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If \(3x+ky=40\) and \(x+2y=13\) have solution \(x=6,\ y=\frac{7}{2}\), what is the value of (k)?

Answer and explanation

Correct answer: \(\frac{44}{7}\)

Substitute the given values \(x=6\) and \(y=\frac{7}{2}\) into the first equation \(3x+ky=40\). This gives \(3(6)+k\left(\frac{7}{2}\right)=40\), or \(18+\frac{7k}{2}=40\). Hence \(\frac{7k}{2}=22\), so \(k=\frac{44}{7}\). For example, \(\frac{48}{7}\) would not make the left-hand side equal to 40. Exam tip: when a solution is given, substitute it first into the equation containing the unknown parameter.

Related tags

Pair Of Linear EquationsSubstitution MethodParameterValue Of KClass 10 AlgebraAlgebraic Methods: Substitution Method And Elimination Method.Algebraic Methods Substitution Method And Elimination MethodPair Of Linear Equations In Two Variables

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