Concept-wise Practice

parameter MCQ Questions for Class 10

parameter se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

737 questions tagged with parameter.

किस मान पर (4x+ay=16) और (8x+10y=35) की रेखाएं समांतर अलग-अलग होंगी?

For which value will the lines (4x+ay=16) and (8x+10y=35) be distinct and parallel?

Explanation opens after your attempt
Correct Answer

B. (a=5)

Step 1

Concept

For parallel lines, \(\frac{4}{8}=\frac{a}{10}\), so (a=5). Since \(\frac{16}{35}\neq\frac{1}{2}\), they will not be coincident.

Step 2

Why this answer is correct

The correct answer is B. (a=5). For parallel lines, \(\frac{4}{8}=\frac{a}{10}\), so (a=5). Since \(\frac{16}{35}\neq\frac{1}{2}\), they will not be coincident.

Step 3

Exam Tip

समांतर के लिए \(\frac{4}{8}=\frac{a}{10}\), इसलिए (a=5)। चूंकि \(\frac{16}{35}\neq\frac{1}{2}\), वे संपाती नहीं होंगी।

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यदि (5x+ky=20) और (15x+6y=60) संपाती रेखाएं हों, तो (k) का मान क्या है?

If (5x+ky=20) and (15x+6y=60) are coincident lines, what is the value of (k)?

Explanation opens after your attempt
Correct Answer

B. (2)

Step 1

Concept

The second equation is (3) times the first, so (3k=6) and (k=2). In coincident lines, all terms are in the same ratio.

Step 2

Why this answer is correct

The correct answer is B. (2). The second equation is (3) times the first, so (3k=6) and (k=2). In coincident lines, all terms are in the same ratio.

Step 3

Exam Tip

दूसरा समीकरण पहले का (3) गुना है, इसलिए (3k=6) और (k=2)। संपाती रेखाओं में सभी पद समान अनुपात में होते हैं।

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किस मान पर (x+4y=12) और (2x+8y=k) की रेखाएं समांतर अलग-अलग होंगी?

For which value will (x+4y=12) and (2x+8y=k) be distinct parallel lines?

Explanation opens after your attempt
Correct Answer

B. (k=20)

Step 1

Concept

The coefficient ratio is \(\frac{1}{2}\), so coincidence needs (k=24). For (k=20), the lines are distinct and parallel.

Step 2

Why this answer is correct

The correct answer is B. (k=20). The coefficient ratio is \(\frac{1}{2}\), so coincidence needs (k=24). For (k=20), the lines are distinct and parallel.

Step 3

Exam Tip

गुणांक का अनुपात \(\frac{1}{2}\) है, इसलिए संपाती होने के लिए (k=24) चाहिए। (k=20) पर रेखाएं समांतर अलग-अलग हैं।

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यदि (4x+ay=16) और (8x+10y=32) की रेखाएं संपाती हों, तो (a) का मान क्या है?

If the lines (4x+ay=16) and (8x+10y=32) are coincident, what is the value of (a)?

Explanation opens after your attempt
Correct Answer

B. (5)

Step 1

Concept

The second equation is (2) times the first, so (2a=10) and (a=5). Include the constant term in ratio checking.

Step 2

Why this answer is correct

The correct answer is B. (5). The second equation is (2) times the first, so (2a=10) and (a=5). Include the constant term in ratio checking.

Step 3

Exam Tip

दूसरा समीकरण पहले का (2) गुना है, इसलिए (2a=10) और (a=5)। अनुपात जांच में स्थिर पद भी शामिल करें।

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यदि (x+ky=8) और (2x+6y=16) अनंत समाधान देते हैं, तो (k) का मान क्या है?

If (x+ky=8) and (2x+6y=16) give infinitely many solutions, what is the value of (k)?

Explanation opens after your attempt
Correct Answer

B. (3)

Step 1

Concept

The second equation is (2) times the first, so (2k=6) and (k=3). For infinite solutions, the lines must be coincident.

Step 2

Why this answer is correct

The correct answer is B. (3). The second equation is (2) times the first, so (2k=6) and (k=3). For infinite solutions, the lines must be coincident.

Step 3

Exam Tip

दूसरा समीकरण पहले का (2) गुना है, इसलिए (2k=6) और (k=3)। अनंत समाधान के लिए रेखाएं संपाती होनी चाहिए।

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यदि (2x+3y=12) और (4x+my=24) की रेखाएं संपाती हैं, तो (m) क्या होगा?

If the lines (2x+3y=12) and (4x+my=24) are coincident, what is (m)?

Explanation opens after your attempt
Correct Answer

D. (6)

Step 1

Concept

The second equation is (2) times the first, so (m=6). In a coincident line, the coefficient of (y) also changes in the same ratio.

Step 2

Why this answer is correct

The correct answer is D. (6). The second equation is (2) times the first, so (m=6). In a coincident line, the coefficient of (y) also changes in the same ratio.

Step 3

Exam Tip

दूसरा समीकरण पहले का (2) गुना है, इसलिए (m=6)। संपाती रेखा में (y) का गुणांक भी उसी अनुपात में बदलता है।

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यदि (ax+6y=18) और (2x+3y=9) संपाती रेखाएं हैं, तो (a) का मान क्या है?

If (ax+6y=18) and (2x+3y=9) are coincident lines, what is the value of (a)?

Explanation opens after your attempt
Correct Answer

C. (4)

Step 1

Concept

The first equation must be (2) times the second, so (a=4). In coincident lines, all terms change by the same multiplier.

Step 2

Why this answer is correct

The correct answer is C. (4). The first equation must be (2) times the second, so (a=4). In coincident lines, all terms change by the same multiplier.

Step 3

Exam Tip

पहला समीकरण दूसरे का (2) गुना होना चाहिए, इसलिए (a=4)। संपाती रेखाओं में सभी पद समान गुणक से बदलते हैं।

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किस मान पर (5x+2y=13) और (10x+4y=k) का कोई समाधान नहीं होगा?

For which value will (5x+2y=13) and (10x+4y=k) have no solution?

Explanation opens after your attempt
Correct Answer

B. (k=13)

Step 1

Concept

The coefficient ratio is \(\frac{1}{2}\); coincidence needs (k=26). For (k=13), the lines are distinct and parallel, so there is no solution.

Step 2

Why this answer is correct

The correct answer is B. (k=13). The coefficient ratio is \(\frac{1}{2}\); coincidence needs (k=26). For (k=13), the lines are distinct and parallel, so there is no solution.

Step 3

Exam Tip

गुणांक अनुपात \(\frac{1}{2}\) है; संपाती के लिए (k=26) चाहिए। (k=13) पर रेखाएं समांतर अलग-अलग हैं, इसलिए कोई समाधान नहीं।

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यदि (3x+2y=p) और (6x+4y=20) की रेखाएं अनंत समाधान देती हैं, तो (p) क्या है?

If (3x+2y=p) and (6x+4y=20) give infinitely many solutions, what is (p)?

Explanation opens after your attempt
Correct Answer

B. (10)

Step 1

Concept

For infinitely many solutions, the second equation must be (2) times the first. Therefore (2p=20) and (p=10).

Step 2

Why this answer is correct

The correct answer is B. (10). For infinitely many solutions, the second equation must be (2) times the first. Therefore (2p=20) and (p=10).

Step 3

Exam Tip

अनंत समाधान के लिए दूसरा समीकरण पहले का (2) गुना होना चाहिए। इसलिए (2p=20) और (p=10)।

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किस मान पर (2x+ay=10) और (6x+9y=31) की रेखाएं समांतर अलग-अलग होंगी?

For which value will (2x+ay=10) and (6x+9y=31) be distinct parallel lines?

Explanation opens after your attempt
Correct Answer

B. (a=3)

Step 1

Concept

For parallel lines, \(\frac{2}{6}=\frac{a}{9}\), so (a=3). Since \(\frac{10}{31}\neq\frac{1}{3}\), the lines are not coincident.

Step 2

Why this answer is correct

The correct answer is B. (a=3). For parallel lines, \(\frac{2}{6}=\frac{a}{9}\), so (a=3). Since \(\frac{10}{31}\neq\frac{1}{3}\), the lines are not coincident.

Step 3

Exam Tip

समांतर के लिए \(\frac{2}{6}=\frac{a}{9}\), इसलिए (a=3)। चूंकि \(\frac{10}{31}\neq\frac{1}{3}\), रेखाएं संपाती नहीं होंगी।

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यदि (kx+4y=12) और (6x+8y=24) की रेखाएं संपाती हैं, तो (k) का मान क्या होगा?

If the lines (kx+4y=12) and (6x+8y=24) are coincident, what is the value of (k)?

Explanation opens after your attempt
Correct Answer

B. (3)

Step 1

Concept

For coincident lines, \(\frac{k}{6}=\frac{4}{8}=\frac{12}{24}\), so (k=3). In coincidence, the whole equation stays in the same ratio.

Step 2

Why this answer is correct

The correct answer is B. (3). For coincident lines, \(\frac{k}{6}=\frac{4}{8}=\frac{12}{24}\), so (k=3). In coincidence, the whole equation stays in the same ratio.

Step 3

Exam Tip

संपाती रेखाओं के लिए \(\frac{k}{6}=\frac{4}{8}=\frac{12}{24}\), इसलिए (k=3)। संपाती स्थिति में पूरा समीकरण समान अनुपात में होता है।

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यदि (2x+3y=6) और (kx+6y=12) की रेखाएं संपाती हों, तो (k) क्या होगा?

If the lines (2x+3y=6) and (kx+6y=12) are coincident, what is (k)?

Explanation opens after your attempt
Correct Answer

C. (4)

Step 1

Concept

The second equation must be (2) times the first, so (kx=4x) and (k=4). In the coincident case, the whole line remains the same.

Step 2

Why this answer is correct

The correct answer is C. (4). The second equation must be (2) times the first, so (kx=4x) and (k=4). In the coincident case, the whole line remains the same.

Step 3

Exam Tip

दूसरा समीकरण पहले का (2) गुना होना चाहिए, इसलिए (kx=4x) और (k=4)। संपाती स्थिति में पूरी रेखा समान रहती है।

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यदि (3x+2y=7) और (6x+4y=k) की रेखाएं समांतर अलग-अलग हों, तो (k) के लिए कौन सा विकल्प सही है?

If the lines (3x+2y=7) and (6x+4y=k) are parallel and distinct, which option is correct for (k)?

Explanation opens after your attempt
Correct Answer

B. (7)

Step 1

Concept

The coefficient ratio is \(\frac{3}{6}=\frac{2}{4}=\frac{1}{2}\); for coincidence, (k=14) is needed. With (k=7), the lines are parallel and distinct.

Step 2

Why this answer is correct

The correct answer is B. (7). The coefficient ratio is \(\frac{3}{6}=\frac{2}{4}=\frac{1}{2}\); for coincidence, (k=14) is needed. With (k=7), the lines are parallel and distinct.

Step 3

Exam Tip

गुणांक अनुपात \(\frac{3}{6}=\frac{2}{4}=\frac{1}{2}\) है; संपाती होने के लिए (k=14) चाहिए। (k=7) होने पर रेखाएं समांतर अलग-अलग होंगी।

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यदि (x+y=6) और (2x+2y=k) का ग्राफ संपाती है, तो (k) का मान क्या होगा?

If the graph of (x+y=6) and (2x+2y=k) is coincident, what is the value of (k)?

Explanation opens after your attempt
Correct Answer

D. (12)

Step 1

Concept

The second equation must be (2) times the first, so (k=12). For coincident lines, the constant term also changes in the same ratio.

Step 2

Why this answer is correct

The correct answer is D. (12). The second equation must be (2) times the first, so (k=12). For coincident lines, the constant term also changes in the same ratio.

Step 3

Exam Tip

दूसरा समीकरण पहले का (2) गुना होना चाहिए, इसलिए (k=12)। संपाती रेखा के लिए स्थिर पद भी उसी अनुपात में बदलता है।

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यदि दो रेखाएं (2x+ay=10) और (6x+9y=30) संपाती हों, तो (a) का मान क्या है?

If the lines (2x+ay=10) and (6x+9y=30) are coincident, what is the value of (a)?

Explanation opens after your attempt
Correct Answer

C. (3)

Step 1

Concept

For coincident lines, \(\frac{2}{6}=\frac{a}{9}=\frac{10}{30}\), so (a=3). All coefficients must be in the same ratio.

Step 2

Why this answer is correct

The correct answer is C. (3). For coincident lines, \(\frac{2}{6}=\frac{a}{9}=\frac{10}{30}\), so (a=3). All coefficients must be in the same ratio.

Step 3

Exam Tip

संपाती के लिए \(\frac{2}{6}=\frac{a}{9}=\frac{10}{30}\), इसलिए (a=3)। सभी गुणांक समान अनुपात में होने चाहिए।

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यदि (px+3y=9) और (4x+6y=18) संपाती रेखाएं हों, तो (p) का मान क्या है?

If (px+3y=9) and (4x+6y=18) are coincident lines, what is the value of (p)?

Explanation opens after your attempt
Correct Answer

B. (2)

Step 1

Concept

For coincident lines, \(\frac{p}{4}=\frac{3}{6}=\frac{9}{18}\), so (p=2). In the coincident case, all ratios must be equal.

Step 2

Why this answer is correct

The correct answer is B. (2). For coincident lines, \(\frac{p}{4}=\frac{3}{6}=\frac{9}{18}\), so (p=2). In the coincident case, all ratios must be equal.

Step 3

Exam Tip

संपाती के लिए \(\frac{p}{4}=\frac{3}{6}=\frac{9}{18}\), इसलिए (p=2)। संपाती स्थिति में सभी अनुपात बराबर होने चाहिए।

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यदि (2x+ky=8) और (4x+6y=12) की रेखाएं समांतर हों और संपाती न हों, तो (k) का मान क्या होगा?

If the lines (2x+ky=8) and (4x+6y=12) are parallel but not coincident, what is the value of (k)?

Explanation opens after your attempt
Correct Answer

B. (3)

Step 1

Concept

For parallel lines, \(\frac{2}{4}=\frac{k}{6}\), so (k=3). Also \(\frac{8}{12}\neq\frac{1}{2}\), so they are not coincident.

Step 2

Why this answer is correct

The correct answer is B. (3). For parallel lines, \(\frac{2}{4}=\frac{k}{6}\), so (k=3). Also \(\frac{8}{12}\neq\frac{1}{2}\), so they are not coincident.

Step 3

Exam Tip

समांतर के लिए \(\frac{2}{4}=\frac{k}{6}\), इसलिए (k=3)। साथ ही \(\frac{8}{12}\neq\frac{1}{2}\), इसलिए वे संपाती नहीं हैं।

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समीकरण (4x+ay=20) रेखा (2x+3y=10) से संपाती हो, तो (a) का मान क्या होगा?

If (4x+ay=20) is coincident with the line (2x+3y=10), what will be the value of (a)?

Explanation opens after your attempt
Correct Answer

A. (6)

Step 1

Concept

Multiplying (2x+3y=10) by (2) gives (4x+6y=20). Therefore (a=6).

Step 2

Why this answer is correct

The correct answer is A. (6). Multiplying (2x+3y=10) by (2) gives (4x+6y=20). Therefore (a=6).

Step 3

Exam Tip

(2x+3y=10) को (2) से गुणा करने पर (4x+6y=20) मिलता है। इसलिए (a=6) होगा।

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यदि रेखा (kx-2y=7) रेखा (3x-6y=12) के समांतर और अलग हो, तो (k) का मान क्या होगा?

If the line (kx-2y=7) is parallel and distinct to the line (3x-6y=12), what will be the value of (k)?

Explanation opens after your attempt
Correct Answer

A. (1)

Step 1

Concept

For parallel lines, \(\frac{k}{3}=\frac{-2}{-6}\), so (k=1). The constants ratio is different, so the lines are distinct parallel lines.

Step 2

Why this answer is correct

The correct answer is A. (1). For parallel lines, \(\frac{k}{3}=\frac{-2}{-6}\), so (k=1). The constants ratio is different, so the lines are distinct parallel lines.

Step 3

Exam Tip

समांतर होने के लिए \(\frac{k}{3}=\frac{-2}{-6}\), इसलिए (k=1)। नियतांकों का अनुपात अलग है, इसलिए रेखाएँ अलग समांतर हैं।

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समीकरण (x+by=8) रेखा (3x+12y=30) के समांतर और अलग हो, तो (b) का उचित मान कौन-सा है?

For (x+by=8) to be parallel and distinct to (3x+12y=30), which value of (b) is suitable?

Explanation opens after your attempt
Correct Answer

A. (4)

Step 1

Concept

Dividing (3x+12y=30) by (3) gives (x+4y=10). Thus (b=4) makes the lines parallel and distinct.

Step 2

Why this answer is correct

The correct answer is A. (4). Dividing (3x+12y=30) by (3) gives (x+4y=10). Thus (b=4) makes the lines parallel and distinct.

Step 3

Exam Tip

(3x+12y=30) को (3) से भाग देने पर (x+4y=10) मिलता है। इसलिए (b=4) देने पर रेखाएँ समांतर और अलग होंगी।

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समीकरण (3x+ay=24) रेखा (3x+4y=24) से संपाती हो, तो (a) का मान क्या होगा?

If (3x+ay=24) is coincident with (3x+4y=24), what will be the value of (a)?

Explanation opens after your attempt
Correct Answer

B. (4)

Step 1

Concept

For coincident lines, both equations must be in the same form. Therefore (a=4).

Step 2

Why this answer is correct

The correct answer is B. (4). For coincident lines, both equations must be in the same form. Therefore (a=4).

Step 3

Exam Tip

संपाती होने के लिए दोनों समीकरण समान रूप में होने चाहिए। इसलिए (a=4) होगा।

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यदि रेखाएँ (kx+4y=22) और (x+y=6) बिंदु (\left\(2,4\right\)) पर मिलती हैं, तो (k) क्या होगा?

If the lines (kx+4y=22) and (x+y=6) meet at (\left\(2,4\right\)), what will (k) be?

Explanation opens after your attempt
Correct Answer

B. (3)

Step 1

Concept

Putting (\left\(2,4\right\)) in the first equation gives (2k+16=22). This gives (k=3).

Step 2

Why this answer is correct

The correct answer is B. (3). Putting (\left\(2,4\right\)) in the first equation gives (2k+16=22). This gives (k=3).

Step 3

Exam Tip

पहले समीकरण में (\left\(2,4\right\)) रखने पर (2k+16=22)। इससे (k=3) मिलता है।

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यदि दो रेखाएँ (x+ay=11) और (3x-y=10) बिंदु (\left\(4,2\right\)) पर मिलती हैं, तो (a) का मान क्या है?

If two lines (x+ay=11) and (3x-y=10) meet at (\left\(4,2\right\)), what is the value of (a)?

Explanation opens after your attempt
Correct Answer

A. \(\frac{7}{2}\)

Step 1

Concept

Putting (\left\(4,2\right\)) in (x+ay=11) gives (4+2a=11). Hence \(a=\frac{7}{2}\).

Step 2

Why this answer is correct

The correct answer is A. \(\frac{7}{2}\). Putting (\left\(4,2\right\)) in (x+ay=11) gives (4+2a=11). Hence \(a=\frac{7}{2}\).

Step 3

Exam Tip

(\left\(4,2\right\)) को (x+ay=11) में रखने पर (4+2a=11)। इसलिए \(a=\frac{7}{2}\)।

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यदि (3x+ay=22) और (x+y=7) का ग्राफीय हल (\left\(4,3\right\)) है, तो (a) कितना होगा?

If the graphical solution of (3x+ay=22) and (x+y=7) is (\left\(4,3\right\)), what is (a)?

Explanation opens after your attempt
Correct Answer

A. \(\frac{10}{3}\)

Step 1

Concept

Putting (\left\(4,3\right\)) in (3x+ay=22) gives (12+3a=22). Thus \(a=\frac{10}{3}\).

Step 2

Why this answer is correct

The correct answer is A. \(\frac{10}{3}\). Putting (\left\(4,3\right\)) in (3x+ay=22) gives (12+3a=22). Thus \(a=\frac{10}{3}\).

Step 3

Exam Tip

(3x+ay=22) में (\left\(4,3\right\)) रखने पर (12+3a=22)। इससे \(a=\frac{10}{3}\) मिलता है।

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यदि दो रेखाएँ (x+y=9) और (kx+3y=23) बिंदु (\left\(4,5\right\)) से गुजरती हैं, तो (k) का मान क्या है?

If the two lines (x+y=9) and (kx+3y=23) pass through (\left\(4,5\right\)), what is the value of (k)?

Explanation opens after your attempt
Correct Answer

A. (2)

Step 1

Concept

Putting (\left\(4,5\right\)) in (kx+3y=23) gives (4k+15=23). Hence (k=2).

Step 2

Why this answer is correct

The correct answer is A. (2). Putting (\left\(4,5\right\)) in (kx+3y=23) gives (4k+15=23). Hence (k=2).

Step 3

Exam Tip

(kx+3y=23) में (\left\(4,5\right\)) रखने पर (4k+15=23)। इसलिए (k=2)।

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यदि रेखा (kx+3y=15) रेखा (2x+6y=18) के समांतर और अलग हो, तो (k) का मान क्या होगा?

If the line (kx+3y=15) is parallel and distinct to the line (2x+6y=18), what will be the value of (k)?

Explanation opens after your attempt
Correct Answer

A. (1)

Step 1

Concept

For parallel lines, \(\frac{k}{2}=\frac{3}{6}\), so (k=1). The constants ratio is different, so the lines are distinct parallel lines.

Step 2

Why this answer is correct

The correct answer is A. (1). For parallel lines, \(\frac{k}{2}=\frac{3}{6}\), so (k=1). The constants ratio is different, so the lines are distinct parallel lines.

Step 3

Exam Tip

समांतर होने के लिए \(\frac{k}{2}=\frac{3}{6}\), इसलिए (k=1)। नियतांकों का अनुपात अलग है, इसलिए रेखाएँ अलग समांतर हैं।

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समीकरण (x+by=7) रेखा (2x+6y=18) के समांतर और अलग हो, तो (b) का उचित मान कौन-सा है?

For (x+by=7) to be parallel and distinct to (2x+6y=18), which value of (b) is suitable?

Explanation opens after your attempt
Correct Answer

A. (3)

Step 1

Concept

Dividing (2x+6y=18) by (2) gives (x+3y=9). Thus (b=3) makes the lines parallel and distinct.

Step 2

Why this answer is correct

The correct answer is A. (3). Dividing (2x+6y=18) by (2) gives (x+3y=9). Thus (b=3) makes the lines parallel and distinct.

Step 3

Exam Tip

(2x+6y=18) को (2) से भाग देने पर (x+3y=9) मिलता है। इसलिए (b=3) देने पर रेखाएँ समांतर और अलग होंगी।

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समीकरण (2x+ay=18) रेखा (2x+3y=18) से संपाती हो, तो (a) का मान क्या होगा?

If (2x+ay=18) is coincident with (2x+3y=18), what will be the value of (a)?

Explanation opens after your attempt
Correct Answer

B. (3)

Step 1

Concept

For coincident lines, both equations must be in the same form. Therefore (a=3).

Step 2

Why this answer is correct

The correct answer is B. (3). For coincident lines, both equations must be in the same form. Therefore (a=3).

Step 3

Exam Tip

संपाती होने के लिए दोनों समीकरण समान रूप में होने चाहिए। इसलिए (a=3) होगा।

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यदि रेखाएँ (kx+2y=14) और (x+y=6) बिंदु (\left\(2,4\right\)) पर मिलती हैं, तो (k) क्या होगा?

If the lines (kx+2y=14) and (x+y=6) meet at (\left\(2,4\right\)), what will (k) be?

Explanation opens after your attempt
Correct Answer

B. (3)

Step 1

Concept

Putting (\left\(2,4\right\)) in the first equation gives (2k+8=14). This gives (k=3).

Step 2

Why this answer is correct

The correct answer is B. (3). Putting (\left\(2,4\right\)) in the first equation gives (2k+8=14). This gives (k=3).

Step 3

Exam Tip

पहले समीकरण में (\left\(2,4\right\)) रखने पर (2k+8=14)। इससे (k=3) मिलता है।

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यदि दो रेखाएँ (x+ay=10) और (2x-y=5) बिंदु (\left\(3,1\right\)) पर मिलती हैं, तो (a) का मान क्या है?

If two lines (x+ay=10) and (2x-y=5) meet at (\left\(3,1\right\)), what is the value of (a)?

Explanation opens after your attempt
Correct Answer

A. (7)

Step 1

Concept

Putting (\left\(3,1\right\)) in (x+ay=10) gives (3+a=10). Hence (a=7).

Step 2

Why this answer is correct

The correct answer is A. (7). Putting (\left\(3,1\right\)) in (x+ay=10) gives (3+a=10). Hence (a=7).

Step 3

Exam Tip

(\left\(3,1\right\)) को (x+ay=10) में रखने पर (3+a=10)। इसलिए (a=7)।

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