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complete square MCQ Questions for Class 10

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15 questions tagged with complete square.

Question 1/15 Expert Mathematics Chapter 2: Polynomials Geometrical meaning of the zeroes of a polynomial. Class 10 Level 24

यदि (p(x)=x-2+6x+10) है तो ग्राफ का (x)-अक्ष से संबंध क्या होगा?

If (p(x)=x-2+6x+10), what will be the relation of the graph with the (x)-axis?

Explanation opens after your attempt
Correct Answer

A. यह (x)-अक्ष को नहीं मिलेगाIt will not meet the (x)-axis

Step 1

Concept

(x-2+6x+10=(x+3)2+1), which is always positive. So there is no real zero.

Step 2

Why this answer is correct

The correct answer is A. यह (x)-अक्ष को नहीं मिलेगा / It will not meet the (x)-axis. (x-2+6x+10=(x+3)2+1), which is always positive. So there is no real zero.

Step 3

Exam Tip

(x-2+6x+10=(x+3)2+1) है जो हमेशा धनात्मक है। इसलिए कोई वास्तविक शून्यक नहीं है।

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Question 2/15 Expert Mathematics Chapter 2: Polynomials Geometrical meaning of the zeroes of a polynomial. Class 10 Level 23

यदि (p(x)=6x-2-72x+216) है, तो ग्राफ (x)-अक्ष से कैसे मिलेगा?

If (p(x)=6x-2-72x+216), how will the graph meet the (x)-axis?

Explanation opens after your attempt
Correct Answer

A. (x=6) पर स्पर्श करेगाIt will touch at (x=6)

Step 1

Concept

(6x-2-72x+216=6(x-6)2), so it touches at (x=6). Tip: the outside (6) does not change the zero.

Step 2

Why this answer is correct

The correct answer is A. (x=6) पर स्पर्श करेगा / It will touch at (x=6). (6x-2-72x+216=6(x-6)2), so it touches at (x=6). Tip: the outside (6) does not change the zero.

Step 3

Exam Tip

(6x-2-72x+216=6(x-6)2) है, इसलिए (x=6) पर स्पर्श होगा। टिप: बाहरी (6) शून्यक नहीं बदलता।

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Question 3/15 Expert Mathematics Chapter 2: Polynomials Geometrical meaning of the zeroes of a polynomial. Class 10 Level 23

यदि (p(x)=x-2+16x+80) है, तो (p(x)=0) का ग्राफीय अर्थ क्या है?

If (p(x)=x-2+16x+80), what is the graphical meaning of (p(x)=0)?

Explanation opens after your attempt
Correct Answer

C. ग्राफ (x)-अक्ष को नहीं काटताThe graph does not cut the (x)-axis

Step 1

Concept

(x-2+16x+80=(x+8)2+16), so there is no real zero. Tip: an always positive form gives no intersection.

Step 2

Why this answer is correct

The correct answer is C. ग्राफ (x)-अक्ष को नहीं काटता / The graph does not cut the (x)-axis. (x-2+16x+80=(x+8)2+16), so there is no real zero. Tip: an always positive form gives no intersection.

Step 3

Exam Tip

(x-2+16x+80=(x+8)2+16) है, इसलिए वास्तविक शून्यक नहीं है। टिप: हमेशा धनात्मक रूप कटान नहीं देता।

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Question 4/15 Expert Mathematics Chapter 2: Polynomials Geometrical meaning of the zeroes of a polynomial. Class 10 Level 23

यदि (p(x)=x-2-14x+53) है, तो ग्राफ (x)-अक्ष को क्यों नहीं काटेगा?

If (p(x)=x-2-14x+53), why will the graph not cut the (x)-axis?

Explanation opens after your attempt
Correct Answer

A. क्योंकि यह ((x-7)2+4) हैBecause it is ((x-7)2+4)

Step 1

Concept

((x-7)2+4) is always positive, so (p(x)=0) will not occur. Tip: adding a positive number to a square gives no real intersection.

Step 2

Why this answer is correct

The correct answer is A. क्योंकि यह ((x-7)2+4) है / Because it is ((x-7)2+4). ((x-7)2+4) is always positive, so (p(x)=0) will not occur. Tip: adding a positive number to a square gives no real intersection.

Step 3

Exam Tip

((x-7)2+4) हमेशा धनात्मक है इसलिए (p(x)=0) नहीं होगा। टिप: वर्ग में धनात्मक संख्या जुड़ने पर वास्तविक कटान नहीं मिलता।

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Question 5/15 Expert Mathematics Chapter 2: Polynomials Geometrical meaning of the zeroes of a polynomial. Class 10 Level 22

यदि (p(x)=5x-2-50x+125) है, तो ग्राफ (x)-अक्ष से कैसे मिलेगा?

If (p(x)=5x-2-50x+125), how will the graph meet the (x)-axis?

Explanation opens after your attempt
Correct Answer

A. (x=5) पर स्पर्श करेगाIt will touch at (x=5)

Step 1

Concept

(5x-2-50x+125=5(x-5)2), so it touches at (x=5). Tip: the outside (5) does not change the zero.

Step 2

Why this answer is correct

The correct answer is A. (x=5) पर स्पर्श करेगा / It will touch at (x=5). (5x-2-50x+125=5(x-5)2), so it touches at (x=5). Tip: the outside (5) does not change the zero.

Step 3

Exam Tip

(5x-2-50x+125=5(x-5)2) है, इसलिए (x=5) पर स्पर्श होगा। टिप: बाहरी (5) शून्यक नहीं बदलता।

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Question 6/15 Expert Mathematics Chapter 2: Polynomials Geometrical meaning of the zeroes of a polynomial. Class 10 Level 22

यदि (p(x)=x-2+6x+18) है, तो (p(x)=0) का ग्राफीय अर्थ क्या है?

If (p(x)=x-2+6x+18), what is the graphical meaning of (p(x)=0)?

Explanation opens after your attempt
Correct Answer

C. ग्राफ (x)-अक्ष को नहीं काटताThe graph does not cut the (x)-axis

Step 1

Concept

(x-2+6x+18=(x+3)2+9), so there is no real zero. Tip: an always positive form gives no intersection.

Step 2

Why this answer is correct

The correct answer is C. ग्राफ (x)-अक्ष को नहीं काटता / The graph does not cut the (x)-axis. (x-2+6x+18=(x+3)2+9), so there is no real zero. Tip: an always positive form gives no intersection.

Step 3

Exam Tip

(x-2+6x+18=(x+3)2+9) है, इसलिए वास्तविक शून्यक नहीं है। टिप: हमेशा धनात्मक रूप कटान नहीं देता।

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Question 7/15 Expert Mathematics Chapter 2: Polynomials Geometrical meaning of the zeroes of a polynomial. Class 10 Level 22

यदि (p(x)=x-2-10x+29) है, तो ग्राफ (x)-अक्ष को क्यों नहीं काटेगा?

If (p(x)=x-2-10x+29), why will the graph not cut the (x)-axis?

Explanation opens after your attempt
Correct Answer

A. क्योंकि यह ((x-5)2+4) हैBecause it is ((x-5)2+4)

Step 1

Concept

((x-5)2+4) is always positive, so (p(x)=0) will not occur. Tip: adding a positive number to a square gives no real intersection.

Step 2

Why this answer is correct

The correct answer is A. क्योंकि यह ((x-5)2+4) है / Because it is ((x-5)2+4). ((x-5)2+4) is always positive, so (p(x)=0) will not occur. Tip: adding a positive number to a square gives no real intersection.

Step 3

Exam Tip

((x-5)2+4) हमेशा धनात्मक है, इसलिए (p(x)=0) नहीं होगा। टिप: वर्ग में धनात्मक संख्या जुड़ने पर वास्तविक कटान नहीं मिलता।

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Question 8/15 Hard Mathematics Chapter 2: Polynomials Geometrical meaning of the zeroes of a polynomial. Class 10 Level 24

यदि (p(x)=4x-2-24x+36) है तो ग्राफ (x)-अक्ष से कैसे मिलेगा?

If (p(x)=4x-2-24x+36), how will the graph meet the (x)-axis?

Explanation opens after your attempt
Correct Answer

A. (x=3) पर स्पर्श करेगाIt will touch at (x=3)

Step 1

Concept

(4x-2-24x+36=4(x-3)2), so it touches at (x=3). Tip: the outside (4) does not change the zero.

Step 2

Why this answer is correct

The correct answer is A. (x=3) पर स्पर्श करेगा / It will touch at (x=3). (4x-2-24x+36=4(x-3)2), so it touches at (x=3). Tip: the outside (4) does not change the zero.

Step 3

Exam Tip

(4x-2-24x+36=4(x-3)2) है इसलिए (x=3) पर स्पर्श होगा। टिप: बाहरी (4) शून्यक नहीं बदलता।

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Question 9/15 Hard Mathematics Chapter 2: Polynomials Geometrical meaning of the zeroes of a polynomial. Class 10 Level 24

यदि (p(x)=x-2-2x+10) है तो (p(x)=0) का ग्राफीय अर्थ क्या है?

If (p(x)=x-2-2x+10), what is the graphical meaning of (p(x)=0)?

Explanation opens after your attempt
Correct Answer

C. ग्राफ (x)-अक्ष को नहीं काटताThe graph does not cut the (x)-axis

Step 1

Concept

(x-2-2x+10=(x-1)2+9), so there is no real zero. Tip: an always positive form gives no intersection.

Step 2

Why this answer is correct

The correct answer is C. ग्राफ (x)-अक्ष को नहीं काटता / The graph does not cut the (x)-axis. (x-2-2x+10=(x-1)2+9), so there is no real zero. Tip: an always positive form gives no intersection.

Step 3

Exam Tip

(x-2-2x+10=(x-1)2+9) है इसलिए वास्तविक शून्यक नहीं है। टिप: हमेशा धनात्मक रूप कटान नहीं देता।

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Question 10/15 Hard Mathematics Chapter 2: Polynomials Geometrical meaning of the zeroes of a polynomial. Class 10 Level 24

यदि (p(x)=x-2-8x+20) है तो ग्राफ (x)-अक्ष को क्यों नहीं काटेगा?

If (p(x)=x-2-8x+20), why will the graph not cut the (x)-axis?

Explanation opens after your attempt
Correct Answer

A. क्योंकि यह ((x-4)2+4) हैBecause it is ((x-4)2+4)

Step 1

Concept

((x-4)2+4) is always positive, so (p(x)=0) will not occur. Tip: adding a positive number to a square can prevent intersection.

Step 2

Why this answer is correct

The correct answer is A. क्योंकि यह ((x-4)2+4) है / Because it is ((x-4)2+4). ((x-4)2+4) is always positive, so (p(x)=0) will not occur. Tip: adding a positive number to a square can prevent intersection.

Step 3

Exam Tip

((x-4)2+4) हमेशा धनात्मक है इसलिए (p(x)=0) नहीं होगा। टिप: वर्ग में धनात्मक संख्या जुड़ने पर कटान रुक सकता है।

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Question 11/15 Hard Mathematics Chapter 2: Polynomials Geometrical meaning of the zeroes of a polynomial. Class 10 Level 23

यदि (p(x)=3x-2-18x+27) है, तो ग्राफ (x)-अक्ष से कैसे मिलेगा?

If (p(x)=3x-2-18x+27), how will the graph meet the (x)-axis?

Explanation opens after your attempt
Correct Answer

A. (x=3) पर स्पर्श करेगाIt will touch at (x=3)

Step 1

Concept

(3x-2-18x+27=3(x-3)2), so it touches at (x=3). Tip: the outside (3) does not change the zero.

Step 2

Why this answer is correct

The correct answer is A. (x=3) पर स्पर्श करेगा / It will touch at (x=3). (3x-2-18x+27=3(x-3)2), so it touches at (x=3). Tip: the outside (3) does not change the zero.

Step 3

Exam Tip

(3x-2-18x+27=3(x-3)2) है, इसलिए (x=3) पर स्पर्श होगा। टिप: बाहरी (3) शून्यक नहीं बदलता।

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Question 12/15 Hard Mathematics Chapter 2: Polynomials Geometrical meaning of the zeroes of a polynomial. Class 10 Level 23

यदि (p(x)=x-2+10x+29), तो (p(x)=0) का ग्राफीय अर्थ क्या है?

If (p(x)=x-2+10x+29), what is the graphical meaning of (p(x)=0)?

Explanation opens after your attempt
Correct Answer

C. ग्राफ (x)-अक्ष को नहीं काटताThe graph does not cut the (x)-axis

Step 1

Concept

(x-2+10x+29=(x+5)2+4), so there is no real zero. Tip: an always positive form gives no intersection.

Step 2

Why this answer is correct

The correct answer is C. ग्राफ (x)-अक्ष को नहीं काटता / The graph does not cut the (x)-axis. (x-2+10x+29=(x+5)2+4), so there is no real zero. Tip: an always positive form gives no intersection.

Step 3

Exam Tip

(x-2+10x+29=(x+5)2+4) है, इसलिए वास्तविक शून्यक नहीं है। टिप: हमेशा धनात्मक रूप कटान नहीं देता।

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Question 13/15 Hard Mathematics Chapter 2: Polynomials Geometrical meaning of the zeroes of a polynomial. Class 10 Level 23

यदि (p(x)=x-2+4x+8) है, तो ग्राफ (x)-अक्ष को क्यों नहीं काटेगा?

If (p(x)=x-2+4x+8), why will the graph not cut the (x)-axis?

Explanation opens after your attempt
Correct Answer

A. क्योंकि यह ((x+2)2+4) हैBecause it is ((x+2)2+4)

Step 1

Concept

((x+2)2+4) is always positive, so (p(x)=0) will not occur. Tip: adding a positive number to a square can prevent intersection.

Step 2

Why this answer is correct

The correct answer is A. क्योंकि यह ((x+2)2+4) है / Because it is ((x+2)2+4). ((x+2)2+4) is always positive, so (p(x)=0) will not occur. Tip: adding a positive number to a square can prevent intersection.

Step 3

Exam Tip

((x+2)2+4) हमेशा धनात्मक है, इसलिए (p(x)=0) नहीं होगा। टिप: वर्ग में धनात्मक संख्या जुड़ने पर कटान रुक सकता है।

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Question 14/15 Hard Mathematics Chapter 2: Polynomials Geometrical meaning of the zeroes of a polynomial. Class 10 Level 22

यदि (p(x)=2x-2+12x+18) है, तो ग्राफ (x)-अक्ष से कैसे मिलेगा?

If (p(x)=2x-2+12x+18), how will the graph meet the (x)-axis?

Explanation opens after your attempt
Correct Answer

A. (x=-3) पर स्पर्श करेगाIt will touch at (x=-3)

Step 1

Concept

(2x-2+12x+18=2(x+3)2), so it touches at (x=-3). Tip: the outside (2) does not change the zero.

Step 2

Why this answer is correct

The correct answer is A. (x=-3) पर स्पर्श करेगा / It will touch at (x=-3). (2x-2+12x+18=2(x+3)2), so it touches at (x=-3). Tip: the outside (2) does not change the zero.

Step 3

Exam Tip

(2x-2+12x+18=2(x+3)2), इसलिए (x=-3) पर स्पर्श होगा। टिप: बाहरी (2) शून्यक नहीं बदलता।

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Question 15/15 Hard Mathematics Chapter 2: Polynomials Geometrical meaning of the zeroes of a polynomial. Class 10 Level 22

यदि (p(x)=x-2-6x+13) है, तो ग्राफ (x)-अक्ष को क्यों नहीं काटेगा?

If (p(x)=x-2-6x+13), why will the graph not cut the (x)-axis?

Explanation opens after your attempt
Correct Answer

A. क्योंकि यह ((x-3)2+4) हैBecause it is ((x-3)2+4)

Step 1

Concept

((x-3)2+4) is always positive, so (p(x)=0) will not occur. Tip: a positive number added to a square can prevent intersection.

Step 2

Why this answer is correct

The correct answer is A. क्योंकि यह ((x-3)2+4) है / Because it is ((x-3)2+4). ((x-3)2+4) is always positive, so (p(x)=0) will not occur. Tip: a positive number added to a square can prevent intersection.

Step 3

Exam Tip

((x-3)2+4) हमेशा धनात्मक है, इसलिए (p(x)=0) नहीं होगा। टिप: पूर्ण वर्ग में जोड़ी गई धनात्मक संख्या कटान रोक सकती है।

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