Class 11 Mathematics Sets Complement of a Set and its properties Expert Level 21

यदि \(U={1,2,\ldots,18}\), \(A=\{2,4,6,8,10,12,14,16,18\}\) और \(B=\{1,2,3,5,8,13\}\), तो \(A'\cap B'\) क्या है?

If \(U={1,2,\ldots,18}\), \(A=\{2,4,6,8,10,12,14,16,18\}\), and \(B=\{1,2,3,5,8,13\}\), what is \(A'\cap B'\)?

Explanation opens after your attempt
Correct Answer

A. ({7,9,11,15,17})

Step 1

Concept

(A') is the set of odd numbers, and (1,3,5,13) from (B) are removed. Thus ({7,9,11,15,17}) remains.

Step 2

Why this answer is correct

The correct answer is A. ({7,9,11,15,17}). (A') is the set of odd numbers, and (1,3,5,13) from (B) are removed. Thus ({7,9,11,15,17}) remains.

Step 3

Exam Tip

(A') विषम संख्याओं का समुच्चय है और उसमें से (B) के (1,3,5,13) हटेंगे। इसलिए ({7,9,11,15,17}) बचेगा।

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Mathematics Answer, Explanation and Revision Hints

यदि \(U={1,2,\ldots,18}\), \(A=\{2,4,6,8,10,12,14,16,18\}\) और \(B=\{1,2,3,5,8,13\}\), तो \(A'\cap B'\) क्या है? / If \(U={1,2,\ldots,18}\), \(A=\{2,4,6,8,10,12,14,16,18\}\), and \(B=\{1,2,3,5,8,13\}\), what is \(A'\cap B'\)?

Correct Answer: A. ({7,9,11,15,17}). Explanation: (A') विषम संख्याओं का समुच्चय है और उसमें से (B) के (1,3,5,13) हटेंगे। इसलिए ({7,9,11,15,17}) बचेगा। / (A') is the set of odd numbers, and (1,3,5,13) from (B) are removed. Thus ({7,9,11,15,17}) remains.

Which concept should I revise for this Mathematics MCQ?

(A') is the set of odd numbers, and (1,3,5,13) from (B) are removed. Thus ({7,9,11,15,17}) remains.

What exam hint can help solve this Mathematics question?

(A') विषम संख्याओं का समुच्चय है और उसमें से (B) के (1,3,5,13) हटेंगे। इसलिए ({7,9,11,15,17}) बचेगा।