\(यदि (U={1,2,\ldots,32}), (A={x:x\in U,x\) सम है\(}), तो (A'\times A') में कितने क्रमित युग्म होंगे\)?
\(If (U={1,2,\ldots,32}), (A={x:x\in U,x\) is even\(}), how many ordered pairs are in (A'\times A')\)?
Explanation opens after your attempt
Correct Answer
A. (256)
Concept
(A') has (16) odd numbers. Hence (n\(A'\times A'\)=16\times 16=256).
Why this answer is correct
The correct answer is A. (256). (A') has (16) odd numbers. Hence (n\(A'\times A'\)=16\times 16=256).
Exam Tip
(A') में (16) विषम संख्याएं हैं। अतः (n\(A'\times A'\)=16\times 16=256) होगा।
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