यदि ( (x+y)2 =81 ) और (xy=14) है तो \(x^2+y^2\) का मान क्या होगा?
If ( (x+y)2 =81 ) and (xy=14), what is the value of \(x^2+y^2\)?
#sum square
#expert identity
#value based
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A (53)
B (67)
C (95)
D (109)
Explanation opens after your attempt
Step 1
Concept
(x-2 +y-2 =(x+y)2 -2xy=81-28=53). Exam tip: subtract (2xy) from the square of the sum.
Step 2
Why this answer is correct
The correct answer is A. (53). (x-2 +y-2 =(x+y)2 -2xy=81-28=53). Exam tip: subtract (2xy) from the square of the sum.
Step 3
Exam Tip
(x-2 +y-2 =(x+y)2 -2xy=81-28=53) है। परीक्षा में वर्ग योग से (2xy) घटाएँ।
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यदि (a-b=7) और (ab=18) है तो \(a^2+b^2\) कितना होगा?
If (a-b=7) and (ab=18), what is \(a^2+b^2\)?
#difference square
#given values
#algebraic identities
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A (49)
B (85)
C (67)
D (31)
Explanation opens after your attempt
Step 1
Concept
(a-2 +b-2 =(a-b)2 +2ab=49+36=85). Exam tip: add (2ab) to the square of the difference.
Step 2
Why this answer is correct
The correct answer is B. (85). (a-2 +b-2 =(a-b)2 +2ab=49+36=85). Exam tip: add (2ab) to the square of the difference.
Step 3
Exam Tip
(a-2 +b-2 =(a-b)2 +2ab=49+36=85) होता है। परीक्षा में अंतर के वर्ग में (2ab) जोड़ें।
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यदि (p+q=12) और (p-q=4) है तो \(p^2-q^2\) का मान क्या है?
If (p+q=12) and (p-q=4), what is the value of \(p^2-q^2\)?
#difference of squares
#given sum difference
#expert
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A (16)
B (36)
C (48)
D (64)
Explanation opens after your attempt
Step 1
Concept
(p-2 -q-2 =(p+q)(p-q)=12\times4=48). Exam tip: directly apply the difference of squares identity.
Step 2
Why this answer is correct
The correct answer is C. (48). (p-2 -q-2 =(p+q)(p-q)=12\times4=48). Exam tip: directly apply the difference of squares identity.
Step 3
Exam Tip
(p-2 -q-2 =(p+q)(p-q)=12\times4=48) है। परीक्षा में अंतर वर्ग पहचान सीधे लगाएँ।
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( (5a-2b)2 -\(25a^2+4b^2\) ) को सरल कीजिए।
Simplify ( (5a-2b)2 -\(25a^2+4b^2\) ).
#minus square
#simplification
#middle term
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A (20ab)
B (-20ab)
C (10ab)
D (-10ab)
Explanation opens after your attempt
Correct Answer
B. (-20ab)
Step 1
Concept
The expansion is \(25a^2-20ab+4b^2\), so like terms cancel and (-20ab) remains. Exam tip: watch the negative middle term.
Step 2
Why this answer is correct
The correct answer is B. (-20ab). The expansion is \(25a^2-20ab+4b^2\), so like terms cancel and (-20ab) remains. Exam tip: watch the negative middle term.
Step 3
Exam Tip
विस्तार \(25a^2-20ab+4b^2\) है इसलिए समान पद घटकर (-20ab) बचता है। परीक्षा में ऋणात्मक मध्य पद पर ध्यान दें।
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यदि ( (x+k)2 =x-2 +24x+144 ) है तो (k) का मान क्या होगा?
If ( (x+k)2 =x-2 +24x+144 ), what is the value of (k)?
#unknown coefficient
#perfect square
#identity
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A (6)
B (10)
C (12)
D (24)
Explanation opens after your attempt
Step 1
Concept
\(144=12^2\) and (2k=24), so (k=12). Exam tip: verify using both the last term and the middle term.
Step 2
Why this answer is correct
The correct answer is C. (12). \(144=12^2\) and (2k=24), so (k=12). Exam tip: verify using both the last term and the middle term.
Step 3
Exam Tip
\(144=12^2\) और (2k=24) इसलिए (k=12) है। परीक्षा में अंतिम पद और मध्य पद दोनों से जाँच करें।
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यदि ( (x-k)2 =x-2 -30x+225 ) है तो (k) कितना है?
If ( (x-k)2 =x-2 -30x+225 ), what is (k)?
#unknown value
#minus square
#perfect square
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A (15)
B (30)
C (225)
D (10)
Explanation opens after your attempt
Step 1
Concept
\(225=15^2\) and (-2kx=-30x) gives (k=15). Exam tip: the middle term of ((x-k)2 ) is (-2kx).
Step 2
Why this answer is correct
The correct answer is A. (15). \(225=15^2\) and (-2kx=-30x) gives (k=15). Exam tip: the middle term of ((x-k)2 ) is (-2kx).
Step 3
Exam Tip
\(225=15^2\) और (-2kx=-30x) से (k=15) मिलता है। परीक्षा में ((x-k)2 ) का मध्य पद (-2kx) होता है।
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( (3x+4)(3x-4)-\(9x^2-20\) ) का मान क्या है?
What is the value of ( (3x+4)(3x-4)-\(9x^2-20\) )?
#difference of squares
#combined simplification
#expert
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A (4)
B (20)
C (36)
D (-4)
Explanation opens after your attempt
Step 1
Concept
The first product is \(9x^2-16\), then \(9x^2-20\) is subtracted. Exam tip: apply the minus sign to the whole bracket.
Step 2
Why this answer is correct
The correct answer is A. (4). The first product is \(9x^2-16\), then \(9x^2-20\) is subtracted. Exam tip: apply the minus sign to the whole bracket.
Step 3
Exam Tip
पहला गुणनफल \(9x^2-16\) है और फिर \(9x^2-20\) घटता है। परीक्षा में पूरे कोष्ठक पर ऋण लगाएँ।
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( (x+2y+3z)2 ) में (yz) वाला पद कौन सा होगा?
Which term containing (yz) appears in ( (x+2y+3z)2 )?
#three term square
#mixed term
#yz
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A (6yz)
B (12yz)
C (5yz)
D (2yz)
Explanation opens after your attempt
Step 1
Concept
\(2\times2y\times3z=12yz\). Exam tip: in the square of three terms, take twice the product of every pair.
Step 2
Why this answer is correct
The correct answer is B. (12yz). \(2\times2y\times3z=12yz\). Exam tip: in the square of three terms, take twice the product of every pair.
Step 3
Exam Tip
\(2\times2y\times3z=12yz\) होता है। परीक्षा में तीन पदों के वर्ग में हर जोड़े का दुगुना गुणन लें।
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( (2a-b+4c)2 ) में (ab) वाला पद क्या है?
What is the term containing (ab) in ( (2a-b+4c)2 )?
#three term square
#negative mixed term
#coefficients
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A (2ab)
B (-2ab)
C (-4ab)
D (4ab)
Explanation opens after your attempt
Step 1
Concept
\(2\times2a\times(-b)=-4ab\). Exam tip: keep the negative sign with the term.
Step 2
Why this answer is correct
The correct answer is C. (-4ab). \(2\times2a\times(-b)=-4ab\). Exam tip: keep the negative sign with the term.
Step 3
Exam Tip
\(2\times2a\times(-b)=-4ab\) है। परीक्षा में ऋण चिन्ह को पद के साथ रखें।
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( (x+y)2 -(x-y)2 ) का मान (72) है तो (xy) का मान क्या है?
If ( (x+y)2 -(x-y)2 =72 ), what is the value of (xy)?
#identity equation
#xy value
#algebra
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A (12)
B (18)
C (24)
D (36)
Explanation opens after your attempt
Step 1
Concept
By identity, the difference is (4xy), so (4xy=72). Exam tip: use the identity first to shorten the equation.
Step 2
Why this answer is correct
The correct answer is B. (18). By identity, the difference is (4xy), so (4xy=72). Exam tip: use the identity first to shorten the equation.
Step 3
Exam Tip
पहचान से अंतर (4xy) होता है इसलिए (4xy=72)। परीक्षा में पहले पहचान लगाकर समीकरण छोटा करें।
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यदि ( (m+n)2 +(m-n)2 =100 ) है तो \(m^2+n^2\) कितना होगा?
If ( (m+n)2 +(m-n)2 =100 ), what is \(m^2+n^2\)?
#sum identity
#given value
#expert algebra
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A (25)
B (40)
C (50)
D (100)
Explanation opens after your attempt
Step 1
Concept
The sum is (2m-2 +2n-2 =2\(m^2+n^2\)). Exam tip: take half of the sum of the two squares.
Step 2
Why this answer is correct
The correct answer is C. (50). The sum is (2m-2 +2n-2 =2\(m^2+n^2\)). Exam tip: take half of the sum of the two squares.
Step 3
Exam Tip
योग (2m-2 +2n-2 =2\(m^2+n^2\)) होता है। परीक्षा में दोनों वर्गों का योग आधा करें।
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\( 1005^2-995^2 \) का मान पहचान से क्या होगा?
What is the value of \( 1005^2-995^2 \) using an identity?
#numeric difference
#large numbers
#identity
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A (10000)
B (20000)
C (5000)
D (1000)
Explanation opens after your attempt
Correct Answer
B. (20000)
Step 1
Concept
(a-2 -b-2 =(a+b)(a-b)=2000\times10=20000). Exam tip: difference of squares is useful for large numbers.
Step 2
Why this answer is correct
The correct answer is B. (20000). (a-2 -b-2 =(a+b)(a-b)=2000\times10=20000). Exam tip: difference of squares is useful for large numbers.
Step 3
Exam Tip
(a-2 -b-2 =(a+b)(a-b)=2000\times10=20000) है। परीक्षा में बड़ी संख्याओं में अंतर वर्ग उपयोगी है।
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\( 123\times117 \) को पहचान से निकालने पर क्या मिलेगा?
What do we get for \( 123\times117 \) using an identity?
#numeric product
#difference of squares
#mental math
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A (14391)
B (14400)
C (14381)
D (14409)
Explanation opens after your attempt
Correct Answer
A. (14391)
Step 1
Concept
(123\times117=(120+3)(120-3)=1202 -32 =14391). Exam tip: identify the common centre (120).
Step 2
Why this answer is correct
The correct answer is A. (14391). (123\times117=(120+3)(120-3)=1202 -32 =14391). Exam tip: identify the common centre (120).
Step 3
Exam Tip
(123\times117=(120+3)(120-3)=1202 -32 =14391)। परीक्षा में समान केंद्र (120) पहचानें।
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\( 998^2 \) का मान ( (1000-2)2 ) से क्या होगा?
What is the value of \( 998^2 \) using ( (1000-2)2 )?
#large square
#minus identity
#numeric
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A (996004)
B (998004)
C (1000004)
D (996000)
Explanation opens after your attempt
Correct Answer
A. (996004)
Step 1
Concept
( (1000-2)2 =1000000-4000+4=996004 ). Exam tip: keep the subtracted middle term correct.
Step 2
Why this answer is correct
The correct answer is A. (996004). ( (1000-2)2 =1000000-4000+4=996004 ). Exam tip: keep the subtracted middle term correct.
Step 3
Exam Tip
( (1000-2)2 =1000000-4000+4=996004 ) है। परीक्षा में घटने वाले मध्य पद को सही रखें।
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( (4x+1)2 -(4x-1)2 ) का सरल रूप क्या है?
What is the simplified form of ( (4x+1)2 -(4x-1)2 )?
#difference identity
#quick simplification
#binomial
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A (8x)
B (16x)
C (32x)
D (64x)
Explanation opens after your attempt
Step 1
Concept
This is (4AB) where (A=4x) and (B=1). Exam tip: calculate \(4\times4x\times1=16x\).
Step 2
Why this answer is correct
The correct answer is B. (16x). This is (4AB) where (A=4x) and (B=1). Exam tip: calculate \(4\times4x\times1=16x\).
Step 3
Exam Tip
यह (4AB) है जहाँ (A=4x) और (B=1)। परीक्षा में \(4\times4x\times1=16x\) करें।
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( (x+3)(x+8)-(x+4)(x+7) ) का मान क्या है?
What is the value of ( (x+3)(x+8)-(x+4)(x+7) )?
#binomial product
#comparison
#simplification
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A (2)
B (-2)
C (x)
D (-x)
Explanation opens after your attempt
Step 1
Concept
The first is \(x^2+11x+24\) and the second is \(x^2+11x+28\). Exam tip: cancel like terms and check the constant difference.
Step 2
Why this answer is correct
The correct answer is B. (-2). The first is \(x^2+11x+24\) and the second is \(x^2+11x+28\). Exam tip: cancel like terms and check the constant difference.
Step 3
Exam Tip
पहला \(x^2+11x+24\) और दूसरा \(x^2+11x+28\) है। परीक्षा में समान पद घटाकर केवल स्थिर अंतर देखें।
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( (2x+5)(2x-3) ) में (x) का गुणांक क्या है?
What is the coefficient of (x) in ( (2x+5)(2x-3) )?
#coefficient
#binomial expansion
#like terms
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A (4)
B (10)
C (4x)
D (15)
Explanation opens after your attempt
Step 1
Concept
The middle terms are (-6x+10x=4x), so the coefficient is (4). Exam tip: add both middle products.
Step 2
Why this answer is correct
The correct answer is A. (4). The middle terms are (-6x+10x=4x), so the coefficient is (4). Exam tip: add both middle products.
Step 3
Exam Tip
मध्य पद (-6x+10x=4x) है इसलिए गुणांक (4) है। परीक्षा में दोनों मध्य गुणनों को जोड़ें।
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( (3x-2)(3x+6) ) का स्थिर पद क्या है?
What is the constant term in ( (3x-2)(3x+6) )?
#constant term
#signed multiplication
#binomial
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A (12)
B (-12)
C (18)
D (-18)
Explanation opens after your attempt
Step 1
Concept
The constant term is ((-2)\times6=-12). Exam tip: multiply only the constants for the constant term.
Step 2
Why this answer is correct
The correct answer is B. (-12). The constant term is ((-2)\times6=-12). Exam tip: multiply only the constants for the constant term.
Step 3
Exam Tip
स्थिर पद ((-2)\times6=-12) है। परीक्षा में स्थिर पद के लिए केवल स्थिर संख्याएँ गुणा करें।
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( (x-1)(x-2)(x-3) ) में \(x^2\) का गुणांक क्या है?
What is the coefficient of \(x^2\) in ( (x-1)(x-2)(x-3) )?
#coefficient
#cubic expansion
#expert
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A (6)
B (-6)
C (11)
D (-11)
Explanation opens after your attempt
Step 1
Concept
The sum of constants is (1+2+3=6) and the sign is negative. Exam tip: stepwise multiplication also gives the same result.
Step 2
Why this answer is correct
The correct answer is B. (-6). The sum of constants is (1+2+3=6) and the sign is negative. Exam tip: stepwise multiplication also gives the same result.
Step 3
Exam Tip
तीनों स्थिर पदों का योग (1+2+3=6) है और चिन्ह ऋणात्मक होता है। परीक्षा में क्रमिक गुणन से भी यही मिलेगा।
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( (a+b)3 -(a-b)3 ) का सरल रूप क्या है?
What is the simplified form of ( (a+b)3 -(a-b)3 )?
#cube identity
#advanced simplification
#expert
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A (2b\(3a^2+b^2\))
B (2a\(a^2+3b^2\))
C (6ab)
D \(a^3-b^3\)
Explanation opens after your attempt
Correct Answer
A. (2b\(3a^2+b^2\))
Step 1
Concept
On expansion, (6a-2 b+2b-3 =2b\(3a^2+b^2\)). Exam tip: handle signs carefully in cube expansions.
Step 2
Why this answer is correct
The correct answer is A. (2b\(3a^2+b^2\)). On expansion, (6a-2 b+2b-3 =2b\(3a^2+b^2\)). Exam tip: handle signs carefully in cube expansions.
Step 3
Exam Tip
विस्तार करने पर (6a-2 b+2b-3 =2b\(3a^2+b^2\)) मिलता है। परीक्षा में घन विस्तार में चिन्ह सावधानी से रखें।
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( (a+b)3 +(a-b)3 ) किसके बराबर है?
What is ( (a+b)3 +(a-b)3 ) equal to?
#cube identity
#sum of cubes
#binomial cube
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A (2a\(a^2+3b^2\))
B (2b\(3a^2+b^2\))
C \(6a^2b\)
D \(2a^3+2b^3\)
Explanation opens after your attempt
Correct Answer
A. (2a\(a^2+3b^2\))
Step 1
Concept
On adding, terms with odd powers of (b) cancel and \(2a^3+6ab^2\) remains. Exam tip: use symmetry.
Step 2
Why this answer is correct
The correct answer is A. (2a\(a^2+3b^2\)). On adding, terms with odd powers of (b) cancel and \(2a^3+6ab^2\) remains. Exam tip: use symmetry.
Step 3
Exam Tip
जोड़ने पर (b) की विषम शक्ति वाले पद कटते हैं और \(2a^3+6ab^2\) बचता है। परीक्षा में सममिति का लाभ लें।
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\( x^3+27 \) का गुणनखंड रूप क्या है?
What is the factor form of \( x^3+27 \)?
#sum of cubes
#factorization
#cube identity
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A ( (x+3)\(x^2-3x+9\) )
B ( (x-3)\(x^2+3x+9\) )
C ( (x+3)3 )
D ( (x+9)\(x^2-9x+9\) )
Explanation opens after your attempt
Correct Answer
A. ( (x+3)\(x^2-3x+9\) )
Step 1
Concept
This is the form (a-3 +b-3 =(a+b)\(a^2-ab+b^2\)). Exam tip: identify \(27=3^3\).
Step 2
Why this answer is correct
The correct answer is A. ( (x+3)\(x^2-3x+9\) ). This is the form (a-3 +b-3 =(a+b)\(a^2-ab+b^2\)). Exam tip: identify \(27=3^3\).
Step 3
Exam Tip
यह (a-3 +b-3 =(a+b)\(a^2-ab+b^2\)) का रूप है। परीक्षा में \(27=3^3\) पहचानें।
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\( 8x^3-125 \) का गुणनखंड रूप कौन सा है?
Which is the factor form of \( 8x^3-125 \)?
#difference of cubes
#factorization
#expert identity
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A ( (2x-5)\(4x^2+10x+25\) )
B ( (2x+5)\(4x^2-10x+25\) )
C ( (2x-5)3 )
D ( (8x-5)\(x^2+5x+25\) )
Explanation opens after your attempt
Correct Answer
A. ( (2x-5)\(4x^2+10x+25\) )
Step 1
Concept
(8x-3 =(2x)3 ) and \(125=5^3\). Exam tip: apply the \(a^3-b^3\) formula correctly.
Step 2
Why this answer is correct
The correct answer is A. ( (2x-5)\(4x^2+10x+25\) ). (8x-3 =(2x)3 ) and \(125=5^3\). Exam tip: apply the \(a^3-b^3\) formula correctly.
Step 3
Exam Tip
(8x-3 =(2x)3 ) और \(125=5^3\) है। परीक्षा में \(a^3-b^3\) का सूत्र सही लगाएँ।
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यदि (a+b+c=0) है तो \(a^3+b^3+c^3\) किसके बराबर होगा?
If (a+b+c=0), what is \(a^3+b^3+c^3\) equal to?
#three variable identity
#cube relation
#expert
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A (ab+bc+ca)
B (abc)
C (3abc)
D (0)
Explanation opens after your attempt
Step 1
Concept
By identity, (a-3 +b-3 +c-3 -3abc=(a+b+c)\(\cdots\)). Exam tip: if (a+b+c=0), remember \(a^3+b^3+c^3=3abc\).
Step 2
Why this answer is correct
The correct answer is C. (3abc). By identity, (a-3 +b-3 +c-3 -3abc=(a+b+c)\(\cdots\)). Exam tip: if (a+b+c=0), remember \(a^3+b^3+c^3=3abc\).
Step 3
Exam Tip
पहचान के अनुसार (a-3 +b-3 +c-3 -3abc=(a+b+c)\(\cdots\)) है। परीक्षा में (a+b+c=0) होने पर \(a^3+b^3+c^3=3abc\) याद रखें।
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\( x^3+y^3+z^3-3xyz \) में यदि (x+y+z=0) हो तो मान क्या होगा?
If (x+y+z=0), what is the value of \( x^3+y^3+z^3-3xyz \)?
#three variable identity
#zero condition
#cube
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A (xyz)
B (3xyz)
C \(x^2+y^2+z^2\)
D (0)
Explanation opens after your attempt
Step 1
Concept
In the identity, this expression is multiplied by (x+y+z), so the value is (0). Exam tip: check the condition first.
Step 2
Why this answer is correct
The correct answer is D. (0). In the identity, this expression is multiplied by (x+y+z), so the value is (0). Exam tip: check the condition first.
Step 3
Exam Tip
पहचान में यह पद (x+y+z) से गुणा होता है इसलिए मान (0) होगा। परीक्षा में शर्त को पहले जाँचें।
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यदि (x+y+z=6) और (xy+yz+zx=11) है तो \(x^2+y^2+z^2\) कितना है?
If (x+y+z=6) and (xy+yz+zx=11), what is \(x^2+y^2+z^2\)?
#three term square
#given values
#sum of squares
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A (14)
B (25)
C (36)
D (47)
Explanation opens after your attempt
Step 1
Concept
(x-2 +y-2 +z-2 =(x+y+z)2 -2(xy+yz+zx)=36-22=14). Exam tip: use the three-term identity.
Step 2
Why this answer is correct
The correct answer is A. (14). (x-2 +y-2 +z-2 =(x+y+z)2 -2(xy+yz+zx)=36-22=14). Exam tip: use the three-term identity.
Step 3
Exam Tip
(x-2 +y-2 +z-2 =(x+y+z)2 -2(xy+yz+zx)=36-22=14)। परीक्षा में तीन पदों की पहचान उपयोग करें।
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( (x+y+z)2 ) में \(x^2+y^2+z^2\) हटाने पर क्या बचेगा?
What remains when \(x^2+y^2+z^2\) is removed from ( (x+y+z)2 )?
#three term square
#mixed terms
#identity
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A (xy+yz+zx)
B (2xy+2yz+2zx)
C (xyz)
D (x+y+z)
Explanation opens after your attempt
Correct Answer
B. (2xy+2yz+2zx)
Step 1
Concept
The extra mixed terms in the square of three terms are (2xy+2yz+2zx). Exam tip: write all three mixed terms.
Step 2
Why this answer is correct
The correct answer is B. (2xy+2yz+2zx). The extra mixed terms in the square of three terms are (2xy+2yz+2zx). Exam tip: write all three mixed terms.
Step 3
Exam Tip
तीन पदों के वर्ग में अतिरिक्त मिश्र पद (2xy+2yz+2zx) होते हैं। परीक्षा में सभी तीन मिश्र पद लिखें।
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( (2x+3)2 -(2x+3)(2x-3) ) का सरल रूप क्या है?
What is the simplified form of ( (2x+3)2 -(2x+3)(2x-3) )?
#common factor
#combined identity
#simplification
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A (12x+18)
B (6x+9)
C (18)
D \(4x^2+9\)
Explanation opens after your attempt
Correct Answer
A. (12x+18)
Step 1
Concept
((2x+3)) is common, giving ((2x+3)[(2x+3)-(2x-3)]). Exam tip: taking common factors makes work easier.
Step 2
Why this answer is correct
The correct answer is A. (12x+18). ((2x+3)) is common, giving ((2x+3)[(2x+3)-(2x-3)]). Exam tip: taking common factors makes work easier.
Step 3
Exam Tip
((2x+3)) सामान्य लेकर ((2x+3)[(2x+3)-(2x-3)]) मिलता है। परीक्षा में common factor लेने से काम आसान होता है।
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( (x+4)3 -(x-4)3 ) में \(x^2\) वाला पद क्या होगा?
What will be the term containing \(x^2\) in ( (x+4)3 -(x-4)3 )?
#cube expansion
#term identification
#expert
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A \(12x^2\)
B \(24x^2\)
C \(48x^2\)
D \(96x^2\)
Explanation opens after your attempt
Correct Answer
B. \(24x^2\)
Step 1
Concept
The difference gives \(6x^2\cdot4=24x^2\). Exam tip: identify the \(x^2\) term quickly in cube differences.
Step 2
Why this answer is correct
The correct answer is B. \(24x^2\). The difference gives \(6x^2\cdot4=24x^2\). Exam tip: identify the \(x^2\) term quickly in cube differences.
Step 3
Exam Tip
अंतर में \(6x^2\cdot4=24x^2\) मिलता है। परीक्षा में घन अंतर में \(x^2\) वाला पद जल्दी पहचानें।
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( (x+2)3 +(x-2)3 ) का सरल रूप क्या है?
What is the simplified form of ( (x+2)3 +(x-2)3 )?
#cube identity
#symmetric expression
#simplification
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A \(2x^3+24x\)
B \(2x^3+12x\)
C \(x^3+8\)
D \(2x^3+16\)
Explanation opens after your attempt
Correct Answer
A. \(2x^3+24x\)
Step 1
Concept
In the sum, constant cube terms cancel and \(2x^3+6x\cdot4=2x^3+24x\) remains. Exam tip: understand symmetric cube expansion.
Step 2
Why this answer is correct
The correct answer is A. \(2x^3+24x\). In the sum, constant cube terms cancel and \(2x^3+6x\cdot4=2x^3+24x\) remains. Exam tip: understand symmetric cube expansion.
Step 3
Exam Tip
योग में स्थिर घन कटते हैं और \(2x^3+6x\cdot4=2x^3+24x\) बचता है। परीक्षा में सममित घन विस्तार समझें।
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( (a+b)2 -\(a^2-b^2\) ) का सरल रूप क्या है?
What is the simplified form of ( (a+b)2 -\(a^2-b^2\) )?
#identity comparison
#sign handling
#simplification
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A \(2ab+2b^2\)
B (2ab)
C \(a^2+2ab\)
D \(b^2\)
Explanation opens after your attempt
Correct Answer
A. \(2ab+2b^2\)
Step 1
Concept
\(a^2+2ab+b^2-a^2+b^2=2ab+2b^2\). Exam tip: apply the minus sign to the whole second expression.
Step 2
Why this answer is correct
The correct answer is A. \(2ab+2b^2\). \(a^2+2ab+b^2-a^2+b^2=2ab+2b^2\). Exam tip: apply the minus sign to the whole second expression.
Step 3
Exam Tip
\(a^2+2ab+b^2-a^2+b^2=2ab+2b^2\)। परीक्षा में ऋण चिन्ह को पूरे दूसरे पद पर लगाएँ।
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( (a-b)2 -\(a^2+b^2\) ) किसके बराबर है?
What is ( (a-b)2 -\(a^2+b^2\) ) equal to?
#minus square
#middle term
#identity
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A (2ab)
B (-2ab)
C \(a^2-b^2\)
D \(-b^2\)
Explanation opens after your attempt
Step 1
Concept
( (a-b)2 =a-2 -2ab+b-2 ), so subtracting leaves (-2ab). Exam tip: remember the negative middle term.
Step 2
Why this answer is correct
The correct answer is B. (-2ab). ( (a-b)2 =a-2 -2ab+b-2 ), so subtracting leaves (-2ab). Exam tip: remember the negative middle term.
Step 3
Exam Tip
( (a-b)2 =a-2 -2ab+b-2 ) है इसलिए घटाने पर (-2ab) बचता है। परीक्षा में नकारात्मक मध्य पद याद रखें।
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यदि \(x+\frac{1}{x}=5\) है तो \(x^2+\frac{1}{x^2}\) का मान क्या होगा?
If \(x+\frac{1}{x}=5\), what is the value of \(x^2+\frac{1}{x^2}\)?
#reciprocal identity
#square relation
#expert
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A (23)
B (25)
C (27)
D (20)
Explanation opens after your attempt
Step 1
Concept
On squaring, \(x^2+2+\frac{1}{x^2}=25\). Exam tip: do not forget to subtract (2).
Step 2
Why this answer is correct
The correct answer is A. (23). On squaring, \(x^2+2+\frac{1}{x^2}=25\). Exam tip: do not forget to subtract (2).
Step 3
Exam Tip
वर्ग करने पर \(x^2+2+\frac{1}{x^2}=25\) मिलता है। परीक्षा में (2) घटाना न भूलें।
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यदि \(t-\frac{1}{t}=6\) है तो \(t^2+\frac{1}{t^2}\) कितना होगा?
If \(t-\frac{1}{t}=6\), what is \(t^2+\frac{1}{t^2}\)?
#reciprocal expression
#minus square
#identity
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A (34)
B (36)
C (38)
D (40)
Explanation opens after your attempt
Step 1
Concept
On squaring, \(t^2-2+\frac{1}{t^2}=36\), so the value is (38). Exam tip: the square of a difference gives (-2).
Step 2
Why this answer is correct
The correct answer is C. (38). On squaring, \(t^2-2+\frac{1}{t^2}=36\), so the value is (38). Exam tip: the square of a difference gives (-2).
Step 3
Exam Tip
वर्ग करने पर \(t^2-2+\frac{1}{t^2}=36\) इसलिए मान (38) है। परीक्षा में अंतर के वर्ग में (-2) आता है।
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( \(x+\frac{1}{x}\)2 -\(x-\frac{1}{x}\)2 ) का मान क्या है?
What is the value of ( \(x+\frac{1}{x}\)2 -\(x-\frac{1}{x}\)2 )?
#reciprocal identity
#difference
#expert
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A (2)
B (4)
C \(x^2+\frac{1}{x^2}\)
D (0)
Explanation opens after your attempt
Step 1
Concept
This is (4AB) where (A=x) and \(B=\frac{1}{x}\), so the value is (4). Exam tip: reciprocal terms multiply to (1).
Step 2
Why this answer is correct
The correct answer is B. (4). This is (4AB) where (A=x) and \(B=\frac{1}{x}\), so the value is (4). Exam tip: reciprocal terms multiply to (1).
Step 3
Exam Tip
यह (4AB) है जहाँ (A=x) और \(B=\frac{1}{x}\), इसलिए मान (4) है। परीक्षा में reciprocal terms का गुणन (1) होता है।
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( (x-2)(x+2)\(x^2+4\) ) का सरल रूप क्या है?
What is the simplified form of ( (x-2)(x+2)\(x^2+4\) )?
#nested identity
#difference of squares
#quartic
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A \(x^4+16\)
B \(x^4-8\)
C \(x^4-16\)
D \(x^4+8x^2+16\)
Explanation opens after your attempt
Correct Answer
C. \(x^4-16\)
Step 1
Concept
First ( (x-2)(x+2)=x-2 -4 ), then (\(x^2-4\)\(x^2+4\)=x-4 -16). Exam tip: apply difference of squares twice.
Step 2
Why this answer is correct
The correct answer is C. \(x^4-16\). First ( (x-2)(x+2)=x-2 -4 ), then (\(x^2-4\)\(x^2+4\)=x-4 -16). Exam tip: apply difference of squares twice.
Step 3
Exam Tip
पहले ( (x-2)(x+2)=x-2 -4 ) और फिर (\(x^2-4\)\(x^2+4\)=x-4 -16)। परीक्षा में दो बार अंतर वर्ग लगाएँ।
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\( 16x^4-81y^4 \) का गुणनखंडों में सही पहला चरण क्या है?
What is the correct first factorization step for \( 16x^4-81y^4 \)?
#higher powers
#difference of squares
#factorization
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A ( \(4x^2-9y^2\)\(4x^2+9y^2\) )
B ( (4x-9y)(4x+9y) )
C ( \(2x^2-3y^2\)\(2x^2+3y^2\) )
D ( \(16x^2-81y^2\)\(x^2+y^2\) )
Explanation opens after your attempt
Correct Answer
A. ( \(4x^2-9y^2\)\(4x^2+9y^2\) )
Step 1
Concept
(16x-4 =\(4x^2\)2 ) and (81y-4 =\(9y^2\)2 ). Exam tip: identify larger squares first.
Step 2
Why this answer is correct
The correct answer is A. ( \(4x^2-9y^2\)\(4x^2+9y^2\) ). (16x-4 =\(4x^2\)2 ) and (81y-4 =\(9y^2\)2 ). Exam tip: identify larger squares first.
Step 3
Exam Tip
(16x-4 =\(4x^2\)2 ) और (81y-4 =\(9y^2\)2 ) है। परीक्षा में पहले बड़े वर्ग पहचानें।
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( \(x^2+3\)2 -\(x^2-3\)2 ) का सरल रूप क्या है?
What is the simplified form of ( \(x^2+3\)2 -\(x^2-3\)2 )?
#higher power
#square difference
#shortcut
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A \(6x^2\)
B \(9x^2\)
C \(12x^2\)
D \(18x^2\)
Explanation opens after your attempt
Correct Answer
C. \(12x^2\)
Step 1
Concept
This is (4AB) where \(A=x^2\) and (B=3). Exam tip: treat \(x^2\) as one whole term.
Step 2
Why this answer is correct
The correct answer is C. \(12x^2\). This is (4AB) where \(A=x^2\) and (B=3). Exam tip: treat \(x^2\) as one whole term.
Step 3
Exam Tip
यह (4AB) है जहाँ \(A=x^2\) और (B=3)। परीक्षा में \(x^2\) को एक पूरा पद मानें।
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यदि \(x^2+y^2=50\) और (xy=7) है तो ( (x+y)2 ) कितना होगा?
If \(x^2+y^2=50\) and (xy=7), what is ( (x+y)2 )?
#given values
#sum square
#xy
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A (57)
B (64)
C (43)
D (14)
Explanation opens after your attempt
Step 1
Concept
( (x+y)2 =x-2 +y-2 +2xy=50+14=64). Exam tip: remember to add (2xy).
Step 2
Why this answer is correct
The correct answer is B. (64). ( (x+y)2 =x-2 +y-2 +2xy=50+14=64). Exam tip: remember to add (2xy).
Step 3
Exam Tip
( (x+y)2 =x-2 +y-2 +2xy=50+14=64)। परीक्षा में (2xy) जोड़ना याद रखें।
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यदि \(u^2+v^2=29\) और (uv=10) है तो ( (u-v)2 ) का मान क्या है?
If \(u^2+v^2=29\) and (uv=10), what is the value of ( (u-v)2 )?
#given values
#difference square
#expert
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A (9)
B (19)
C (39)
D (49)
Explanation opens after your attempt
Step 1
Concept
( (u-v)2 =u-2 +v-2 -2uv=29-20=9). Exam tip: subtract (2uv) in the square of difference.
Step 2
Why this answer is correct
The correct answer is A. (9). ( (u-v)2 =u-2 +v-2 -2uv=29-20=9). Exam tip: subtract (2uv) in the square of difference.
Step 3
Exam Tip
( (u-v)2 =u-2 +v-2 -2uv=29-20=9)। परीक्षा में अंतर के वर्ग में (2uv) घटता है।
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( (a+2b-c)2 ) में (bc) वाला पद कौन सा होगा?
Which term containing (bc) appears in ( (a+2b-c)2 )?
#three term square
#negative mixed term
#bc
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A (2bc)
B (-2bc)
C (-4bc)
D (4bc)
Explanation opens after your attempt
Step 1
Concept
\(2\times2b\times(-c)=-4bc\). Exam tip: handle signs carefully in squares of three terms.
Step 2
Why this answer is correct
The correct answer is C. (-4bc). \(2\times2b\times(-c)=-4bc\). Exam tip: handle signs carefully in squares of three terms.
Step 3
Exam Tip
\(2\times2b\times(-c)=-4bc\) है। परीक्षा में तीन पदों के वर्ग में चिन्हों को ध्यान से रखें।
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( (2x-3y+z)2 ) में (xz) वाला पद क्या है?
What is the term containing (xz) in ( (2x-3y+z)2 )?
#three term square
#xz term
#coefficients
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A (2xz)
B (4xz)
C (-6xz)
D (6xz)
Explanation opens after your attempt
Step 1
Concept
\(2\times2x\times z=4xz\). Exam tip: find the mixed term for the required pair only.
Step 2
Why this answer is correct
The correct answer is B. (4xz). \(2\times2x\times z=4xz\). Exam tip: find the mixed term for the required pair only.
Step 3
Exam Tip
\(2\times2x\times z=4xz\) मिलता है। परीक्षा में जिस जोड़ी की बात हो वही मिश्र पद निकालें।
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यदि ( (x+2)(x+5)=x-2 +kx+10 ) है तो (k) का मान क्या है?
If ( (x+2)(x+5)=x-2 +kx+10 ), what is the value of (k)?
#unknown coefficient
#product identity
#binomial
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A (5)
B (7)
C (10)
D (12)
Explanation opens after your attempt
Step 1
Concept
The coefficient of (x) is (2+5=7). Exam tip: in ((x+a)(x+b)), the coefficient of (x) is (a+b).
Step 2
Why this answer is correct
The correct answer is B. (7). The coefficient of (x) is (2+5=7). Exam tip: in ((x+a)(x+b)), the coefficient of (x) is (a+b).
Step 3
Exam Tip
(x) का गुणांक (2+5=7) है। परीक्षा में ((x+a)(x+b)) में (x) का गुणांक (a+b) होता है।
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यदि ( (x-4)(x+k)=x-2 +3x-28 ) है तो (k) का मान क्या है?
If ( (x-4)(x+k)=x-2 +3x-28 ), what is the value of (k)?
#unknown constant
#product expansion
#verification
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A (4)
B (5)
C (7)
D (9)
Explanation opens after your attempt
Step 1
Concept
The constant term (-4k=-28) gives (k=7), and the middle term also becomes (3x). Exam tip: verify using both conditions.
Step 2
Why this answer is correct
The correct answer is C. (7). The constant term (-4k=-28) gives (k=7), and the middle term also becomes (3x). Exam tip: verify using both conditions.
Step 3
Exam Tip
स्थिर पद (-4k=-28) से (k=7) मिलता है और मध्य पद भी (3x) बनता है। परीक्षा में दोनों शर्तों से जाँच करें।
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( (x+3)2 -(x-1)(x+7) ) का सरल रूप क्या है?
What is the simplified form of ( (x+3)2 -(x-1)(x+7) )?
#error check
#identity comparison
#simplification
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A (2)
B (4)
C (6)
D (8)
Explanation opens after your attempt
Step 1
Concept
The first is \(x^2+6x+9\) and the second is \(x^2+6x-7\). Subtracting gives (9-(-7)=16), so the correct option should be (16).
Step 2
Why this answer is correct
The correct answer is B. (4). The first is \(x^2+6x+9\) and the second is \(x^2+6x-7\). Subtracting gives (9-(-7)=16), so the correct option should be (16).
Step 3
Exam Tip
पहला \(x^2+6x+9\) और दूसरा \(x^2+6x-7\) है। घटाने पर (16) नहीं बल्कि (9-(-7)=16) होगा इसलिए सही विकल्प (16) होना चाहिए।
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( (2x+1)(2x+9)-(2x+5)2 ) का मान क्या है?
What is the value of ( (2x+1)(2x+9)-(2x+5)2 )?
#comparison
#binomial product
#simplification
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A (4)
B (8)
C (-8)
D (-16)
Explanation opens after your attempt
Step 1
Concept
The first product is \(4x^2+20x+9\) and the second is \(4x^2+20x+25\). Exam tip: cancel like terms and compare constants.
Step 2
Why this answer is correct
The correct answer is D. (-16). The first product is \(4x^2+20x+9\) and the second is \(4x^2+20x+25\). Exam tip: cancel like terms and compare constants.
Step 3
Exam Tip
पहला गुणनफल \(4x^2+20x+9\) और दूसरा \(4x^2+20x+25\) है। परीक्षा में समान पद काटकर स्थिर पदों का अंतर लें।
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( (x+6)2 -(x+2)(x+10) ) का सरल मान क्या है?
What is the simplified value of ( (x+6)2 -(x+2)(x+10) )?
#combined identities
#binomial product
#simplification
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A (8)
B (12)
C (16)
D (20)
Explanation opens after your attempt
Step 1
Concept
The first expansion is \(x^2+12x+36\) and the second is \(x^2+12x+20\). Exam tip: cancel like terms and compare constants.
Step 2
Why this answer is correct
The correct answer is C. (16). The first expansion is \(x^2+12x+36\) and the second is \(x^2+12x+20\). Exam tip: cancel like terms and compare constants.
Step 3
Exam Tip
पहला विस्तार \(x^2+12x+36\) और दूसरा \(x^2+12x+20\) है। परीक्षा में समान पद काटकर स्थिर पदों का अंतर लें।
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यदि \(x+\frac{1}{x}=7\) है तो \(x^3+\frac{1}{x^3}\) का मान क्या होगा?
If \(x+\frac{1}{x}=7\), what is the value of \(x^3+\frac{1}{x^3}\)?
#reciprocal identity
#cube identity
#expert
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A (336)
B (322)
C (343)
D (364)
Explanation opens after your attempt
Step 1
Concept
Use (a-3 +b-3 =(a+b)3 -3ab(a+b)) where (ab=1). Exam tip: remember \(7^3-3\times7=322\).
Step 2
Why this answer is correct
The correct answer is B. (322). Use (a-3 +b-3 =(a+b)3 -3ab(a+b)) where (ab=1). Exam tip: remember \(7^3-3\times7=322\).
Step 3
Exam Tip
पहचान (a-3 +b-3 =(a+b)3 -3ab(a+b)) लगाएँ जहाँ (ab=1)। परीक्षा में \(7^3-3\times7=322\) याद रखें।
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\(27a^3+8b^3\) का सही गुणनखंड रूप कौन सा है?
Which is the correct factor form of \(27a^3+8b^3\)?
#sum of cubes
#factorization
#algebraic identities
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A ( (3a-2b)\(9a^2+6ab+4b^2\) )
B ( (3a+2b)\(9a^2+6ab+4b^2\) )
C ( (27a+8b)\(a^2-ab+b^2\) )
D ( (3a+2b)\(9a^2-6ab+4b^2\) )
Explanation opens after your attempt
Correct Answer
D. ( (3a+2b)\(9a^2-6ab+4b^2\) )
Step 1
Concept
This is ((3a)3 +(2b)3 ), so the sum of cubes identity applies. Exam tip: the middle term inside the second factor is negative.
Step 2
Why this answer is correct
The correct answer is D. ( (3a+2b)\(9a^2-6ab+4b^2\) ). This is ((3a)3 +(2b)3 ), so the sum of cubes identity applies. Exam tip: the middle term inside the second factor is negative.
Step 3
Exam Tip
यह ((3a)3 +(2b)3 ) है इसलिए \(a^3+b^3\) की पहचान लगेगी। परीक्षा में योग घन में बीच वाला पद ऋणात्मक होता है।
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यदि (a+b+c=9) और (ab+bc+ca=20) है तो \(a^2+b^2+c^2\) कितना होगा?
If (a+b+c=9) and (ab+bc+ca=20), what is \(a^2+b^2+c^2\)?
#three term square
#given values
#sum of squares
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A (41)
B (49)
C (61)
D (81)
Explanation opens after your attempt
Step 1
Concept
(a-2 +b-2 +c-2 =(a+b+c)2 -2(ab+bc+ca)=81-40=41). Exam tip: directly use the square identity of three terms.
Step 2
Why this answer is correct
The correct answer is A. (41). (a-2 +b-2 +c-2 =(a+b+c)2 -2(ab+bc+ca)=81-40=41). Exam tip: directly use the square identity of three terms.
Step 3
Exam Tip
(a-2 +b-2 +c-2 =(a+b+c)2 -2(ab+bc+ca)=81-40=41)। परीक्षा में तीन पदों की वर्ग पहचान सीधे लगाएँ।
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