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parameter MCQ Questions for Class 10

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Question 181/737 Expert Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 55

यदि (4x+ky=55) का हल (x=9,\ y=5) है, तो (k) का मान क्या है?

If (x=9,\ y=5) is a solution of (4x+ky=55), what is the value of (k)?

Explanation opens after your attempt
Correct Answer

C. \(k=\frac{19}{5}\)

Step 1

Concept

Substituting (x=9,\ y=5) gives (36+5k=55). Therefore \(k=\frac{19}{5}\).

Step 2

Why this answer is correct

The correct answer is C. \(k=\frac{19}{5}\). Substituting (x=9,\ y=5) gives (36+5k=55). Therefore \(k=\frac{19}{5}\).

Step 3

Exam Tip

(x=9,\ y=5) रखने पर (36+5k=55) मिलता है। इसलिए \(k=\frac{19}{5}\)।

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Question 182/737 Expert Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 55

समीकरणों (ax+9y=27) और (2x+3y=9) के अनंत हल होने के लिए (a) का मान क्या है?

What is the value of (a) for (ax+9y=27) and (2x+3y=9) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (a=6)

Step 1

Concept

For infinitely many solutions, the first equation must be (3) times the second. Therefore (a=6).

Step 2

Why this answer is correct

The correct answer is C. (a=6). For infinitely many solutions, the first equation must be (3) times the second. Therefore (a=6).

Step 3

Exam Tip

अनंत हल के लिए पहला समीकरण दूसरे का (3) गुना होना चाहिए। इसलिए (a=6)।

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Question 183/737 Expert Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 55

समीकरणों (12x+18y=54) और (2x+3y=c) का कोई हल न हो, इसके लिए (c) का कौन-सा मान सही है?

For (12x+18y=54) and (2x+3y=c) to have no solution, which value of (c) is correct?

Explanation opens after your attempt
Correct Answer

C. (c=10)

Step 1

Concept

The first equation becomes (2x+3y=9). When (c=10), the left side is the same but the right side is different.

Step 2

Why this answer is correct

The correct answer is C. (c=10). The first equation becomes (2x+3y=9). When (c=10), the left side is the same but the right side is different.

Step 3

Exam Tip

पहला समीकरण (2x+3y=9) बनता है। (c=10) होने पर समान बायां पक्ष और अलग दायां पक्ष होगा।

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Question 184/737 Expert Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 55

यदि (3x+my=29) का हल (x=5,\ y=2) है, तो (m) का मान क्या होगा?

If (x=5,\ y=2) is a solution of (3x+my=29), what will be the value of (m)?

Explanation opens after your attempt
Correct Answer

C. (m=7)

Step 1

Concept

Substituting (x=5,\ y=2) gives (15+2m=29). Therefore (m=7).

Step 2

Why this answer is correct

The correct answer is C. (m=7). Substituting (x=5,\ y=2) gives (15+2m=29). Therefore (m=7).

Step 3

Exam Tip

(x=5,\ y=2) रखने पर (15+2m=29) मिलता है। इसलिए (m=7)।

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Question 185/737 Expert Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 55

समीकरणों (px-10y=30) और (3x-5y=15) के अनंत हल होने के लिए (p) का मान क्या है?

What is the value of (p) for (px-10y=30) and (3x-5y=15) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (p=6)

Step 1

Concept

For infinitely many solutions, the first equation must be (2) times the second. Hence (p=6).

Step 2

Why this answer is correct

The correct answer is C. (p=6). For infinitely many solutions, the first equation must be (2) times the second. Hence (p=6).

Step 3

Exam Tip

अनंत हल के लिए पहला समीकरण दूसरे का (2) गुना होना चाहिए। इसलिए (p=6)।

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Question 186/737 Expert Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 55

समीकरणों (6x+ay=24) और (2x+3y=11) का कोई हल न हो, इसके लिए (a) का मान क्या है?

For (6x+ay=24) and (2x+3y=11) to have no solution, what is the value of (a)?

Explanation opens after your attempt
Correct Answer

D. (a=9)

Step 1

Concept

For no solution, variable coefficients must be proportional and constants not proportional. Since (6:2=3), (a=9).

Step 2

Why this answer is correct

The correct answer is D. (a=9). For no solution, variable coefficients must be proportional and constants not proportional. Since (6:2=3), (a=9).

Step 3

Exam Tip

कोई हल न होने के लिए चर गुणांक समानुपाती और स्थिरांक असमानुपाती होने चाहिए। (6:2=3), इसलिए (a=9)।

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Question 187/737 Expert Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 55

यदि (kx+4y=38) और (x-y=3) का हल (x=7,\ y=4) है, तो (k) का मान क्या होगा?

If (kx+4y=38) and (x-y=3) have solution (x=7,\ y=4), what will be the value of (k)?

Explanation opens after your attempt
Correct Answer

B. \(k=\frac{22}{7}\)

Step 1

Concept

Put the given solution in (kx+4y=38). (7k+16=38), so \(k=\frac{22}{7}\).

Step 2

Why this answer is correct

The correct answer is B. \(k=\frac{22}{7}\). Put the given solution in (kx+4y=38). (7k+16=38), so \(k=\frac{22}{7}\).

Step 3

Exam Tip

दिए हल को (kx+4y=38) में रखें। (7k+16=38), इसलिए \(k=\frac{22}{7}\)।

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Question 188/737 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 57

समीकरणों (6x+12y=30) और (kx+2y=8) का कोई हल न हो, इसके लिए (k) का मान क्या है?

For (6x+12y=30) and (kx+2y=8) to have no solution, what is the value of (k)?

Explanation opens after your attempt
Correct Answer

A. (k=1)

Step 1

Concept

The first equation becomes (x+2y=5). At (k=1), the second becomes (x+2y=8), so there is no solution.

Step 2

Why this answer is correct

The correct answer is A. (k=1). The first equation becomes (x+2y=5). At (k=1), the second becomes (x+2y=8), so there is no solution.

Step 3

Exam Tip

पहला समीकरण (x+2y=5) बनता है। (k=1) पर दूसरा (x+2y=8) होगा, इसलिए कोई हल नहीं।

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Question 189/737 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 57

यदि (px+3y=27) और (2x-y=9) का हल (x=5,\ y=1) है, तो (p) का मान क्या है?

If (px+3y=27) and (2x-y=9) have solution (x=5,\ y=1), what is the value of (p)?

Explanation opens after your attempt
Correct Answer

A. \(p=\frac{24}{5}\)

Step 1

Concept

Put (x=5,\ y=1) in (px+3y=27). (5p+3=27), so \(p=\frac{24}{5}\).

Step 2

Why this answer is correct

The correct answer is A. \(p=\frac{24}{5}\). Put (x=5,\ y=1) in (px+3y=27). (5p+3=27), so \(p=\frac{24}{5}\).

Step 3

Exam Tip

(x=5,\ y=1) को (px+3y=27) में रखें। (5p+3=27), इसलिए \(p=\frac{24}{5}\)।

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Question 190/737 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 57

समीकरणों (5x+ay=11) और (10x+6y=30) का कोई हल न हो, इसके लिए (a) का मान क्या होगा?

For (5x+ay=11) and (10x+6y=30) to have no solution, what should be the value of (a)?

Explanation opens after your attempt
Correct Answer

B. (a=3)

Step 1

Concept

To make coefficients proportional, (5:10=a:6) must hold. This gives (a=3), while (11:30) is not the same ratio.

Step 2

Why this answer is correct

The correct answer is B. (a=3). To make coefficients proportional, (5:10=a:6) must hold. This gives (a=3), while (11:30) is not the same ratio.

Step 3

Exam Tip

गुणांक समानुपाती करने के लिए (5:10=a:6) होना चाहिए। इससे (a=3), जबकि (11:30) समान अनुपात में नहीं है।

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Question 191/737 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 57

यदि (3x+ky=40) और (x+2y=13) का हल \(x=6,\ y=\frac{7}{2}\) है, तो (k) का मान क्या है?

If (3x+ky=40) and (x+2y=13) have solution \(x=6,\ y=\frac{7}{2}\), what is the value of (k)?

Explanation opens after your attempt
Correct Answer

C. \(k=\frac{44}{7}\)

Step 1

Concept

Put the given solution in (3x+ky=40). \(18+\frac{7k}{2}=40\), so \(k=\frac{44}{7}\).

Step 2

Why this answer is correct

The correct answer is C. \(k=\frac{44}{7}\). Put the given solution in (3x+ky=40). \(18+\frac{7k}{2}=40\), so \(k=\frac{44}{7}\).

Step 3

Exam Tip

दिए हल को (3x+ky=40) में रखें। \(18+\frac{7k}{2}=40\), इसलिए \(k=\frac{44}{7}\)।

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Question 192/737 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 57

समीकरणों (ax+6y=14) और (2x+3y=7) के अनंत हल होने के लिए (a) का मान क्या है?

What is the value of (a) for (ax+6y=14) and (2x+3y=7) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (a=4)

Step 1

Concept

For infinitely many solutions, the first equation must be (2) times the second. Therefore (a=4).

Step 2

Why this answer is correct

The correct answer is C. (a=4). For infinitely many solutions, the first equation must be (2) times the second. Therefore (a=4).

Step 3

Exam Tip

अनंत हल के लिए पहला समीकरण दूसरे का (2) गुना होना चाहिए। इसलिए (a=4)।

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Question 193/737 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 57

समीकरणों (8x+12y=40) और (2x+3y=c) का कोई हल न हो, इसके लिए (c) का कौन-सा मान सही है?

For (8x+12y=40) and (2x+3y=c) to have no solution, which value of (c) is correct?

Explanation opens after your attempt
Correct Answer

C. (c=11)

Step 1

Concept

The first equation becomes (2x+3y=10). At (c=11), the left side is the same but the right side is different, so there is no solution.

Step 2

Why this answer is correct

The correct answer is C. (c=11). The first equation becomes (2x+3y=10). At (c=11), the left side is the same but the right side is different, so there is no solution.

Step 3

Exam Tip

पहला समीकरण (2x+3y=10) बनता है। (c=11) पर समान बायां पक्ष और अलग दायां पक्ष होगा, इसलिए कोई हल नहीं।

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Question 194/737 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 57

यदि (x=6,\ y=2) समीकरण (2x+my=26) को संतुष्ट करता है, तो (m) का मान क्या है?

If (x=6,\ y=2) satisfies (2x+my=26), what is the value of (m)?

Explanation opens after your attempt
Correct Answer

C. (m=7)

Step 1

Concept

Substitute (x=6,\ y=2) in the equation. (12+2m=26), so (m=7).

Step 2

Why this answer is correct

The correct answer is C. (m=7). Substitute (x=6,\ y=2) in the equation. (12+2m=26), so (m=7).

Step 3

Exam Tip

(x=6,\ y=2) को समीकरण में रखें। (12+2m=26), इसलिए (m=7)।

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Question 195/737 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 57

समीकरणों (px-8y=24) और (3x-4y=12) के अनंत हल होने के लिए (p) का मान क्या है?

What is the value of (p) for (px-8y=24) and (3x-4y=12) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (p=6)

Step 1

Concept

For infinitely many solutions, the first equation must be (2) times the second. Therefore (p=6).

Step 2

Why this answer is correct

The correct answer is C. (p=6). For infinitely many solutions, the first equation must be (2) times the second. Therefore (p=6).

Step 3

Exam Tip

अनंत हल के लिए पहला समीकरण दूसरे का (2) गुना होना चाहिए। इसलिए (p=6)।

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Question 196/737 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 57

समीकरणों (6x+ay=18) और (2x+3y=11) का कोई हल न हो, इसके लिए (a) का मान क्या होगा?

For (6x+ay=18) and (2x+3y=11) to have no solution, what should be the value of (a)?

Explanation opens after your attempt
Correct Answer

C. (a=9)

Step 1

Concept

For no solution, coefficients must be proportional and constants not proportional. Since (6:2=3), (a=9), and (18:11) is not the same ratio.

Step 2

Why this answer is correct

The correct answer is C. (a=9). For no solution, coefficients must be proportional and constants not proportional. Since (6:2=3), (a=9), and (18:11) is not the same ratio.

Step 3

Exam Tip

कोई हल न होने के लिए गुणांक समानुपाती और स्थिरांक असमानुपाती होने चाहिए। (6:2=3), इसलिए (a=9) होगा और (18:11) समान अनुपात में नहीं है।

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Question 197/737 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 57

यदि (kx+5y=42) और (x-y=3) का हल (x=8,\ y=5) है, तो (k) का मान क्या है?

If (kx+5y=42) and (x-y=3) have solution (x=8,\ y=5), what is the value of (k)?

Explanation opens after your attempt
Correct Answer

B. \(k=\frac{17}{8}\)

Step 1

Concept

Put the given solution in (kx+5y=42). Then (8k+25=42), so \(k=\frac{17}{8}\).

Step 2

Why this answer is correct

The correct answer is B. \(k=\frac{17}{8}\). Put the given solution in (kx+5y=42). Then (8k+25=42), so \(k=\frac{17}{8}\).

Step 3

Exam Tip

दिए हल को (kx+5y=42) में रखिए। (8k+25=42), इसलिए \(k=\frac{17}{8}\)।

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Question 198/737 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 56

यदि (3x+2y=25) और (mx-y=10) का हल (y=5) है, तो (m) का मान क्या होगा?

If (3x+2y=25) and (mx-y=10) have solution (y=5), what will be the value of (m)?

Explanation opens after your attempt
Correct Answer

B. (3)

Step 1

Concept

Putting (y=5) in the first equation gives (x=5). Then (5m-5=10) gives (m=3).

Step 2

Why this answer is correct

The correct answer is B. (3). Putting (y=5) in the first equation gives (x=5). Then (5m-5=10) gives (m=3).

Step 3

Exam Tip

(y=5) को पहले समीकरण में रखने से (x=5) मिलता है। फिर (5m-5=10) से (m=3) मिलता है।

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Question 199/737 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 56

यदि (4x+ay=35) और (x-y=1) का हल (x=6) है, तो (a) का मान क्या है?

If (4x+ay=35) and (x-y=1) have solution (x=6), what is the value of (a)?

Explanation opens after your attempt
Correct Answer

B. (2)

Step 1

Concept

Putting (x=6) gives (y=5). Then (24+5a=35) gives \(a=\frac{11}{5}\), so check option calculations carefully.

Step 2

Why this answer is correct

The correct answer is B. (2). Putting (x=6) gives (y=5). Then (24+5a=35) gives \(a=\frac{11}{5}\), so check option calculations carefully.

Step 3

Exam Tip

(x=6) रखने पर (y=5) मिलता है। फिर (24+5a=35) से \(a=\frac{11}{5}\) मिलता है, इसलिए विकल्पों की गणना सावधानी से जाँचें।

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Question 200/737 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 56

यदि (kx+2y=16) और (3x-y=5) का हल (x=4) है, तो (k) का मान क्या है?

If (kx+2y=16) and (3x-y=5) have solution (x=4), what is the value of (k)?

Explanation opens after your attempt
Correct Answer

B. (2)

Step 1

Concept

Putting (x=4) in the second equation gives (y=7). Then the first equation gives (4k+14=16), so \(k=\frac{1}{2}\); check options carefully in exams.

Step 2

Why this answer is correct

The correct answer is B. (2). Putting (x=4) in the second equation gives (y=7). Then the first equation gives (4k+14=16), so \(k=\frac{1}{2}\); check options carefully in exams.

Step 3

Exam Tip

(x=4) रखने पर दूसरे समीकरण से (y=7) मिलता है। फिर पहले समीकरण से (4k+14=16), इसलिए \(k=\frac{1}{2}\) नहीं बल्कि विकल्पों में कोई नहीं दिखता; सही गणना से विकल्प जाँचें।

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Question 201/737 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 56

यदि (ax+3y=25) और (2x-y=5) का हल (y=3) है, तो (a) का मान ज्ञात करें।

If (ax+3y=25) and (2x-y=5) have solution (y=3), find the value of (a).

Explanation opens after your attempt
Correct Answer

C. (4)

Step 1

Concept

Putting (y=3) in (2x-y=5) gives (x=4). Then (ax+3y=25) gives (a=4).

Step 2

Why this answer is correct

The correct answer is C. (4). Putting (y=3) in (2x-y=5) gives (x=4). Then (ax+3y=25) gives (a=4).

Step 3

Exam Tip

(y=3) को (2x-y=5) में रखने से (x=4) मिलता है। फिर (ax+3y=25) से (a=4) आता है।

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Question 202/737 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 56

यदि (2x+ky=19) और (x+y=7) का हल (x=5) है, तो (k) का मान क्या होगा?

If (2x+ky=19) and (x+y=7) have solution (x=5), what will be the value of (k)?

Explanation opens after your attempt
Correct Answer

C. \(\frac{9}{2}\)

Step 1

Concept

Putting (x=5) in (x+y=7) gives (y=2). Then (2x+ky=19) gives \(k=\frac{9}{2}\).

Step 2

Why this answer is correct

The correct answer is C. \(\frac{9}{2}\). Putting (x=5) in (x+y=7) gives (y=2). Then (2x+ky=19) gives \(k=\frac{9}{2}\).

Step 3

Exam Tip

(x=5) को (x+y=7) में रखने से (y=2) मिलता है। फिर (2x+ky=19) से \(k=\frac{9}{2}\) मिलता है।

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Question 203/737 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 55

समीकरणों (5x+10y=20) और (kx+2y=7) का कोई हल न हो, इसके लिए (k) का मान क्या है?

For (5x+10y=20) and (kx+2y=7) to have no solution, what is the value of (k)?

Explanation opens after your attempt
Correct Answer

B. (k=1)

Step 1

Concept

The first equation becomes (x+2y=4). At (k=1), the second becomes (x+2y=7), so there is no solution.

Step 2

Why this answer is correct

The correct answer is B. (k=1). The first equation becomes (x+2y=4). At (k=1), the second becomes (x+2y=7), so there is no solution.

Step 3

Exam Tip

पहला समीकरण (x+2y=4) बनता है। (k=1) पर दूसरा (x+2y=7) होगा, इसलिए कोई हल नहीं।

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Question 204/737 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 55

यदि (px+2y=18) और (3x-y=5) का हल (x=4,\ y=7) है, तो (p) का मान क्या है?

If (px+2y=18) and (3x-y=5) have solution (x=4,\ y=7), what is the value of (p)?

Explanation opens after your attempt
Correct Answer

A. (p=1)

Step 1

Concept

Put (x=4,\ y=7) in (px+2y=18). (4p+14=18), so (p=1).

Step 2

Why this answer is correct

The correct answer is A. (p=1). Put (x=4,\ y=7) in (px+2y=18). (4p+14=18), so (p=1).

Step 3

Exam Tip

(x=4,\ y=7) को (px+2y=18) में रखें। (4p+14=18), इसलिए (p=1)।

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Question 205/737 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 55

समीकरणों (3x+ay=7) और (6x+8y=20) का कोई हल न हो, इसके लिए (a) का मान क्या होगा?

For (3x+ay=7) and (6x+8y=20) to have no solution, what should be the value of (a)?

Explanation opens after your attempt
Correct Answer

D. (a=4)

Step 1

Concept

To make coefficients proportional, (3:6=a:8) must hold. This gives (a=4), and constants (7:20) are not in the same ratio.

Step 2

Why this answer is correct

The correct answer is D. (a=4). To make coefficients proportional, (3:6=a:8) must hold. This gives (a=4), and constants (7:20) are not in the same ratio.

Step 3

Exam Tip

गुणांक समानुपाती करने के लिए (3:6=a:8) होना चाहिए। इससे (a=4), और स्थिरांक (7:20) समान अनुपात में नहीं हैं।

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Question 206/737 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 55

यदि (2x+ky=15) और (x-2y=1) का हल (x=5,\ y=2) है, तो (k) का मान क्या है?

If (2x+ky=15) and (x-2y=1) have solution (x=5,\ y=2), what is the value of (k)?

Explanation opens after your attempt
Correct Answer

C. \(k=\frac{5}{2}\)

Step 1

Concept

Put (x=5,\ y=2) in (2x+ky=15). (10+2k=15), so \(k=\frac{5}{2}\).

Step 2

Why this answer is correct

The correct answer is C. \(k=\frac{5}{2}\). Put (x=5,\ y=2) in (2x+ky=15). (10+2k=15), so \(k=\frac{5}{2}\).

Step 3

Exam Tip

(x=5,\ y=2) को (2x+ky=15) में रखें। (10+2k=15), इसलिए \(k=\frac{5}{2}\)।

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Question 207/737 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 55

समीकरणों (ax+4y=10) और (3x+6y=15) के अनंत हल होने के लिए (a) का मान क्या है?

What is the value of (a) for (ax+4y=10) and (3x+6y=15) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

B. (a=2)

Step 1

Concept

For infinitely many solutions, coefficients and constants must be in the same ratio. Since (4:6=10:15=2:3), (a=2).

Step 2

Why this answer is correct

The correct answer is B. (a=2). For infinitely many solutions, coefficients and constants must be in the same ratio. Since (4:6=10:15=2:3), (a=2).

Step 3

Exam Tip

अनंत हल के लिए गुणांक और स्थिरांक समान अनुपात में होने चाहिए। (4:6=10:15=2:3), इसलिए (a=2)।

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Question 208/737 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 55

समीकरणों (6x+9y=18) और (2x+3y=c) का कोई हल न हो, इसके लिए (c) का कौन-सा मान सही है?

For (6x+9y=18) and (2x+3y=c) to have no solution, which value of (c) is correct?

Explanation opens after your attempt
Correct Answer

D. (c=8)

Step 1

Concept

The first equation becomes (2x+3y=6). When (c=8), the left side is the same but the right side is different, so there is no solution.

Step 2

Why this answer is correct

The correct answer is D. (c=8). The first equation becomes (2x+3y=6). When (c=8), the left side is the same but the right side is different, so there is no solution.

Step 3

Exam Tip

पहला समीकरण (2x+3y=6) बनता है। (c=8) होने पर समान बायां पक्ष और अलग दायां पक्ष मिलेगा, इसलिए कोई हल नहीं।

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Question 209/737 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 55

यदि (2x+my=34) का हल (x=7,\ y=4) है, तो (m) का मान क्या होगा?

If (x=7,\ y=4) is a solution of (2x+my=34), what will be the value of (m)?

Explanation opens after your attempt
Correct Answer

B. (m=5)

Step 1

Concept

Substitute (x=7,\ y=4) in the equation. (14+4m=34), so (m=5).

Step 2

Why this answer is correct

The correct answer is B. (m=5). Substitute (x=7,\ y=4) in the equation. (14+4m=34), so (m=5).

Step 3

Exam Tip

(x=7,\ y=4) को समीकरण में रखें। (14+4m=34), इसलिए (m=5)।

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Question 210/737 Hard Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 55

समीकरणों (px-6y=18) और (2x-3y=9) के अनंत हल होने के लिए (p) का मान क्या है?

What is the value of (p) for (px-6y=18) and (2x-3y=9) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

B. (p=4)

Step 1

Concept

For infinitely many solutions, the first equation must be (2) times the second. Hence (p=4).

Step 2

Why this answer is correct

The correct answer is B. (p=4). For infinitely many solutions, the first equation must be (2) times the second. Hence (p=4).

Step 3

Exam Tip

अनंत हल के लिए पहला समीकरण दूसरे का (2) गुना होना चाहिए। इसलिए (p=4)।

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