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Which option is the value of \((\sqrt{13}-\sqrt{3})(\sqrt{13}+\sqrt{3})\)?

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Answer and explanation

Correct answer: 10

Use the identity \((a-b)(a+b)=a^2-b^2\). With \(a=\sqrt{13}\) and \(b=\sqrt{3}\) we get \(13-3=10\), so the value is 10. Option C (\(\sqrt{39}\)) confuses the product of the individual square roots with the whole conjugate product; \(\sqrt{13}\cdot\sqrt{3}=\sqrt{39}\) is not equal to \((\sqrt{13}-\sqrt{3})(\sqrt{13}+\sqrt{3})\). Exam tip: spot the conjugate pair and apply the difference-of-squares formula to simplify quickly.

Related tags

PolynomialsConjugateDifference-Of-SquaresRadicals

Frequently asked questions

What is the correct answer to this question?

10

Why is this the correct answer?

Use the identity \((a-b)(a+b)=a^2-b^2\). With \(a=\sqrt{13}\) and \(b=\sqrt{3}\) we get \(13-3=10\), so the value is 10. Option C (\(\sqrt{39}\)) confuses the product of the individual square roots with the whole conjugate product; \(\sqrt{13}\cdot\sqrt{3}=\sqrt{39}\) is not equal to \((\sqrt{13}-\sqrt{3})(\sqrt{13}+\sqrt{3})\). Exam tip: spot the conjugate pair and apply the difference-of-squares formula to simplify quickly.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Irrational numbers and real numbers.

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