यदि \(U=\mathbb{R}\), (A=(-2,6]) और (B=[0,9)), तो \(A'\cup B'\) क्या है?
If \(U=\mathbb{R}\), (A=(-2,6]), and (B=[0,9)), what is \(A'\cup B'\)?
Explanation opens after your attempt
A. (\(-\infty,0\)\cup\(6,\infty\))
Concept
By De Morgan's law, (A'\cup B'=\(A\cap B\)'). Since \(A\cap B=[0,6]\), the complement is (\(-\infty,0\)\cup\(6,\infty\)).
Why this answer is correct
The correct answer is A. (\(-\infty,0\)\cup\(6,\infty\)). By De Morgan's law, (A'\cup B'=\(A\cap B\)'). Since \(A\cap B=[0,6]\), the complement is (\(-\infty,0\)\cup\(6,\infty\)).
Exam Tip
डी मॉर्गन से (A'\cup B'=\(A\cap B\)') है। \(A\cap B=[0,6]\), इसलिए पूरक (\(-\infty,0\)\cup\(6,\infty\)) है।
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