समीकरण \(x^2+10x+21=0\) के मूल कौन से हैं?

What are the roots of \(x^2+10x+21=0\)?

Explanation opens after your attempt
Correct Answer

A. (-3) और (-7)(-3) and (-7)

Step 1

Concept

(x-2+10x+21=(x+3)(x+7)). Therefore the roots are (-3) and (-7).

Step 2

Why this answer is correct

The correct answer is A. (-3) और (-7) / (-3) and (-7). (x-2+10x+21=(x+3)(x+7)). Therefore the roots are (-3) and (-7).

Step 3

Exam Tip

(x-2+10x+21=(x+3)(x+7)) है। इसलिए मूल (-3) और (-7) हैं।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

समीकरण \(x^2+10x+21=0\) के मूल कौन से हैं? / What are the roots of \(x^2+10x+21=0\)?

Correct Answer: A. (-3) और (-7) / (-3) and (-7). Explanation: (x-2+10x+21=(x+3)(x+7)) है। इसलिए मूल (-3) और (-7) हैं। / (x-2+10x+21=(x+3)(x+7)). Therefore the roots are (-3) and (-7).

Which concept should I revise for this Mathematics MCQ?

(x-2+10x+21=(x+3)(x+7)). Therefore the roots are (-3) and (-7).

What exam hint can help solve this Mathematics question?

(x-2+10x+21=(x+3)(x+7)) है। इसलिए मूल (-3) और (-7) हैं।