Concept-wise Practice

parameter MCQ Questions for Class 10

parameter se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

737 questions tagged with parameter.

समीकरणों (4x+ay=12) और (2x+3y=9) का कोई हल न हो, इसके लिए (a) का मान क्या होगा?

For (4x+ay=12) and (2x+3y=9) to have no solution, what should be the value of (a)?

Explanation opens after your attempt
Correct Answer

C. (a=6)

Step 1

Concept

For no solution, coefficients of (x) and (y) are proportional but constants are not. Since (4:2=2), (a=6) is correct.

Step 2

Why this answer is correct

The correct answer is C. (a=6). For no solution, coefficients of (x) and (y) are proportional but constants are not. Since (4:2=2), (a=6) is correct.

Step 3

Exam Tip

कोई हल न होने पर (x) और (y) के गुणांक समानुपाती होते हैं लेकिन स्थिरांक नहीं। (4:2=2), इसलिए (a=6) सही है।

Open Question Page
Ask Friends

यदि (kx+3y=25) और (x-y=2) का हल (x=5,\ y=3) है, तो (k) का मान क्या है?

If (kx+3y=25) and (x-y=2) have solution (x=5,\ y=3), what is the value of (k)?

Explanation opens after your attempt
Correct Answer

A. \(k=\frac{16}{5}\)

Step 1

Concept

Substitute the given solution in (kx+3y=25). (5k+9=25), so \(k=\frac{16}{5}\).

Step 2

Why this answer is correct

The correct answer is A. \(k=\frac{16}{5}\). Substitute the given solution in (kx+3y=25). (5k+9=25), so \(k=\frac{16}{5}\).

Step 3

Exam Tip

दिए हल को (kx+3y=25) में रखें। (5k+9=25), इसलिए \(k=\frac{16}{5}\)।

Open Question Page
Ask Friends

यदि (x=3,\ y=2) समीकरण (2x+ky=16) को संतुष्ट करता है, तो (k) का मान क्या है?

If (x=3,\ y=2) satisfies (2x+ky=16), what is the value of (k)?

Explanation opens after your attempt
Correct Answer

D. (k=5)

Step 1

Concept

Substituting (x=3,\ y=2) gives (6+2k=16). Therefore (k=5).

Step 2

Why this answer is correct

The correct answer is D. (k=5). Substituting (x=3,\ y=2) gives (6+2k=16). Therefore (k=5).

Step 3

Exam Tip

(x=3,\ y=2) रखने पर (6+2k=16) मिलता है। इसलिए (k=5)।

Open Question Page
Ask Friends

(2x+py=10) और (4x+6y=20) के अनंत हल होने के लिए (p) का मान क्या है?

What is the value of (p) for (2x+py=10) and (4x+6y=20) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

A. (p=3)

Step 1

Concept

Twice the first equation must become the second equation. Hence (2p=6), so (p=3).

Step 2

Why this answer is correct

The correct answer is A. (p=3). Twice the first equation must become the second equation. Hence (2p=6), so (p=3).

Step 3

Exam Tip

पहले समीकरण का (2) गुना दूसरा समीकरण बनना चाहिए। इसलिए (2p=6), अतः (p=3)।

Open Question Page
Ask Friends

(ax+4y=12) और (3x+2y=6) के अनंत हल होने के लिए (a) का मान क्या है?

What is the value of (a) for (ax+4y=12) and (3x+2y=6) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

B. (a=6)

Step 1

Concept

For infinitely many solutions, both equations must be proportional. The ratio of (4) and (2) is (2), so (a=6).

Step 2

Why this answer is correct

The correct answer is B. (a=6). For infinitely many solutions, both equations must be proportional. The ratio of (4) and (2) is (2), so (a=6).

Step 3

Exam Tip

अनंत हल के लिए दोनों समीकरण समानुपाती होने चाहिए। (4) और (2) का अनुपात (2) है, इसलिए (a=6) होना चाहिए।

Open Question Page
Ask Friends

यदि (3x+my=23) और (x-y=1) का हल (x=5,\ y=4) है, तो (m) का मान क्या है?

If (3x+my=23) and (x-y=1) have solution (x=5,\ y=4), what is the value of (m)?

Explanation opens after your attempt
Correct Answer

A. (m=2)

Step 1

Concept

Put (x=5,\ y=4) in (3x+my=23). Then (15+4m=23), so (m=2).

Step 2

Why this answer is correct

The correct answer is A. (m=2). Put (x=5,\ y=4) in (3x+my=23). Then (15+4m=23), so (m=2).

Step 3

Exam Tip

(x=5,\ y=4) को (3x+my=23) में रखें। (15+4m=23), इसलिए (m=2)।

Open Question Page
Ask Friends

(kx+6y=12) और (2x+3y=9) का कोई हल न हो, इसके लिए (k) का मान क्या होगा?

For (kx+6y=12) and (2x+3y=9) to have no solution, what should be the value of (k)?

Explanation opens after your attempt
Correct Answer

C. (4)

Step 1

Concept

For no solution, coefficients must be proportional while constants are not. At (k=4), the left sides are proportional but (12) and (9) are not in the same ratio.

Step 2

Why this answer is correct

The correct answer is C. (4). For no solution, coefficients must be proportional while constants are not. At (k=4), the left sides are proportional but (12) and (9) are not in the same ratio.

Step 3

Exam Tip

कोई हल न होने के लिए गुणांक समानुपाती और स्थिरांक असमानुपाती होने चाहिए। (k=4) पर बायां पक्ष समानुपाती है, पर (12) और (9) अनुपात में नहीं हैं।

Open Question Page
Ask Friends

यदि (kx+2y=20) और (x+y=8) का हल (x=4,\ y=4) है, तो (k) का मान क्या है?

If (kx+2y=20) and (x+y=8) have solution (x=4,\ y=4), what is the value of (k)?

Explanation opens after your attempt
Correct Answer

A. (k=3)

Step 1

Concept

Substituting (x=4,\ y=4) gives (4k+8=20). Therefore (k=3).

Step 2

Why this answer is correct

The correct answer is A. (k=3). Substituting (x=4,\ y=4) gives (4k+8=20). Therefore (k=3).

Step 3

Exam Tip

(x=4,\ y=4) रखने पर (4k+8=20) मिलता है। इसलिए (k=3)।

Open Question Page
Ask Friends

किस मान पर (x=2,\ y=3) समीकरण (kx+4y=22) को संतुष्ट करेगा?

For what value will (x=2,\ y=3) satisfy the equation (kx+4y=22)?

Explanation opens after your attempt
Correct Answer

C. (k=5)

Step 1

Concept

Substituting (x=2,\ y=3) gives (2k+12=22). Therefore (k=5).

Step 2

Why this answer is correct

The correct answer is C. (k=5). Substituting (x=2,\ y=3) gives (2k+12=22). Therefore (k=5).

Step 3

Exam Tip

(x=2,\ y=3) रखने पर (2k+12=22) मिलता है। इसलिए (k=5)।

Open Question Page
Ask Friends

यदि (ax+2y=16) और (x+y=7) का हल (x=2,\ y=5) है, तो (a) का मान क्या होगा?

If (ax+2y=16) and (x+y=7) have solution (x=2,\ y=5), what will be the value of (a)?

Explanation opens after your attempt
Correct Answer

C. (3)

Step 1

Concept

Substituting (x=2,\ y=5) gives (2a+10=16). Therefore (a=3).

Step 2

Why this answer is correct

The correct answer is C. (3). Substituting (x=2,\ y=5) gives (2a+10=16). Therefore (a=3).

Step 3

Exam Tip

(x=2,\ y=5) रखने पर (2a+10=16) मिलता है। इसलिए (a=3)।

Open Question Page
Ask Friends

यदि (2x+ky=18) और (x+y=7) का हल (x=4,\ y=3) है, तो (k) का मान क्या है?

If (2x+ky=18) and (x+y=7) have solution (x=4,\ y=3), what is the value of (k)?

Explanation opens after your attempt
Correct Answer

C. \(\frac{10}{3}\)

Step 1

Concept

Put (x=4,\ y=3) in (2x+ky=18). Then (8+3k=18), so \(k=\frac{10}{3}\).

Step 2

Why this answer is correct

The correct answer is C. \(\frac{10}{3}\). Put (x=4,\ y=3) in (2x+ky=18). Then (8+3k=18), so \(k=\frac{10}{3}\).

Step 3

Exam Tip

(x=4,\ y=3) को (2x+ky=18) में रखें। (8+3k=18), इसलिए \(k=\frac{10}{3}\)।

Open Question Page
Ask Friends

यदि (7x+3y=42) और (21x+9y=k) की रेखाएं संपाती हों, तो (k) का मान क्या होगा?

If the lines (7x+3y=42) and (21x+9y=k) are coincident, what will be the value of (k)?

Explanation opens after your attempt
Correct Answer

C. (126)

Step 1

Concept

The second equation must be (3) times the first, so (k=126). In coincident lines, the constant term also changes in the same ratio.

Step 2

Why this answer is correct

The correct answer is C. (126). The second equation must be (3) times the first, so (k=126). In coincident lines, the constant term also changes in the same ratio.

Step 3

Exam Tip

दूसरा समीकरण पहले का (3) गुना होना चाहिए, इसलिए (k=126)। संपाती रेखाओं में स्थिर पद भी उसी अनुपात में बदलता है।

Open Question Page
Ask Friends

यदि (9x+2y=18) और (27x+my=55) की रेखाएं समांतर अलग-अलग हों, तो (m) का मान क्या होगा?

If the lines (9x+2y=18) and (27x+my=55) are distinct parallel lines, what will be the value of (m)?

Explanation opens after your attempt
Correct Answer

C. (6)

Step 1

Concept

For parallel lines, \(\frac{9}{27}=\frac{2}{m}\), so (m=6). Since \(\frac{18}{55}\neq\frac{1}{3}\), the lines are not coincident.

Step 2

Why this answer is correct

The correct answer is C. (6). For parallel lines, \(\frac{9}{27}=\frac{2}{m}\), so (m=6). Since \(\frac{18}{55}\neq\frac{1}{3}\), the lines are not coincident.

Step 3

Exam Tip

समांतर के लिए \(\frac{9}{27}=\frac{2}{m}\), इसलिए (m=6)। क्योंकि \(\frac{18}{55}\neq\frac{1}{3}\), रेखाएं संपाती नहीं हैं।

Open Question Page
Ask Friends

किस मान पर (5x+9y=45) और (10x+18y=k) की रेखाएं समांतर अलग-अलग होंगी?

For which value will (5x+9y=45) and (10x+18y=k) be distinct parallel lines?

Explanation opens after your attempt
Correct Answer

B. (k=88)

Step 1

Concept

The coefficient ratio is \(\frac{1}{2}\), so coincidence needs (k=90). For (k=88), the lines are distinct and parallel.

Step 2

Why this answer is correct

The correct answer is B. (k=88). The coefficient ratio is \(\frac{1}{2}\), so coincidence needs (k=90). For (k=88), the lines are distinct and parallel.

Step 3

Exam Tip

गुणांक का अनुपात \(\frac{1}{2}\) है, इसलिए संपाती होने के लिए (k=90) चाहिए। (k=88) पर रेखाएं समांतर अलग-अलग हैं।

Open Question Page
Ask Friends

यदि (8x+ay=40) और (24x+18y=120) की रेखाएं संपाती हों, तो (a) का मान क्या है?

If the lines (8x+ay=40) and (24x+18y=120) are coincident, what is the value of (a)?

Explanation opens after your attempt
Correct Answer

C. (6)

Step 1

Concept

The second equation is (3) times the first, so (3a=18) and (a=6). Include the constant term in ratio checking.

Step 2

Why this answer is correct

The correct answer is C. (6). The second equation is (3) times the first, so (3a=18) and (a=6). Include the constant term in ratio checking.

Step 3

Exam Tip

दूसरा समीकरण पहले का (3) गुना है, इसलिए (3a=18) और (a=6)। अनुपात जांच में स्थिर पद भी शामिल करें।

Open Question Page
Ask Friends

यदि (3x+ky=21) और (12x+20y=84) अनंत समाधान देते हैं, तो (k) का मान क्या है?

If (3x+ky=21) and (12x+20y=84) give infinitely many solutions, what is the value of (k)?

Explanation opens after your attempt
Correct Answer

C. (5)

Step 1

Concept

The second equation is (4) times the first, so (4k=20) and (k=5). For infinite solutions, the lines must be coincident.

Step 2

Why this answer is correct

The correct answer is C. (5). The second equation is (4) times the first, so (4k=20) and (k=5). For infinite solutions, the lines must be coincident.

Step 3

Exam Tip

दूसरा समीकरण पहले का (4) गुना है, इसलिए (4k=20) और (k=5)। अनंत समाधान के लिए रेखाएं संपाती होनी चाहिए।

Open Question Page
Ask Friends

यदि (4x+7y=28) और (12x+my=84) की रेखाएं संपाती हैं, तो (m) क्या होगा?

If the lines (4x+7y=28) and (12x+my=84) are coincident, what is (m)?

Explanation opens after your attempt
Correct Answer

C. (21)

Step 1

Concept

The second equation is (3) times the first, so (m=21). In a coincident line, the coefficient of (y) also changes in the same ratio.

Step 2

Why this answer is correct

The correct answer is C. (21). The second equation is (3) times the first, so (m=21). In a coincident line, the coefficient of (y) also changes in the same ratio.

Step 3

Exam Tip

दूसरा समीकरण पहले का (3) गुना है, इसलिए (m=21)। संपाती रेखा में (y) का गुणांक भी उसी अनुपात में बदलता है।

Open Question Page
Ask Friends

यदि (ax+12y=48) और (5x+3y=12) संपाती रेखाएं हैं, तो (a) का मान क्या है?

If (ax+12y=48) and (5x+3y=12) are coincident lines, what is the value of (a)?

Explanation opens after your attempt
Correct Answer

C. (20)

Step 1

Concept

The first equation must be (4) times the second, so (a=20). In coincident lines, all terms change by the same multiplier.

Step 2

Why this answer is correct

The correct answer is C. (20). The first equation must be (4) times the second, so (a=20). In coincident lines, all terms change by the same multiplier.

Step 3

Exam Tip

पहला समीकरण दूसरे का (4) गुना होना चाहिए, इसलिए (a=20)। संपाती रेखाओं में सभी पद समान गुणक से बदलते हैं।

Open Question Page
Ask Friends

किस मान पर (8x+3y=27) और (16x+6y=k) का कोई समाधान नहीं होगा?

For which value will (8x+3y=27) and (16x+6y=k) have no solution?

Explanation opens after your attempt
Correct Answer

B. (k=50)

Step 1

Concept

The coefficient ratio is \(\frac{1}{2}\); coincidence needs (k=54). For (k=50), the lines will be distinct and parallel.

Step 2

Why this answer is correct

The correct answer is B. (k=50). The coefficient ratio is \(\frac{1}{2}\); coincidence needs (k=54). For (k=50), the lines will be distinct and parallel.

Step 3

Exam Tip

गुणांक अनुपात \(\frac{1}{2}\) है; संपाती होने के लिए (k=54) चाहिए। (k=50) पर रेखाएं समांतर अलग-अलग होंगी।

Open Question Page
Ask Friends

यदि (5x+4y=p) और (15x+12y=96) की रेखाएं अनंत समाधान देती हैं, तो (p) क्या है?

If (5x+4y=p) and (15x+12y=96) give infinitely many solutions, what is (p)?

Explanation opens after your attempt
Correct Answer

C. (32)

Step 1

Concept

For infinitely many solutions, the second equation must be (3) times the first. Therefore (3p=96) and (p=32).

Step 2

Why this answer is correct

The correct answer is C. (32). For infinitely many solutions, the second equation must be (3) times the first. Therefore (3p=96) and (p=32).

Step 3

Exam Tip

अनंत समाधान के लिए दूसरा समीकरण पहले का (3) गुना होना चाहिए। इसलिए (3p=96) और (p=32)।

Open Question Page
Ask Friends

किस मान पर (3x+ay=15) और (9x+12y=47) की रेखाएं समांतर अलग-अलग होंगी?

For which value will the lines (3x+ay=15) and (9x+12y=47) be distinct and parallel?

Explanation opens after your attempt
Correct Answer

C. (a=4)

Step 1

Concept

For parallel lines, \(\frac{3}{9}=\frac{a}{12}\), so (a=4). Since \(\frac{15}{47}\neq\frac{1}{3}\), they will not be coincident.

Step 2

Why this answer is correct

The correct answer is C. (a=4). For parallel lines, \(\frac{3}{9}=\frac{a}{12}\), so (a=4). Since \(\frac{15}{47}\neq\frac{1}{3}\), they will not be coincident.

Step 3

Exam Tip

समांतर के लिए \(\frac{3}{9}=\frac{a}{12}\), इसलिए (a=4)। चूंकि \(\frac{15}{47}\neq\frac{1}{3}\), वे संपाती नहीं होंगी।

Open Question Page
Ask Friends

यदि (6x+ky=30) और (18x+15y=90) संपाती रेखाएं हों, तो (k) का मान क्या है?

If (6x+ky=30) and (18x+15y=90) are coincident lines, what is the value of (k)?

Explanation opens after your attempt
Correct Answer

C. (5)

Step 1

Concept

The second equation is (3) times the first, so (3k=15) and (k=5). In coincident lines, all terms are in the same ratio.

Step 2

Why this answer is correct

The correct answer is C. (5). The second equation is (3) times the first, so (3k=15) and (k=5). In coincident lines, all terms are in the same ratio.

Step 3

Exam Tip

दूसरा समीकरण पहले का (3) गुना है, इसलिए (3k=15) और (k=5)। संपाती रेखाओं में सभी पद समान अनुपात में होते हैं।

Open Question Page
Ask Friends

यदि (7x+by=21) और (14x+10y=50) की रेखाएं समांतर अलग-अलग हों, तो (b) का मान क्या होगा?

If the lines (7x+by=21) and (14x+10y=50) are distinct parallel lines, what will be the value of (b)?

Explanation opens after your attempt
Correct Answer

B. (5)

Step 1

Concept

For parallel lines, \(\frac{7}{14}=\frac{b}{10}\), so (b=5). Since \(\frac{21}{50}\neq\frac{1}{2}\), the lines are not coincident.

Step 2

Why this answer is correct

The correct answer is B. (5). For parallel lines, \(\frac{7}{14}=\frac{b}{10}\), so (b=5). Since \(\frac{21}{50}\neq\frac{1}{2}\), the lines are not coincident.

Step 3

Exam Tip

समांतर के लिए \(\frac{7}{14}=\frac{b}{10}\), इसलिए (b=5)। क्योंकि \(\frac{21}{50}\neq\frac{1}{2}\), रेखाएं संपाती नहीं हैं।

Open Question Page
Ask Friends

किस मान पर (3x+7y=21) और (6x+14y=k) की रेखाएं समांतर अलग-अलग होंगी?

For which value will (3x+7y=21) and (6x+14y=k) be distinct parallel lines?

Explanation opens after your attempt
Correct Answer

B. (k=40)

Step 1

Concept

The coefficient ratio is \(\frac{1}{2}\), so coincidence needs (k=42). For (k=40), the lines are distinct and parallel.

Step 2

Why this answer is correct

The correct answer is B. (k=40). The coefficient ratio is \(\frac{1}{2}\), so coincidence needs (k=42). For (k=40), the lines are distinct and parallel.

Step 3

Exam Tip

गुणांक का अनुपात \(\frac{1}{2}\) है, इसलिए संपाती होने के लिए (k=42) चाहिए। (k=40) पर रेखाएं समांतर अलग-अलग हैं।

Open Question Page
Ask Friends

यदि (6x+ay=30) और (18x+12y=90) की रेखाएं संपाती हों, तो (a) का मान क्या है?

If the lines (6x+ay=30) and (18x+12y=90) are coincident, what is the value of (a)?

Explanation opens after your attempt
Correct Answer

C. (4)

Step 1

Concept

The second equation is (3) times the first, so (3a=12) and (a=4). Include the constant term in ratio checking.

Step 2

Why this answer is correct

The correct answer is C. (4). The second equation is (3) times the first, so (3a=12) and (a=4). Include the constant term in ratio checking.

Step 3

Exam Tip

दूसरा समीकरण पहले का (3) गुना है, इसलिए (3a=12) और (a=4)। अनुपात जांच में स्थिर पद भी शामिल करें।

Open Question Page
Ask Friends

यदि (2x+ky=18) और (6x+12y=54) अनंत समाधान देते हैं, तो (k) का मान क्या है?

If (2x+ky=18) and (6x+12y=54) give infinitely many solutions, what is the value of (k)?

Explanation opens after your attempt
Correct Answer

C. (4)

Step 1

Concept

The second equation is (3) times the first, so (3k=12) and (k=4). For infinite solutions, the lines must be coincident.

Step 2

Why this answer is correct

The correct answer is C. (4). The second equation is (3) times the first, so (3k=12) and (k=4). For infinite solutions, the lines must be coincident.

Step 3

Exam Tip

दूसरा समीकरण पहले का (3) गुना है, इसलिए (3k=12) और (k=4)। अनंत समाधान के लिए रेखाएं संपाती होनी चाहिए।

Open Question Page
Ask Friends

यदि (3x+5y=25) और (6x+my=50) की रेखाएं संपाती हैं, तो (m) क्या होगा?

If the lines (3x+5y=25) and (6x+my=50) are coincident, what is (m)?

Explanation opens after your attempt
Correct Answer

C. (10)

Step 1

Concept

The second equation is (2) times the first, so (m=10). In a coincident line, the coefficient of (y) also changes in the same ratio.

Step 2

Why this answer is correct

The correct answer is C. (10). The second equation is (2) times the first, so (m=10). In a coincident line, the coefficient of (y) also changes in the same ratio.

Step 3

Exam Tip

दूसरा समीकरण पहले का (2) गुना है, इसलिए (m=10)। संपाती रेखा में (y) का गुणांक भी उसी अनुपात में बदलता है।

Open Question Page
Ask Friends

यदि (ax+9y=27) और (4x+3y=9) संपाती रेखाएं हैं, तो (a) का मान क्या है?

If (ax+9y=27) and (4x+3y=9) are coincident lines, what is the value of (a)?

Explanation opens after your attempt
Correct Answer

C. (12)

Step 1

Concept

The first equation must be (3) times the second, so (a=12). In coincident lines, all terms change by the same multiplier.

Step 2

Why this answer is correct

The correct answer is C. (12). The first equation must be (3) times the second, so (a=12). In coincident lines, all terms change by the same multiplier.

Step 3

Exam Tip

पहला समीकरण दूसरे का (3) गुना होना चाहिए, इसलिए (a=12)। संपाती रेखाओं में सभी पद समान गुणक से बदलते हैं।

Open Question Page
Ask Friends

किस मान पर (6x+y=17) और (12x+2y=k) का कोई समाधान नहीं होगा?

For which value will (6x+y=17) and (12x+2y=k) have no solution?

Explanation opens after your attempt
Correct Answer

B. (k=30)

Step 1

Concept

The coefficient ratio is \(\frac{1}{2}\); coincidence needs (k=34). For (k=30), the lines will be distinct and parallel.

Step 2

Why this answer is correct

The correct answer is B. (k=30). The coefficient ratio is \(\frac{1}{2}\); coincidence needs (k=34). For (k=30), the lines will be distinct and parallel.

Step 3

Exam Tip

गुणांक अनुपात \(\frac{1}{2}\) है; संपाती होने के लिए (k=34) चाहिए। (k=30) पर रेखाएं समांतर अलग-अलग होंगी।

Open Question Page
Ask Friends

यदि (4x+3y=p) और (8x+6y=42) की रेखाएं अनंत समाधान देती हैं, तो (p) क्या है?

If (4x+3y=p) and (8x+6y=42) give infinitely many solutions, what is (p)?

Explanation opens after your attempt
Correct Answer

C. (21)

Step 1

Concept

For infinitely many solutions, the second equation must be (2) times the first. Therefore (2p=42) and (p=21).

Step 2

Why this answer is correct

The correct answer is C. (21). For infinitely many solutions, the second equation must be (2) times the first. Therefore (2p=42) and (p=21).

Step 3

Exam Tip

अनंत समाधान के लिए दूसरा समीकरण पहले का (2) गुना होना चाहिए। इसलिए (2p=42) और (p=21)।

Open Question Page
Ask Friends