If the lines (2x+ky=8) and (4x+6y=12) are parallel but not coincident, what is the value of (k)?

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Answer and explanation

Correct answer: (3)

For parallel lines, (\frac{2}{4}=\frac{k}{6}), so (k=3). Also (\frac{8}{12}\neq\frac{1}{2}), so they are not coincident.

What is the correct answer to this question?

(3)

Why is this the correct answer?

For parallel lines, (\frac{2}{4}=\frac{k}{6}), so (k=3). Also (\frac{8}{12}\neq\frac{1}{2}), so they are not coincident.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Pair of Linear Equations in Two Variables. Topic: Graphical method of finding solutions..

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