यदि (p(x)=x-2 -2x+5), तो (p(1)) का मान क्या है और क्या (1) शून्यक है?
If (p(x)=x-2 -2x+5), what is (p(1)), and is (1) a zero?
#polynomials
#evaluation
#zero_check
#hard
A (4), नहीं / (4), no
B (0), हां / (0), yes
C (2), नहीं / (2), no
D (5), नहीं / (5), no
Explanation opens after your attempt
Correct Answer
A. (4), नहीं / (4), no
Step 1
Concept
(p(1)=1-2+5=4), so (1) is not a zero. A zero must make the value (0).
Step 2
Why this answer is correct
The correct answer is A. (4), नहीं / (4), no. (p(1)=1-2+5=4), so (1) is not a zero. A zero must make the value (0).
Step 3
Exam Tip
(p(1)=1-2+5=4) है इसलिए (1) शून्यक नहीं है। शून्यक तभी होगा जब मान (0) हो।
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\(x^4-1\) के रैखिक गुणनखंडों में से कौन सा गलत है?
Which one is not a linear factor of \(x^4-1\)?
#polynomials
#factors
#degree
#hard
A (x-1)
B (x+1)
C \(x^2+1\)
D (x-i)
Explanation opens after your attempt
Correct Answer
C. \(x^2+1\)
Step 1
Concept
\(x^2+1\) is not linear because its degree is (2). Over real numbers, it is not a linear factor.
Step 2
Why this answer is correct
The correct answer is C. \(x^2+1\). \(x^2+1\) is not linear because its degree is (2). Over real numbers, it is not a linear factor.
Step 3
Exam Tip
\(x^2+1\) रैखिक नहीं है क्योंकि उसकी घात (2) है। वास्तविक संख्याओं में इसे रैखिक गुणनखंड नहीं माना जाता।
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यदि (p(x)) को (x-4) से भाग देने पर शेषफल (7) है, तो (p(4)) क्या होगा?
If the remainder when (p(x)) is divided by (x-4) is (7), what is (p(4))?
#polynomials
#remainder_theorem
#concept
#hard
A (4)
B (7)
C (-7)
D (0)
Explanation opens after your attempt
Step 1
Concept
By the remainder theorem, the remainder on division by (x-4) is (p(4)). Therefore, (p(4)=7).
Step 2
Why this answer is correct
The correct answer is B. (7). By the remainder theorem, the remainder on division by (x-4) is (p(4)). Therefore, (p(4)=7).
Step 3
Exam Tip
शेषफल प्रमेय के अनुसार (x-4) से भाग देने पर शेषफल (p(4)) होता है। इसलिए (p(4)=7)।
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\(3x^3-2x^2+x+7\) को (x+2) से भाग देने पर शेषफल क्या है?
What is the remainder when \(3x^3-2x^2+x+7\) is divided by (x+2)?
#polynomials
#remainder
#substitution
#hard
A (-27)
B (-25)
C (25)
D (27)
Explanation opens after your attempt
Step 1
Concept
The remainder is (p(-2)). (3(-8)-2(4)-2+7=-27).
Step 2
Why this answer is correct
The correct answer is A. (-27). The remainder is (p(-2)). (3(-8)-2(4)-2+7=-27).
Step 3
Exam Tip
शेषफल (p(-2)) होगा। (3(-8)-2(4)-2+7=-27) है।
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\(x^3-5x^2+8x-4\) को (x-1) से भाग देने पर शेषफल क्या होगा?
What is the remainder when \(x^3-5x^2+8x-4\) is divided by (x-1)?
#polynomials
#remainder_theorem
#hard
A (0)
B (1)
C (-1)
D (4)
Explanation opens after your attempt
Step 1
Concept
By the remainder theorem, the remainder is (p(1)). We get (1-5+8-4=0).
Step 2
Why this answer is correct
The correct answer is A. (0). By the remainder theorem, the remainder is (p(1)). We get (1-5+8-4=0).
Step 3
Exam Tip
शेषफल प्रमेय से शेषफल (p(1)) है। (1-5+8-4=0) मिलता है।
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यदि (x+1) बहुपद \(2x^3+kx^2-5x+2\) का गुणनखंड है, तो (k) का सही मान क्या है?
If (x+1) is a factor of \(2x^3+kx^2-5x+2\), what is the correct value of (k)?
#polynomials
#factor_theorem
#parameter
#hard
A (-5)
B (5)
C (-1)
D (1)
Explanation opens after your attempt
Step 1
Concept
Putting (p(-1)=0) gives (-2+k+5+2=0). Therefore, (k=-5) is correct.
Step 2
Why this answer is correct
The correct answer is A. (-5). Putting (p(-1)=0) gives (-2+k+5+2=0). Therefore, (k=-5) is correct.
Step 3
Exam Tip
(p(-1)=0) रखने पर (-2+k+5+2=0) मिलता है। इसलिए (k=-5) सही है।
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यदि (x+1) बहुपद \(2x^3+kx^2-5x+2\) का गुणनखंड है, तो (k) का मान क्या है?
If (x+1) is a factor of \(2x^3+kx^2-5x+2\), what is (k)?
#polynomials
#factor_theorem
#parameter
#hard
A (5)
B (-5)
C (1)
D (-1)
Explanation opens after your attempt
Step 1
Concept
If (x+1) is a factor, then (p(-1)=0). From (-2+k+5+2=0), we get (k=-5).
Step 2
Why this answer is correct
The correct answer is A. (5). If (x+1) is a factor, then (p(-1)=0). From (-2+k+5+2=0), we get (k=-5).
Step 3
Exam Tip
(x+1) गुणनखंड होने पर (p(-1)=0) होगा। (-2+k+5+2=0) से (k=-5) नहीं बल्कि (k=-5) मिलता है।
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यदि (p(x)=x-3 -3x-2 -4x+12) है, तो कौन सा (p(x)) का गुणनखंड है?
If (p(x)=x-3 -3x-2 -4x+12), which is a factor of (p(x))?
#polynomials
#factor_theorem
#hard
A (x-2)
B (x+2)
C (x-3)
D (x+3)
Explanation opens after your attempt
Step 1
Concept
Since (p(2)=8-12-8+12=0), (x-2) is a factor. Use the factor theorem.
Step 2
Why this answer is correct
The correct answer is A. (x-2). Since (p(2)=8-12-8+12=0), (x-2) is a factor. Use the factor theorem.
Step 3
Exam Tip
(p(2)=8-12-8+12=0) है इसलिए (x-2) गुणनखंड है। गुणनखंड प्रमेय का प्रयोग करें।
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बहुपद \(x^3-6x^2+11x-6\) के शून्यक कौन से हैं?
What are the zeroes of \(x^3-6x^2+11x-6\)?
#polynomials
#cubic_zeroes
#hard
A (1,2,3)
B (-1,-2,-3)
C (1,1,6)
D (2,2,2)
Explanation opens after your attempt
Correct Answer
A. (1,2,3)
Step 1
Concept
It equals ((x-1)(x-2)(x-3)). Therefore, the zeroes are (1), (2), and (3).
Step 2
Why this answer is correct
The correct answer is A. (1,2,3). It equals ((x-1)(x-2)(x-3)). Therefore, the zeroes are (1), (2), and (3).
Step 3
Exam Tip
यह ((x-1)(x-2)(x-3)) के बराबर है। अतः शून्यक (1), (2) और (3) हैं।
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यदि (x-a), (x-b) और (x-c) किसी घन बहुपद के गुणनखंड हैं, तो उसका एक संभावित बहुपद कौन सा है?
If (x-a), (x-b), and (x-c) are factors of a cubic polynomial, which is a possible polynomial?
#polynomials
#cubic
#factors
#hard
A (x-3 -(a+b+c)x-2 +(ab+bc+ca)x-abc)
B (x-3 +(a+b+c)x-2 +(ab+bc+ca)x+abc)
C (x-3 -(ab+bc+ca)x-2 +(a+b+c)x-abc)
D (x-3 +abcx-2 -(a+b+c)x+ab+bc+ca)
Explanation opens after your attempt
Correct Answer
A. (x-3 -(a+b+c)x-2 +(ab+bc+ca)x-abc)
Step 1
Concept
Expanding ((x-a)(x-b)(x-c)) gives the first form. Remember the link between zeroes and factors.
Step 2
Why this answer is correct
The correct answer is A. (x-3 -(a+b+c)x-2 +(ab+bc+ca)x-abc). Expanding ((x-a)(x-b)(x-c)) gives the first form. Remember the link between zeroes and factors.
Step 3
Exam Tip
((x-a)(x-b)(x-c)) फैलाने पर पहला रूप मिलता है। शून्यकों और गुणनखंडों का संबंध याद रखें।
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बहुपद \(x^2-6x+9\) के शून्यकों के बारे में सही कथन कौन सा है?
Which statement about the zeroes of \(x^2-6x+9\) is correct?
#polynomials
#equal_zeroes
#factorisation
#hard
A दोनों शून्यक अलग हैं / Both zeroes are distinct
B दोनों शून्यक बराबर हैं / Both zeroes are equal
C कोई वास्तविक शून्यक नहीं है / There is no real zero
D शून्यकों का गुणनफल (6) है / Product of zeroes is (6)
Explanation opens after your attempt
Correct Answer
B. दोनों शून्यक बराबर हैं / Both zeroes are equal
Step 1
Concept
(x-2 -6x+9=(x-3)2 ), so both zeroes are (3). Recognizing square form is a fast exam method.
Step 2
Why this answer is correct
The correct answer is B. दोनों शून्यक बराबर हैं / Both zeroes are equal. (x-2 -6x+9=(x-3)2 ), so both zeroes are (3). Recognizing square form is a fast exam method.
Step 3
Exam Tip
(x-2 -6x+9=(x-3)2 ) है इसलिए दोनों शून्यक (3) हैं। वर्ग रूप को पहचानना परीक्षा में तेज तरीका है।
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यदि (p(x)=3x-2 -10x+m) के शून्यकों का गुणनफल \(\frac{4}{3}\) है, तो (m) का मान क्या है?
If the product of zeroes of (p(x)=3x-2 -10x+m) is \(\frac{4}{3}\), what is (m)?
#polynomials
#product_zeroes
#hard
A (4)
B (3)
C \(\frac{4}{9}\)
D (12)
Explanation opens after your attempt
Step 1
Concept
The product is \(\frac{m}{3}\). From \(\frac{m}{3}=\frac{4}{3}\), we get (m=4).
Step 2
Why this answer is correct
The correct answer is A. (4). The product is \(\frac{m}{3}\). From \(\frac{m}{3}=\frac{4}{3}\), we get (m=4).
Step 3
Exam Tip
गुणनफल \(\frac{m}{3}\) है। \(\frac{m}{3}=\frac{4}{3}\) से (m=4) मिलता है।
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यदि (p(x)=2x-2 +kx+8) के शून्यकों का योग (3) है, तो (k) क्या होगा?
If the sum of zeroes of (p(x)=2x-2 +kx+8) is (3), what is (k)?
#polynomials
#sum_zeroes
#hard
A (6)
B (-6)
C (3)
D (-3)
Explanation opens after your attempt
Step 1
Concept
The sum is \(-\frac{k}{2}\), and it equals (3). Hence (k=-6).
Step 2
Why this answer is correct
The correct answer is B. (-6). The sum is \(-\frac{k}{2}\), and it equals (3). Hence (k=-6).
Step 3
Exam Tip
योग \(-\frac{k}{2}\) होता है और यह (3) है। इसलिए (k=-6) है।
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यदि (p(x)=x-2 -5x+6) है, तो (p(3)-p(2)) का मान क्या है?
If (p(x)=x-2 -5x+6), what is the value of (p(3)-p(2))?
#polynomials
#evaluation
#zeroes
#hard
A (0)
B (1)
C (-1)
D (6)
Explanation opens after your attempt
Step 1
Concept
Both (2) and (3) are zeroes, so (p(3)=0) and (p(2)=0). Therefore, the difference is (0).
Step 2
Why this answer is correct
The correct answer is A. (0). Both (2) and (3) are zeroes, so (p(3)=0) and (p(2)=0). Therefore, the difference is (0).
Step 3
Exam Tip
(2) और (3) दोनों शून्यक हैं, इसलिए (p(3)=0) और (p(2)=0)। अतः अंतर (0) है।
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किस बहुपद की घात (4) है?
Which polynomial has degree (4)?
#polynomials
#degree
#zero_coefficient
#hard
A \(7x^4+0x^5-3x+1\)
B \(0x^6+5x^3-2\)
C \(x^2+x+1\)
D (9)
Explanation opens after your attempt
Correct Answer
A. \(7x^4+0x^5-3x+1\)
Step 1
Concept
The term \(0x^5\) does not affect degree because its coefficient is (0). The highest non-zero power is (4).
Step 2
Why this answer is correct
The correct answer is A. \(7x^4+0x^5-3x+1\). The term \(0x^5\) does not affect degree because its coefficient is (0). The highest non-zero power is (4).
Step 3
Exam Tip
\(0x^5\) पद घात नहीं बढ़ाता क्योंकि उसका गुणांक (0) है। सबसे बड़ा शून्येतर घात (4) है।
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यदि \(x^2+ax+b\) के शून्यक (4) और (-7) हैं, तो (a-b) क्या होगा?
If the zeroes of \(x^2+ax+b\) are (4) and (-7), what is (a-b)?
#polynomials
#zeroes
#coefficient_relation
#hard
A (25)
B (31)
C (-25)
D (-31)
Explanation opens after your attempt
Step 1
Concept
The sum is (-3), so (a=3), and the product is (-28), so (b=-28). Hence (a-b=31).
Step 2
Why this answer is correct
The correct answer is B. (31). The sum is (-3), so (a=3), and the product is (-28), so (b=-28). Hence (a-b=31).
Step 3
Exam Tip
योग (-3) है इसलिए (a=3) और गुणनफल (-28) है इसलिए (b=-28)। अतः (a-b=31) है।
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द्विघात बहुपद जिसके शून्यक \(\frac{2}{3}\) और \(-\frac{5}{4}\) हैं, कौन सा हो सकता है?
Which can be a quadratic polynomial whose zeroes are \(\frac{2}{3}\) and \(-\frac{5}{4}\)?
#polynomials
#formation
#zeroes
#hard
A \(12x^2+7x-10\)
B \(12x^2-7x-10\)
C \(12x^2+7x+10\)
D \(12x^2-7x+10\)
Explanation opens after your attempt
Correct Answer
A. \(12x^2+7x-10\)
Step 1
Concept
The sum is \(-\frac{7}{12}\) and the product is \(-\frac{5}{6}\). So \(12x^2+7x-10\) is correct.
Step 2
Why this answer is correct
The correct answer is A. \(12x^2+7x-10\). The sum is \(-\frac{7}{12}\) and the product is \(-\frac{5}{6}\). So \(12x^2+7x-10\) is correct.
Step 3
Exam Tip
शून्यकों का योग \(-\frac{7}{12}\) और गुणनफल \(-\frac{5}{6}\) है। इसलिए \(12x^2+7x-10\) सही है।
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यदि (p(x)=x-3 +px-2 +qx-6) के शून्यक (1), (2) और (3) हैं, तो (p+q) का सही मान क्या है?
If the zeroes of (p(x)=x-3 +px-2 +qx-6) are (1), (2), and (3), what is the correct value of (p+q)?
#polynomials
#cubic
#coefficient_matching
#hard
A (5)
B (-5)
C (17)
D (-17)
Explanation opens after your attempt
Step 1
Concept
From ((x-1)(x-2)(x-3)=x-3 -6x-2 +11x-6), (p=-6) and (q=11). Hence (p+q=5).
Step 2
Why this answer is correct
The correct answer is A. (5). From ((x-1)(x-2)(x-3)=x-3 -6x-2 +11x-6), (p=-6) and (q=11). Hence (p+q=5).
Step 3
Exam Tip
((x-1)(x-2)(x-3)=x-3 -6x-2 +11x-6) से (p=-6) और (q=11)। अतः (p+q=5) है।
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यदि (p(x)=x-3 +px-2 +qx-6) के शून्यक (1), (2) और (3) हैं, तो (p+q) का मान क्या है?
If the zeroes of (p(x)=x-3 +px-2 +qx-6) are (1), (2), and (3), what is (p+q)?
#polynomials
#cubic
#coefficients
#hard
A (-5)
B (5)
C (11)
D (0)
Explanation opens after your attempt
Step 1
Concept
The polynomial is ((x-1)(x-2)(x-3)=x-3 -6x-2 +11x-6). Hence (p=-6), (q=11), so (p+q=5).
Step 2
Why this answer is correct
The correct answer is A. (-5). The polynomial is ((x-1)(x-2)(x-3)=x-3 -6x-2 +11x-6). Hence (p=-6), (q=11), so (p+q=5).
Step 3
Exam Tip
बहुपद ((x-1)(x-2)(x-3)=x-3 -6x-2 +11x-6) है। इसलिए (p=-6), (q=11) और (p+q=5) नहीं बल्कि (5) है।
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बहुपद \(x^3-4x^2+x+6\) में (x=2) रखने पर क्या निष्कर्ष निकलेगा?
What conclusion follows when (x=2) is substituted in \(x^3-4x^2+x+6\)?
#polynomials
#zero
#substitution
#hard
A (2) शून्यक है / (2) is a zero
B (2) शून्यक नहीं है / (2) is not a zero
C बहुपद रैखिक है / The polynomial is linear
D बहुपद स्थिर है / The polynomial is constant
Explanation opens after your attempt
Correct Answer
A. (2) शून्यक है / (2) is a zero
Step 1
Concept
(p(2)=8-16+2+6=0), so (2) is a zero. Direct substitution is the quickest check.
Step 2
Why this answer is correct
The correct answer is A. (2) शून्यक है / (2) is a zero. (p(2)=8-16+2+6=0), so (2) is a zero. Direct substitution is the quickest check.
Step 3
Exam Tip
(p(2)=8-16+2+6=0) है इसलिए (2) शून्यक है। सीधे प्रतिस्थापन से जल्दी जांच होती है।
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यदि \(x^2-9x+k\) के शून्यक बराबर हैं, तो (k) का मान क्या है?
If the zeroes of \(x^2-9x+k\) are equal, what is the value of (k)?
#polynomials
#equal_zeroes
#discriminant
#hard
A (18)
B (81)
C \(\frac{81}{4}\)
D \(\frac{9}{4}\)
Explanation opens after your attempt
Correct Answer
C. \(\frac{81}{4}\)
Step 1
Concept
For equal zeroes, the discriminant \(b^2-4ac=0\). Thus (81-4k=0), giving \(k=\frac{81}{4}\).
Step 2
Why this answer is correct
The correct answer is C. \(\frac{81}{4}\). For equal zeroes, the discriminant \(b^2-4ac=0\). Thus (81-4k=0), giving \(k=\frac{81}{4}\).
Step 3
Exam Tip
बराबर शून्यकों के लिए विविक्तकर \(b^2-4ac=0\) होता है। इसलिए (81-4k=0) से \(k=\frac{81}{4}\) मिलता है।
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द्विघात बहुपद \(2x^2-7x+3\) के शून्यकों का गुणनफल क्या है?
What is the product of the zeroes of the quadratic polynomial \(2x^2-7x+3\)?
#polynomials
#zeroes
#product
#hard
A (3)
B \(\frac{3}{2}\)
C \(-\frac{7}{2}\)
D (2)
Explanation opens after your attempt
Correct Answer
B. \(\frac{3}{2}\)
Step 1
Concept
For \(ax^2+bx+c\), the product is \(\frac{c}{a}\). Here, \(\frac{3}{2}\) is correct.
Step 2
Why this answer is correct
The correct answer is B. \(\frac{3}{2}\). For \(ax^2+bx+c\), the product is \(\frac{c}{a}\). Here, \(\frac{3}{2}\) is correct.
Step 3
Exam Tip
द्विघात \(ax^2+bx+c\) में गुणनफल \(\frac{c}{a}\) होता है। यहां \(\frac{3}{2}\) सही है।
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यदि (p(x)=x-2 -(m+3)x+12) के शून्यक (3) और (4) हैं, तो (m) का मान क्या है?
If the zeroes of (p(x)=x-2 -(m+3)x+12) are (3) and (4), what is (m)?
#polynomials
#zeroes
#sum
#hard
A (3)
B (4)
C (5)
D (7)
Explanation opens after your attempt
Step 1
Concept
The sum of zeroes is (7), which equals (m+3). Therefore, (m=4).
Step 2
Why this answer is correct
The correct answer is B. (4). The sum of zeroes is (7), which equals (m+3). Therefore, (m=4).
Step 3
Exam Tip
शून्यकों का योग (7) है और यह (m+3) के बराबर है। इसलिए (m=4) मिलेगा।
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यदि (p(x)=kx-2 -5x+6) का एक शून्यक (2) है, तो (k) का मान क्या होगा?
If (2) is a zero of (p(x)=kx-2 -5x+6), what is the value of (k)?
#polynomials
#zero
#value
#hard
A (1)
B (2)
C (-1)
D (-2)
Explanation opens after your attempt
Step 1
Concept
Putting (p(2)=0) gives (4k-10+6=0), so (k=1). For a zero, use (p\(\alpha\)=0).
Step 2
Why this answer is correct
The correct answer is A. (1). Putting (p(2)=0) gives (4k-10+6=0), so (k=1). For a zero, use (p\(\alpha\)=0).
Step 3
Exam Tip
(p(2)=0) रखने पर (4k-10+6=0) से (k=1) मिलता है। शून्यक के लिए (p\(\alpha\)=0) लगाएं।
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बहुपद (p(x)=ax-3 +bx-2 +cx+d) में \(a\ne0\) है। यदि (p(x)) को रैखिक बहुपद कहा जाए, तो यह कथन क्यों गलत है?
In the polynomial (p(x)=ax-3 +bx-2 +cx+d), \(a\ne0\). Why is it wrong to call (p(x)) a linear polynomial?
#polynomials
#degree
#cubic
#hard
A क्योंकि घात (1) है / Because degree is (1)
B क्योंकि घात (2) है / Because degree is (2)
C क्योंकि घात (3) है / Because degree is (3)
D क्योंकि स्थिर पद (d) है / Because constant term is (d)
Explanation opens after your attempt
Correct Answer
C. क्योंकि घात (3) है / Because degree is (3)
Step 1
Concept
The highest power is (3), so the polynomial is cubic. In exams, always check the highest non-zero exponent.
Step 2
Why this answer is correct
The correct answer is C. क्योंकि घात (3) है / Because degree is (3). The highest power is (3), so the polynomial is cubic. In exams, always check the highest non-zero exponent.
Step 3
Exam Tip
सबसे बड़ी घात (3) है इसलिए बहुपद घन है। परीक्षा में हमेशा सबसे बड़े शून्येतर घातांक को देखें।
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\(5x^2-6x+2\) और \(2x^2+9x-1\) में (x) के गुणांकों का योग क्या है?
What is the sum of the coefficients of (x) in \(5x^2-6x+2\) and \(2x^2+9x-1\)?
#coefficients
#like terms
#polynomials
A (1)
B (2)
C (3)
D (4)
Explanation opens after your attempt
Step 1
Concept
The coefficient of (x) is (-6) in the first polynomial and (9) in the second, so the sum is (3). Add coefficients of like powers only.
Step 2
Why this answer is correct
The correct answer is C. (3). The coefficient of (x) is (-6) in the first polynomial and (9) in the second, so the sum is (3). Add coefficients of like powers only.
Step 3
Exam Tip
पहले बहुपद में (x) का गुणांक (-6) और दूसरे में (9) है, योग (3) है। समान घात के गुणांक ही जोड़ें।
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(p(x)=6x-2 -x+3) से (r(x)=2x-2 +5x-8) घटाने पर क्या मिलेगा?
What is obtained when (r(x)=2x-2 +5x-8) is subtracted from (p(x)=6x-2 -x+3)?
#subtraction
#like terms
#polynomials
A \(4x^2-6x+11\)
B \(8x^2+4x-5\)
C \(4x^2+6x+11\)
D \(8x^2-6x-11\)
Explanation opens after your attempt
Correct Answer
A. \(4x^2-6x+11\)
Step 1
Concept
(p(x)-r(x)=6x-2 -x+3-\(2x^2+5x-8\)=4x-2 -6x+11). Change all signs inside the bracket while subtracting.
Step 2
Why this answer is correct
The correct answer is A. \(4x^2-6x+11\). (p(x)-r(x)=6x-2 -x+3-\(2x^2+5x-8\)=4x-2 -6x+11). Change all signs inside the bracket while subtracting.
Step 3
Exam Tip
(p(x)-r(x)=6x-2 -x+3-\(2x^2+5x-8\)=4x-2 -6x+11)। घटाते समय कोष्ठक के सभी संकेत बदलें।
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(p(x)=4x-2 -9x+2) और (q(x)=3x-2 +x-7) का योग क्या है?
What is the sum of (p(x)=4x-2 -9x+2) and (q(x)=3x-2 +x-7)?
#addition
#like terms
#polynomials
A \(7x^2-8x-5\)
B \(x^2-10x+9\)
C \(7x^2+8x-5\)
D \(12x^4-9x-14\)
Explanation opens after your attempt
Correct Answer
A. \(7x^2-8x-5\)
Step 1
Concept
Adding like terms gives \(7x^2-8x-5\). Add only like terms.
Step 2
Why this answer is correct
The correct answer is A. \(7x^2-8x-5\). Adding like terms gives \(7x^2-8x-5\). Add only like terms.
Step 3
Exam Tip
समान घात वाले पद जोड़ने पर \(7x^2-8x-5\) मिलता है। केवल समान पदों को ही जोड़ें।
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यदि (p(x)=ax-2 +3x+5) की घात (1) है, तो (a) का मान क्या होगा?
If (p(x)=ax-2 +3x+5) has degree (1), what will be the value of (a)?
#polynomials
#degree
#parameter
A (0)
B (1)
C (3)
D (5)
Explanation opens after your attempt
Step 1
Concept
For degree (1), the coefficient of \(x^2\) must be (0). Therefore (a=0).
Step 2
Why this answer is correct
The correct answer is A. (0). For degree (1), the coefficient of \(x^2\) must be (0). Therefore (a=0).
Step 3
Exam Tip
घात (1) होने के लिए \(x^2\) का गुणांक (0) होना चाहिए। इसलिए (a=0) है।
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बहुपद (p(x)=2x-2 +3) में (p(0)) का मान क्या है?
For the polynomial (p(x)=2x-2 +3), what is the value of (p(0))?
#polynomials
#substitution
#constant-term
A (0)
B (2)
C (3)
D (5)
Explanation opens after your attempt
Step 1
Concept
(p(0)=2(0)2 +3=3). When (x=0), the constant term remains.
Step 2
Why this answer is correct
The correct answer is C. (3). (p(0)=2(0)2 +3=3). When (x=0), the constant term remains.
Step 3
Exam Tip
(p(0)=2(0)2 +3=3) है। (x=0) रखने पर नियत पद बचता है।
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