यदि \(U={1,2,\ldots,100}\), \(A={x:x\in U,10\mid x}\) और \(B={x:x\in U,15\mid x}\), तो (n\(A'\cup B'\)) क्या है?

If \(U={1,2,\ldots,100}\), \(A={x:x\in U,10\mid x}\), and \(B={x:x\in U,15\mid x}\), what is (n\(A'\cup B'\))?

Explanation opens after your attempt
Correct Answer

A. (97)

Step 1

Concept

(A'\cup B'=\(A\cap B\)'). \(A\cap B\) has (3) multiples of (30), so the complement is (100-3=97).

Step 2

Why this answer is correct

The correct answer is A. (97). (A'\cup B'=\(A\cap B\)'). \(A\cap B\) has (3) multiples of (30), so the complement is (100-3=97).

Step 3

Exam Tip

(A'\cup B'=\(A\cap B\)') है। \(A\cap B\) में (30) के (3) गुणज हैं, इसलिए पूरक (100-3=97) है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(U={1,2,\ldots,100}\), \(A={x:x\in U,10\mid x}\) और \(B={x:x\in U,15\mid x}\), तो (n\(A'\cup B'\)) क्या है? / If \(U={1,2,\ldots,100}\), \(A={x:x\in U,10\mid x}\), and \(B={x:x\in U,15\mid x}\), what is (n\(A'\cup B'\))?

Correct Answer: A. (97). Explanation: (A'\cup B'=\(A\cap B\)') है। \(A\cap B\) में (30) के (3) गुणज हैं, इसलिए पूरक (100-3=97) है। / (A'\cup B'=\(A\cap B\)'). \(A\cap B\) has (3) multiples of (30), so the complement is (100-3=97).

Which concept should I revise for this Mathematics MCQ?

(A'\cup B'=\(A\cap B\)'). \(A\cap B\) has (3) multiples of (30), so the complement is (100-3=97).

What exam hint can help solve this Mathematics question?

(A'\cup B'=\(A\cap B\)') है। \(A\cap B\) में (30) के (3) गुणज हैं, इसलिए पूरक (100-3=97) है।