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cubic_zeroes MCQ Questions for Class 10

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4 questions tagged with cubic_zeroes.

Question 1/4 Expert Mathematics Polynomials Polynomials in one variable Class 10 Level 48

यदि (p(x)=x-3+px-2+qx+15) के शून्यक (-1,3,-5) हैं, तो (p+q) क्या है?

If the zeroes of (p(x)=x-3+px-2+qx+15) are (-1,3,-5), what is (p+q)?

Explanation opens after your attempt
Correct Answer

B. (2)

Step 1

Concept

The sum of zeroes is (-3), so (p=3). The pairwise product sum is (-3+5-15=-13), so (q=-13) and (p+q=-10).

Step 2

Why this answer is correct

The correct answer is B. (2). The sum of zeroes is (-3), so (p=3). The pairwise product sum is (-3+5-15=-13), so (q=-13) and (p+q=-10).

Step 3

Exam Tip

शून्यकों का योग (-3) है, इसलिए (p=3)। युग्म गुणनफलों का योग (-3+5-15=-13), इसलिए (q=-13) और (p+q=-10)।

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Question 2/4 Expert Mathematics Polynomials Polynomials in one variable Class 10 Level 48

यदि (p(x)=x-3+ax-2+bx-12) के शून्यक (1,3,-4) हैं, तो (a+b) क्या है?

If the zeroes of (p(x)=x-3+ax-2+bx-12) are (1,3,-4), what is (a+b)?

Explanation opens after your attempt
Correct Answer

A. -(9)

Step 1

Concept

The sum (1+3-4=0), so (a=0). The sum of pairwise products is (3-4-12=-13), so (b=-13) and (a+b=-13).

Step 2

Why this answer is correct

The correct answer is A. -(9). The sum (1+3-4=0), so (a=0). The sum of pairwise products is (3-4-12=-13), so (b=-13) and (a+b=-13).

Step 3

Exam Tip

योग (1+3-4=0) है, इसलिए (a=0)। युग्म गुणनफलों का योग (3-4-12=-13), इसलिए (b=-13) और (a+b=-13)।

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Question 3/4 Hard Mathematics Polynomials Polynomials in one variable Class 10 Level 46

यदि (p(x)=x-3+ax-2+bx+8) के शून्यक (-1), (-2) और (-4) हैं, तो (a+b) क्या है?

If the zeroes of (p(x)=x-3+ax-2+bx+8) are (-1), (-2), and (-4), what is (a+b)?

Explanation opens after your attempt
Correct Answer

A. (21)

Step 1

Concept

The polynomial is ((x+1)(x+2)(x+4)=x-3+7x-2+14x+8). Hence (a+b=21).

Step 2

Why this answer is correct

The correct answer is A. (21). The polynomial is ((x+1)(x+2)(x+4)=x-3+7x-2+14x+8). Hence (a+b=21).

Step 3

Exam Tip

बहुपद ((x+1)(x+2)(x+4)=x-3+7x-2+14x+8) है। इसलिए (a+b=21)।

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Question 4/4 Hard Mathematics Polynomials Polynomials in one variable Class 10 Level 46

बहुपद \(x^3-6x^2+11x-6\) के शून्यक कौन से हैं?

What are the zeroes of \(x^3-6x^2+11x-6\)?

Explanation opens after your attempt
Correct Answer

A. (1,2,3)

Step 1

Concept

It equals ((x-1)(x-2)(x-3)). Therefore, the zeroes are (1), (2), and (3).

Step 2

Why this answer is correct

The correct answer is A. (1,2,3). It equals ((x-1)(x-2)(x-3)). Therefore, the zeroes are (1), (2), and (3).

Step 3

Exam Tip

यह ((x-1)(x-2)(x-3)) के बराबर है। अतः शून्यक (1), (2) और (3) हैं।

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