यदि \(U={x:x\in\mathbb{N},x\le 96}\), \(A={x:x\in U,8\mid x}\) और \(B={x:x\in U,12\mid x}\), तो (n\(A'\cap B'\)) क्या है?
If \(U={x:x\in\mathbb{N},x\le 96}\), \(A={x:x\in U,8\mid x}\), and \(B={x:x\in U,12\mid x}\), what is (n\(A'\cap B'\))?
#sets
#complement
#de-morgan
#cardinality
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A (80)
B (16)
C (72)
D (84)
Explanation opens after your attempt
Step 1
Concept
By De Morgan's law, (A'\cap B'=\(A\cup B\)'). Since (n\(A\cup B\)=12+8-4=16), the complement has (96-16=80) elements.
Step 2
Why this answer is correct
The correct answer is A. (80). By De Morgan's law, (A'\cap B'=\(A\cup B\)'). Since (n\(A\cup B\)=12+8-4=16), the complement has (96-16=80) elements.
Step 3
Exam Tip
डी मॉर्गन से (A'\cap B'=\(A\cup B\)') है। (n\(A\cup B\)=12+8-4=16), इसलिए पूरक में (96-16=80) सदस्य हैं।
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यदि \(U={x:x\in\mathbb{N},x\le 120}\), \(A={x:x\in U,8\mid x}\), \(B={x:x\in U,15\mid x}\) और \(C={x:x\in U,20\mid x}\), तो (n(\(A\cup B\cup C\)')) क्या है?
If \(U={x:x\in\mathbb{N},x\le 120}\), \(A={x:x\in U,8\mid x}\), \(B={x:x\in U,15\mid x}\), and \(C={x:x\in U,20\mid x}\), what is (n(\(A\cup B\cup C\)'))?
#sets
#three-sets
#complement
#inclusion-exclusion
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A (96)
B (24)
C (90)
D (102)
Explanation opens after your attempt
Step 1
Concept
By inclusion-exclusion, (n\(A\cup B\cup C\)=15+8+6-1-3-2+1=24). Therefore the complement has (120-24=96) elements.
Step 2
Why this answer is correct
The correct answer is A. (96). By inclusion-exclusion, (n\(A\cup B\cup C\)=15+8+6-1-3-2+1=24). Therefore the complement has (120-24=96) elements.
Step 3
Exam Tip
समावेशन-बहिष्करण से (n\(A\cup B\cup C\)=15+8+6-1-3-2+1=24) है। इसलिए पूरक में (120-24=96) सदस्य होंगे।
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यदि \(U={x:x\in\mathbb{Z},-12\le x\le 12}\) और \(A={x:x\in U,x^2-9x+18\le 0}\), तो (n(A')) क्या है?
If \(U={x:x\in\mathbb{Z},-12\le x\le 12}\) and \(A={x:x\in U,x^2-9x+18\le 0}\), what is (n(A'))?
#sets
#quadratic-inequality
#integers
#complement
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A (20)
B (5)
C (19)
D (21)
Explanation opens after your attempt
Step 1
Concept
The inequality gives \(3\le x\le 6\), so (A) has (4) elements. Since (U) has (25) elements, (n(A')=25-4=21).
Step 2
Why this answer is correct
The correct answer is A. (20). The inequality gives \(3\le x\le 6\), so (A) has (4) elements. Since (U) has (25) elements, (n(A')=25-4=21).
Step 3
Exam Tip
असमानता से \(3\le x\le 6\) मिलता है, इसलिए (A) में (4) सदस्य हैं। (U) में (25) सदस्य हैं, अतः (n(A')=25-4=21) नहीं बल्कि (21) होता है।
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यदि \(U=\mathbb{R}\), \(A=\{x:x\in\mathbb{R},(x-2)(x+5)\le 0\}\) और \(B={x:x\in\mathbb{R},|x-1|<3}\), तो (\(A'\cap B\)') क्या है?
If \(U=\mathbb{R}\), \(A=\{x:x\in\mathbb{R},(x-2)(x+5)\le 0\}\), and \(B={x:x\in\mathbb{R},|x-1|<3}\), what is (\(A'\cap B\)')?
#sets
#intervals
#nested-complement
#real-numbers
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A (\(-\infty,2]\cup[4,\infty\))
B ((2,4))
C \([-5,2]\cup[-2,4]\)
D (\(-\infty,-5\)\cup\(4,\infty\))
Explanation opens after your attempt
Correct Answer
A. (\(-\infty,2]\cup[4,\infty\))
Step 1
Concept
Here (A=[-5,2]) and (B=(-2,4)), so \(A'\cap B=(2,4)\). Its complement is (\(-\infty,2]\cup[4,\infty\)).
Step 2
Why this answer is correct
The correct answer is A. (\(-\infty,2]\cup[4,\infty\)). Here (A=[-5,2]) and (B=(-2,4)), so \(A'\cap B=(2,4)\). Its complement is (\(-\infty,2]\cup[4,\infty\)).
Step 3
Exam Tip
यहाँ (A=[-5,2]) और (B=(-2,4)) है, इसलिए \(A'\cap B=(2,4)\) होगा। इसका पूरक (\(-\infty,2]\cup[4,\infty\)) है।
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यदि \(U=\mathbb{R}\) और (A=\(-\infty,-5\)\cup[1,4]\cup\(9,\infty\)), तो (A') क्या है?
If \(U=\mathbb{R}\) and (A=\(-\infty,-5\)\cup[1,4]\cup\(9,\infty\)), what is (A')?
#sets
#intervals
#real-line
#complement
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A ([-5,1)\cup(4,9])
B (\(-5,1]\cup[4,9\))
C \([-5,1]\cup[4,9]\)
D \((-5,1)\cup(4,9)\)
Explanation opens after your attempt
Correct Answer
A. ([-5,1)\cup(4,9])
Step 1
Concept
The point (-5) is not in (A), (1) and (4) are in (A), and (9) is not in (A). Checking endpoints gives ([-5,1)\cup(4,9]).
Step 2
Why this answer is correct
The correct answer is A. ([-5,1)\cup(4,9]). The point (-5) is not in (A), (1) and (4) are in (A), and (9) is not in (A). Checking endpoints gives ([-5,1)\cup(4,9]).
Step 3
Exam Tip
(-5) (A) में नहीं है, (1) और (4) (A) में हैं, और (9) (A) में नहीं है। सिरों को देखकर पूरक ([-5,1)\cup(4,9]) होगा।
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यदि \(A\subseteq B\subseteq C\subseteq U\), तो कौन सा संबंध हमेशा सत्य है?
If \(A\subseteq B\subseteq C\subseteq U\), which relation is always true?
#sets
#subset
#complement
#order-reversal
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A \(C'\subseteq B'\subseteq A'\)
B \(A'\subseteq B'\subseteq C'\)
C \(A'\subseteq C'\subseteq B'\)
D (A'=B'=C')
Explanation opens after your attempt
Correct Answer
A. \(C'\subseteq B'\subseteq A'\)
Step 1
Concept
Taking complements reverses inclusion. Hence \(A\subseteq B\subseteq C\) gives \(C'\subseteq B'\subseteq A'\).
Step 2
Why this answer is correct
The correct answer is A. \(C'\subseteq B'\subseteq A'\). Taking complements reverses inclusion. Hence \(A\subseteq B\subseteq C\) gives \(C'\subseteq B'\subseteq A'\).
Step 3
Exam Tip
पूरक लेने पर समावेशन की दिशा उलट जाती है। इसलिए \(A\subseteq B\subseteq C\) से \(C'\subseteq B'\subseteq A'\) मिलता है।
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यदि \(U={1,2,\ldots,42}\), \(A={x:x\in U,3\mid x}\) और \(B={x:x\in U,7\mid x}\), तो (n((A-B)')) क्या है?
If \(U={1,2,\ldots,42}\), \(A={x:x\in U,3\mid x}\), and \(B={x:x\in U,7\mid x}\), what is (n((A-B)'))?
#sets
#difference
#complement
#divisibility
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A (34)
B (8)
C (28)
D (36)
Explanation opens after your attempt
Step 1
Concept
(A-B) contains multiples of (3) that are not divisible by (7), and their count is (14-2=12). Therefore (n((A-B)')=42-12=30).
Step 2
Why this answer is correct
The correct answer is A. (34). (A-B) contains multiples of (3) that are not divisible by (7), and their count is (14-2=12). Therefore (n((A-B)')=42-12=30).
Step 3
Exam Tip
(A-B) में (3) के वे गुणज हैं जो (7) से विभाज्य नहीं हैं, उनकी संख्या (14-2=12) है। इसलिए (n((A-B)')=42-12=30) नहीं बल्कि (30) होता है।
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यदि \(U={1,2,\ldots,40}\), (A) (5) के गुणजों का समुच्चय है और (B) (8) के गुणजों का समुच्चय है, तो (n(\(A\cap B\)')) क्या है?
If \(U={1,2,\ldots,40}\), (A) is the set of multiples of (5), and (B) is the set of multiples of (8), what is (n(\(A\cap B\)'))?
#sets
#lcm
#intersection
#complement
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A (39)
B (1)
C (32)
D (35)
Explanation opens after your attempt
Step 1
Concept
\(A\cap B\) contains multiples of (\operatorname{lcm}(5,8)=40). Up to (40), there is only (1) such element, so the complement is (39).
Step 2
Why this answer is correct
The correct answer is A. (39). \(A\cap B\) contains multiples of (\operatorname{lcm}(5,8)=40). Up to (40), there is only (1) such element, so the complement is (39).
Step 3
Exam Tip
\(A\cap B\) में (\operatorname{lcm}(5,8)=40) के गुणज आएंगे। (40) तक केवल (1) ऐसा सदस्य है, इसलिए पूरक (39) है।
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यदि \(U=\{a,b,c,d,e,f,g,i\}\), \(A=\{a,c,f\}\) और \(B=\{b,c,e,i\}\), तो (\(A\cup B\)') क्या है?
If \(U=\{a,b,c,d,e,f,g,i\}\), \(A=\{a,c,f\}\), and \(B=\{b,c,e,i\}\), what is (\(A\cup B\)')?
#sets
#finite-set
#union
#complement
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A ({d,g})
B ({a,b,c,e,f,i})
C ({c})
D ({d,f,g})
Explanation opens after your attempt
Correct Answer
A. ({d,g})
Step 1
Concept
First form \(A\cup B={a,b,c,e,f,i}\). Removing it from (U) gives ({d,g}).
Step 2
Why this answer is correct
The correct answer is A. ({d,g}). First form \(A\cup B={a,b,c,e,f,i}\). Removing it from (U) gives ({d,g}).
Step 3
Exam Tip
पहले \(A\cup B={a,b,c,e,f,i}\) बनाएं। इसे (U) से हटाने पर ({d,g}) मिलता है।
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यदि \(U=\mathbb{R}\), \(A={x:x\in\mathbb{R},|x+1|\ge 4}\), तो (A') क्या है?
If \(U=\mathbb{R}\), \(A={x:x\in\mathbb{R},|x+1|\ge 4}\), what is (A')?
#sets
#absolute-value
#real-numbers
#complement
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A ((-5,3))
B ([-5,3])
C (\(-\infty,-5]\cup[3,\infty\))
D (\(-\infty,-5\)\cup\(3,\infty\))
Explanation opens after your attempt
Correct Answer
A. ((-5,3))
Step 1
Concept
The solution of \(|x+1|\ge 4\) is \(x\le -5\) or \(x\ge 3\). Hence its complement is (-5<x<3).
Step 2
Why this answer is correct
The correct answer is A. ((-5,3)). The solution of \(|x+1|\ge 4\) is \(x\le -5\) or \(x\ge 3\). Hence its complement is (-5<x<3).
Step 3
Exam Tip
\(|x+1|\ge 4\) का हल \(x\le -5\) या \(x\ge 3\) है। इसलिए इसका पूरक (-5<x<3) है।
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\(यदि (U={1,2,\ldots,30}), (A={x:x\in U,x\) पूर्ण वर्ग है\(}) और (B={x:x\in U,x\) सम है\(}), तो (A'\cap B) क्या है\)?
\(If (U={1,2,\ldots,30}), (A={x:x\in U,x\) is a perfect square\(}), and (B={x:x\in U,x\) is even\(}), what is (A'\cap B)\)?
#sets
#perfect-squares
#complement
#intersection
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A ({2,6,8,10,12,14,18,20,22,24,26,28,30})
B ({4,16})
C ({2,4,6,8,10,12,14,16,18,20,22,24,26,28,30})
D ({1,9,25})
Explanation opens after your attempt
Correct Answer
A. ({2,6,8,10,12,14,18,20,22,24,26,28,30})
Step 1
Concept
From the even numbers in (B), the perfect squares (4) and (16) are removed. Therefore \(A'\cap B\) contains the remaining even numbers.
Step 2
Why this answer is correct
The correct answer is A. ({2,6,8,10,12,14,18,20,22,24,26,28,30}). From the even numbers in (B), the perfect squares (4) and (16) are removed. Therefore \(A'\cap B\) contains the remaining even numbers.
Step 3
Exam Tip
(B) की सम संख्याओं में से पूर्ण वर्ग (4) और (16) हटेंगे। इसलिए \(A'\cap B\) में बाकी सम संख्याएं आएंगी।
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यदि \(A\cap B=A\cap B'\), तो कौन सा निष्कर्ष अवश्य सत्य है?
If \(A\cap B=A\cap B'\), which conclusion must be true?
#sets
#complement
#reasoning
#empty-set
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A \(A=\varnothing\)
B \(B=\varnothing\)
C (A=U)
D (B=U)
Explanation opens after your attempt
Correct Answer
A. \(A=\varnothing\)
Step 1
Concept
(B) and (B') are disjoint, so \(A\cap B\) and \(A\cap B'\) are also disjoint. Two equal disjoint sets must be \(\varnothing\), so \(A=\varnothing\) is necessary.
Step 2
Why this answer is correct
The correct answer is A. \(A=\varnothing\). (B) and (B') are disjoint, so \(A\cap B\) and \(A\cap B'\) are also disjoint. Two equal disjoint sets must be \(\varnothing\), so \(A=\varnothing\) is necessary.
Step 3
Exam Tip
(B) और (B') असंयुक्त होते हैं, इसलिए \(A\cap B\) और \(A\cap B'\) भी असंयुक्त हैं। दो असंयुक्त समान समुच्चय केवल \(\varnothing\) हो सकते हैं, इसलिए \(A=\varnothing\) आवश्यक है।
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यदि \(U={1,2,\ldots,72}\), \(A={x:x\in U,4\mid x}\), \(B={x:x\in U,6\mid x}\) और \(C={x:x\in U,9\mid x}\), तो (n(\(A\cup B\cup C\)')) क्या है?
If \(U={1,2,\ldots,72}\), \(A={x:x\in U,4\mid x}\), \(B={x:x\in U,6\mid x}\), and \(C={x:x\in U,9\mid x}\), what is (n(\(A\cup B\cup C\)'))?
#sets
#three-sets
#complement
#inclusion-exclusion
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A (42)
B (30)
C (36)
D (48)
Explanation opens after your attempt
Step 1
Concept
By inclusion-exclusion, (n\(A\cup B\cup C\)=18+12+8-6-2-4+2=28). Therefore the complement is (72-28=44).
Step 2
Why this answer is correct
The correct answer is A. (42). By inclusion-exclusion, (n\(A\cup B\cup C\)=18+12+8-6-2-4+2=28). Therefore the complement is (72-28=44).
Step 3
Exam Tip
समावेशन-बहिष्करण से (n\(A\cup B\cup C\)=18+12+8-6-2-4+2=28) है। इसलिए पूरक (72-28=44) नहीं बल्कि (44) है।
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यदि \(U=\mathbb{R}\), (A=(-2,6]) और (B=[0,9)), तो \(A'\cup B'\) क्या है?
If \(U=\mathbb{R}\), (A=(-2,6]), and (B=[0,9)), what is \(A'\cup B'\)?
#sets
#intervals
#de-morgan
#complement
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A (\(-\infty,0\)\cup\(6,\infty\))
B ([0,6])
C (\(-\infty,-2]\cup[9,\infty\))
D (\(-\infty,0]\cup[6,\infty\))
Explanation opens after your attempt
Correct Answer
A. (\(-\infty,0\)\cup\(6,\infty\))
Step 1
Concept
By De Morgan's law, (A'\cup B'=\(A\cap B\)'). Since \(A\cap B=[0,6]\), the complement is (\(-\infty,0\)\cup\(6,\infty\)).
Step 2
Why this answer is correct
The correct answer is A. (\(-\infty,0\)\cup\(6,\infty\)). By De Morgan's law, (A'\cup B'=\(A\cap B\)'). Since \(A\cap B=[0,6]\), the complement is (\(-\infty,0\)\cup\(6,\infty\)).
Step 3
Exam Tip
डी मॉर्गन से (A'\cup B'=\(A\cap B\)') है। \(A\cap B=[0,6]\), इसलिए पूरक (\(-\infty,0\)\cup\(6,\infty\)) है।
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\(यदि (U={1,2,\ldots,36}), (A={x:x\in U,x\) अभाज्य नहीं है}), तो (A') में कितने सदस्य हैं?
\(If (U={1,2,\ldots,36}), (A={x:x\in U,x\) is not prime}), how many elements are in (A')?
#sets
#prime-numbers
#complement
#counting
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A (11)
B (25)
C (12)
D (10)
Explanation opens after your attempt
Step 1
Concept
If (A) contains non-prime numbers, then (A') contains prime numbers. There are (11) primes up to (36).
Step 2
Why this answer is correct
The correct answer is A. (11). If (A) contains non-prime numbers, then (A') contains prime numbers. There are (11) primes up to (36).
Step 3
Exam Tip
यदि (A) में अभाज्य नहीं संख्याएं हैं, तो (A') में अभाज्य संख्याएं होंगी। (36) तक अभाज्य संख्याएं (11) हैं।
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यदि \(U={x:x\in\mathbb{Z},-5\le x\le 15}\) और \(A={x:x\in U,x\equiv 2 \pmod{5}}\), तो (n(A')) क्या है?
If \(U={x:x\in\mathbb{Z},-5\le x\le 15}\) and \(A={x:x\in U,x\equiv 2 \pmod{5}}\), what is (n(A'))?
#sets
#modular-arithmetic
#integers
#complement
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A (17)
B (4)
C (16)
D (21)
Explanation opens after your attempt
Step 1
Concept
\(A=\{-3,2,7,12\}\), so (n(A)=4). Since (U) has (21) elements, (n(A')=17).
Step 2
Why this answer is correct
The correct answer is A. (17). \(A=\{-3,2,7,12\}\), so (n(A)=4). Since (U) has (21) elements, (n(A')=17).
Step 3
Exam Tip
\(A=\{-3,2,7,12\}\) है, इसलिए (n(A)=4)। (U) में (21) सदस्य हैं, अतः (n(A')=17) है।
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यदि (n(U)=300), (n(A')=120), (n(B')=150) और (n\(A'\cup B'\)=210), तो (n\(A\cup B\)) क्या है?
If (n(U)=300), (n(A')=120), (n(B')=150), and (n\(A'\cup B'\)=210), what is (n\(A\cup B\))?
#sets
#cardinality
#de-morgan
#complement
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A (240)
B (90)
C (210)
D (180)
Explanation opens after your attempt
Step 1
Concept
(n\(A'\cap B'\)=120+150-210=60). Since (\(A\cup B\)'=A'\cap B'), (n\(A\cup B\)=300-60=240).
Step 2
Why this answer is correct
The correct answer is A. (240). (n\(A'\cap B'\)=120+150-210=60). Since (\(A\cup B\)'=A'\cap B'), (n\(A\cup B\)=300-60=240).
Step 3
Exam Tip
(n\(A'\cap B'\)=120+150-210=60) है। क्योंकि (\(A\cup B\)'=A'\cap B'), इसलिए (n\(A\cup B\)=300-60=240) है।
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\(यदि (U={1,2,\ldots,20}), (A={x:x\in U,x\le 12}) और (B={x:x\in U,x\) विषम है\(}), तो (A'\cap B) क्या है\)?
\(If (U={1,2,\ldots,20}), (A={x:x\in U,x\le 12}), and (B={x:x\in U,x\) is odd\(}), what is (A'\cap B)\)?
#sets
#complement
#odd-numbers
#intersection
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A ({13,15,17,19})
B ({14,16,18,20})
C ({1,3,5,7,9,11})
D ({13,14,15,16,17,18,19,20})
Explanation opens after your attempt
Correct Answer
A. ({13,15,17,19})
Step 1
Concept
(A') contains numbers from (13) to (20). The odd members among them are ({13,15,17,19}).
Step 2
Why this answer is correct
The correct answer is A. ({13,15,17,19}). (A') contains numbers from (13) to (20). The odd members among them are ({13,15,17,19}).
Step 3
Exam Tip
(A') में (13) से (20) तक संख्याएं हैं। इनमें विषम सदस्य ({13,15,17,19}) हैं।
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यदि \(A\cup B'=U\), तो निम्न में से कौन सा कथन अवश्य सत्य है?
If \(A\cup B'=U\), which of the following statements must be true?
#sets
#subset
#complement
#reasoning
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A \(B\subseteq A\)
B \(A\subseteq B\)
C (A=B')
D \(A\cap B=\varnothing\)
Explanation opens after your attempt
Correct Answer
A. \(B\subseteq A\)
Step 1
Concept
Taking the complement of \(A\cup B'=U\) gives \(A'\cap B=\varnothing\). Therefore every element of (B) is in (A).
Step 2
Why this answer is correct
The correct answer is A. \(B\subseteq A\). Taking the complement of \(A\cup B'=U\) gives \(A'\cap B=\varnothing\). Therefore every element of (B) is in (A).
Step 3
Exam Tip
\(A\cup B'=U\) का पूरक लेने पर \(A'\cap B=\varnothing\) मिलता है। इसलिए (B) का हर सदस्य (A) में है।
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यदि \(U=\mathbb{R}\) और \(A={x:x\in\mathbb{R},x^2+2x-8<0}\), तो (A') क्या है?
If \(U=\mathbb{R}\) and \(A={x:x\in\mathbb{R},x^2+2x-8<0}\), what is (A')?
#sets
#quadratic-inequality
#intervals
#complement
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A (\(-\infty,-4]\cup[2,\infty\))
B ((-4,2))
C (\(-\infty,-4\)\cup\(2,\infty\))
D ([-4,2])
Explanation opens after your attempt
Correct Answer
A. (\(-\infty,-4]\cup[2,\infty\))
Step 1
Concept
The solution of \(x^2+2x-8<0\) is (-4<x<2). Hence the complement is (\(-\infty,-4]\cup[2,\infty\)).
Step 2
Why this answer is correct
The correct answer is A. (\(-\infty,-4]\cup[2,\infty\)). The solution of \(x^2+2x-8<0\) is (-4<x<2). Hence the complement is (\(-\infty,-4]\cup[2,\infty\)).
Step 3
Exam Tip
असमानता \(x^2+2x-8<0\) का हल (-4<x<2) है। इसलिए पूरक में (\(-\infty,-4]\cup[2,\infty\)) आएगा।
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\(यदि (U={1,2,\ldots,64}) और (A={x:x\in U,x=2^k\) जहाँ \(k\in\mathbb{N}_0}), तो (A') में (4) से विभाज्य संख्याओं की संख्या कितनी है\)?
\(If (U={1,2,\ldots,64}) and (A={x:x\in U,x=2^k\) where \(k\in\mathbb{N}_0}), how many numbers divisible by (4) are in (A')\)?
#sets
#powers
#complement
#divisibility
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A (10)
B (16)
C (6)
D (12)
Explanation opens after your attempt
Step 1
Concept
There are (16) numbers divisible by (4) up to (64). Among them (4,8,16,32,64) are powers of (2), so (11) remain.
Step 2
Why this answer is correct
The correct answer is A. (10). There are (16) numbers divisible by (4) up to (64). Among them (4,8,16,32,64) are powers of (2), so (11) remain.
Step 3
Exam Tip
(64) तक (4) से विभाज्य संख्याएं (16) हैं। इनमें (4,8,16,32,64) (2) की घातें हैं, इसलिए (11) नहीं बल्कि (11) बचते हैं।
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यदि \(U={1,2,\ldots,18}\), \(A=\{2,4,6,8,10,12,14,16,18\}\) और \(B=\{1,2,3,5,8,13\}\), तो \(A'\cap B'\) क्या है?
If \(U={1,2,\ldots,18}\), \(A=\{2,4,6,8,10,12,14,16,18\}\), and \(B=\{1,2,3,5,8,13\}\), what is \(A'\cap B'\)?
#sets
#complement
#intersection
#finite-set
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A ({7,9,11,15,17})
B ({1,3,5,7,9,11,13,15,17})
C ({2,8})
D ({4,6,10,12,14,16,18})
Explanation opens after your attempt
Correct Answer
A. ({7,9,11,15,17})
Step 1
Concept
(A') is the set of odd numbers, and (1,3,5,13) from (B) are removed. Thus ({7,9,11,15,17}) remains.
Step 2
Why this answer is correct
The correct answer is A. ({7,9,11,15,17}). (A') is the set of odd numbers, and (1,3,5,13) from (B) are removed. Thus ({7,9,11,15,17}) remains.
Step 3
Exam Tip
(A') विषम संख्याओं का समुच्चय है और उसमें से (B) के (1,3,5,13) हटेंगे। इसलिए ({7,9,11,15,17}) बचेगा।
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यदि \(U={1,2,\ldots,100}\), \(A={x:x\in U,10\mid x}\) और \(B={x:x\in U,15\mid x}\), तो (n\(A'\cup B'\)) क्या है?
If \(U={1,2,\ldots,100}\), \(A={x:x\in U,10\mid x}\), and \(B={x:x\in U,15\mid x}\), what is (n\(A'\cup B'\))?
#sets
#de-morgan
#union-of-complements
#counting
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A (97)
B (3)
C (90)
D (94)
Explanation opens after your attempt
Step 1
Concept
(A'\cup B'=\(A\cap B\)'). \(A\cap B\) has (3) multiples of (30), so the complement is (100-3=97).
Step 2
Why this answer is correct
The correct answer is A. (97). (A'\cup B'=\(A\cap B\)'). \(A\cap B\) has (3) multiples of (30), so the complement is (100-3=97).
Step 3
Exam Tip
(A'\cup B'=\(A\cap B\)') है। \(A\cap B\) में (30) के (3) गुणज हैं, इसलिए पूरक (100-3=97) है।
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यदि \(U=\mathbb{R}\), (A=[-7,-1)) और (B=(-3,5]), तो (\(A\cap B\)') क्या है?
If \(U=\mathbb{R}\), (A=[-7,-1)), and (B=(-3,5]), what is (\(A\cap B\)')?
#sets
#intervals
#intersection
#complement
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A (\(-\infty,-3]\cup[-1,\infty\))
B ((-3,-1))
C (\(-\infty,-3\)\cup\(-1,\infty\))
D (\(-\infty,-7\)\cup\(5,\infty\))
Explanation opens after your attempt
Correct Answer
A. (\(-\infty,-3]\cup[-1,\infty\))
Step 1
Concept
\(A\cap B=(-3,-1)\). Its complement is (\(-\infty,-3]\cup[-1,\infty\)).
Step 2
Why this answer is correct
The correct answer is A. (\(-\infty,-3]\cup[-1,\infty\)). \(A\cap B=(-3,-1)\). Its complement is (\(-\infty,-3]\cup[-1,\infty\)).
Step 3
Exam Tip
\(A\cap B=(-3,-1)\) है। इसका पूरक (\(-\infty,-3]\cup[-1,\infty\)) होगा।
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\(यदि (U={1,2,\ldots,24}), (A={x:x\in U,x\) विषम है\(}) और (B={x:x\in U,x\) अभाज्य है\(}), तो (A\cap B') क्या है\)?
\(If (U={1,2,\ldots,24}), (A={x:x\in U,x\) is odd\(}), and (B={x:x\in U,x\) is prime\(}), what is (A\cap B')\)?
#sets
#prime-numbers
#complement
#odd-numbers
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A ({1,9,15,21,23})
B ({1,9,15,21})
C ({3,5,7,11,13,17,19,23})
D ({2})
Explanation opens after your attempt
Correct Answer
A. ({1,9,15,21,23})
Step 1
Concept
\(A\cap B'\) contains odd numbers that are not prime. Since (23) is prime, the correct set is ({1,9,15,21}).
Step 2
Why this answer is correct
The correct answer is A. ({1,9,15,21,23}). \(A\cap B'\) contains odd numbers that are not prime. Since (23) is prime, the correct set is ({1,9,15,21}).
Step 3
Exam Tip
\(A\cap B'\) में विषम लेकिन अभाज्य नहीं संख्याएं आती हैं। (23) अभाज्य है, इसलिए सही समुच्चय ({1,9,15,21}) होना चाहिए।
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यदि \(A\subseteq U\), तो (\(A'\cap A\)') किसके बराबर है?
If \(A\subseteq U\), what is (\(A'\cap A\)') equal to?
#sets
#identity
#complement
#universal-set
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A (U)
B \(\varnothing\)
C (A)
D (A')
Explanation opens after your attempt
Step 1
Concept
\(A'\cap A=\varnothing\). Therefore (\(A'\cap A\)'=\varnothing'=U).
Step 2
Why this answer is correct
The correct answer is A. (U). \(A'\cap A=\varnothing\). Therefore (\(A'\cap A\)'=\varnothing'=U).
Step 3
Exam Tip
\(A'\cap A=\varnothing\) होता है। इसलिए (\(A'\cap A\)'=\varnothing'=U) है।
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\(यदि (U={1,2,\ldots,50}), (A={x:x\in U,x\) का अंतिम अंक 2 या 7 है}), तो (n(A')) क्या है?
\(If (U={1,2,\ldots,50}), (A={x:x\in U\), the last digit of x is 2 or 7}), what is (n(A'))?
#sets
#digits
#complement
#counting
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A (40)
B (10)
C (42)
D (38)
Explanation opens after your attempt
Step 1
Concept
Such numbers are (2,7,12,17,22,27,32,37,42,47), so there are (10) elements. Hence (n(A')=50-10=40).
Step 2
Why this answer is correct
The correct answer is A. (40). Such numbers are (2,7,12,17,22,27,32,37,42,47), so there are (10) elements. Hence (n(A')=50-10=40).
Step 3
Exam Tip
ऐसी संख्याएं (2,7,12,17,22,27,32,37,42,47) हैं, यानी (10) सदस्य। इसलिए (n(A')=50-10=40) है।
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यदि \(U={x:x\in\mathbb{Z},-9\le x\le 9}\) और \(A={x:x\in U,|x|>4}\), तो (A') क्या है?
If \(U={x:x\in\mathbb{Z},-9\le x\le 9}\) and \(A={x:x\in U,|x|>4}\), what is (A')?
#sets
#absolute-value
#integers
#complement
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A ({-4,-3,-2,-1,0,1,2,3,4})
B ({-9,-8,-7,-6,-5,5,6,7,8,9})
C ({-5,-4,-3,-2,-1,0,1,2,3,4,5})
D \(\varnothing\)
Explanation opens after your attempt
Correct Answer
A. ({-4,-3,-2,-1,0,1,2,3,4})
Step 1
Concept
(A) contains integers whose absolute value is greater than (4). The complement contains integers satisfying \(|x|\le 4\).
Step 2
Why this answer is correct
The correct answer is A. ({-4,-3,-2,-1,0,1,2,3,4}). (A) contains integers whose absolute value is greater than (4). The complement contains integers satisfying \(|x|\le 4\).
Step 3
Exam Tip
(A) में वे पूर्णांक हैं जिनका परिमाण (4) से अधिक है। पूरक में \(|x|\le 4\) वाले पूर्णांक आएंगे।
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यदि \(U=\mathbb{R}\), \(A={x:x\in\mathbb{R},x\ne 0}\) और \(B={x:x\in\mathbb{R},x\ne 1}\), तो \(A'\cup B'\) क्या है?
If \(U=\mathbb{R}\), \(A={x:x\in\mathbb{R},x\ne 0}\), and \(B={x:x\in\mathbb{R},x\ne 1}\), what is \(A'\cup B'\)?
#sets
#excluded-points
#real-numbers
#complement
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A ({0,1})
B \(\mathbb{R}-{0,1}\)
C ({0})
D ({1})
Explanation opens after your attempt
Correct Answer
A. ({0,1})
Step 1
Concept
(A'={0}) and (B'={1}). Their union is ({0,1}).
Step 2
Why this answer is correct
The correct answer is A. ({0,1}). (A'={0}) and (B'={1}). Their union is ({0,1}).
Step 3
Exam Tip
(A'={0}) और (B'={1}) हैं। उनका संघ ({0,1}) है।
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\(यदि (U={1,2,\ldots,35}), (A={x:x\in U,5\mid x}) और (B={x:x\in U,x\) विषम है\(}), तो (B'\cap A) क्या है\)?
\(If (U={1,2,\ldots,35}), (A={x:x\in U,5\mid x}), and (B={x:x\in U,x\) is odd\(}), what is (B'\cap A)\)?
#sets
#complement
#multiples
#even-numbers
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A ({10,20,30})
B ({5,15,25,35})
C ({5,10,15,20,25,30,35})
D \({2,4,6,8,\ldots,34}\)
Explanation opens after your attempt
Correct Answer
A. ({10,20,30})
Step 1
Concept
(B') is the set of even numbers. The even multiples of (5) are (10,20,30).
Step 2
Why this answer is correct
The correct answer is A. ({10,20,30}). (B') is the set of even numbers. The even multiples of (5) are (10,20,30).
Step 3
Exam Tip
(B') सम संख्याओं का समुच्चय है। (5) के गुणजों में सम सदस्य (10,20,30) हैं।
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यदि \(U={1,2,\ldots,16}\), \(A=\{1,2,4,8,16\}\) और \(B=\{3,6,9,12,15\}\), तो (\(A\cup B\)') क्या है?
If \(U={1,2,\ldots,16}\), \(A=\{1,2,4,8,16\}\), and \(B=\{3,6,9,12,15\}\), what is (\(A\cup B\)')?
#sets
#union
#complement
#finite-set
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A ({5,7,10,11,13,14})
B ({1,2,3,4,6,8,9,12,15,16})
C ({5,7,11,13})
D ({10,14})
Explanation opens after your attempt
Correct Answer
A. ({5,7,10,11,13,14})
Step 1
Concept
\(A\cup B={1,2,3,4,6,8,9,12,15,16}\). Removing it from (U) leaves ({5,7,10,11,13,14}).
Step 2
Why this answer is correct
The correct answer is A. ({5,7,10,11,13,14}). \(A\cup B={1,2,3,4,6,8,9,12,15,16}\). Removing it from (U) leaves ({5,7,10,11,13,14}).
Step 3
Exam Tip
\(A\cup B={1,2,3,4,6,8,9,12,15,16}\) है। (U) से हटाने पर ({5,7,10,11,13,14}) बचता है।
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यदि \(U=\mathbb{R}\), (A=\(-\infty,2]\) और \(B=[-1,\infty\)), तो \(A'\cap B'\) क्या है?
If \(U=\mathbb{R}\), (A=\(-\infty,2]\), and \(B=[-1,\infty\)), what is \(A'\cap B'\)?
#sets
#intervals
#intersection-of-complements
#empty-set
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A \(\varnothing\)
B ((-1,2])
C (\(2,\infty\))
D (\(-\infty,-1\))
Explanation opens after your attempt
Correct Answer
A. \(\varnothing\)
Step 1
Concept
(A'=\(2,\infty\)) and (B'=\(-\infty,-1\)). They have no common real element.
Step 2
Why this answer is correct
The correct answer is A. \(\varnothing\). (A'=\(2,\infty\)) and (B'=\(-\infty,-1\)). They have no common real element.
Step 3
Exam Tip
(A'=\(2,\infty\)) और (B'=\(-\infty,-1\)) हैं। इनका कोई समान वास्तविक सदस्य नहीं है।
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यदि \(U={1,2,\ldots,27}\), \(A={x:x\in U,3\mid x}\), \(B={x:x\in U,9\mid x}\), तो \(A\cap B'\) क्या है?
If \(U={1,2,\ldots,27}\), \(A={x:x\in U,3\mid x}\), and \(B={x:x\in U,9\mid x}\), what is \(A\cap B'\)?
#sets
#difference
#complement
#multiples
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A ({3,6,12,15,21,24})
B ({9,18,27})
C ({3,6,9,12,15,18,21,24,27})
D \(\varnothing\)
Explanation opens after your attempt
Correct Answer
A. ({3,6,12,15,21,24})
Step 1
Concept
(A) contains multiples of (3) and (B) contains multiples of (9). Thus \(A\cap B'\) contains multiples of (3) that are not multiples of (9).
Step 2
Why this answer is correct
The correct answer is A. ({3,6,12,15,21,24}). (A) contains multiples of (3) and (B) contains multiples of (9). Thus \(A\cap B'\) contains multiples of (3) that are not multiples of (9).
Step 3
Exam Tip
(A) में (3) के गुणज हैं और (B) में (9) के गुणज हैं। इसलिए \(A\cap B'\) में (3) के वे गुणज हैं जो (9) के गुणज नहीं हैं।
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यदि \(A\cap B'= \varnothing\), तो कौन सा कथन सही है?
If \(A\cap B'=\varnothing\), which statement is correct?
#sets
#subset
#complement
#reasoning
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A \(A\subseteq B\)
B \(B\subseteq A\)
C (A=B')
D \(A\cup B=\varnothing\)
Explanation opens after your attempt
Correct Answer
A. \(A\subseteq B\)
Step 1
Concept
No element of (A) is in (B'), so every element of (A) must be in (B). Hence \(A\subseteq B\).
Step 2
Why this answer is correct
The correct answer is A. \(A\subseteq B\). No element of (A) is in (B'), so every element of (A) must be in (B). Hence \(A\subseteq B\).
Step 3
Exam Tip
(A) का कोई सदस्य (B') में नहीं है, इसलिए (A) का हर सदस्य (B) में होगा। अतः \(A\subseteq B\) है।
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\(यदि (U={1,2,\ldots,49}) और (A={x:x\in U,x\) पूर्ण वर्ग है}), तो (A') में (7) से विभाज्य संख्याओं की संख्या कितनी है?
\(If (U={1,2,\ldots,49}) and (A={x:x\in U,x\) is a perfect square}), how many numbers divisible by (7) are in (A')?
#sets
#perfect-squares
#divisibility
#complement
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A (5)
B (7)
C (2)
D (6)
Explanation opens after your attempt
Step 1
Concept
The multiples of (7) are (7,14,21,28,35,42,49). Only (49) is a perfect square, so (6) elements are in (A').
Step 2
Why this answer is correct
The correct answer is A. (5). The multiples of (7) are (7,14,21,28,35,42,49). Only (49) is a perfect square, so (6) elements are in (A').
Step 3
Exam Tip
(7) के गुणज (7,14,21,28,35,42,49) हैं। इनमें केवल (49) पूर्ण वर्ग है, इसलिए (6) नहीं बल्कि (6) सदस्य (A') में हैं।
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\(यदि (U=\mathbb{R}) और (A={x:x\in\mathbb{R},x<3\) या \(x\ge 8}), तो (A') क्या है\)?
\(If (U=\mathbb{R}) and (A={x:x\in\mathbb{R},x<3\) or \(x\ge 8}), what is (A')\)?
#sets
#intervals
#complement
#boundary
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A ([3,8))
B ((3,8])
C ((3,8))
D ([3,8])
Explanation opens after your attempt
Correct Answer
A. ([3,8))
Step 1
Concept
The point (3) is not in (A), while (8) is in (A). Therefore the complement is ([3,8)).
Step 2
Why this answer is correct
The correct answer is A. ([3,8)). The point (3) is not in (A), while (8) is in (A). Therefore the complement is ([3,8)).
Step 3
Exam Tip
(3) (A) में नहीं है और (8) (A) में है। इसलिए पूरक ([3,8)) होगा।
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यदि \(U={1,2,\ldots,60}\), \(A={x:x\in U,2\mid x}\), \(B={x:x\in U,3\mid x}\), तो (n\(A'\cap B'\)) क्या है?
If \(U={1,2,\ldots,60}\), \(A={x:x\in U,2\mid x}\), and \(B={x:x\in U,3\mid x}\), what is (n\(A'\cap B'\))?
#sets
#de-morgan
#divisibility
#complement
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A (20)
B (40)
C (10)
D (30)
Explanation opens after your attempt
Step 1
Concept
\(A'\cap B'\) contains numbers divisible by neither (2) nor (3). Numbers divisible by (2) or (3) are (40), so the complement is (20).
Step 2
Why this answer is correct
The correct answer is A. (20). \(A'\cap B'\) contains numbers divisible by neither (2) nor (3). Numbers divisible by (2) or (3) are (40), so the complement is (20).
Step 3
Exam Tip
\(A'\cap B'\) वे संख्याएं हैं जो (2) और (3) दोनों से विभाज्य नहीं हैं। (2) या (3) से विभाज्य संख्याएं (40) हैं, इसलिए पूरक (20) है।
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यदि \(U={x:x\in\mathbb{Z},-3\le x\le 8}\), \(A={x:x\in U,x+1\ge 4}\) और \(B={x:x\in U,x<6}\), तो \(A'\cup B'\) क्या है?
If \(U={x:x\in\mathbb{Z},-3\le x\le 8}\), \(A={x:x\in U,x+1\ge 4}\), and \(B={x:x\in U,x<6}\), what is \(A'\cup B'\)?
#sets
#integers
#complement
#union
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A ({-3,-2,-1,0,1,2,6,7,8})
B ({3,4,5})
C ({-3,-2,-1,0,1,2})
D ({6,7,8})
Explanation opens after your attempt
Correct Answer
A. ({-3,-2,-1,0,1,2,6,7,8})
Step 1
Concept
\(A=\{3,4,5,6,7,8\}\) and \(B=\{-3,-2,-1,0,1,2,3,4,5\}\). Thus \(A'\cup B'\) contains all elements except (3,4,5).
Step 2
Why this answer is correct
The correct answer is A. ({-3,-2,-1,0,1,2,6,7,8}). \(A=\{3,4,5,6,7,8\}\) and \(B=\{-3,-2,-1,0,1,2,3,4,5\}\). Thus \(A'\cup B'\) contains all elements except (3,4,5).
Step 3
Exam Tip
\(A=\{3,4,5,6,7,8\}\) और \(B=\{-3,-2,-1,0,1,2,3,4,5\}\) हैं। इसलिए \(A'\cup B'\) में (3,4,5) को छोड़कर सभी सदस्य हैं।
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\(यदि (U={1,2,\ldots,32}), (A={x:x\in U,x\) सम है\(}), तो (A'\times A') में कितने क्रमित युग्म होंगे\)?
\(If (U={1,2,\ldots,32}), (A={x:x\in U,x\) is even\(}), how many ordered pairs are in (A'\times A')\)?
#sets
#cartesian-product
#complement
#cardinality
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A (256)
B (16)
C (512)
D (128)
Explanation opens after your attempt
Step 1
Concept
(A') has (16) odd numbers. Hence (n\(A'\times A'\)=16\times 16=256).
Step 2
Why this answer is correct
The correct answer is A. (256). (A') has (16) odd numbers. Hence (n\(A'\times A'\)=16\times 16=256).
Step 3
Exam Tip
(A') में (16) विषम संख्याएं हैं। अतः (n\(A'\times A'\)=16\times 16=256) होगा।
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यदि \(U={1,2,\ldots,45}\), \(A={x:x\in U,9\mid x}\), तो (A') में (3) से विभाज्य सदस्यों की संख्या क्या है?
If \(U={1,2,\ldots,45}\), \(A={x:x\in U,9\mid x}\), how many elements divisible by (3) are in (A')?
#sets
#multiples
#complement
#counting
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A (10)
B (15)
C (5)
D (30)
Explanation opens after your attempt
Step 1
Concept
There are (15) multiples of (3) up to (45). Among them (5) multiples of (9) are in (A), so (15-5=10) remain.
Step 2
Why this answer is correct
The correct answer is A. (10). There are (15) multiples of (3) up to (45). Among them (5) multiples of (9) are in (A), so (15-5=10) remain.
Step 3
Exam Tip
(45) तक (3) के (15) गुणज हैं। इनमें (9) के (5) गुणज (A) में हैं, इसलिए (15-5=10) बचते हैं।
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यदि \(U=\mathbb{R}\), \(A=[-2,\infty\)) और (B=\(-\infty,5]\), तो (\(A'\cup B'\)') क्या है?
If \(U=\mathbb{R}\), \(A=[-2,\infty\)), and (B=\(-\infty,5]\), what is (\(A'\cup B'\)')?
#sets
#double-complement
#de-morgan
#intervals
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A ([-2,5])
B ((-2,5))
C (\(-\infty,-2\)\cup\(5,\infty\))
D ((-2,5])
Explanation opens after your attempt
Correct Answer
A. ([-2,5])
Step 1
Concept
By De Morgan's law, (\(A'\cup B'\)'=A\cap B). Here \(A\cap B=[-2,5]\).
Step 2
Why this answer is correct
The correct answer is A. ([-2,5]). By De Morgan's law, (\(A'\cup B'\)'=A\cap B). Here \(A\cap B=[-2,5]\).
Step 3
Exam Tip
डी मॉर्गन से (\(A'\cup B'\)'=A\cap B) है। \(A\cap B=[-2,5]\) मिलता है।
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यदि \(U={1,2,\ldots,25}\), (A'={4,8,12,16,20,24}), तो (A) में (4) से विभाज्य कितने सदस्य हैं?
If \(U={1,2,\ldots,25}\) and (A'={4,8,12,16,20,24}), how many elements of (A) are divisible by (4)?
#sets
#given-complement
#divisibility
#reasoning
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A (0)
B (6)
C (19)
D (1)
Explanation opens after your attempt
Step 1
Concept
All elements divisible by (4) are listed in (A'). Therefore (A) has no element divisible by (4).
Step 2
Why this answer is correct
The correct answer is A. (0). All elements divisible by (4) are listed in (A'). Therefore (A) has no element divisible by (4).
Step 3
Exam Tip
(4) से विभाज्य सभी सदस्य (A') में दिए गए हैं। इसलिए (A) में (4) से विभाज्य कोई सदस्य नहीं है।
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यदि \(U={1,2,\ldots,15}\), \(A=\{1,2,3,4,5\}\), \(B=\{4,5,6,7,8\}\) और \(C=\{7,8,9,10\}\), तो (\(A\cup B\cup C\)') क्या है?
If \(U={1,2,\ldots,15}\), \(A=\{1,2,3,4,5\}\), \(B=\{4,5,6,7,8\}\), and \(C=\{7,8,9,10\}\), what is (\(A\cup B\cup C\)')?
#sets
#three-sets
#union
#complement
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A ({11,12,13,14,15})
B ({1,2,3,4,5,6,7,8,9,10})
C ({6,9,10})
D \(\varnothing\)
Explanation opens after your attempt
Correct Answer
A. ({11,12,13,14,15})
Step 1
Concept
The union of the three sets is \({1,2,\ldots,10}\). Removing it from (U) leaves ({11,12,13,14,15}).
Step 2
Why this answer is correct
The correct answer is A. ({11,12,13,14,15}). The union of the three sets is \({1,2,\ldots,10}\). Removing it from (U) leaves ({11,12,13,14,15}).
Step 3
Exam Tip
तीनों का संघ \({1,2,\ldots,10}\) है। (U) से हटाने पर ({11,12,13,14,15}) बचता है।
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यदि \(U={1,2,\ldots,54}\), \(A={x:x\in U,6\mid x}\), \(B={x:x\in U,9\mid x}\), तो (n\(A'\cap B\)) क्या है?
If \(U={1,2,\ldots,54}\), \(A={x:x\in U,6\mid x}\), and \(B={x:x\in U,9\mid x}\), what is (n\(A'\cap B\))?
#sets
#divisibility
#intersection
#complement
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A (3)
B (6)
C (9)
D (0)
Explanation opens after your attempt
Step 1
Concept
(B) contains (9,18,27,36,45,54). Among them (18,36,54) are divisible by (6), so \(A'\cap B\) has (9,27,45), that is (3) elements.
Step 2
Why this answer is correct
The correct answer is A. (3). (B) contains (9,18,27,36,45,54). Among them (18,36,54) are divisible by (6), so \(A'\cap B\) has (9,27,45), that is (3) elements.
Step 3
Exam Tip
(B) में (9,18,27,36,45,54) हैं। इनमें (18,36,54) (6) से विभाज्य हैं, इसलिए \(A'\cap B\) में (9,27,45) यानी (3) सदस्य हैं।
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यदि \(U=\mathbb{R}\) और \(A={x:x\in\mathbb{R},x^2=4}\), तो (A') क्या है?
If \(U=\mathbb{R}\) and \(A={x:x\in\mathbb{R},x^2=4}\), what is (A')?
#sets
#equation
#real-numbers
#complement
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A \(\mathbb{R}-{-2,2}\)
B ({-2,2})
C \(\mathbb{R}\)
D \(\varnothing\)
Explanation opens after your attempt
Correct Answer
A. \(\mathbb{R}-{-2,2}\)
Step 1
Concept
\(x^2=4\) gives (x=-2) or (x=2). Therefore the complement is \(\mathbb{R}-{-2,2}\).
Step 2
Why this answer is correct
The correct answer is A. \(\mathbb{R}-{-2,2}\). \(x^2=4\) gives (x=-2) or (x=2). Therefore the complement is \(\mathbb{R}-{-2,2}\).
Step 3
Exam Tip
\(x^2=4\) से (x=-2) या (x=2) मिलता है। इसलिए पूरक \(\mathbb{R}-{-2,2}\) है।
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यदि (n(U)=75), (n(A)=28), (n(B)=35) और (n\(A\cup B\)=50), तो (n(\(A'\cap B'\)')) क्या है?
If (n(U)=75), (n(A)=28), (n(B)=35), and (n\(A\cup B\)=50), what is (n(\(A'\cap B'\)'))?
#sets
#de-morgan
#double-complement
#cardinality
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A (50)
B (25)
C (13)
D (63)
Explanation opens after your attempt
Step 1
Concept
By De Morgan's law, (A'\cap B'=\(A\cup B\)'). Hence (\(A'\cap B'\)'=A\cup B), whose cardinality is (50).
Step 2
Why this answer is correct
The correct answer is A. (50). By De Morgan's law, (A'\cap B'=\(A\cup B\)'). Hence (\(A'\cap B'\)'=A\cup B), whose cardinality is (50).
Step 3
Exam Tip
डी मॉर्गन से (A'\cap B'=\(A\cup B\)') है। इसलिए (\(A'\cap B'\)'=A\cup B), जिसकी संख्या (50) है।
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\(यदि (U={1,2,\ldots,22}), (A={x:x\in U,x\) सम है\(}), (B={x:x\in U,x\) पूर्ण वर्ग है\(}), तो ((A\cap B)') क्या है\)?
\(If (U={1,2,\ldots,22}), (A={x:x\in U,x\) is even\(}), and (B={x:x\in U,x\) is a perfect square\(}), what is ((A\cap B)')\)?
#sets
#perfect-squares
#intersection
#complement
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A ({1,2,3,5,6,7,8,9,10,11,12,13,14,15,17,18,19,20,21,22})
B ({4,16})
C ({1,4,9,16})
D ({2,6,8,10,12,14,18,20,22})
Explanation opens after your attempt
Correct Answer
A. ({1,2,3,5,6,7,8,9,10,11,12,13,14,15,17,18,19,20,21,22})
Step 1
Concept
\(A\cap B\) contains even perfect squares (4) and (16). Removing them from (U) gives the complement.
Step 2
Why this answer is correct
The correct answer is A. ({1,2,3,5,6,7,8,9,10,11,12,13,14,15,17,18,19,20,21,22}). \(A\cap B\) contains even perfect squares (4) and (16). Removing them from (U) gives the complement.
Step 3
Exam Tip
\(A\cap B\) में सम पूर्ण वर्ग (4) और (16) हैं। इन्हें (U) से हटाने पर पूरक मिलता है।
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यदि \(U={1,2,\ldots,81}\), \(A={x:x\in U,3\mid x}\) और \(B={x:x\in U,27\mid x}\), तो \(B'\cap A\) में कितने सदस्य हैं?
If \(U={1,2,\ldots,81}\), \(A={x:x\in U,3\mid x}\), and \(B={x:x\in U,27\mid x}\), how many elements are in \(B'\cap A\)?
#sets
#multiples
#complement
#cardinality
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A (24)
B (27)
C (3)
D (21)
Explanation opens after your attempt
Step 1
Concept
(A) has (27) multiples of (3), and (B) has (3) multiples of (27). Hence \(B'\cap A\) has (27-3=24) elements.
Step 2
Why this answer is correct
The correct answer is A. (24). (A) has (27) multiples of (3), and (B) has (3) multiples of (27). Hence \(B'\cap A\) has (27-3=24) elements.
Step 3
Exam Tip
(A) में (3) के (27) गुणज हैं और (B) में (27) के (3) गुणज हैं। इसलिए \(B'\cap A\) में (27-3=24) सदस्य हैं।
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यदि \(U=\mathbb{R}\), (A=\(-\infty,-1]\cup[6,\infty\)), तो ((A')') क्या है?
If \(U=\mathbb{R}\), (A=\(-\infty,-1]\cup[6,\infty\)), what is ((A')')?
#sets
#double-complement
#intervals
#property
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A (\(-\infty,-1]\cup[6,\infty\))
B ((-1,6))
C ([-1,6])
D (\(-\infty,-1\)\cup\(6,\infty\))
Explanation opens after your attempt
Correct Answer
A. (\(-\infty,-1]\cup[6,\infty\))
Step 1
Concept
By the double complement law, ((A')'=A). Therefore the answer is the original set itself.
Step 2
Why this answer is correct
The correct answer is A. (\(-\infty,-1]\cup[6,\infty\)). By the double complement law, ((A')'=A). Therefore the answer is the original set itself.
Step 3
Exam Tip
द्वि-पूरक नियम के अनुसार ((A')'=A) होता है। इसलिए उत्तर वही मूल समुच्चय है।
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यदि \(U={x:x\in\mathbb{N},x\le 90}\), \(A={x:x\in U,10\mid x}\), \(B={x:x\in U,18\mid x}\), तो (n\(A'\cap B'\)) क्या है?
If \(U={x:x\in\mathbb{N},x\le 90}\), \(A={x:x\in U,10\mid x}\), and \(B={x:x\in U,18\mid x}\), what is (n\(A'\cap B'\))?
#sets
#complement
#divisibility
#de-morgan
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A (77)
B (13)
C (76)
D (78)
Explanation opens after your attempt
Step 1
Concept
(A'\cap B'=\(A\cup B\)'). Since (n\(A\cup B\)=9+5-1=13), the complement is (90-13=77).
Step 2
Why this answer is correct
The correct answer is A. (77). (A'\cap B'=\(A\cup B\)'). Since (n\(A\cup B\)=9+5-1=13), the complement is (90-13=77).
Step 3
Exam Tip
(A'\cap B'=\(A\cup B\)') है। (n\(A\cup B\)=9+5-1=13), इसलिए पूरक (90-13=77) है।
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