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If the difference between the two zeroes of the polynomial \(p(x)=x^2-6x+s\) is 2, what is the value of \(s\)?

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Answer and explanation

Correct answer: 8

Let the two zeroes be \(t\) and \(t+2\). Their sum is \(6\), so \(t+(t+2)=6\), giving \(t=2\) and the other zero as \(4\). The product of the zeroes equals \(s\); hence, \(s=2\times4=8\). Exam tip: For \(x^2+bx+c\), the sum of the zeroes is \(-b\) and their product is \(c\).

Related tags

PolynomialsZeroes Of PolynomialsQuadratic PolynomialVieta Relations

Frequently asked questions

What is the correct answer to this question?

8

Why is this the correct answer?

Let the two zeroes be \(t\) and \(t+2\). Their sum is \(6\), so \(t+(t+2)=6\), giving \(t=2\) and the other zero as \(4\). The product of the zeroes equals \(s\); hence, \(s=2\times4=8\). Exam tip: For \(x^2+bx+c\), the sum of the zeroes is \(-b\) and their product is \(c\).

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Polynomials in one variable.

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