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For which value will (2x+ay=10) and (6x+9y=31) be distinct parallel lines?

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Answer and explanation

Correct answer: (a=3)

For parallel lines, (\frac{2}{6}=\frac{a}{9}), so (a=3). Since (\frac{10}{31}\neq\frac{1}{3}), the lines are not coincident.

Related tags

Graphical MethodParameterParallel DistinctNo Solution

Frequently asked questions

What is the correct answer to this question?

(a=3)

Why is this the correct answer?

For parallel lines, (\frac{2}{6}=\frac{a}{9}), so (a=3). Since (\frac{10}{31}\neq\frac{1}{3}), the lines are not coincident.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Pair of Linear Equations in Two Variables. Topic: Graphical method of finding solutions..

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