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If the zeroes of the polynomial \(x^2+ax+b\) are \(4\) and \(-7\), what is the value of \(a-b\)?यदि बहुपद \(x^2+ax+b\) के शून्यक \(4\) और \(-7\) हैं, तो \(a-b\) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(31\)\(31\)
For \(x^2+ax+b\), the sum of the zeroes is \(-a\) and their product is \(b\). Thus, \(4+(-7)=-3=-a\), so \(a=3\); and \(b=4(-7)=-28\). Therefore, \(a-b=3-(-28)=31\), which is option B.\(x^2+ax+b\) में शून्यकों का योग \(-a\) और उनका गुणनफल \(b\) होता है। इसलिए \(4+(-7)=-3=-a\), अतः \(a=3\); और \(b=4(-7)=-28\)। इस प्रकार \(a-b=3-(-28)=31\), यानी विकल्प B।
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