1
Concept
Write \(x^2=9x\) as \(x^2-9x=0\). Then (x(x-9)=0) gives roots (0) and (9).
Step 2
Why this answer is correct
The correct answer is A. (0) और (9) / (0) and (9). Write \(x^2=9x\) as \(x^2-9x=0\). Then (x(x-9)=0) gives roots (0) and (9).
Step 3
Exam Tip
\(x^2=9x\) को \(x^2-9x=0\) लिखें। फिर (x(x-9)=0) से मूल (0) और (9) मिलते हैं।
Login to save your score, XP, coins and progress. Login
