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Which equation has roots 2 and 5?

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Answer and explanation

Correct answer: x² − 7x + 10 = 0

The governing construction is the equation formed from known roots. If α and β are the roots of a monic quadratic, its equation is (x − α)(x − β) = 0. Substituting α = 2 and β = 5 gives (x − 2)(x − 5) = 0. On expansion, x² − 5x − 2x + 10 = x² − 7x + 10, so the required equation is x² − 7x + 10 = 0, which is option A. The same result follows from Vieta’s relations: the sum of roots is 7, so the coefficient of x is −7, and the product is 10, so the constant term is 10. Option B has the wrong sign for the sum, option C has the wrong sum, and option D has incorrect signs and product.

Related tags

Quadratic-EquationsForming-Equation-From-RootsVieta-RelationsRoots Of A Quadratic EquationQuadratic EquationsMathematicsClass 10 Mcq

Frequently asked questions

What is the correct answer to this question?

x² − 7x + 10 = 0

Why is this the correct answer?

The governing construction is the equation formed from known roots. If α and β are the roots of a monic quadratic, its equation is (x − α)(x − β) = 0. Substituting α = 2 and β = 5 gives (x − 2)(x − 5) = 0. On expansion, x² − 5x − 2x + 10 = x² − 7x + 10, so the required equation is x² − 7x + 10 = 0, which is option A. The same result follows from Vieta’s relations: the sum of roots is 7, so the coefficient of x is −7, and the product is 10, so the constant term is 10. Option B has the wrong sign for the sum, option C has the wrong sum, and option D has incorrect signs and product.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Roots of a Quadratic Equation.

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