Concept-wise Practice

parallel distinct MCQ Questions for Class 10

parallel distinct se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

8 questions tagged with parallel distinct.

Question 1/8 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 54

किस मान पर (5x+9y=45) और (10x+18y=k) की रेखाएं समांतर अलग-अलग होंगी?

For which value will (5x+9y=45) and (10x+18y=k) be distinct parallel lines?

Explanation opens after your attempt
Correct Answer

B. (k=88)

Step 1

Concept

The coefficient ratio is \(\frac{1}{2}\), so coincidence needs (k=90). For (k=88), the lines are distinct and parallel.

Step 2

Why this answer is correct

The correct answer is B. (k=88). The coefficient ratio is \(\frac{1}{2}\), so coincidence needs (k=90). For (k=88), the lines are distinct and parallel.

Step 3

Exam Tip

गुणांक का अनुपात \(\frac{1}{2}\) है, इसलिए संपाती होने के लिए (k=90) चाहिए। (k=88) पर रेखाएं समांतर अलग-अलग हैं।

Login to save your score, XP, coins and progress.

Open Question Page
Ask Friends
Question 2/8 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 54

किस मान पर (3x+ay=15) और (9x+12y=47) की रेखाएं समांतर अलग-अलग होंगी?

For which value will the lines (3x+ay=15) and (9x+12y=47) be distinct and parallel?

Explanation opens after your attempt
Correct Answer

C. (a=4)

Step 1

Concept

For parallel lines, \(\frac{3}{9}=\frac{a}{12}\), so (a=4). Since \(\frac{15}{47}\neq\frac{1}{3}\), they will not be coincident.

Step 2

Why this answer is correct

The correct answer is C. (a=4). For parallel lines, \(\frac{3}{9}=\frac{a}{12}\), so (a=4). Since \(\frac{15}{47}\neq\frac{1}{3}\), they will not be coincident.

Step 3

Exam Tip

समांतर के लिए \(\frac{3}{9}=\frac{a}{12}\), इसलिए (a=4)। चूंकि \(\frac{15}{47}\neq\frac{1}{3}\), वे संपाती नहीं होंगी।

Login to save your score, XP, coins and progress.

Open Question Page
Ask Friends
Question 3/8 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 53

किस मान पर (3x+7y=21) और (6x+14y=k) की रेखाएं समांतर अलग-अलग होंगी?

For which value will (3x+7y=21) and (6x+14y=k) be distinct parallel lines?

Explanation opens after your attempt
Correct Answer

B. (k=40)

Step 1

Concept

The coefficient ratio is \(\frac{1}{2}\), so coincidence needs (k=42). For (k=40), the lines are distinct and parallel.

Step 2

Why this answer is correct

The correct answer is B. (k=40). The coefficient ratio is \(\frac{1}{2}\), so coincidence needs (k=42). For (k=40), the lines are distinct and parallel.

Step 3

Exam Tip

गुणांक का अनुपात \(\frac{1}{2}\) है, इसलिए संपाती होने के लिए (k=42) चाहिए। (k=40) पर रेखाएं समांतर अलग-अलग हैं।

Login to save your score, XP, coins and progress.

Open Question Page
Ask Friends
Question 4/8 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 53

किस मान पर (4x+ay=16) और (8x+10y=35) की रेखाएं समांतर अलग-अलग होंगी?

For which value will the lines (4x+ay=16) and (8x+10y=35) be distinct and parallel?

Explanation opens after your attempt
Correct Answer

B. (a=5)

Step 1

Concept

For parallel lines, \(\frac{4}{8}=\frac{a}{10}\), so (a=5). Since \(\frac{16}{35}\neq\frac{1}{2}\), they will not be coincident.

Step 2

Why this answer is correct

The correct answer is B. (a=5). For parallel lines, \(\frac{4}{8}=\frac{a}{10}\), so (a=5). Since \(\frac{16}{35}\neq\frac{1}{2}\), they will not be coincident.

Step 3

Exam Tip

समांतर के लिए \(\frac{4}{8}=\frac{a}{10}\), इसलिए (a=5)। चूंकि \(\frac{16}{35}\neq\frac{1}{2}\), वे संपाती नहीं होंगी।

Login to save your score, XP, coins and progress.

Open Question Page
Ask Friends
Question 5/8 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 52

किस मान पर (x+4y=12) और (2x+8y=k) की रेखाएं समांतर अलग-अलग होंगी?

For which value will (x+4y=12) and (2x+8y=k) be distinct parallel lines?

Explanation opens after your attempt
Correct Answer

B. (k=20)

Step 1

Concept

The coefficient ratio is \(\frac{1}{2}\), so coincidence needs (k=24). For (k=20), the lines are distinct and parallel.

Step 2

Why this answer is correct

The correct answer is B. (k=20). The coefficient ratio is \(\frac{1}{2}\), so coincidence needs (k=24). For (k=20), the lines are distinct and parallel.

Step 3

Exam Tip

गुणांक का अनुपात \(\frac{1}{2}\) है, इसलिए संपाती होने के लिए (k=24) चाहिए। (k=20) पर रेखाएं समांतर अलग-अलग हैं।

Login to save your score, XP, coins and progress.

Open Question Page
Ask Friends
Question 6/8 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 52

किस मान पर (2x+ay=10) और (6x+9y=31) की रेखाएं समांतर अलग-अलग होंगी?

For which value will (2x+ay=10) and (6x+9y=31) be distinct parallel lines?

Explanation opens after your attempt
Correct Answer

B. (a=3)

Step 1

Concept

For parallel lines, \(\frac{2}{6}=\frac{a}{9}\), so (a=3). Since \(\frac{10}{31}\neq\frac{1}{3}\), the lines are not coincident.

Step 2

Why this answer is correct

The correct answer is B. (a=3). For parallel lines, \(\frac{2}{6}=\frac{a}{9}\), so (a=3). Since \(\frac{10}{31}\neq\frac{1}{3}\), the lines are not coincident.

Step 3

Exam Tip

समांतर के लिए \(\frac{2}{6}=\frac{a}{9}\), इसलिए (a=3)। चूंकि \(\frac{10}{31}\neq\frac{1}{3}\), रेखाएं संपाती नहीं होंगी।

Login to save your score, XP, coins and progress.

Open Question Page
Ask Friends
Question 7/8 Hard Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 54

ग्राफ में रेखाएं (2x+y=7) और (6x+3y=20) कैसी होंगी?

How will the lines (2x+y=7) and (6x+3y=20) appear on a graph?

Explanation opens after your attempt
Correct Answer

B. समांतर अलग-अलगParallel distinct

Step 1

Concept

\(\frac{2}{6}=\frac{1}{3}\neq\frac{7}{20}\), so the lines are distinct and parallel. This case gives no solution.

Step 2

Why this answer is correct

The correct answer is B. समांतर अलग-अलग / Parallel distinct. \(\frac{2}{6}=\frac{1}{3}\neq\frac{7}{20}\), so the lines are distinct and parallel. This case gives no solution.

Step 3

Exam Tip

\(\frac{2}{6}=\frac{1}{3}\neq\frac{7}{20}\), इसलिए रेखाएं समांतर अलग-अलग हैं। यह स्थिति कोई समाधान नहीं देती।

Login to save your score, XP, coins and progress.

Open Question Page
Ask Friends
Question 8/8 Hard Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 54

यदि (3x+2y=7) और (6x+4y=k) की रेखाएं समांतर अलग-अलग हों, तो (k) के लिए कौन सा विकल्प सही है?

If the lines (3x+2y=7) and (6x+4y=k) are parallel and distinct, which option is correct for (k)?

Explanation opens after your attempt
Correct Answer

B. (7)

Step 1

Concept

The coefficient ratio is \(\frac{3}{6}=\frac{2}{4}=\frac{1}{2}\); for coincidence, (k=14) is needed. With (k=7), the lines are parallel and distinct.

Step 2

Why this answer is correct

The correct answer is B. (7). The coefficient ratio is \(\frac{3}{6}=\frac{2}{4}=\frac{1}{2}\); for coincidence, (k=14) is needed. With (k=7), the lines are parallel and distinct.

Step 3

Exam Tip

गुणांक अनुपात \(\frac{3}{6}=\frac{2}{4}=\frac{1}{2}\) है; संपाती होने के लिए (k=14) चाहिए। (k=7) होने पर रेखाएं समांतर अलग-अलग होंगी।

Login to save your score, XP, coins and progress.

Open Question Page
Ask Friends
Student Class Required

Select your class first

Quiz questions, daily challenge and practice pages will open according to your selected class. Class 11/12 ke liye stream bhi select karein.