समीकरण \(x^2+9x+20=0\) के मूल कौन से हैं?
What are the roots of \(x^2+9x+20=0\)?
#roots
#factorisation
#signs
A (-4) और (-5) / (-4) and (-5)
B (4) और (5) / (4) and (5)
C (-2) और (-10) / (-2) and (-10)
D (2) और (10) / (2) and (10)
Explanation opens after your attempt
Correct Answer
A. (-4) और (-5) / (-4) and (-5)
Step 1
Concept
(x-2 +9x+20=(x+4)(x+5)). Therefore the roots are (-4) and (-5).
Step 2
Why this answer is correct
The correct answer is A. (-4) और (-5) / (-4) and (-5). (x-2 +9x+20=(x+4)(x+5)). Therefore the roots are (-4) and (-5).
Step 3
Exam Tip
(x-2 +9x+20=(x+4)(x+5)) है। इसलिए मूल (-4) और (-5) हैं।
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समीकरण \(x^2-7x+12=0\) के मूल कौन से हैं?
What are the roots of \(x^2-7x+12=0\)?
#roots
#factorisation
#numerical
A (3) और (4) / (3) and (4)
B (-3) और (-4) / (-3) and (-4)
C (2) और (6) / (2) and (6)
D (1) और (12) / (1) and (12)
Explanation opens after your attempt
Correct Answer
A. (3) और (4) / (3) and (4)
Step 1
Concept
(x-2 -7x+12=(x-3)(x-4)). Therefore the roots are (3) and (4).
Step 2
Why this answer is correct
The correct answer is A. (3) और (4) / (3) and (4). (x-2 -7x+12=(x-3)(x-4)). Therefore the roots are (3) and (4).
Step 3
Exam Tip
(x-2 -7x+12=(x-3)(x-4)) है। इसलिए मूल (3) और (4) हैं।
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समीकरण \(x^2-25=0\) के मूल कौन से हैं?
What are the roots of \(x^2-25=0\)?
#roots
#difference_of_squares
#factorisation
A (5) और (-5) / (5) and (-5)
B (25) और (-25) / (25) and (-25)
C (0) और (5) / (0) and (5)
D केवल (5) / Only (5)
Explanation opens after your attempt
Correct Answer
A. (5) और (-5) / (5) and (-5)
Step 1
Concept
(x-2 -25=(x-5)(x+5)). Therefore the roots are (5) and (-5).
Step 2
Why this answer is correct
The correct answer is A. (5) और (-5) / (5) and (-5). (x-2 -25=(x-5)(x+5)). Therefore the roots are (5) and (-5).
Step 3
Exam Tip
(x-2 -25=(x-5)(x+5)) है। इसलिए मूल (5) और (-5) हैं।
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समीकरण \(2x^2-5x+3=0\) के मूल कौन से हैं?
What are the roots of \(2x^2-5x+3=0\)?
#roots
#factorisation
#coefficient
A (1) और \(\frac{3}{2}\) / (1) and \(\frac{3}{2}\)
B (-1) और \(\frac{3}{2}\) / (-1) and \(\frac{3}{2}\)
C (2) और (3) / (2) and (3)
D \(\frac{1}{2}\) और (3) / \(\frac{1}{2}\) and (3)
Explanation opens after your attempt
Correct Answer
A. (1) और \(\frac{3}{2}\) / (1) and \(\frac{3}{2}\)
Step 1
Concept
(2x-2 -5x+3=(2x-3)(x-1)) so the roots are \(\frac{3}{2}\) and (1). Be careful with factors that contain coefficients.
Step 2
Why this answer is correct
The correct answer is A. (1) और \(\frac{3}{2}\) / (1) and \(\frac{3}{2}\). (2x-2 -5x+3=(2x-3)(x-1)) so the roots are \(\frac{3}{2}\) and (1). Be careful with factors that contain coefficients.
Step 3
Exam Tip
(2x-2 -5x+3=(2x-3)(x-1)) इसलिए मूल \(\frac{3}{2}\) और (1) हैं। गुणांक वाले गुणनखंडों में सावधानी रखें।
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समीकरण \(x^2+2x-8=0\) के मूल कौन से हैं?
What are the roots of \(x^2+2x-8=0\)?
#roots
#factorisation
#mixed_signs
A (4) और (-2) / (4) and (-2)
B (2) और (-4) / (2) and (-4)
C (-2) और (-4) / (-2) and (-4)
D (2) और (4) / (2) and (4)
Explanation opens after your attempt
Correct Answer
B. (2) और (-4) / (2) and (-4)
Step 1
Concept
(x-2 +2x-8=(x+4)(x-2)) so the roots are (-4) and (2). Roots have opposite signs to the factor constants.
Step 2
Why this answer is correct
The correct answer is B. (2) और (-4) / (2) and (-4). (x-2 +2x-8=(x+4)(x-2)) so the roots are (-4) and (2). Roots have opposite signs to the factor constants.
Step 3
Exam Tip
(x-2 +2x-8=(x+4)(x-2)) इसलिए मूल (-4) और (2) हैं। गुणनखंड के चिन्ह उलटकर मूल मिलते हैं।
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सूत्र या गुणनखंडन से \(x^2-3x+2=0\) के मूल कौन से हैं?
Using formula or factorisation what are the roots of \(x^2-3x+2=0\)?
#roots
#factorisation
#formula_check
A (1) और (2) / (1) and (2)
B (-1) और (-2) / (-1) and (-2)
C (0) और (3) / (0) and (3)
D (2) और (3) / (2) and (3)
Explanation opens after your attempt
Correct Answer
A. (1) और (2) / (1) and (2)
Step 1
Concept
(x-2 -3x+2=(x-1)(x-2)) so the roots are (1) and (2). For small numbers factorisation is faster.
Step 2
Why this answer is correct
The correct answer is A. (1) और (2) / (1) and (2). (x-2 -3x+2=(x-1)(x-2)) so the roots are (1) and (2). For small numbers factorisation is faster.
Step 3
Exam Tip
(x-2 -3x+2=(x-1)(x-2)) इसलिए मूल (1) और (2) हैं। छोटे अंकों में गुणनखंडन तेज रहता है।
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समीकरण \(3x^2-12x=0\) के मूल कौन से हैं?
What are the roots of \(3x^2-12x=0\)?
#roots
#common_factor
#factorisation
A (0) और (4) / (0) and (4)
B (3) और (4) / (3) and (4)
C (-4) और (0) / (-4) and (0)
D (0) और (12) / (0) and (12)
Explanation opens after your attempt
Correct Answer
A. (0) और (4) / (0) and (4)
Step 1
Concept
(3x-2 -12x=3x(x-4)) so the roots are (0) and (4). Take out the common factor first.
Step 2
Why this answer is correct
The correct answer is A. (0) और (4) / (0) and (4). (3x-2 -12x=3x(x-4)) so the roots are (0) and (4). Take out the common factor first.
Step 3
Exam Tip
(3x-2 -12x=3x(x-4)) इसलिए मूल (0) और (4) हैं। सामान्य गुणनखंड पहले बाहर निकालें।
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निम्न में से कौन सा मान \(x^2-2x=0\) का मूल है?
Which of the following values is a root of \(x^2-2x=0\)?
#roots
#select_root
#factorisation
A (3)
B (-2)
C (2)
D (4)
Explanation opens after your attempt
Step 1
Concept
(x-2 -2x=x(x-2)) so the roots are (0) and (2). Choose the root that appears in the options.
Step 2
Why this answer is correct
The correct answer is C. (2). (x-2 -2x=x(x-2)) so the roots are (0) and (2). Choose the root that appears in the options.
Step 3
Exam Tip
(x-2 -2x=x(x-2)) इसलिए मूल (0) और (2) हैं। विकल्पों में मौजूद मूल को चुनें।
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समीकरण \(x^2-6x+8=0\) का एक मूल (4) है तो दूसरा मूल क्या है?
If one root of \(x^2-6x+8=0\) is (4) then what is the other root?
#roots
#other_root
#factorisation
A (1)
B (2)
C (-2)
D (8)
Explanation opens after your attempt
Step 1
Concept
(x-2 -6x+8=(x-4)(x-2)) so the other root is (2). Use the given root to find the other factor.
Step 2
Why this answer is correct
The correct answer is B. (2). (x-2 -6x+8=(x-4)(x-2)) so the other root is (2). Use the given root to find the other factor.
Step 3
Exam Tip
(x-2 -6x+8=(x-4)(x-2)) इसलिए दूसरा मूल (2) है। दिए गए एक मूल से दूसरा गुणनखंड खोजें।
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किस समीकरण के मूल (2) और (5) हैं?
Which equation has roots (2) and (5)?
#roots
#equation_from_roots
#factorisation
A \(x^2-7x+10=0\)
B \(x^2+7x+10=0\)
C \(x^2-3x+10=0\)
D \(x^2+3x-10=0\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-7x+10=0\)
Step 1
Concept
The equation ((x-2)(x-5)=0) gives \(x^2-7x+10=0\). You can also check the sum and product of roots.
Step 2
Why this answer is correct
The correct answer is A. \(x^2-7x+10=0\). The equation ((x-2)(x-5)=0) gives \(x^2-7x+10=0\). You can also check the sum and product of roots.
Step 3
Exam Tip
समीकरण ((x-2)(x-5)=0) से \(x^2-7x+10=0\) मिलता है। मूलों का योग और गुणनफल भी जांच सकते हैं।
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समीकरण \(x^2=x\) के मूल कौन से हैं?
What are the roots of \(x^2=x\)?
#roots
#factorisation
#simple_equation
A (0) और (1) / (0) and (1)
B (1) और (2) / (1) and (2)
C (-1) और (1) / (-1) and (1)
D (0) और (-1) / (0) and (-1)
Explanation opens after your attempt
Correct Answer
A. (0) और (1) / (0) and (1)
Step 1
Concept
Writing \(x^2=x\) as \(x^2-x=0\) gives (x(x-1)=0). So the roots are (0) and (1).
Step 2
Why this answer is correct
The correct answer is A. (0) और (1) / (0) and (1). Writing \(x^2=x\) as \(x^2-x=0\) gives (x(x-1)=0). So the roots are (0) and (1).
Step 3
Exam Tip
\(x^2=x\) को \(x^2-x=0\) लिखने पर (x(x-1)=0) मिलता है। इसलिए मूल (0) और (1) हैं।
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समीकरण \(x^2+5x+6=0\) के मूल कौन से हैं?
What are the roots of \(x^2+5x+6=0\)?
#roots
#factorisation
#signs
A (-2) और (-3) / (-2) and (-3)
B (2) और (3) / (2) and (3)
C (-1) और (-6) / (-1) and (-6)
D (0) और (-5) / (0) and (-5)
Explanation opens after your attempt
Correct Answer
A. (-2) और (-3) / (-2) and (-3)
Step 1
Concept
(x-2 +5x+6=(x+2)(x+3)) so the roots are (-2) and (-3). Pay special attention to signs.
Step 2
Why this answer is correct
The correct answer is A. (-2) और (-3) / (-2) and (-3). (x-2 +5x+6=(x+2)(x+3)) so the roots are (-2) and (-3). Pay special attention to signs.
Step 3
Exam Tip
(x-2 +5x+6=(x+2)(x+3)) इसलिए मूल (-2) और (-3) हैं। चिन्हों पर विशेष ध्यान दें।
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समीकरण \(x^2-4x+3=0\) के मूल कौन से हैं?
What are the roots of \(x^2-4x+3=0\)?
#roots
#factorisation
#quadratic
A (1) और (3) / (1) and (3)
B (-1) और (-3) / (-1) and (-3)
C (2) और (2) / (2) and (2)
D (0) और (3) / (0) and (3)
Explanation opens after your attempt
Correct Answer
A. (1) और (3) / (1) and (3)
Step 1
Concept
(x-2 -4x+3=(x-1)(x-3)) so the roots are (1) and (3). Factorisation is the fastest method for easy questions.
Step 2
Why this answer is correct
The correct answer is A. (1) और (3) / (1) and (3). (x-2 -4x+3=(x-1)(x-3)) so the roots are (1) and (3). Factorisation is the fastest method for easy questions.
Step 3
Exam Tip
(x-2 -4x+3=(x-1)(x-3)) इसलिए मूल (1) और (3) हैं। आसान प्रश्न में गुणनखंड बनाना सबसे तेज तरीका है।
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समीकरण \(x^2-9=0\) के मूल कौन से हैं?
What are the roots of \(x^2-9=0\)?
#roots
#factorisation
#difference_of_squares
A (3) और (-3) / (3) and (-3)
B (9) और (-9) / (9) and (-9)
C (0) और (9) / (0) and (9)
D केवल (3) / Only (3)
Explanation opens after your attempt
Correct Answer
A. (3) और (-3) / (3) and (-3)
Step 1
Concept
(x-2 -9=(x-3)(x+3)) so the roots are (3) and (-3). In exams quickly identify the difference of squares.
Step 2
Why this answer is correct
The correct answer is A. (3) और (-3) / (3) and (-3). (x-2 -9=(x-3)(x+3)) so the roots are (3) and (-3). In exams quickly identify the difference of squares.
Step 3
Exam Tip
(x-2 -9=(x-3)(x+3)) इसलिए मूल (3) और (-3) हैं। परीक्षा में वर्गों के अंतर को तुरंत पहचानें।
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समीकरण \(x^2-17x+72=0\) के गुणनखंड पहचानने के लिए कौन-सी संख्या जोड़ी उपयोगी है?
Which pair of numbers is useful to identify the factors of \(x^2-17x+72=0\)?
#quadratic-equations
#factorisation
#number-pair
#medium
A (8) और (9) / (8) and (9)
B (6) और (12) / (6) and (12)
C (4) और (18) / (4) and (18)
D (3) और (24) / (3) and (24)
Explanation opens after your attempt
Correct Answer
A. (8) और (9) / (8) and (9)
Step 1
Concept
\(8\cdot9=72\) and (8+9=17). Because the middle term is negative, the factors are ((x-8)(x-9)).
Step 2
Why this answer is correct
The correct answer is A. (8) और (9) / (8) and (9). \(8\cdot9=72\) and (8+9=17). Because the middle term is negative, the factors are ((x-8)(x-9)).
Step 3
Exam Tip
\(8\cdot9=72\) और (8+9=17) होता है। ऋण मध्य पद के कारण गुणनखंड ((x-8)(x-9)) बनते हैं।
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समीकरण \(x^2-3x-40=0\) के मूलों का सही युग्म कौन-सा है?
Which pair is the correct roots of \(x^2-3x-40=0\)?
#quadratic-equations
#roots
#factorisation
#medium
A (8,-5)
B (5,-8)
C (-8,-5)
D (8,5)
Explanation opens after your attempt
Step 1
Concept
From ((x-8)(x+5)=0), the roots are (8) and (-5). Check both product and sum.
Step 2
Why this answer is correct
The correct answer is A. (8,-5). From ((x-8)(x+5)=0), the roots are (8) and (-5). Check both product and sum.
Step 3
Exam Tip
((x-8)(x+5)=0) से मूल (8) और (-5) मिलते हैं। गुणनफल और योग दोनों मिलाकर जांचें।
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समीकरण \(x^2-10x=0\) के मूल कौन-से हैं?
What are the roots of \(x^2-10x=0\)?
#quadratic-equations
#roots
#factorisation
#medium
A (0,10)
B (0,-10)
C (1,10)
D (-1,10)
Explanation opens after your attempt
Step 1
Concept
(x-2 -10x=x(x-10)), so the roots are (0) and (10). Taking the common factor is a quick method.
Step 2
Why this answer is correct
The correct answer is A. (0,10). (x-2 -10x=x(x-10)), so the roots are (0) and (10). Taking the common factor is a quick method.
Step 3
Exam Tip
(x-2 -10x=x(x-10)), इसलिए मूल (0) और (10) हैं। समान गुणनखंड निकालना तेज तरीका है।
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समीकरण \(x^2-13x+42=0\) के गुणनखंड पहचानने के लिए कौन-सी संख्या जोड़ी उपयोगी है?
Which pair of numbers is useful to identify the factors of \(x^2-13x+42=0\)?
#quadratic-equations
#factorisation
#number-pair
#medium
A (6) और (7) / (6) and (7)
B (3) और (14) / (3) and (14)
C (2) और (21) / (2) and (21)
D (1) और (42) / (1) and (42)
Explanation opens after your attempt
Correct Answer
A. (6) और (7) / (6) and (7)
Step 1
Concept
\(6\cdot7=42\) and (6+7=13). Because the middle term is negative, the factors are ((x-6)(x-7)).
Step 2
Why this answer is correct
The correct answer is A. (6) और (7) / (6) and (7). \(6\cdot7=42\) and (6+7=13). Because the middle term is negative, the factors are ((x-6)(x-7)).
Step 3
Exam Tip
\(6\cdot7=42\) और (6+7=13) होता है। ऋण मध्य पद के कारण गुणनखंड ((x-6)(x-7)) बनते हैं।
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समीकरण \(x^2+2x-35=0\) के मूलों का सही युग्म कौन-सा है?
Which pair is the correct roots of \(x^2+2x-35=0\)?
#quadratic-equations
#roots
#factorisation
#medium
A (5,-7)
B (7,-5)
C (-5,-7)
D (5,7)
Explanation opens after your attempt
Step 1
Concept
From ((x+7)(x-5)=0), the roots are (-7) and (5). Check both product and sum.
Step 2
Why this answer is correct
The correct answer is A. (5,-7). From ((x+7)(x-5)=0), the roots are (-7) and (5). Check both product and sum.
Step 3
Exam Tip
((x+7)(x-5)=0) से मूल (-7) और (5) मिलते हैं। गुणनफल और योग दोनों मिलाकर जांचें।
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समीकरण \(x^2+9x=0\) के मूल कौन-से हैं?
What are the roots of \(x^2+9x=0\)?
#quadratic-equations
#roots
#factorisation
#medium
A (0,-9)
B (0,9)
C (1,-9)
D (-1,9)
Explanation opens after your attempt
Step 1
Concept
(x-2 +9x=x(x+9)), so the roots are (0) and (-9). Taking the common factor is a quick method.
Step 2
Why this answer is correct
The correct answer is A. (0,-9). (x-2 +9x=x(x+9)), so the roots are (0) and (-9). Taking the common factor is a quick method.
Step 3
Exam Tip
(x-2 +9x=x(x+9)), इसलिए मूल (0) और (-9) हैं। समान गुणनखंड निकालना जल्दी तरीका है।
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समीकरण \(x^2-11x+30=0\) में मूलों की पहचान के लिए कौन-सी संख्या जोड़ी उपयोगी है?
Which pair of numbers is useful to identify the roots of \(x^2-11x+30=0\)?
#quadratic-equations
#factorisation
#number-pair
#medium
A (5) और (6) / (5) and (6)
B (3) और (10) / (3) and (10)
C (2) और (15) / (2) and (15)
D (1) और (30) / (1) and (30)
Explanation opens after your attempt
Correct Answer
A. (5) और (6) / (5) and (6)
Step 1
Concept
\(5\cdot6=30\) and (5+6=11). Because the middle term is negative, the factors are ((x-5)(x-6)).
Step 2
Why this answer is correct
The correct answer is A. (5) और (6) / (5) and (6). \(5\cdot6=30\) and (5+6=11). Because the middle term is negative, the factors are ((x-5)(x-6)).
Step 3
Exam Tip
\(5\cdot6=30\) और (5+6=11) होता है। ऋण मध्य पद के कारण गुणनखंड ((x-5)(x-6)) बनते हैं।
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समीकरण \(x^2-2x-15=0\) के मूलों में से कौन-सा सही युग्म है?
Which pair is the correct roots of \(x^2-2x-15=0\)?
#quadratic-equations
#roots
#factorisation
#medium
A (3,-5)
B (5,-3)
C (-5,-3)
D (5,3)
Explanation opens after your attempt
Step 1
Concept
From ((x-5)(x+3)=0), the roots are (5) and (-3). Match both product and sum in such questions.
Step 2
Why this answer is correct
The correct answer is B. (5,-3). From ((x-5)(x+3)=0), the roots are (5) and (-3). Match both product and sum in such questions.
Step 3
Exam Tip
((x-5)(x+3)=0) से मूल (5) और (-3) मिलते हैं। ऐसे प्रश्नों में गुणनफल और योग दोनों मिलाएं।
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समीकरण \(x^2-8x=0\) के मूल कौन-से हैं?
What are the roots of \(x^2-8x=0\)?
#quadratic-equations
#roots
#factorisation
#medium
A (0,8)
B (0,-8)
C (1,8)
D (-1,8)
Explanation opens after your attempt
Step 1
Concept
(x-2 -8x=x(x-8)), so the roots are (0) and (8). Taking the common factor is an easy method.
Step 2
Why this answer is correct
The correct answer is A. (0,8). (x-2 -8x=x(x-8)), so the roots are (0) and (8). Taking the common factor is an easy method.
Step 3
Exam Tip
(x-2 -8x=x(x-8)), इसलिए मूल (0) और (8) हैं। समान गुणनखंड बाहर निकालना आसान तरीका है।
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यदि (p(x)=x-2 -\sqrt{5}x), तो इसके शून्यक कौन से हैं?
If (p(x)=x-2 -\sqrt{5}x), what are its zeroes?
#factorisation
#zeroes
#irrational
A \(0,\sqrt{5}\)
B \(1,\sqrt{5}\)
C \(0,-\sqrt{5}\)
D \(\sqrt{5},-\sqrt{5}\)
Explanation opens after your attempt
Correct Answer
A. \(0,\sqrt{5}\)
Step 1
Concept
(p(x)=x\(x-\sqrt{5}\)), so the zeroes are (0) and \(\sqrt{5}\). Taking the common factor is a fast method in exams.
Step 2
Why this answer is correct
The correct answer is A. \(0,\sqrt{5}\). (p(x)=x\(x-\sqrt{5}\)), so the zeroes are (0) and \(\sqrt{5}\). Taking the common factor is a fast method in exams.
Step 3
Exam Tip
(p(x)=x\(x-\sqrt{5}\)), इसलिए शून्यक (0) और \(\sqrt{5}\) हैं। परीक्षा में सामान्य गुणनखंड निकालना तेज तरीका है।
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यदि (p(x)=x-2 -2\sqrt{2}x+2) है, तो (p(x)) का सही गुणनखंड रूप कौन सा है?
If (p(x)=x-2 -2\sqrt{2}x+2), which is the correct factorized form of (p(x))?
#factorisation
#perfect-square
#irrational
A (\(x-\sqrt{2}\)2 )
B (\(x+\sqrt{2}\)2 )
C ((x-2)2 )
D (\(x-\sqrt{2}\)\(x+\sqrt{2}\))
Explanation opens after your attempt
Correct Answer
A. (\(x-\sqrt{2}\)2 )
Step 1
Concept
(x-2 -2\sqrt{2}x+2=\(x-\sqrt{2}\)2 ). Recognizing a perfect square gives equal irrational zeroes.
Step 2
Why this answer is correct
The correct answer is A. (\(x-\sqrt{2}\)2 ). (x-2 -2\sqrt{2}x+2=\(x-\sqrt{2}\)2 ). Recognizing a perfect square gives equal irrational zeroes.
Step 3
Exam Tip
(x-2 -2\sqrt{2}x+2=\(x-\sqrt{2}\)2 ) है। पूर्ण वर्ग पहचानने से समान अपरिमेय शून्यक मिलते हैं।
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यदि (p(x)=x-2 -11x+30) का ग्राफ खींचा जाए तो (x)-अक्ष पर कौन से बिंदु मिलेंगे?
If the graph of (p(x)=x-2 -11x+30) is drawn, which points will lie on the (x)-axis?
#quadratic
#factorisation
#graph-points
A ((5,0)) और ((6,0)) / ((5,0)) and ((6,0))
B ((-5,0)) और ((-6,0)) / ((-5,0)) and ((-6,0))
C ((0,5)) और ((0,6)) / ((0,5)) and ((0,6))
D ((30,0)) और ((11,0)) / ((30,0)) and ((11,0))
Explanation opens after your attempt
Correct Answer
A. ((5,0)) और ((6,0)) / ((5,0)) and ((6,0))
Step 1
Concept
(x-2 -11x+30=(x-5)(x-6)). So the graph meets the (x)-axis at (x=5) and (x=6).
Step 2
Why this answer is correct
The correct answer is A. ((5,0)) और ((6,0)) / ((5,0)) and ((6,0)). (x-2 -11x+30=(x-5)(x-6)). So the graph meets the (x)-axis at (x=5) and (x=6).
Step 3
Exam Tip
(x-2 -11x+30=(x-5)(x-6)) है। इसलिए (x=5) और (x=6) पर ग्राफ (x)-अक्ष से मिलता है।
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द्विघात (p(x)=x-2 +2x-15) का ग्राफ (x)-अक्ष को किन (x)-मानों पर काटेगा?
At which (x)-values will the graph of (p(x)=x-2 +2x-15) cut the (x)-axis?
#quadratic
#factorisation
#x-intercepts
A (3) और (-5) / (3) and (-5)
B (-3) और (5) / (-3) and (5)
C (5) और (3) / (5) and (3)
D (-5) और (-3) / (-5) and (-3)
Explanation opens after your attempt
Correct Answer
A. (3) और (-5) / (3) and (-5)
Step 1
Concept
(x-2 +2x-15=(x+5)(x-3)). Zeroes are the (x)-values of (x)-axis intersections.
Step 2
Why this answer is correct
The correct answer is A. (3) और (-5) / (3) and (-5). (x-2 +2x-15=(x+5)(x-3)). Zeroes are the (x)-values of (x)-axis intersections.
Step 3
Exam Tip
(x-2 +2x-15=(x+5)(x-3)) है। शून्यक (x)-अक्ष पर कटान के (x)-मान होते हैं।
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