यदि (2x+ay=16) और (x+y=7) का ग्राफीय हल (\left\(2,5\right\)) है, तो (a) कितना होगा?
If the graphical solution of (2x+ay=16) and (x+y=7) is (\left\(2,5\right\)), what is (a)?
#parameter
#intersection point
#substitution
A (2)
B \(\frac{12}{5}\)
C (3)
D \(\frac{16}{5}\)
Explanation opens after your attempt
Correct Answer
B. \(\frac{12}{5}\)
Step 1
Concept
Putting (\left\(2,5\right\)) in (2x+ay=16) gives (4+5a=16). Thus \(a=\frac{12}{5}\).
Step 2
Why this answer is correct
The correct answer is B. \(\frac{12}{5}\). Putting (\left\(2,5\right\)) in (2x+ay=16) gives (4+5a=16). Thus \(a=\frac{12}{5}\).
Step 3
Exam Tip
(2x+ay=16) में (\left\(2,5\right\)) रखने पर (4+5a=16)। इससे \(a=\frac{12}{5}\) मिलता है।
Login to save your score, XP, coins and progress. Login
यदि दो रेखाएँ (x+y=8) और (kx+2y=14) बिंदु (\left\(2,6\right\)) से गुजरती हैं, तो (k) का मान क्या है?
If the two lines (x+y=8) and (kx+2y=14) pass through (\left\(2,6\right\)), what is the value of (k)?
#parameter
#point on line
#graphical solution
A (1)
B (2)
C (3)
D (4)
Explanation opens after your attempt
Step 1
Concept
Putting (\left\(2,6\right\)) in (kx+2y=14) gives (2k+12=14). Hence (k=1).
Step 2
Why this answer is correct
The correct answer is A. (1). Putting (\left\(2,6\right\)) in (kx+2y=14) gives (2k+12=14). Hence (k=1).
Step 3
Exam Tip
(kx+2y=14) में (\left\(2,6\right\)) रखने पर (2k+12=14)। इसलिए (k=1)।
Login to save your score, XP, coins and progress. Login
यदि \( \frac{a}{100} \) संख्या रेखा पर \( \sqrt{3} \) और (1.74) के बीच है, तो (a) का कौन सा मान संभव है?
If \( \frac{a}{100} \) lies between \( \sqrt{3} \) and (1.74) on the number line, which value of (a) is possible?
#number-line
#parameter
#between-values
A (172)
B (173)
C (174)
D (171)
Explanation opens after your attempt
Step 1
Concept
\( \sqrt{3}\approx1.732 \), so \( \frac{a}{100} \) must be between (1.732) and (1.74). (a=173) gives (1.73), which is slightly smaller, so check the bound carefully.
Step 2
Why this answer is correct
The correct answer is B. (173). \( \sqrt{3}\approx1.732 \), so \( \frac{a}{100} \) must be between (1.732) and (1.74). (a=173) gives (1.73), which is slightly smaller, so check the bound carefully.
Step 3
Exam Tip
\( \sqrt{3}\approx1.732 \), इसलिए \( \frac{a}{100} \) को (1.732) और (1.74) के बीच होना चाहिए। (a=173) से (1.73) मिलता है जो थोड़ा छोटा है, इसलिए सीमा सावधानी से जाँचें।
Login to save your score, XP, coins and progress. Login
यदि \( \frac{a}{100} \) संख्या रेखा पर \( \sqrt{2} \) और (1.42) के बीच है, तो (a) का कौन सा मान संभव है?
If \( \frac{a}{100} \) lies between \( \sqrt{2} \) and (1.42) on the number line, which value of (a) is possible?
#number-line
#parameter
#between-values
A (141)
B (142)
C (143)
D (140)
Explanation opens after your attempt
Step 1
Concept
\( \sqrt{2}\approx1.414 \), so \( \frac{a}{100} \) must be between (1.414) and (1.42). (a=141) gives (1.41), which is not correct.
Step 2
Why this answer is correct
The correct answer is A. (141). \( \sqrt{2}\approx1.414 \), so \( \frac{a}{100} \) must be between (1.414) and (1.42). (a=141) gives (1.41), which is not correct.
Step 3
Exam Tip
\( \sqrt{2}\approx1.414 \), इसलिए \( \frac{a}{100} \) को (1.414) और (1.42) के बीच होना चाहिए। (a=141) से (1.41) मिलता है जो सही नहीं है।
Login to save your score, XP, coins and progress. Login
यदि \( \frac{a}{10} \) संख्या रेखा पर \( \sqrt{2} \) और (1.5) के बीच है, तो (a) का कौन सा पूर्णांक मान संभव है?
If \( \frac{a}{10} \) lies between \( \sqrt{2} \) and (1.5) on the number line, which integer value of (a) is possible?
#number-line
#parameter
#between-values
A (14.5)
B (13)
C (15)
D (16)
Explanation opens after your attempt
Step 1
Concept
\( \sqrt{2}\approx1.414 \), so \( \frac{a}{10} \) must be between (1.414) and (1.5). (a=14.5) gives (1.45).
Step 2
Why this answer is correct
The correct answer is A. (14.5). \( \sqrt{2}\approx1.414 \), so \( \frac{a}{10} \) must be between (1.414) and (1.5). (a=14.5) gives (1.45).
Step 3
Exam Tip
\( \sqrt{2}\approx1.414 \), इसलिए \( \frac{a}{10} \) को (1.414) और (1.5) के बीच होना चाहिए। (a=14.5) से (1.45) मिलता है।
Login to save your score, XP, coins and progress. Login
यदि (p(x)=x-2 +2x+c) का कोई वास्तविक शून्यक नहीं है, तो (c) के लिए कौन-सी शर्त सही है?
If (p(x)=x-2 +2x+c) has no real zero, which condition on (c) is correct?
#discriminant
#real-zeroes
#parameter
A (c>1)
B (c=1)
C (c<1)
D (c=0)
Explanation opens after your attempt
Step 1
Concept
For no real zero, the discriminant must satisfy (4-4c<0). This gives (c>1).
Step 2
Why this answer is correct
The correct answer is A. (c>1). For no real zero, the discriminant must satisfy (4-4c<0). This gives (c>1).
Step 3
Exam Tip
कोई वास्तविक शून्यक नहीं होने के लिए विविक्तकर (4-4c<0) चाहिए। इससे (c>1) मिलता है।
Login to save your score, XP, coins and progress. Login
यदि (p(x)=x-2 +ax+a) में (p(1)=0), तो (a) क्या है?
If (p(x)=x-2 +ax+a) and (p(1)=0), what is (a)?
#evaluation
#parameter
#polynomial
A -\(\frac{1}{2}\)
B -(1)
C \(\frac{1}{2}\)
D (1)
Explanation opens after your attempt
Correct Answer
A. -\(\frac{1}{2}\)
Step 1
Concept
(p(1)=1+a+a=0), so (2a=-1). Therefore \(a=-\frac{1}{2}\).
Step 2
Why this answer is correct
The correct answer is A. -\(\frac{1}{2}\). (p(1)=1+a+a=0), so (2a=-1). Therefore \(a=-\frac{1}{2}\).
Step 3
Exam Tip
(p(1)=1+a+a=0), इसलिए (2a=-1)। अतः \(a=-\frac{1}{2}\) है।
Login to save your score, XP, coins and progress. Login
यदि (x=2) पर (p(x)=x-3 +mx-10) का मान (0) है, तो (m) क्या है?
If the value of (p(x)=x-3 +mx-10) at (x=2) is (0), what is (m)?
#evaluation
#parameter
#cubic
A (1)
B -(1)
C (2)
D -(2)
Explanation opens after your attempt
Step 1
Concept
(p(2)=8+2m-10=0). This gives (2m=2) and (m=1).
Step 2
Why this answer is correct
The correct answer is A. (1). (p(2)=8+2m-10=0). This gives (2m=2) and (m=1).
Step 3
Exam Tip
(p(2)=8+2m-10=0) है। इससे (2m=2) और (m=1) मिलता है।
Login to save your score, XP, coins and progress. Login
यदि (p(x)=x-2 -kx+36) के शून्यक धनात्मक और अनुपात (1:4) में हैं, तो (k) क्या है?
If the zeroes of (p(x)=x-2 -kx+36) are positive and in the ratio (1:4), what is (k)?
#ratio-zeroes
#parameter
#quadratic
A (15)
B (12)
C (9)
D (18)
Explanation opens after your attempt
Step 1
Concept
Let the zeroes be (t) and (4t), then \(4t^2=36\) gives (t=3). The sum is (15), so (k=15).
Step 2
Why this answer is correct
The correct answer is A. (15). Let the zeroes be (t) and (4t), then \(4t^2=36\) gives (t=3). The sum is (15), so (k=15).
Step 3
Exam Tip
शून्यक (t) और (4t) मानें, तो \(4t^2=36\) से (t=3) है। योग (15) है, इसलिए (k=15)।
Login to save your score, XP, coins and progress. Login
यदि (p(x)=(k-3)x-5 +2x-3 -x+9) की घात (3) है, तो (k) क्या है?
If (p(x)=(k-3)x-5 +2x-3 -x+9) has degree (3), what is (k)?
#degree
#parameter
#polynomial
A (3)
B (0)
C (2)
D (5)
Explanation opens after your attempt
Step 1
Concept
For degree (3), the coefficient of \(x^5\) must be (0). Thus (k-3=0) and (k=3).
Step 2
Why this answer is correct
The correct answer is A. (3). For degree (3), the coefficient of \(x^5\) must be (0). Thus (k-3=0) and (k=3).
Step 3
Exam Tip
घात (3) होने के लिए \(x^5\) का गुणांक (0) होना चाहिए। इसलिए (k-3=0) और (k=3)।
Login to save your score, XP, coins and progress. Login
यदि (p(x)=x-2 -6x+s) का एक शून्यक दूसरे से (2) अधिक है, तो (s) का मान क्या है?
If one zero of (p(x)=x-2 -6x+s) is (2) more than the other, what is (s)?
#zeroes
#difference
#parameter
A (8)
B (9)
C (10)
D (12)
Explanation opens after your attempt
Step 1
Concept
Let the zeroes be (t) and (t+2), then (2t+2=6) gives (t=2). The product is \(2\cdot4=8\), so (s=8).
Step 2
Why this answer is correct
The correct answer is A. (8). Let the zeroes be (t) and (t+2), then (2t+2=6) gives (t=2). The product is \(2\cdot4=8\), so (s=8).
Step 3
Exam Tip
शून्यक (t) और (t+2) मानें, तो (2t+2=6) से (t=2)। गुणनफल \(2\cdot4=8\), इसलिए (s=8)।
Login to save your score, XP, coins and progress. Login
यदि (p(x)=2x-3 +kx-2 -11x+5) को (x+1) से भाग देने पर शेष (7) है, तो (k) क्या है?
If (p(x)=2x-3 +kx-2 -11x+5) leaves remainder (7) when divided by (x+1), what is (k)?
#remainder-theorem
#parameter
#trap
A (5)
B (-9)
C (-11)
D (3)
Explanation opens after your attempt
Step 1
Concept
By the remainder theorem (p(-1)=7), so (-2+k+11+5=7). This gives (k=-7), so none of the listed options is correct.
Step 2
Why this answer is correct
The correct answer is B. (-9). By the remainder theorem (p(-1)=7), so (-2+k+11+5=7). This gives (k=-7), so none of the listed options is correct.
Step 3
Exam Tip
शेष प्रमेय से (p(-1)=7), इसलिए (-2+k+11+5=7)। इससे (k=-7) नहीं बल्कि (k=-7) आता है, इसलिए विकल्पों में सही मान नहीं है।
Login to save your score, XP, coins and progress. Login
यदि (p(x)=x-3 -5x-2 +ax+12) में (x-3) गुणनखंड है, तो (a) का मान क्या है?
If (x-3) is a factor of (p(x)=x-3 -5x-2 +ax+12), what is the value of (a)?
#factor-theorem
#polynomials
#parameter
A (2)
B (4)
C (6)
D (8)
Explanation opens after your attempt
Step 1
Concept
By the factor theorem (p(3)=0), so (27-45+3a+12=0) and (a=2). In exams, substitute the zero from the given factor directly.
Step 2
Why this answer is correct
The correct answer is A. (2). By the factor theorem (p(3)=0), so (27-45+3a+12=0) and (a=2). In exams, substitute the zero from the given factor directly.
Step 3
Exam Tip
गुणनखंड प्रमेय से (p(3)=0), इसलिए (27-45+3a+12=0) और (a=2)। परीक्षा में दिए गए गुणनखंड से मूल तुरंत रखिए।
Login to save your score, XP, coins and progress. Login
यदि (p(x)=x-3 +ax-2 +bx+20), (p(1)=0) और (p(-4)=0), तो (a-b) का मान क्या है?
If (p(x)=x-3 +ax-2 +bx+20), (p(1)=0), and (p(-4)=0), what is the value of (a-b)?
#parameter
#zeros
#cubic polynomial
A (13)
B (15)
C (17)
D (19)
Explanation opens after your attempt
Step 1
Concept
The conditions give (a+b=-21) and (4a-b=11), so (a=-2), (b=-19), and (a-b=17). When two zeros are given, form two equations.
Step 2
Why this answer is correct
The correct answer is C. (17). The conditions give (a+b=-21) and (4a-b=11), so (a=-2), (b=-19), and (a-b=17). When two zeros are given, form two equations.
Step 3
Exam Tip
शर्तों से (a+b=-21) और (4a-b=11) मिलते हैं, इसलिए (a=-2), (b=-19) और (a-b=17)। दो शून्य दिए हों तो दो समीकरण बनाएं।
Login to save your score, XP, coins and progress. Login
यदि (p(x)=x-2 +px+q), (p(0)=12) और (p(3)=0), तो (p) का मान क्या है?
If (p(x)=x-2 +px+q), (p(0)=12), and (p(3)=0), what is the value of (p)?
#parameter
#quadratic
#evaluation
A (-7)
B (-6)
C (-5)
D (-4)
Explanation opens after your attempt
Step 1
Concept
(p(0)=q=12) and (p(3)=9+3p+12=0), so (3p=-21) and (p=-7). Find the constant term first.
Step 2
Why this answer is correct
The correct answer is A. (-7). (p(0)=q=12) and (p(3)=9+3p+12=0), so (3p=-21) and (p=-7). Find the constant term first.
Step 3
Exam Tip
(p(0)=q=12) और (p(3)=9+3p+12=0), इसलिए (3p=-21) और (p=-7)। पहले अचर पद निकालें।
Login to save your score, XP, coins and progress. Login
यदि (p(x)=x-2 +kx+25) पूर्ण वर्ग बहुपद है और (k<0), तो (k) क्या है?
If (p(x)=x-2 +kx+25) is a perfect square polynomial and (k<0), what is (k)?
#perfect square
#parameter
#quadratic
A (-10)
B (-5)
C (5)
D (10)
Explanation opens after your attempt
Step 1
Concept
For (x-2 +kx+25=(x-5)2 ), (k=-10). In a perfect square, the middle term is (2ab).
Step 2
Why this answer is correct
The correct answer is A. (-10). For (x-2 +kx+25=(x-5)2 ), (k=-10). In a perfect square, the middle term is (2ab).
Step 3
Exam Tip
(x-2 +kx+25=(x-5)2 ) होने पर (k=-10)। पूर्ण वर्ग में मध्य पद (2ab) होता है।
Login to save your score, XP, coins and progress. Login
यदि (p(x)=mx-5 +(m-4 )x-4 +3x-2 +1) की घात (4) है, तो (m) क्या है?
If the degree of (p(x)=mx-5 +(m-4 )x-4 +3x-2 +1) is (4), what is (m)?
#degree
#parameter
#conditions
A (0)
B (2)
C (4)
D कोई मान नहीं / No value
Explanation opens after your attempt
Step 1
Concept
For degree (4), the coefficient of \(x^5\) must be (0) and the coefficient of \(x^4\) must be non-zero. For (m=0), (m-4 =-4).
Step 2
Why this answer is correct
The correct answer is A. (0). For degree (4), the coefficient of \(x^5\) must be (0) and the coefficient of \(x^4\) must be non-zero. For (m=0), (m-4 =-4).
Step 3
Exam Tip
घात (4) के लिए \(x^5\) का गुणांक (0) और \(x^4\) का गुणांक अशून्य चाहिए। (m=0) पर (m-4 =-4) है।
Login to save your score, XP, coins and progress. Login
यदि (p(x)=x-3 +ax-2 +bx-10) में (x=1) और (x=5) दोनों शून्य हैं, तो (a) क्या है?
If (x=1) and (x=5) are both zeros of (p(x)=x-3 +ax-2 +bx-10), what is (a)?
#zeros
#cubic
#parameter
A (-7)
B (-6)
C (6)
D (7)
Explanation opens after your attempt
Step 1
Concept
(p(1)=0) gives (a+b=9) and (p(5)=0) gives (5a+b=-23), so (a=-8). None of the listed choices is correct.
Step 2
Why this answer is correct
The correct answer is B. (-6). (p(1)=0) gives (a+b=9) and (p(5)=0) gives (5a+b=-23), so (a=-8). None of the listed choices is correct.
Step 3
Exam Tip
(p(1)=0) से (a+b=9) और (p(5)=0) से (5a+b=-23), इसलिए (a=-8) नहीं बल्कि (a=-8) आता है। विकल्पों में कोई सही नहीं है।
Login to save your score, XP, coins and progress. Login
यदि (p(x)=x-3 +ax-2 +bx+18) में (x=1) और (x=-2) दोनों शून्य हैं, तो (a+b) क्या है?
If (x=1) and (x=-2) are both zeros of (p(x)=x-3 +ax-2 +bx+18), what is (a+b)?
#zeros
#cubic
#parameter
A (-19)
B (-18)
C (-17)
D (-16)
Explanation opens after your attempt
Step 1
Concept
From (p(1)=0), (1+a+b+18=0), so (a+b=-19). This condition is directly enough for the asked sum.
Step 2
Why this answer is correct
The correct answer is A. (-19). From (p(1)=0), (1+a+b+18=0), so (a+b=-19). This condition is directly enough for the asked sum.
Step 3
Exam Tip
(p(1)=0) से (1+a+b+18=0), इसलिए (a+b=-19)। पूछे गए योग के लिए यह शर्त सीधे पर्याप्त है।
Login to save your score, XP, coins and progress. Login
यदि (p(x)=5x-2 +bx+c), (p(0)=-4) और (p(1)=3), तो (b) क्या है?
If (p(x)=5x-2 +bx+c), (p(0)=-4), and (p(1)=3), what is (b)?
#parameter
#constant term
#evaluation
A (1)
B (2)
C (3)
D (4)
Explanation opens after your attempt
Step 1
Concept
(p(0)=c=-4) and (p(1)=5+b-4=3), so (b=2). First use (x=0) to find the constant term.
Step 2
Why this answer is correct
The correct answer is B. (2). (p(0)=c=-4) and (p(1)=5+b-4=3), so (b=2). First use (x=0) to find the constant term.
Step 3
Exam Tip
(p(0)=c=-4) और (p(1)=5+b-4=3), इसलिए (b=2)। पहले (x=0) से अचर पद निकालें।
Login to save your score, XP, coins and progress. Login
किस मान के लिए ((r+4)x-3 +(r-1)x-2 +9) अचर बहुपद बन सकता है?
For what value of (r) can ((r+4)x-3 +(r-1)x-2 +9) become a constant polynomial?
#constant polynomial
#parameter
#condition
A (r=-4)
B (r=1)
C (r=0)
D ऐसा कोई मान नहीं / No such value
Explanation opens after your attempt
Correct Answer
D. ऐसा कोई मान नहीं / No such value
Step 1
Concept
For a constant polynomial, both (r+4=0) and (r-1=0) are needed, which is impossible together. All variable terms must vanish.
Step 2
Why this answer is correct
The correct answer is D. ऐसा कोई मान नहीं / No such value. For a constant polynomial, both (r+4=0) and (r-1=0) are needed, which is impossible together. All variable terms must vanish.
Step 3
Exam Tip
अचर बहुपद के लिए (r+4=0) और (r-1=0) दोनों चाहिए, जो साथ संभव नहीं हैं। सभी चर वाले पद हटने चाहिए।
Login to save your score, XP, coins and progress. Login
यदि (p(x)=x-3 +ax+b), (p(1)=6) और (p(-2)=-9), तो (a) का मान क्या है?
If (p(x)=x-3 +ax+b), (p(1)=6), and (p(-2)=-9), what is the value of (a)?
#parameter
#cubic
#evaluation
A (1)
B (2)
C (3)
D (4)
Explanation opens after your attempt
Step 1
Concept
The conditions give (a+b=5) and (-2a+b=-1). Subtracting gives (3a=6), so (a=2).
Step 2
Why this answer is correct
The correct answer is C. (3). The conditions give (a+b=5) and (-2a+b=-1). Subtracting gives (3a=6), so (a=2).
Step 3
Exam Tip
शर्तों से (a+b=5) और (-2a+b=-1) मिलते हैं। घटाने पर (3a=6) नहीं बल्कि (3a=6), इसलिए (a=2)।
Login to save your score, XP, coins and progress. Login
यदि (p(x)=x-3 +ax+b), (p(2)=13) और (p(-1)=-7), तो (a+b) का मान क्या है?
If (p(x)=x-3 +ax+b), (p(2)=13), and (p(-1)=-7), what is the value of (a+b)?
#parameter
#cubic
#evaluation
A (1)
B (2)
C (3)
D (4)
Explanation opens after your attempt
Step 1
Concept
The conditions give (2a+b=5) and (-a+b=-6), so \(a=\frac{11}{3}\) and \(b=-\frac{7}{3}\). Hence \(a+b=\frac{4}{3}\), so none of the listed choices is correct.
Step 2
Why this answer is correct
The correct answer is B. (2). The conditions give (2a+b=5) and (-a+b=-6), so \(a=\frac{11}{3}\) and \(b=-\frac{7}{3}\). Hence \(a+b=\frac{4}{3}\), so none of the listed choices is correct.
Step 3
Exam Tip
शर्तों से (2a+b=5) और (-a+b=-6) मिलते हैं, इसलिए \(a=\frac{11}{3}\) और \(b=-\frac{7}{3}\)। अतः \(a+b=\frac{4}{3}\) नहीं बल्कि विकल्पों में कोई सही नहीं होता।
Login to save your score, XP, coins and progress. Login
यदि (p(x)=4x-4 +kx-3 -6x+1) में सभी गुणांकों का योग (5) है, तो (k) क्या है?
If the sum of all coefficients of (p(x)=4x-4 +kx-3 -6x+1) is (5), what is (k)?
#sum of coefficients
#parameter
#polynomial
A (4)
B (5)
C (6)
D (7)
Explanation opens after your attempt
Step 1
Concept
The sum of coefficients is (4+k+0-6+1=k-1), so (k-1=5) and (k=6). The sum of coefficients is found by (p(1)).
Step 2
Why this answer is correct
The correct answer is C. (6). The sum of coefficients is (4+k+0-6+1=k-1), so (k-1=5) and (k=6). The sum of coefficients is found by (p(1)).
Step 3
Exam Tip
गुणांकों का योग (4+k+0-6+1=k-1) है, इसलिए (k-1=5) और (k=6)। गुणांकों का योग (p(1)) से मिलता है।
Login to save your score, XP, coins and progress. Login
यदि (p(x)=x-2 +ax+b), (p(-2)=0) और (p(5)=0), तो (a+b) क्या है?
If (p(x)=x-2 +ax+b), (p(-2)=0), and (p(5)=0), what is (a+b)?
#zeros
#quadratic
#parameter
A (-13)
B (-7)
C (3)
D (7)
Explanation opens after your attempt
Step 1
Concept
The zeros are (-2) and (5), so the polynomial is ((x+2)(x-5)=x-2 -3x-10). Hence (a+b=-3-10=-13).
Step 2
Why this answer is correct
The correct answer is A. (-13). The zeros are (-2) and (5), so the polynomial is ((x+2)(x-5)=x-2 -3x-10). Hence (a+b=-3-10=-13).
Step 3
Exam Tip
शून्य (-2) और (5) हैं, इसलिए बहुपद ((x+2)(x-5)=x-2 -3x-10) है। अतः (a+b=-3-10=-13)।
Login to save your score, XP, coins and progress. Login
किस मान के लिए (p(x)=x-4 -3x-3 +mx-5) में (p(1)=0) होगा?
For what value of (m) will (p(1)=0) in (p(x)=x-4 -3x-3 +mx-5)?
#parameter
#evaluation
#quartic
A (5)
B (6)
C (7)
D (8)
Explanation opens after your attempt
Step 1
Concept
(p(1)=1-3+m-5 =m-7 ), so (m=7). Substitute the given value and form a simple equation.
Step 2
Why this answer is correct
The correct answer is C. (7). (p(1)=1-3+m-5 =m-7 ), so (m=7). Substitute the given value and form a simple equation.
Step 3
Exam Tip
(p(1)=1-3+m-5 =m-7 ), इसलिए (m=7)। दिए गए मान को रखकर सरल समीकरण बनाएं।
Login to save your score, XP, coins and progress. Login
यदि (x=-3), बहुपद (p(x)=x-2 +kx-18) का शून्य है, तो (k) क्या है?
If (x=-3) is a zero of (p(x)=x-2 +kx-18), what is (k)?
#zero
#parameter
#quadratic
A (-3)
B (-2)
C (2)
D (3)
Explanation opens after your attempt
Step 1
Concept
(p(-3)=9-3k-18=0), so (-3k=9) and (k=-3). When a zero is given, set the polynomial value equal to (0).
Step 2
Why this answer is correct
The correct answer is A. (-3). (p(-3)=9-3k-18=0), so (-3k=9) and (k=-3). When a zero is given, set the polynomial value equal to (0).
Step 3
Exam Tip
(p(-3)=9-3k-18=0), इसलिए (-3k=9) और (k=-3)। शून्य दिए होने पर बहुपद का मान (0) रखें।
Login to save your score, XP, coins and progress. Login
यदि (p(x)=kx-3 +2x-2 -7x+5) और (p(-1)=16), तो (k) का मान क्या है?
If (p(x)=kx-3 +2x-2 -7x+5) and (p(-1)=16), what is the value of (k)?
#evaluation
#parameter
#cubic polynomial
A (-2)
B (-1)
C (1)
D (2)
Explanation opens after your attempt
Step 1
Concept
(p(-1)=-k+2+7+5=14-k), so (14-k=16) and (k=-2). Watch signs carefully when substituting a negative value.
Step 2
Why this answer is correct
The correct answer is A. (-2). (p(-1)=-k+2+7+5=14-k), so (14-k=16) and (k=-2). Watch signs carefully when substituting a negative value.
Step 3
Exam Tip
(p(-1)=-k+2+7+5=14-k), इसलिए (14-k=16) और (k=-2)। ऋणात्मक मान रखने पर संकेतों को ध्यान से देखें।
Login to save your score, XP, coins and progress. Login
यदि (p(x)=(a-1)x-6 +(a+2)x-4 -5x+7) की घात (4) है, तो (a) क्या होगा?
If the degree of (p(x)=(a-1)x-6 +(a+2)x-4 -5x+7) is (4), what will (a) be?
#degree
#parameter
#polynomial
A (-2)
B (1)
C (2)
D कोई मान नहीं / No value
Explanation opens after your attempt
Step 1
Concept
For degree (4), the coefficient of \(x^6\) must be (0) and the coefficient of \(x^4\) must be non-zero. Both conditions hold for (a=1).
Step 2
Why this answer is correct
The correct answer is B. (1). For degree (4), the coefficient of \(x^6\) must be (0) and the coefficient of \(x^4\) must be non-zero. Both conditions hold for (a=1).
Step 3
Exam Tip
घात (4) के लिए \(x^6\) का गुणांक (0) और \(x^4\) का गुणांक अशून्य चाहिए। (a=1) पर दोनों शर्तें पूरी होती हैं।
Login to save your score, XP, coins and progress. Login
यदि (p(x)=x-3 +ax-2 +bx-12), (p(2)=0) और (p(3)=0), तो (a+b) का मान क्या है?
If (p(x)=x-3 +ax-2 +bx-12), (p(2)=0), and (p(3)=0), what is the value of (a+b)?
#parameter
#zeros
#cubic polynomial
A (7)
B (8)
C (9)
D (10)
Explanation opens after your attempt
Step 1
Concept
The conditions give (2a+b=2) and (3a+b=-5), so (a=-7), (b=16), and (a+b=9). When two values are given, form two equations.
Step 2
Why this answer is correct
The correct answer is C. (9). The conditions give (2a+b=2) and (3a+b=-5), so (a=-7), (b=16), and (a+b=9). When two values are given, form two equations.
Step 3
Exam Tip
शर्तों से (2a+b=2) और (3a+b=-5) मिलते हैं, इसलिए (a=-7), (b=16) और (a+b=9)। दो मान दिए हों तो दो समीकरण बनाएं।
Login to save your score, XP, coins and progress. Login
