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Class 10 Mathematics Medium Quiz

Level 26 • 50/50 questions • 35 seconds per question.

Level readiness 50/50 Questions
Time Left 29:10 35 sec/question
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Question 1 / 50 0 score
Answered 0/50 Correct 0 Time 29:10

कौन सा विकल्प \(\sqrt{180}\) का सरल रूप है?

Which option is the simplified form of \(\sqrt{180}\)?

Explanation opens after your attempt
Correct Answer

A. \(6\sqrt{5}\)

Step 1

Concept

\(\sqrt{180}=\sqrt{36\times5}=6\sqrt{5}\). Take out the greatest perfect square.

Step 2

Why this answer is correct

The correct answer is A. \(6\sqrt{5}\). \(\sqrt{180}=\sqrt{36\times5}=6\sqrt{5}\). Take out the greatest perfect square.

Step 3

Exam Tip

\(\sqrt{180}=\sqrt{36\times5}=6\sqrt{5}\) है। सबसे बड़ा पूर्ण वर्ग बाहर निकालें।

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यदि \(x=\sqrt{17}\) है तो \(x^2-5\) किस प्रकार की संख्या है?

If \(x=\sqrt{17}\), what type of number is \(x^2-5\)?

Explanation opens after your attempt
Correct Answer

A. परिमेय संख्याRational number

Step 1

Concept

Here \(x^2=17\), so \(x^2-5=12\). This is a rational number.

Step 2

Why this answer is correct

The correct answer is A. परिमेय संख्या / Rational number. Here \(x^2=17\), so \(x^2-5=12\). This is a rational number.

Step 3

Exam Tip

\(x^2=17\) इसलिए \(x^2-5=12\) है। यह परिमेय संख्या है।

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कौन सा विकल्प \(4+\sqrt{13}\) की प्रकृति सही बताता है?

Which option correctly describes the nature of \(4+\sqrt{13}\)?

Explanation opens after your attempt
Correct Answer

A. अपरिमेय संख्याIrrational number

Step 1

Concept

(4) is rational and \(\sqrt{13}\) is irrational. The sum of a rational and an irrational number is irrational.

Step 2

Why this answer is correct

The correct answer is A. अपरिमेय संख्या / Irrational number. (4) is rational and \(\sqrt{13}\) is irrational. The sum of a rational and an irrational number is irrational.

Step 3

Exam Tip

(4) परिमेय है और \(\sqrt{13}\) अपरिमेय है। परिमेय और अपरिमेय का योग अपरिमेय होता है।

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कौन सा विकल्प \(7-\sqrt{19}\) के बारे में सही है?

Which option is correct about \(7-\sqrt{19}\)?

Explanation opens after your attempt
Correct Answer

A. यह अपरिमेय हैIt is irrational

Step 1

Concept

\(\sqrt{19}\) is irrational because (19) is not a perfect square. Subtracting an irrational from a rational gives an irrational result.

Step 2

Why this answer is correct

The correct answer is A. यह अपरिमेय है / It is irrational. \(\sqrt{19}\) is irrational because (19) is not a perfect square. Subtracting an irrational from a rational gives an irrational result.

Step 3

Exam Tip

\(\sqrt{19}\) अपरिमेय है क्योंकि (19) पूर्ण वर्ग नहीं है। परिमेय से अपरिमेय घटाने पर परिणाम अपरिमेय होता है।

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कौन सा विकल्प \(\sqrt{125}+\sqrt{45}\) का सरल रूप है?

Which option is the simplified form of \(\sqrt{125}+\sqrt{45}\)?

Explanation opens after your attempt
Correct Answer

A. \(8\sqrt{5}\)

Step 1

Concept

\(\sqrt{125}=5\sqrt{5}\) and \(\sqrt{45}=3\sqrt{5}\). Adding like terms gives \(8\sqrt{5}\).

Step 2

Why this answer is correct

The correct answer is A. \(8\sqrt{5}\). \(\sqrt{125}=5\sqrt{5}\) and \(\sqrt{45}=3\sqrt{5}\). Adding like terms gives \(8\sqrt{5}\).

Step 3

Exam Tip

\(\sqrt{125}=5\sqrt{5}\) और \(\sqrt{45}=3\sqrt{5}\) है। समान पद जोड़ने पर \(8\sqrt{5}\) मिलता है।

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कौन सा विकल्प \(\sqrt{192}-\sqrt{27}\) का सरल रूप है?

Which option is the simplified form of \(\sqrt{192}-\sqrt{27}\)?

Explanation opens after your attempt
Correct Answer

A. \(5\sqrt{3}\)

Step 1

Concept

\(\sqrt{192}=8\sqrt{3}\) and \(\sqrt{27}=3\sqrt{3}\). The difference is \(5\sqrt{3}\).

Step 2

Why this answer is correct

The correct answer is A. \(5\sqrt{3}\). \(\sqrt{192}=8\sqrt{3}\) and \(\sqrt{27}=3\sqrt{3}\). The difference is \(5\sqrt{3}\).

Step 3

Exam Tip

\(\sqrt{192}=8\sqrt{3}\) और \(\sqrt{27}=3\sqrt{3}\) है। अंतर \(5\sqrt{3}\) है।

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कौन सा विकल्प \(\sqrt{10}\times\sqrt{40}\) का मान है?

Which option is the value of \(\sqrt{10}\times\sqrt{40}\)?

Explanation opens after your attempt
Correct Answer

A. (20)

Step 1

Concept

\(\sqrt{10}\times\sqrt{40}=\sqrt{400}=20\). The product of two irrational numbers can be rational.

Step 2

Why this answer is correct

The correct answer is A. (20). \(\sqrt{10}\times\sqrt{40}=\sqrt{400}=20\). The product of two irrational numbers can be rational.

Step 3

Exam Tip

\(\sqrt{10}\times\sqrt{40}=\sqrt{400}=20\) है। दो अपरिमेय संख्याओं का गुणनफल परिमेय हो सकता है।

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कौन सा विकल्प \(\sqrt{6}\times\sqrt{10}\) की प्रकृति सही बताता है?

Which option correctly describes the nature of \(\sqrt{6}\times\sqrt{10}\)?

Explanation opens after your attempt
Correct Answer

A. अपरिमेय संख्याIrrational number

Step 1

Concept

\(\sqrt{6}\times\sqrt{10}=\sqrt{60}=2\sqrt{15}\). Since (15) is not a perfect square the result is irrational.

Step 2

Why this answer is correct

The correct answer is A. अपरिमेय संख्या / Irrational number. \(\sqrt{6}\times\sqrt{10}=\sqrt{60}=2\sqrt{15}\). Since (15) is not a perfect square the result is irrational.

Step 3

Exam Tip

\(\sqrt{6}\times\sqrt{10}=\sqrt{60}=2\sqrt{15}\) है। (15) पूर्ण वर्ग नहीं है इसलिए परिणाम अपरिमेय है।

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यदि \(a=3+\sqrt{6}\) और \(b=3-\sqrt{6}\) हैं तो (a+b) का मान क्या है?

If \(a=3+\sqrt{6}\) and \(b=3-\sqrt{6}\), what is the value of (a+b)?

Explanation opens after your attempt
Correct Answer

A. (6)

Step 1

Concept

In the sum \(\sqrt{6}\) and \(-\sqrt{6}\) cancel. So (a+b=6).

Step 2

Why this answer is correct

The correct answer is A. (6). In the sum \(\sqrt{6}\) and \(-\sqrt{6}\) cancel. So (a+b=6).

Step 3

Exam Tip

योग में \(\sqrt{6}\) और \(-\sqrt{6}\) कट जाते हैं। इसलिए (a+b=6) है।

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यदि \(u=6+\sqrt{5}\) और \(v=6-\sqrt{5}\) हैं तो (uv) का मान क्या है?

If \(u=6+\sqrt{5}\) and \(v=6-\sqrt{5}\), what is the value of (uv)?

Explanation opens after your attempt
Correct Answer

A. (31)

Step 1

Concept

Conjugate multiplication gives ((6)2-\(\sqrt{5}\)2=36-5=31). Use \(a^2-b^2\) in such questions.

Step 2

Why this answer is correct

The correct answer is A. (31). Conjugate multiplication gives ((6)2-\(\sqrt{5}\)2=36-5=31). Use \(a^2-b^2\) in such questions.

Step 3

Exam Tip

संयुग्मी गुणन से ((6)2-\(\sqrt{5}\)2=36-5=31) मिलता है। ऐसे प्रश्नों में \(a^2-b^2\) प्रयोग करें।

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कौन सा विकल्प (\(\sqrt{11}+2\)\(\sqrt{11}-2\)) का मान है?

Which option is the value of (\(\sqrt{11}+2\)\(\sqrt{11}-2\))?

Explanation opens after your attempt
Correct Answer

A. (7)

Step 1

Concept

This is ((a+b)(a-b)=a-2-b-2). The value is (11-4=7).

Step 2

Why this answer is correct

The correct answer is A. (7). This is ((a+b)(a-b)=a-2-b-2). The value is (11-4=7).

Step 3

Exam Tip

यह ((a+b)(a-b)=a-2-b-2) है। मान (11-4=7) होगा।

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कौन सा विकल्प (\(3+\sqrt{2}\)2) का सही विस्तार है?

Which option is the correct expansion of (\(3+\sqrt{2}\)2)?

Explanation opens after your attempt
Correct Answer

A. \(11+6\sqrt{2}\)

Step 1

Concept

(\(3+\sqrt{2}\)2=9+6\sqrt{2}+2=11+6\sqrt{2}). Do not miss the middle term in the square formula.

Step 2

Why this answer is correct

The correct answer is A. \(11+6\sqrt{2}\). (\(3+\sqrt{2}\)2=9+6\sqrt{2}+2=11+6\sqrt{2}). Do not miss the middle term in the square formula.

Step 3

Exam Tip

(\(3+\sqrt{2}\)2=9+6\sqrt{2}+2=11+6\sqrt{2}) है। वर्ग सूत्र में बीच का पद न छोड़ें।

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कौन सा विकल्प (7) और (8) के बीच की परिमेय संख्या है?

Which option is a rational number between (7) and (8)?

Explanation opens after your attempt
Correct Answer

A. \(\frac{15}{2}\)

Step 1

Concept

\(\frac{15}{2}=7.5\), which lies between (7) and (8). Fraction form shows rationality.

Step 2

Why this answer is correct

The correct answer is A. \(\frac{15}{2}\). \(\frac{15}{2}=7.5\), which lies between (7) and (8). Fraction form shows rationality.

Step 3

Exam Tip

\(\frac{15}{2}=7.5\) है जो (7) और (8) के बीच है। भिन्न रूप परिमेयता बताता है।

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कौन सा विकल्प \(\sqrt{7}\) के निकटतम दो पूर्णांकों को सही बताता है?

Which option correctly gives the two nearest integers between which \(\sqrt{7}\) lies?

Explanation opens after your attempt
Correct Answer

A. (2) और (3)(2) and (3)

Step 1

Concept

Since (4<7<9), \(2<\sqrt{7}<3\). Locate roots using squares.

Step 2

Why this answer is correct

The correct answer is A. (2) और (3) / (2) and (3). Since (4<7<9), \(2<\sqrt{7}<3\). Locate roots using squares.

Step 3

Exam Tip

क्योंकि (4<7<9) इसलिए \(2<\sqrt{7}<3\)। जड़ की स्थिति वर्गों से पहचानें।

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कौन सा विकल्प \(\sqrt{90}\) और \(\sqrt{99}\) की तुलना सही करता है?

Which option correctly compares \(\sqrt{90}\) and \(\sqrt{99}\)?

Explanation opens after your attempt
Correct Answer

A. \(\sqrt{99}>\sqrt{90}\)

Step 1

Concept

For positive numbers a larger number inside the square root gives a larger value. Here (99>90).

Step 2

Why this answer is correct

The correct answer is A. \(\sqrt{99}>\sqrt{90}\). For positive numbers a larger number inside the square root gives a larger value. Here (99>90).

Step 3

Exam Tip

धनात्मक संख्याओं में अंदर की संख्या बड़ी हो तो वर्गमूल भी बड़ा होता है। (99>90) है।

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कौन सा विकल्प \(\sqrt{0.64}+\sqrt{0.09}\) का मान है?

Which option is the value of \(\sqrt{0.64}+\sqrt{0.09}\)?

Explanation opens after your attempt
Correct Answer

A. (1.1)

Step 1

Concept

\(\sqrt{0.64}=0.8\) and \(\sqrt{0.09}=0.3\). The sum is (1.1).

Step 2

Why this answer is correct

The correct answer is A. (1.1). \(\sqrt{0.64}=0.8\) and \(\sqrt{0.09}=0.3\). The sum is (1.1).

Step 3

Exam Tip

\(\sqrt{0.64}=0.8\) और \(\sqrt{0.09}=0.3\) है। योग (1.1) है।

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कौन सा विकल्प \(\frac{\sqrt{80}}{\sqrt{5}}\) का मान है?

Which option is the value of \(\frac{\sqrt{80}}{\sqrt{5}}\)?

Explanation opens after your attempt
Correct Answer

A. (4)

Step 1

Concept

\(\frac{\sqrt{80}}{\sqrt{5}}=\sqrt{16}=4\). In division of roots simplify the quotient inside.

Step 2

Why this answer is correct

The correct answer is A. (4). \(\frac{\sqrt{80}}{\sqrt{5}}=\sqrt{16}=4\). In division of roots simplify the quotient inside.

Step 3

Exam Tip

\(\frac{\sqrt{80}}{\sqrt{5}}=\sqrt{16}=4\) है। जड़ों के भाग में अंदर का भागफल सरल करें।

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कौन सा विकल्प \(\frac{3}{\sqrt{3}}\) का सरल रूप है?

Which option is the simplified form of \(\frac{3}{\sqrt{3}}\)?

Explanation opens after your attempt
Correct Answer

A. \(\sqrt{3}\)

Step 1

Concept

\(\frac{3}{\sqrt{3}}=\sqrt{3}\) because \(3=\sqrt{3}\times\sqrt{3}\). Simplify when a root is in the denominator.

Step 2

Why this answer is correct

The correct answer is A. \(\sqrt{3}\). \(\frac{3}{\sqrt{3}}=\sqrt{3}\) because \(3=\sqrt{3}\times\sqrt{3}\). Simplify when a root is in the denominator.

Step 3

Exam Tip

\(\frac{3}{\sqrt{3}}=\sqrt{3}\) क्योंकि \(3=\sqrt{3}\times\sqrt{3}\)। हर में जड़ हो तो सरल करें।

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कौन सा विकल्प (\sqrt{3}\(4+\sqrt{3}\)) का मान है?

Which option is the value of (\sqrt{3}\(4+\sqrt{3}\))?

Explanation opens after your attempt
Correct Answer

A. \(3+4\sqrt{3}\)

Step 1

Concept

Distributing gives \(4\sqrt{3}+3\). Keep rational and irrational terms separate.

Step 2

Why this answer is correct

The correct answer is A. \(3+4\sqrt{3}\). Distributing gives \(4\sqrt{3}+3\). Keep rational and irrational terms separate.

Step 3

Exam Tip

वितरण करने पर \(4\sqrt{3}+3\) मिलता है। परिमेय और अपरिमेय पद अलग रखें।

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कौन सा विकल्प \(2\sqrt{5}\times3\sqrt{5}\) का मान है?

Which option is the value of \(2\sqrt{5}\times3\sqrt{5}\)?

Explanation opens after your attempt
Correct Answer

A. (30)

Step 1

Concept

\(2\sqrt{5}\times3\sqrt{5}=6\times5=30\). Multiplying same roots can give a rational result.

Step 2

Why this answer is correct

The correct answer is A. (30). \(2\sqrt{5}\times3\sqrt{5}=6\times5=30\). Multiplying same roots can give a rational result.

Step 3

Exam Tip

\(2\sqrt{5}\times3\sqrt{5}=6\times5=30\) है। समान जड़ का गुणन परिमेय परिणाम दे सकता है।

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कौन सा विकल्प \(5\sqrt{2}+3\sqrt{2}-\sqrt{2}\) का सरल रूप है?

Which option is the simplified form of \(5\sqrt{2}+3\sqrt{2}-\sqrt{2}\)?

Explanation opens after your attempt
Correct Answer

A. \(7\sqrt{2}\)

Step 1

Concept

The coefficients of like radical terms add as (5+3-1=7). So the answer is \(7\sqrt{2}\).

Step 2

Why this answer is correct

The correct answer is A. \(7\sqrt{2}\). The coefficients of like radical terms add as (5+3-1=7). So the answer is \(7\sqrt{2}\).

Step 3

Exam Tip

समान जड़ वाले पदों के गुणांक (5+3-1=7) जुड़ते हैं। इसलिए उत्तर \(7\sqrt{2}\) है।

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कौन सा विकल्प \(\sqrt{50}+\sqrt{72}-\sqrt{32}\) का सरल रूप है?

Which option is the simplified form of \(\sqrt{50}+\sqrt{72}-\sqrt{32}\)?

Explanation opens after your attempt
Correct Answer

A. \(7\sqrt{2}\)

Step 1

Concept

\(\sqrt{50}=5\sqrt{2}\), \(\sqrt{72}=6\sqrt{2}\), and \(\sqrt{32}=4\sqrt{2}\). The result is \(7\sqrt{2}\).

Step 2

Why this answer is correct

The correct answer is A. \(7\sqrt{2}\). \(\sqrt{50}=5\sqrt{2}\), \(\sqrt{72}=6\sqrt{2}\), and \(\sqrt{32}=4\sqrt{2}\). The result is \(7\sqrt{2}\).

Step 3

Exam Tip

\(\sqrt{50}=5\sqrt{2}\), \(\sqrt{72}=6\sqrt{2}\) और \(\sqrt{32}=4\sqrt{2}\) है। परिणाम \(7\sqrt{2}\) है।

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कौन सा विकल्प \(\sqrt{200}\) का सही सरल रूप है?

Which option is the correct simplified form of \(\sqrt{200}\)?

Explanation opens after your attempt
Correct Answer

A. \(10\sqrt{2}\)

Step 1

Concept

\(\sqrt{200}=\sqrt{100\times2}=10\sqrt{2}\). In simplest form no perfect square should remain inside the root.

Step 2

Why this answer is correct

The correct answer is A. \(10\sqrt{2}\). \(\sqrt{200}=\sqrt{100\times2}=10\sqrt{2}\). In simplest form no perfect square should remain inside the root.

Step 3

Exam Tip

\(\sqrt{200}=\sqrt{100\times2}=10\sqrt{2}\) है। सरल रूप में जड़ के अंदर पूर्ण वर्ग नहीं रहना चाहिए।

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कौन सा विकल्प \(0.\overline{123}\) की प्रकृति सही बताता है?

Which option correctly describes the nature of \(0.\overline{123}\)?

Explanation opens after your attempt
Correct Answer

A. परिमेय संख्याRational number

Step 1

Concept

The bar shows repetition of (123). A repeating decimal is rational.

Step 2

Why this answer is correct

The correct answer is A. परिमेय संख्या / Rational number. The bar shows repetition of (123). A repeating decimal is rational.

Step 3

Exam Tip

ऊपर की रेखा (123) के आवर्तन को बताती है। आवर्ती दशमलव परिमेय होता है।

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कौन सा विकल्प (3.010010001...) के बारे में सही है?

Which option is correct about (3.010010001...)?

Explanation opens after your attempt
Correct Answer

A. यह अपरिमेय संख्या हैIt is an irrational number

Step 1

Concept

The decimal is infinite and has no fixed repeating block. So it is irrational.

Step 2

Why this answer is correct

The correct answer is A. यह अपरिमेय संख्या है / It is an irrational number. The decimal is infinite and has no fixed repeating block. So it is irrational.

Step 3

Exam Tip

दशमलव अनंत है और कोई निश्चित आवर्ती समूह नहीं है। इसलिए यह अपरिमेय है।

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यदि (m) धनात्मक पूर्णांक है और \(\sqrt{m}\) परिमेय है तो (m) क्या होना चाहिए?

If (m) is a positive integer and \(\sqrt{m}\) is rational, what must (m) be?

Explanation opens after your attempt
Correct Answer

A. पूर्ण वर्गPerfect square

Step 1

Concept

The square root of a positive integer is rational only when it is a perfect square. Apply this rule directly.

Step 2

Why this answer is correct

The correct answer is A. पूर्ण वर्ग / Perfect square. The square root of a positive integer is rational only when it is a perfect square. Apply this rule directly.

Step 3

Exam Tip

धनात्मक पूर्णांक की वर्गमूल परिमेय तभी होती है जब वह पूर्ण वर्ग हो। इस नियम को सीधे लागू करें।

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यदि \(\sqrt{k}\) अपरिमेय है और (k) धनात्मक पूर्णांक है तो (k) के बारे में सही कथन क्या है?

If \(\sqrt{k}\) is irrational and (k) is a positive integer, what is correct about (k)?

Explanation opens after your attempt
Correct Answer

A. (k) पूर्ण वर्ग नहीं है(k) is not a perfect square

Step 1

Concept

If a positive integer is not a perfect square its square root is irrational. So (k) is not a perfect square.

Step 2

Why this answer is correct

The correct answer is A. (k) पूर्ण वर्ग नहीं है / (k) is not a perfect square. If a positive integer is not a perfect square its square root is irrational. So (k) is not a perfect square.

Step 3

Exam Tip

धनात्मक पूर्णांक पूर्ण वर्ग न हो तो उसकी वर्गमूल अपरिमेय होती है। इसलिए (k) पूर्ण वर्ग नहीं होगा।

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कौन सा विकल्प \(\sqrt{289}\) और \(\sqrt{290}\) की प्रकृति सही बताता है?

Which option gives the correct nature of \(\sqrt{289}\) and \(\sqrt{290}\)?

Explanation opens after your attempt
Correct Answer

A. \(\sqrt{289}\) परिमेय है और \(\sqrt{290}\) अपरिमेय है\(\sqrt{289}\) is rational and \(\sqrt{290}\) is irrational

Step 1

Concept

\(\sqrt{289}=17\), but (290) is not a perfect square. So the first root is rational and the second is irrational.

Step 2

Why this answer is correct

The correct answer is A. \(\sqrt{289}\) परिमेय है और \(\sqrt{290}\) अपरिमेय है / \(\sqrt{289}\) is rational and \(\sqrt{290}\) is irrational. \(\sqrt{289}=17\), but (290) is not a perfect square. So the first root is rational and the second is irrational.

Step 3

Exam Tip

\(\sqrt{289}=17\) है लेकिन (290) पूर्ण वर्ग नहीं है। इसलिए पहली जड़ परिमेय और दूसरी अपरिमेय है।

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कौन सा विकल्प \(\sqrt[3]{125}\) की प्रकृति सही बताता है?

Which option correctly describes the nature of \(\sqrt[3]{125}\)?

Explanation opens after your attempt
Correct Answer

A. परिमेय संख्याRational number

Step 1

Concept

\(\sqrt[3]{125}=5\), which is rational. The cube root of a perfect cube is rational.

Step 2

Why this answer is correct

The correct answer is A. परिमेय संख्या / Rational number. \(\sqrt[3]{125}=5\), which is rational. The cube root of a perfect cube is rational.

Step 3

Exam Tip

\(\sqrt[3]{125}=5\) है जो परिमेय है। पूर्ण घन की घनमूल परिमेय होती है।

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कौन सा विकल्प \(\sqrt[3]{12}\) के लिए सही है?

Which option is correct for \(\sqrt[3]{12}\)?

Explanation opens after your attempt
Correct Answer

A. यह अपरिमेय हैIt is irrational

Step 1

Concept

(12) is not a perfect cube so \(\sqrt[3]{12}\) is irrational. Check perfect cubes in cube roots.

Step 2

Why this answer is correct

The correct answer is A. यह अपरिमेय है / It is irrational. (12) is not a perfect cube so \(\sqrt[3]{12}\) is irrational. Check perfect cubes in cube roots.

Step 3

Exam Tip

(12) पूर्ण घन नहीं है इसलिए \(\sqrt[3]{12}\) अपरिमेय है। घनमूल में पूर्ण घन देखें।

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कौन सा विकल्प \(2+\sqrt{m}\) को अपरिमेय बनाता है?

Which option makes \(2+\sqrt{m}\) irrational?

Explanation opens after your attempt
Correct Answer

A. (m=45)

Step 1

Concept

(45) is not a perfect square so \(\sqrt{45}\) is irrational. Adding rational (2) keeps it irrational.

Step 2

Why this answer is correct

The correct answer is A. (m=45). (45) is not a perfect square so \(\sqrt{45}\) is irrational. Adding rational (2) keeps it irrational.

Step 3

Exam Tip

(45) पूर्ण वर्ग नहीं है इसलिए \(\sqrt{45}\) अपरिमेय है। परिमेय (2) जोड़ने पर परिणाम अपरिमेय रहता है।

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कौन सा विकल्प \(9-\sqrt{m}\) को परिमेय बनाता है?

Which option makes \(9-\sqrt{m}\) rational?

Explanation opens after your attempt
Correct Answer

A. (m=100)

Step 1

Concept

\(\sqrt{100}=10\) is rational so \(9-\sqrt{100}\) will be rational. The root of a perfect square is rational.

Step 2

Why this answer is correct

The correct answer is A. (m=100). \(\sqrt{100}=10\) is rational so \(9-\sqrt{100}\) will be rational. The root of a perfect square is rational.

Step 3

Exam Tip

\(\sqrt{100}=10\) परिमेय है इसलिए \(9-\sqrt{100}\) परिमेय होगा। पूर्ण वर्ग वाली जड़ परिमेय होती है।

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कौन सा विकल्प \(1+\sqrt{7}\) और \(1-\sqrt{7}\) के गुणनफल का मान है?

Which option is the value of the product of \(1+\sqrt{7}\) and \(1-\sqrt{7}\)?

Explanation opens after your attempt
Correct Answer

A. (-6)

Step 1

Concept

(\(1+\sqrt{7}\)\(1-\sqrt{7}\)=1-7=-6). In conjugate multiplication the irrational part cancels.

Step 2

Why this answer is correct

The correct answer is A. (-6). (\(1+\sqrt{7}\)\(1-\sqrt{7}\)=1-7=-6). In conjugate multiplication the irrational part cancels.

Step 3

Exam Tip

(\(1+\sqrt{7}\)\(1-\sqrt{7}\)=1-7=-6) है। संयुग्मी गुणन में अपरिमेय भाग हट जाता है।

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कौन सा विकल्प \(\sqrt{48}+\sqrt{108}-\sqrt{12}\) का सरल रूप है?

Which option is the simplified form of \(\sqrt{48}+\sqrt{108}-\sqrt{12}\)?

Explanation opens after your attempt
Correct Answer

A. \(8\sqrt{3}\)

Step 1

Concept

\(\sqrt{48}=4\sqrt{3}\), \(\sqrt{108}=6\sqrt{3}\), and \(\sqrt{12}=2\sqrt{3}\). The result is \(8\sqrt{3}\).

Step 2

Why this answer is correct

The correct answer is A. \(8\sqrt{3}\). \(\sqrt{48}=4\sqrt{3}\), \(\sqrt{108}=6\sqrt{3}\), and \(\sqrt{12}=2\sqrt{3}\). The result is \(8\sqrt{3}\).

Step 3

Exam Tip

\(\sqrt{48}=4\sqrt{3}\), \(\sqrt{108}=6\sqrt{3}\) और \(\sqrt{12}=2\sqrt{3}\) है। परिणाम \(8\sqrt{3}\) है।

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कौन सा विकल्प \(2+\sqrt{3}\) और \(2-\sqrt{3}\) के योग और गुणनफल को सही बताता है?

Which option correctly gives the sum and product of \(2+\sqrt{3}\) and \(2-\sqrt{3}\)?

Explanation opens after your attempt
Correct Answer

A. योग (4), गुणनफल (1)Sum (4), product (1)

Step 1

Concept

The radical terms cancel in the sum and the product is (4-3=1). This method is quick for conjugates.

Step 2

Why this answer is correct

The correct answer is A. योग (4), गुणनफल (1) / Sum (4), product (1). The radical terms cancel in the sum and the product is (4-3=1). This method is quick for conjugates.

Step 3

Exam Tip

योग में जड़ वाले पद कटते हैं और गुणनफल (4-3=1) है। संयुग्मी संख्याओं में यह तरीका तेज है।

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कौन सा विकल्प (\(\sqrt{5}-\sqrt{2}\)2) का सही विस्तार है?

Which option is the correct expansion of (\(\sqrt{5}-\sqrt{2}\)2)?

Explanation opens after your attempt
Correct Answer

A. \(7-2\sqrt{10}\)

Step 1

Concept

(\(\sqrt{5}-\sqrt{2}\)2=5+2-2\sqrt{10}). Apply the (2ab) term carefully in the square formula.

Step 2

Why this answer is correct

The correct answer is A. \(7-2\sqrt{10}\). (\(\sqrt{5}-\sqrt{2}\)2=5+2-2\sqrt{10}). Apply the (2ab) term carefully in the square formula.

Step 3

Exam Tip

(\(\sqrt{5}-\sqrt{2}\)2=5+2-2\sqrt{10}) है। वर्ग सूत्र में (2ab) पद ध्यान से लगाएँ।

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यदि कोई दशमलव सांत या आवर्ती है तो वह किस प्रकार की संख्या है?

If a decimal is terminating or repeating, what type of number is it?

Explanation opens after your attempt
Correct Answer

A. परिमेय संख्याRational number

Step 1

Concept

The decimal expansion of a rational number is terminating or repeating. This identification is very important.

Step 2

Why this answer is correct

The correct answer is A. परिमेय संख्या / Rational number. The decimal expansion of a rational number is terminating or repeating. This identification is very important.

Step 3

Exam Tip

परिमेय संख्या का दशमलव प्रसार सांत या आवर्ती होता है। यह पहचान बहुत महत्वपूर्ण है।

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यदि कोई दशमलव अनंत और अनावर्ती है तो वह किस प्रकार की संख्या है?

If a decimal is non terminating and non repeating, what type of number is it?

Explanation opens after your attempt
Correct Answer

A. अपरिमेय संख्याIrrational number

Step 1

Concept

A non terminating and non repeating decimal identifies an irrational number. Check carefully if no repeating block appears.

Step 2

Why this answer is correct

The correct answer is A. अपरिमेय संख्या / Irrational number. A non terminating and non repeating decimal identifies an irrational number. Check carefully if no repeating block appears.

Step 3

Exam Tip

अनंत और अनावर्ती दशमलव अपरिमेय संख्या की पहचान है। आवर्ती भाग न दिखे तो सावधानी से जाँचें।

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कौन सा विकल्प \(-\sqrt{47}\) की प्रकृति सही बताता है?

Which option correctly describes the nature of \(-\sqrt{47}\)?

Explanation opens after your attempt
Correct Answer

A. अपरिमेय वास्तविक संख्याIrrational real number

Step 1

Concept

\(\sqrt{47}\) is irrational because (47) is not a perfect square. Its negative is also a real irrational number.

Step 2

Why this answer is correct

The correct answer is A. अपरिमेय वास्तविक संख्या / Irrational real number. \(\sqrt{47}\) is irrational because (47) is not a perfect square. Its negative is also a real irrational number.

Step 3

Exam Tip

\(\sqrt{47}\) अपरिमेय है क्योंकि (47) पूर्ण वर्ग नहीं है। उसका ऋण भी वास्तविक अपरिमेय है।

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कौन सा विकल्प \(\frac{1}{3}+\sqrt{11}\) की प्रकृति सही बताता है?

Which option correctly describes the nature of \(\frac{1}{3}+\sqrt{11}\)?

Explanation opens after your attempt
Correct Answer

A. अपरिमेय संख्याIrrational number

Step 1

Concept

\(\frac{1}{3}\) is rational and \(\sqrt{11}\) is irrational. Their sum is irrational.

Step 2

Why this answer is correct

The correct answer is A. अपरिमेय संख्या / Irrational number. \(\frac{1}{3}\) is rational and \(\sqrt{11}\) is irrational. Their sum is irrational.

Step 3

Exam Tip

\(\frac{1}{3}\) परिमेय है और \(\sqrt{11}\) अपरिमेय है। उनका योग अपरिमेय होता है।

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कौन सा विकल्प \(4\sqrt{7}-\sqrt{112}\) का मान है?

Which option is the value of \(4\sqrt{7}-\sqrt{112}\)?

Explanation opens after your attempt
Correct Answer

A. (0)

Step 1

Concept

\(\sqrt{112}=\sqrt{16\times7}=4\sqrt{7}\). Therefore \(4\sqrt{7}-4\sqrt{7}=0\).

Step 2

Why this answer is correct

The correct answer is A. (0). \(\sqrt{112}=\sqrt{16\times7}=4\sqrt{7}\). Therefore \(4\sqrt{7}-4\sqrt{7}=0\).

Step 3

Exam Tip

\(\sqrt{112}=\sqrt{16\times7}=4\sqrt{7}\) है। इसलिए \(4\sqrt{7}-4\sqrt{7}=0\) है।

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कौन सा विकल्प \(\sqrt{245}\) का सरल रूप है?

Which option is the simplified form of \(\sqrt{245}\)?

Explanation opens after your attempt
Correct Answer

A. \(7\sqrt{5}\)

Step 1

Concept

\(\sqrt{245}=\sqrt{49\times5}=7\sqrt{5}\). Identify the perfect square factor inside the root.

Step 2

Why this answer is correct

The correct answer is A. \(7\sqrt{5}\). \(\sqrt{245}=\sqrt{49\times5}=7\sqrt{5}\). Identify the perfect square factor inside the root.

Step 3

Exam Tip

\(\sqrt{245}=\sqrt{49\times5}=7\sqrt{5}\) है। जड़ में पूर्ण वर्ग गुणनखंड पहचानें।

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कौन सा विकल्प (\(4+\sqrt{7}\)\(4-\sqrt{7}\)) का मान है?

Which option is the value of (\(4+\sqrt{7}\)\(4-\sqrt{7}\))?

Explanation opens after your attempt
Correct Answer

A. (9)

Step 1

Concept

Conjugate multiplication gives (42-\(\sqrt{7}\)2=16-7=9). Use the difference of squares formula in such questions.

Step 2

Why this answer is correct

The correct answer is A. (9). Conjugate multiplication gives (42-\(\sqrt{7}\)2=16-7=9). Use the difference of squares formula in such questions.

Step 3

Exam Tip

संयुग्मी गुणन से (42-\(\sqrt{7}\)2=16-7=9) मिलता है। ऐसे प्रश्नों में अंतर वर्ग सूत्र लगाएँ।

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कौन सा विकल्प \(\sqrt{72}+\sqrt{128}-\sqrt{50}\) का सरल रूप है?

Which option is the simplified form of \(\sqrt{72}+\sqrt{128}-\sqrt{50}\)?

Explanation opens after your attempt
Correct Answer

A. \(9\sqrt{2}\)

Step 1

Concept

\(\sqrt{72}=6\sqrt{2}\), \(\sqrt{128}=8\sqrt{2}\), and \(\sqrt{50}=5\sqrt{2}\). The result is \(9\sqrt{2}\).

Step 2

Why this answer is correct

The correct answer is A. \(9\sqrt{2}\). \(\sqrt{72}=6\sqrt{2}\), \(\sqrt{128}=8\sqrt{2}\), and \(\sqrt{50}=5\sqrt{2}\). The result is \(9\sqrt{2}\).

Step 3

Exam Tip

\(\sqrt{72}=6\sqrt{2}\), \(\sqrt{128}=8\sqrt{2}\) और \(\sqrt{50}=5\sqrt{2}\) है। परिणाम \(9\sqrt{2}\) है।

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कौन सा विकल्प (8) और (9) के बीच की अपरिमेय संख्या है?

Which option is an irrational number between (8) and (9)?

Explanation opens after your attempt
Correct Answer

A. \(\sqrt{70}\)

Step 1

Concept

Since (64<70<81), \(\sqrt{70}\) lies between (8) and (9). (70) is not a perfect square so it is irrational.

Step 2

Why this answer is correct

The correct answer is A. \(\sqrt{70}\). Since (64<70<81), \(\sqrt{70}\) lies between (8) and (9). (70) is not a perfect square so it is irrational.

Step 3

Exam Tip

क्योंकि (64<70<81) इसलिए \(\sqrt{70}\) (8) और (9) के बीच है। (70) पूर्ण वर्ग नहीं है इसलिए यह अपरिमेय है।

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यदि \(x=2+\sqrt{10}\) और \(y=2-\sqrt{10}\) हैं तो (x-y) का सरल रूप क्या है?

If \(x=2+\sqrt{10}\) and \(y=2-\sqrt{10}\), what is the simplified form of (x-y)?

Explanation opens after your attempt
Correct Answer

A. \(2\sqrt{10}\)

Step 1

Concept

On subtracting, the (2) terms cancel and (\sqrt{10}-\(-\sqrt{10}\)=2\sqrt{10}). Watch the signs carefully.

Step 2

Why this answer is correct

The correct answer is A. \(2\sqrt{10}\). On subtracting, the (2) terms cancel and (\sqrt{10}-\(-\sqrt{10}\)=2\sqrt{10}). Watch the signs carefully.

Step 3

Exam Tip

घटाने पर (2) पद कटते हैं और (\sqrt{10}-\(-\sqrt{10}\)=2\sqrt{10}) मिलता है। चिह्नों का ध्यान रखें।

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कौन सा विकल्प (\(\sqrt{13}-\sqrt{3}\)\(\sqrt{13}+\sqrt{3}\)) का मान है?

Which option is the value of (\(\sqrt{13}-\sqrt{3}\)\(\sqrt{13}+\sqrt{3}\))?

Explanation opens after your attempt
Correct Answer

A. (10)

Step 1

Concept

This is ((a-b)(a+b)=a-2-b-2). The value is (13-3=10).

Step 2

Why this answer is correct

The correct answer is A. (10). This is ((a-b)(a+b)=a-2-b-2). The value is (13-3=10).

Step 3

Exam Tip

यह ((a-b)(a+b)=a-2-b-2) है। मान (13-3=10) होगा।

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कौन सा विकल्प (\(\sqrt{6}+\sqrt{2}\)2) का सही विस्तार है?

Which option is the correct expansion of (\(\sqrt{6}+\sqrt{2}\)2)?

Explanation opens after your attempt
Correct Answer

A. \(8+4\sqrt{3}\)

Step 1

Concept

(\(\sqrt{6}+\sqrt{2}\)2=6+2+2\sqrt{12}=8+4\sqrt{3}). Apply the (2ab) term correctly.

Step 2

Why this answer is correct

The correct answer is A. \(8+4\sqrt{3}\). (\(\sqrt{6}+\sqrt{2}\)2=6+2+2\sqrt{12}=8+4\sqrt{3}). Apply the (2ab) term correctly.

Step 3

Exam Tip

(\(\sqrt{6}+\sqrt{2}\)2=6+2+2\sqrt{12}=8+4\sqrt{3}) है। वर्ग सूत्र में (2ab) पद सही लगाएँ।

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कौन सा विकल्प \(\sqrt[3]{216}\) की प्रकृति सही बताता है?

Which option correctly describes the nature of \(\sqrt[3]{216}\)?

Explanation opens after your attempt
Correct Answer

A. परिमेय संख्याRational number

Step 1

Concept

\(\sqrt[3]{216}=6\), which is rational. The cube root of a perfect cube is rational.

Step 2

Why this answer is correct

The correct answer is A. परिमेय संख्या / Rational number. \(\sqrt[3]{216}=6\), which is rational. The cube root of a perfect cube is rational.

Step 3

Exam Tip

\(\sqrt[3]{216}=6\) है जो परिमेय है। पूर्ण घन की घनमूल परिमेय होती है।

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कौन सा विकल्प \(5+\sqrt{m}\) को परिमेय बनाता है?

Which option makes \(5+\sqrt{m}\) rational?

Explanation opens after your attempt
Correct Answer

A. (m=121)

Step 1

Concept

\(\sqrt{121}=11\) is rational so \(5+\sqrt{121}\) will be rational. The root of a perfect square is rational.

Step 2

Why this answer is correct

The correct answer is A. (m=121). \(\sqrt{121}=11\) is rational so \(5+\sqrt{121}\) will be rational. The root of a perfect square is rational.

Step 3

Exam Tip

\(\sqrt{121}=11\) परिमेय है इसलिए \(5+\sqrt{121}\) परिमेय होगा। पूर्ण वर्ग वाली जड़ परिमेय होती है।

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Class 10 Mathematics Quiz FAQs

How many questions are in this quiz?

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