(kx+6y=12) और (2x+3y=9) का कोई हल न हो, इसके लिए (k) का मान क्या होगा?
For (kx+6y=12) and (2x+3y=9) to have no solution, what should be the value of (k)?
Explanation opens after your attempt
C. (4)
Concept
For no solution, coefficients must be proportional while constants are not. At (k=4), the left sides are proportional but (12) and (9) are not in the same ratio.
Why this answer is correct
The correct answer is C. (4). For no solution, coefficients must be proportional while constants are not. At (k=4), the left sides are proportional but (12) and (9) are not in the same ratio.
Exam Tip
कोई हल न होने के लिए गुणांक समानुपाती और स्थिरांक असमानुपाती होने चाहिए। (k=4) पर बायां पक्ष समानुपाती है, पर (12) और (9) अनुपात में नहीं हैं।
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