If the line (kx-2y=7) is parallel and distinct to the line (3x-6y=12), what will be the value of (k)?

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Correct answer: (1)

For parallel lines, (\frac{k}{3}=\frac{-2}{-6}), so (k=1). The constants ratio is different, so the lines are distinct parallel lines.

What is the correct answer to this question?

(1)

Why is this the correct answer?

For parallel lines, (\frac{k}{3}=\frac{-2}{-6}), so (k=1). The constants ratio is different, so the lines are distinct parallel lines.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Pair of Linear Equations in Two Variables. Topic: Graphical method of finding solutions..

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