Concept-wise Practice

minus square MCQ Questions for Class 9

minus square se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

100 questions tagged with minus square.

\(x^2+bx+25\) पूर्ण वर्ग हो और (b) ऋणात्मक हो, तो (b) क्या होगा?

If \(x^2+bx+25\) is a perfect square and (b) is negative, what is (b)?

Explanation opens after your attempt
Correct Answer

B. (-10)

Step 1

Concept

Since \(25=5^2\), for the negative perfect square \(b=-2\cdot5=-10\). Exam tip: read the sign condition carefully.

Step 2

Why this answer is correct

The correct answer is B. (-10). Since \(25=5^2\), for the negative perfect square \(b=-2\cdot5=-10\). Exam tip: read the sign condition carefully.

Step 3

Exam Tip

\(25=5^2\), इसलिए ऋणात्मक पूर्ण वर्ग में \(b=-2\cdot5=-10\) है। परीक्षा में संकेत शर्त जरूर पढ़ें।

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\(x^2-14x+49\) किस पूर्ण वर्ग के बराबर है?

Which perfect square equals \(x^2-14x+49\)?

Explanation opens after your attempt
Correct Answer

D. ((x-7)2)

Step 1

Concept

Here \(49=7^2\) and \(-14x=-2\cdot7\cdot x\). Exam tip: identify ((x-7)2) from the negative middle term.

Step 2

Why this answer is correct

The correct answer is D. ((x-7)2). Here \(49=7^2\) and \(-14x=-2\cdot7\cdot x\). Exam tip: identify ((x-7)2) from the negative middle term.

Step 3

Exam Tip

\(49=7^2\) और \(-14x=-2\cdot7\cdot x\) है। परीक्षा में ऋणात्मक मध्य पद से ((x-7)2) पहचानें।

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((x-5)2) का सही विस्तार क्या है?

What is the correct expansion of ((x-5)2)?

Explanation opens after your attempt
Correct Answer

B. \(x^2-10x+25\)

Step 1

Concept

((x-5)2=x-2-2\cdot x\cdot5+25). Exam tip: note both the negative sign and (2ab).

Step 2

Why this answer is correct

The correct answer is B. \(x^2-10x+25\). ((x-5)2=x-2-2\cdot x\cdot5+25). Exam tip: note both the negative sign and (2ab).

Step 3

Exam Tip

((x-5)2=x-2-2\cdot x\cdot5+25) है। परीक्षा में ऋण चिन्ह और (2ab) दोनों ध्यान रखें।

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\(a^2-2ab+b^2\) किसके बराबर है?

What is \(a^2-2ab+b^2\) equal to?

Explanation opens after your attempt
Correct Answer

B. ((a-b)2)

Step 1

Concept

The middle term is negative, so it is a subtraction perfect square. The correct form is ((a-b)2).

Step 2

Why this answer is correct

The correct answer is B. ((a-b)2). The middle term is negative, so it is a subtraction perfect square. The correct form is ((a-b)2).

Step 3

Exam Tip

मध्य पद ऋण है इसलिए यह घटाव वाला पूर्ण वर्ग है। सही रूप ((a-b)2) है।

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((x-4)2) का विस्तार क्या है?

What is the expansion of ((x-4)2)?

Explanation opens after your attempt
Correct Answer

C. \(x^2-8x+16\)

Step 1

Concept

((x-4)2=x-2-2\cdot x\cdot4+16). So \(x^2-8x+16\) is correct.

Step 2

Why this answer is correct

The correct answer is C. \(x^2-8x+16\). ((x-4)2=x-2-2\cdot x\cdot4+16). So \(x^2-8x+16\) is correct.

Step 3

Exam Tip

((x-4)2=x-2-2\cdot x\cdot4+16) है। इसलिए \(x^2-8x+16\) सही है।

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\(x^2-14x+49\) का सही गुणनखंड रूप क्या है?

What is the correct factorised form of \(x^2-14x+49\)?

Explanation opens after your attempt
Correct Answer

B. ((x-7)2)

Step 1

Concept

\(49=7^2\) and \(-14x=-2\times7\times x\). Exam tip: identify ((a-b)2) from the negative middle term.

Step 2

Why this answer is correct

The correct answer is B. ((x-7)2). \(49=7^2\) and \(-14x=-2\times7\times x\). Exam tip: identify ((a-b)2) from the negative middle term.

Step 3

Exam Tip

\(49=7^2\) और \(-14x=-2\times7\times x\) है। परीक्षा में ऋणात्मक मध्य पद देखकर ((a-b)2) पहचानें।

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\(z^2-4z+4\) का गुणनखंड रूप क्या है?

What is the factorised form of \(z^2-4z+4\)?

Explanation opens after your attempt
Correct Answer

C. ((z-2)2)

Step 1

Concept

\(4=2^2\) and \(-4z=-2\times z\times2\), so it is ((z-2)2). Exam tip: identify subtraction perfect squares.

Step 2

Why this answer is correct

The correct answer is C. ((z-2)2). \(4=2^2\) and \(-4z=-2\times z\times2\), so it is ((z-2)2). Exam tip: identify subtraction perfect squares.

Step 3

Exam Tip

\(4=2^2\) और \(-4z=-2\times z\times2\), इसलिए ((z-2)2) है। परीक्षा में घटाव वाले पूर्ण वर्ग को पहचानें।

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\(x^2-6x+9\) किसका वर्ग है?

Whose square is \(x^2-6x+9\)?

Explanation opens after your attempt
Correct Answer

A. ((x-3)2)

Step 1

Concept

Since \(9=3^2\) and the middle term is (-6x), the form is ((x-3)2). Exam tip: watch the negative sign.

Step 2

Why this answer is correct

The correct answer is A. ((x-3)2). Since \(9=3^2\) and the middle term is (-6x), the form is ((x-3)2). Exam tip: watch the negative sign.

Step 3

Exam Tip

\(9=3^2\) और बीच का पद (-6x) है, इसलिए रूप ((x-3)2) है। परीक्षा में ऋण चिह्न ध्यान से देखें।

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\(4x^2-12x+9\) के गुणनखंड क्या होंगे?

What are the factors of \(4x^2-12x+9\)?

Explanation opens after your attempt
Correct Answer

B. ((2x-3)2)

Step 1

Concept

This is the perfect square of the difference of (2x) and (3). In exams, check \(-12x=-2\cdot2x\cdot3\).

Step 2

Why this answer is correct

The correct answer is B. ((2x-3)2). This is the perfect square of the difference of (2x) and (3). In exams, check \(-12x=-2\cdot2x\cdot3\).

Step 3

Exam Tip

यह (2x) और (3) के अंतर का पूर्ण वर्ग है। परीक्षा में \(-12x=-2\cdot2x\cdot3\) देखें।

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\(x^2-2xy+y^2\) को गुणनखंडित कीजिए।

Factorise \(x^2-2xy+y^2\).

Explanation opens after your attempt
Correct Answer

B. ((x-y)2)

Step 1

Concept

This is the perfect square of the difference of (x) and (y). In exams, identify ((x-y)2) from the negative middle term.

Step 2

Why this answer is correct

The correct answer is B. ((x-y)2). This is the perfect square of the difference of (x) and (y). In exams, identify ((x-y)2) from the negative middle term.

Step 3

Exam Tip

यह (x) और (y) के अंतर का पूर्ण वर्ग है। परीक्षा में ऋणात्मक मध्य पद से ((x-y)2) पहचानें।

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\(p^2-12p+36\) का सही गुणनखंड चुनिए।

Choose the correct factorisation of \(p^2-12p+36\).

Explanation opens after your attempt
Correct Answer

B. ((p-6)2)

Step 1

Concept

\(36=6^2\) and the middle term is negative. In exams, use the sign to choose ((p-6)2).

Step 2

Why this answer is correct

The correct answer is B. ((p-6)2). \(36=6^2\) and the middle term is negative. In exams, use the sign to choose ((p-6)2).

Step 3

Exam Tip

\(36=6^2\) और मध्य पद ऋणात्मक है। परीक्षा में चिह्न देखकर ((p-6)2) चुनें।

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\(y^2-10y+25\) का गुणनखंडन कौन सा है?

Which is the factorisation of \(y^2-10y+25\)?

Explanation opens after your attempt
Correct Answer

C. ((y-5)2)

Step 1

Concept

\(25=5^2\) and \(-10y=-2\cdot5y\). So (y-2-10y+25=(y-5)2).

Step 2

Why this answer is correct

The correct answer is C. ((y-5)2). \(25=5^2\) and \(-10y=-2\cdot5y\). So (y-2-10y+25=(y-5)2).

Step 3

Exam Tip

\(25=5^2\) और \(-10y=-2\cdot5y\) है। इसलिए (y-2-10y+25=(y-5)2) है।

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यदि (2a-b) भुजा वाले वर्ग का दृश्य मॉडल बने, तो विस्तार क्या होगा?

If a visual model is made for a square of side (2a-b), what will be the expansion?

Explanation opens after your attempt
Correct Answer

A. \(4a^2-4ab+b^2\)

Step 1

Concept

The subtracted middle term is \(2\cdot2a\cdot b=4ab\). In exams, keep both the negative sign and coefficient.

Step 2

Why this answer is correct

The correct answer is A. \(4a^2-4ab+b^2\). The subtracted middle term is \(2\cdot2a\cdot b=4ab\). In exams, keep both the negative sign and coefficient.

Step 3

Exam Tip

बीच का घटा पद \(2\cdot2a\cdot b=4ab\) है। परीक्षा में ऋण चिह्न और गुणांक दोनों रखें।

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यदि (q-4) भुजा वाले वर्ग का अंतिम क्षेत्रफल चाहिए, तो सही विस्तार कौन-सा होगा?

If the final area of a square of side (q-4) is needed, which expansion is correct?

Explanation opens after your attempt
Correct Answer

C. \(q^2-8q+16\)

Step 1

Concept

The middle term is \(-2\cdot q\cdot4=-8q\). In exams, count (4) in two strips.

Step 2

Why this answer is correct

The correct answer is C. \(q^2-8q+16\). The middle term is \(-2\cdot q\cdot4=-8q\). In exams, count (4) in two strips.

Step 3

Exam Tip

बीच का पद \(-2\cdot q\cdot4=-8q\) है। परीक्षा में (4) को दो पट्टियों में गिनें।

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(n-5) भुजा वाले वर्ग में हटाई गई दो पट्टियों का कुल क्षेत्रफल क्या है?

In a square of side (n-5), what is the total area of the two removed strips?

Explanation opens after your attempt
Correct Answer

B. (10n)

Step 1

Concept

The two strips are (5n) and (5n), so total (10n) is removed. In exams, add both removed parts.

Step 2

Why this answer is correct

The correct answer is B. (10n). The two strips are (5n) and (5n), so total (10n) is removed. In exams, add both removed parts.

Step 3

Exam Tip

दो पट्टियाँ (5n) और (5n) हैं इसलिए कुल (10n) घटता है। परीक्षा में दोनों हटे भाग जोड़ें।

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यदि भुजा (a-b) वाले वर्ग का क्षेत्र \(a^2-2ab+b^2\) है, तो \(b^2\) का चिन्ह कैसा होगा?

If the area of a square with side (a-b) is \(a^2-2ab+b^2\), what will be the sign of \(b^2\)?

Explanation opens after your attempt
Correct Answer

C. धनात्मकPositive

Step 1

Concept

Because (b) is squared, \(b^2\) remains positive. Exam tip: only the middle term is negative.

Step 2

Why this answer is correct

The correct answer is C. धनात्मक / Positive. Because (b) is squared, \(b^2\) remains positive. Exam tip: only the middle term is negative.

Step 3

Exam Tip

(b) का वर्ग बनने से \(b^2\) धनात्मक रहता है। परीक्षा में केवल बीच का पद ऋणात्मक होता है।

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दृश्य मॉडल में \(x^2-10x+25\) किस वर्ग की भुजा को दिखाता है?

In a visual model, \(x^2-10x+25\) shows the side of which square?

Explanation opens after your attempt
Correct Answer

C. (x-5)

Step 1

Concept

Since \(25=5^2\) and \(-10x=-2\times x\times5\), the side is (x-5). Exam tip: look at the negative middle term.

Step 2

Why this answer is correct

The correct answer is C. (x-5). Since \(25=5^2\) and \(-10x=-2\times x\times5\), the side is (x-5). Exam tip: look at the negative middle term.

Step 3

Exam Tip

\(25=5^2\) और \(-10x=-2\times x\times5\), इसलिए भुजा (x-5) है। परीक्षा में ऋणात्मक बीच का पद देखें।

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भुजा (x-5) वाले वर्ग के मॉडल में अंतिम छोटा वर्ग किस क्षेत्र का होगा?

In the model of a square with side (x-5), what will be the area of the final small square?

Explanation opens after your attempt
Correct Answer

C. (25)

Step 1

Concept

The small square has side (5), so its area is (25). Exam tip: the square of the negative part is positive.

Step 2

Why this answer is correct

The correct answer is C. (25). The small square has side (5), so its area is (25). Exam tip: the square of the negative part is positive.

Step 3

Exam Tip

छोटे वर्ग की भुजा (5) है इसलिए उसका क्षेत्र (25) है। परीक्षा में ऋणात्मक भाग का वर्ग धनात्मक होता है।

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भुजा (y-3) वाले वर्ग के क्षेत्र मॉडल में सही विस्तार कौन सा है?

Which expansion is correct in the area model of a square with side (y-3)?

Explanation opens after your attempt
Correct Answer

C. \(y^2-6y+9\)

Step 1

Concept

Two (3y) strips are subtracted, and (9) is added back. Exam tip: keep the middle term negative in ((a-b)2).

Step 2

Why this answer is correct

The correct answer is C. \(y^2-6y+9\). Two (3y) strips are subtracted, and (9) is added back. Exam tip: keep the middle term negative in ((a-b)2).

Step 3

Exam Tip

दो (3y) पट्टियां घटती हैं और (9) वापस जुड़ता है। परीक्षा में ((a-b)2) में बीच का पद ऋणात्मक रखें।

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किस दृश्य मॉडल में पूरा क्षेत्रफल \(x^2-4x+4\) मिलता है?

Which visual model gives the whole area \(x^2-4x+4\)?

Explanation opens after your attempt
Correct Answer

B. भुजा (x-2) का वर्गSquare of side (x-2)

Step 1

Concept

(x-2-4x+4=(x-2)2). Exam tip: identify the subtraction square from the negative middle term.

Step 2

Why this answer is correct

The correct answer is B. भुजा (x-2) का वर्ग / Square of side (x-2). (x-2-4x+4=(x-2)2). Exam tip: identify the subtraction square from the negative middle term.

Step 3

Exam Tip

(x-2-4x+4=(x-2)2) है। परीक्षा में ऋण मध्य पद देखकर घटाव वाला वर्ग पहचानें।

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यदि \(18^2\) को ((20-2)2) से निकालें तो अंत में जोड़ा जाने वाला छोटा वर्ग कितना है?

If \(18^2\) is found using ((20-2)2), what is the small square added at the end?

Explanation opens after your attempt
Correct Answer

B. (4)

Step 1

Concept

In ((20-2)2), the small square is \(2^2=4\). Exam tip: after subtracting two rectangles, add the small square.

Step 2

Why this answer is correct

The correct answer is B. (4). In ((20-2)2), the small square is \(2^2=4\). Exam tip: after subtracting two rectangles, add the small square.

Step 3

Exam Tip

((20-2)2) में छोटा वर्ग \(2^2=4\) है। परीक्षा में दो आयत घटाने के बाद छोटा वर्ग जोड़ें।

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भुजा (20-1) वाले वर्ग का क्षेत्र मॉडल किस संख्या का वर्ग दिखाता है?

The area model of a square with side (20-1) shows the square of which number?

Explanation opens after your attempt
Correct Answer

B. (19)

Step 1

Concept

(20-1=19). So this is the area model of \(19^2\).

Step 2

Why this answer is correct

The correct answer is B. (19). (20-1=19). So this is the area model of \(19^2\).

Step 3

Exam Tip

(20-1=19) है। इसलिए यह \(19^2\) का क्षेत्र मॉडल है।

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एक वर्ग की भुजा (a-b) है। उसका क्षेत्रफल किस रूप में लिखा जाएगा?

A square has side (a-b). How will its area be written?

Explanation opens after your attempt
Correct Answer

A. \(a^2-2ab+b^2\)

Step 1

Concept

The area of the square is ((a-b)2). On expanding, it gives \(a^2-2ab+b^2\).

Step 2

Why this answer is correct

The correct answer is A. \(a^2-2ab+b^2\). The area of the square is ((a-b)2). On expanding, it gives \(a^2-2ab+b^2\).

Step 3

Exam Tip

वर्ग का क्षेत्रफल ((a-b)2) होता है। विस्तार करने पर \(a^2-2ab+b^2\) मिलता है।

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एक (5t-2) भुजा वाले वर्ग में घटाई गई दो पट्टियों का कुल क्षेत्रफल कितना है?

In a square of side (5t-2), what is the total area of the two subtracted strips?

Explanation opens after your attempt
Correct Answer

B. (20t)

Step 1

Concept

The two strips are \(5t\cdot2\) and \(5t\cdot2\), so total (20t) is subtracted. In exams, include both strips.

Step 2

Why this answer is correct

The correct answer is B. (20t). The two strips are \(5t\cdot2\) and \(5t\cdot2\), so total (20t) is subtracted. In exams, include both strips.

Step 3

Exam Tip

दो पट्टियाँ \(5t\cdot2\) और \(5t\cdot2\) हैं, इसलिए कुल (20t) घटता है। परीक्षा में दोनों पट्टियाँ शामिल करें।

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यदि \(x^2-6x+9\) को दृश्य मॉडल से पढ़ना हो, तो कौन सा वर्ग बनता है?

If \(x^2-6x+9\) is read through a visual model, which square is formed?

Explanation opens after your attempt
Correct Answer

B. भुजा (x-3) वाला वर्गSquare with side (x-3)

Step 1

Concept

Since \(9=3^2\) and \(-6x=-2\times x\times3\), it is ((x-3)2). Exam tip: identify a subtraction square from the negative middle term.

Step 2

Why this answer is correct

The correct answer is B. भुजा (x-3) वाला वर्ग / Square with side (x-3). Since \(9=3^2\) and \(-6x=-2\times x\times3\), it is ((x-3)2). Exam tip: identify a subtraction square from the negative middle term.

Step 3

Exam Tip

\(9=3^2\) और \(-6x=-2\times x\times3\), इसलिए यह ((x-3)2) है। परीक्षा में ऋणात्मक बीच के पद से घटाव वर्ग पहचानें।

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किस मॉडल में \(4a^2-12ab+9b^2\) को एक पूर्ण वर्ग के रूप में देखा जा सकता है?

In which model can \(4a^2-12ab+9b^2\) be seen as a complete square?

Explanation opens after your attempt
Correct Answer

A. भुजा (2a-3b) वाला वर्गSquare with side (2a-3b)

Step 1

Concept

Here (4a-2=(2a)2), (9b-2=(3b)2), and the middle term is \(-2\times2a\times3b\). Exam tip: match all three terms with the perfect square pattern.

Step 2

Why this answer is correct

The correct answer is A. भुजा (2a-3b) वाला वर्ग / Square with side (2a-3b). Here (4a-2=(2a)2), (9b-2=(3b)2), and the middle term is \(-2\times2a\times3b\). Exam tip: match all three terms with the perfect square pattern.

Step 3

Exam Tip

(4a-2=(2a)2), (9b-2=(3b)2) और बीच का पद \(-2\times2a\times3b\) है। परीक्षा में तीनों पदों को पूर्ण वर्ग पैटर्न से मिलाएं।

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यदि ((x-6)2) का दृश्य मॉडल \(x^2-12x+36\) देता है, तो (-12x) किससे आता है?

If the visual model of ((x-6)2) gives \(x^2-12x+36\), where does (-12x) come from?

Explanation opens after your attempt
Correct Answer

A. दो घटाए गए (6x) आयतों सेFrom two subtracted (6x) rectangles

Step 1

Concept

The total area of the two removed strips is (6x+6x=12x). Exam tip: connect the negative middle term with removed rectangles.

Step 2

Why this answer is correct

The correct answer is A. दो घटाए गए (6x) आयतों से / From two subtracted (6x) rectangles. The total area of the two removed strips is (6x+6x=12x). Exam tip: connect the negative middle term with removed rectangles.

Step 3

Exam Tip

दोनों हटाई गई पट्टियों का कुल क्षेत्र (6x+6x=12x) है। परीक्षा में ऋणात्मक बीच का पद हटाए गए आयतों से जोड़ें।

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भुजा (a-b) वाले वर्ग के मॉडल में \(a^2\) से दो (ab) पट्टियां हटाने के बाद \(b^2\) क्यों जोड़ा जाता है?

In the model of a square with side (a-b), why is \(b^2\) added after removing two (ab) strips from \(a^2\)?

Explanation opens after your attempt
Correct Answer

A. क्योंकि \(b^2\) दो बार हट गया होता हैBecause \(b^2\) has been removed twice

Step 1

Concept

While removing two strips, the corner \(b^2\) part is subtracted twice. Exam tip: remember to add back the over-subtracted part.

Step 2

Why this answer is correct

The correct answer is A. क्योंकि \(b^2\) दो बार हट गया होता है / Because \(b^2\) has been removed twice. While removing two strips, the corner \(b^2\) part is subtracted twice. Exam tip: remember to add back the over-subtracted part.

Step 3

Exam Tip

दो पट्टियां हटाते समय कोने का \(b^2\) भाग दो बार घट जाता है। परीक्षा में अधिक घटे भाग को वापस जोड़ने का विचार याद रखें।

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यदि क्षेत्र मॉडल में \(x^2-12x+36\) का पूरा वर्ग बनता है, तो हटाए गए दो आयतों का कुल क्षेत्रफल कितना माना जाएगा?

If the area model forms the complete square \(x^2-12x+36\), what is considered the total area of the two removed rectangles?

Explanation opens after your attempt
Correct Answer

B. (12x)

Step 1

Concept

This is ((x-6)2), and the total area of the two removed rectangles is \(2\cdot6x=12x\). Exam tip: identify the subtracted middle area.

Step 2

Why this answer is correct

The correct answer is B. (12x). This is ((x-6)2), and the total area of the two removed rectangles is \(2\cdot6x=12x\). Exam tip: identify the subtracted middle area.

Step 3

Exam Tip

यह ((x-6)2) है और दो हटे आयतों का कुल क्षेत्रफल \(2\cdot6x=12x\) है। परीक्षा में घटाया गया मध्य क्षेत्र पहचानें।

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दृश्य मॉडल में \(x^2-8x+16\) को पूर्ण वर्ग दिखाने के लिए किस भुजा का वर्ग बनाया जाएगा?

To show \(x^2-8x+16\) as a perfect square in a visual model, a square of which side will be made?

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Correct Answer

B. (x-4)

Step 1

Concept

\(16=4^2\) and \(-8x=-2\cdot4x\), so the side is (x-4). Exam tip: read the negative middle term as a subtraction model.

Step 2

Why this answer is correct

The correct answer is B. (x-4). \(16=4^2\) and \(-8x=-2\cdot4x\), so the side is (x-4). Exam tip: read the negative middle term as a subtraction model.

Step 3

Exam Tip

\(16=4^2\) और \(-8x=-2\cdot4x\) है इसलिए भुजा (x-4) है। परीक्षा में ऋण मध्य पद को घटाव वाला मॉडल समझें।

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