100 results found for "decreasing-term" in Class 10.
D. (624)
(S_{24}=\frac{24}{2}[144+23(-4)]=624) है। परीक्षा में ऋणात्मक सार्व अंतर का चिन्ह सावधानी से रखें। / (S_{24}=\frac{24}{2}[144+23(-4)]=624). Exam tip: handle the negative common difference carefully.
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A. (450)
(S_{15}=\frac{15}{2}[130+14(-5)]=450) है। परीक्षा में ऋणात्मक सार्व अंतर का चिन्ह सावधानी से रखें। / (S_{15}=\frac{15}{2}[130+14(-5)]=450). Exam tip: handle the negative common difference carefully.
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In which sequence are terms decreasing by an equal amount but (d) is not (-4)?
B. \(45,40,35,30,\ldots\)
\(45,40,35,30,\ldots\) में (d=-5) है, (-4) नहीं। विकल्पों में मान और चिह्न दोनों जांचें। / In \(45,40,35,30,\ldots\), (d=-5), not (-4). Check both value and sign in the options.
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In which sequence are the terms decreasing by an equal amount but (d) is not (-2)?
A. \(20,17,14,11,\ldots\)
\(20,17,14,11,\ldots\) में (d=-3) है, (-2) नहीं। विकल्पों में चिह्न और मान दोनों जांचें। / In \(20,17,14,11,\ldots\), (d=-3), not (-2). Check both sign and value in options.
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Which of the following is a decreasing arithmetic progression?
A. \(50,45,40,35,\ldots\)
\(50,45,40,35,\ldots\) में समान अंतर (-5) है। घटती अंकगणितीय श्रेणी का (d) ऋणात्मक होता है। / In \(50,45,40,35,\ldots\), the equal difference is (-5). A decreasing arithmetic progression has negative (d).
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What is the (11)th term of the AP \(200,180,160,140,\ldots\)?
D. (0)
यहाँ (d=-20) है, इसलिए (a_{11}=200+10(-20)=0)। घटती श्रेढ़ी में पद शून्य भी हो सकता है। / Here (d=-20), so (a_{11}=200+10(-20)=0). In a decreasing AP, a term can also become zero.
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If \(a_n=30-3n\), what will be the (6)th term?
D. (12)
\(a_6=30-3\times6=12\)। घटते हुए सामान्य पद में घटाव सावधानी से करें। / \(a_6=30-3\times6=12\). Be careful with subtraction in a decreasing general term.
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C. (x+82)
(7d=35) से (d=5)। \(a_{20}=a_{12}+8d=x+42+40=x+82\)। / From (7d=35), (d=5). \(a_{20}=a_{12}+8d=x+42+40=x+82\).
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If the (5)th term of an AP is (27) and the (14)th term is (90), what is the (20)th term?
C. (132)
\(d=\frac{90-27}{14-5}=7\) और \(a_{20}=90+6\times7=132\)। पहले (d) निकालें फिर आगे बढ़ें। / \(d=\frac{90-27}{14-5}=7\) and \(a_{20}=90+6\times7=132\). First find (d) then move forward.
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If the (4)th term of an AP is (15) and the (12)th term is (55), what is the (16)th term?
C. (75)
\(d=\frac{55-15}{12-4}=5\) और \(a_{16}=55+4\times5=75\)। पहले (d) फिर वांछित पद निकालें। / \(d=\frac{55-15}{12-4}=5\) and \(a_{16}=55+4\times5=75\). First find (d), then the required term.
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If the (3)rd term of an AP is (8) and the (8)th term is (3), what is the (11)th term?
A. (0)
\(d=\frac{3-8}{8-3}=-1\), इसलिए (a_{11}=3+3(-1)=0)। ज्ञात पास वाले पद से आगे बढ़ना सरल है। / \(d=\frac{3-8}{8-3}=-1\), so (a_{11}=3+3(-1)=0). Moving from the nearer known term is simple.
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If the (p)th term of an AP is (q) and the (q)th term is (p), what is its ((p+q))th term?
A. (0)
संबंधों को घटाने पर (d=-1) और आगे रखने पर \(a_{p+q}=0\) मिलता है। प्रतीकात्मक AP में भी (a_n=a+(n-1)d) ही लगाएं। / Subtracting the relations gives (d=-1), and substitution gives \(a_{p+q}=0\). Even in symbolic APs, use (a_n=a+(n-1)d).
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If the (5)th term of an AP is (16) and the (9)th term is (32), what is the (13)th term?
C. (48)
\(d=\frac{32-16}{9-5}=4\), इसलिए \(a_{13}=32+4\times4=48\)। समान स्थान अंतर होने पर पदों का अंतर भी समान होता है। / \(d=\frac{32-16}{9-5}=4\), so \(a_{13}=32+4\times4=48\). Equal position gaps give equal term gaps in an AP.
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In the AP \(128,119,110,\ldots\), which is the last term greater than (30)?
C. (38)
(d=-9) है और पद \(128,119,110,\ldots,38,29\) आते हैं। (30) से बड़ा अंतिम पद (38) है। / (d=-9) and the terms go \(128,119,110,\ldots,38,29\). The last term greater than (30) is (38).
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What will be the (13)th term of the AP \(120,109,98,\ldots\)?
C. (-12)
(d=-11) है इसलिए (a_{13}=120+12(-11)=-12)। बड़े ऋणात्मक अंतर में गुणा पहले करें। / (d=-11) so (a_{13}=120+12(-11)=-12). With a large negative difference multiply first.
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Find the (18)th term of the AP \(84,78,72,\ldots\).
B. (-18)
यहां (d=-6) है इसलिए (a_{18}=84+17(-6)=-18)। घटती AP में सार्व अंतर को ऋणात्मक लें। / Here (d=-6) so (a_{18}=84+17(-6)=-18). In a decreasing AP take the common difference as negative.
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In the AP \(90,83,76,\ldots\), which is the last term greater than (20)?
D. (27)
(d=-7) है और पद \(90,83,76,\ldots,27,20\) आते हैं। (20) से बड़ा अंतिम पद (27) है। / (d=-7) and the terms go \(90,83,76,\ldots,27,20\). The last term greater than (20) is (27).
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What is the (12)th term of the AP \(96,87,78,\ldots\)?
A. (-3)
(d=-9) है इसलिए (a_{12}=96+11(-9)=-3)। बड़े घटते अंतर में चिन्ह गलती से न बदलें। / (d=-9) so (a_{12}=96+11(-9)=-3). Do not accidentally change the sign in a large decreasing difference.
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Find the (17)th term of the AP \(38,33,28,\ldots\).
A. (-42)
यहां (a=38) और (d=-5) है इसलिए (a_{17}=38+16(-5)=-42)। घटती श्रेणी में (d) को ऋणात्मक लें। / Here (a=38) and (d=-5) so (a_{17}=38+16(-5)=-42). In a decreasing AP take (d) as negative.
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In the AP \(64,58,52,\ldots\), which is the last term greater than (10)?
C. (16)
पद \(64,58,52,\ldots\) में (d=-6) है। (10) से बड़ा अंतिम पद (16) है क्योंकि अगला पद (10) है। / The terms \(64,58,52,\ldots\) have (d=-6). The last term greater than (10) is (16) because the next term is (10).
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What will be the (15)th term of the AP \(100,92,84,\ldots\)?
D. (-12)
यहां (d=-8), इसलिए (a_{15}=100+14(-8)=-12)। बड़े घटते अंतर में गुणा पहले करें। / Here (d=-8), so (a_{15}=100+14(-8)=-12). In large decreasing differences, multiply first.
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Find the (10)th term of the AP \(45,39,33,27,\ldots\).
B. (-9)
यहाँ (d=-6) है, इसलिए (a_{10}=45+9(-6)=-9)। (9) अंतर घटाने हैं, (10) नहीं। / Here (d=-6), so (a_{10}=45+9(-6)=-9). Subtract (9) differences, not (10).
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Find the (8)th term of the AP \(9,5,1,-3,\ldots\).
B. (-19)
यहाँ (d=-4) है, इसलिए (a_8=9+7(-4)=-19)। ऋणात्मक (d) के साथ कोष्ठक उपयोगी होते हैं। / Here (d=-4), so (a_8=9+7(-4)=-19). Brackets are useful with negative (d).
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What is the (6)th term of the AP \(100,90,80,70,\ldots\)?
A. (50)
यहाँ (d=-10) है, इसलिए (a_6=100+5(-10)=50)। पहले चार पद देखकर (d) सही पहचानें। / Here (d=-10), so (a_6=100+5(-10)=50). Identify (d) correctly from the first terms.
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What will be the (7)th term of the AP \(50,45,40,35,\ldots\)?
C. (20)
यहाँ (d=-5) है, इसलिए (a_7=50+6(-5)=20)। ऋणात्मक अंतर को कोष्ठक में लिखना सुरक्षित है। / Here (d=-5), so (a_7=50+6(-5)=20). Writing a negative difference in brackets is safer.
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C. (x+181)
(12d=72), इसलिए (d=6)। \(a_{35}=x+91+15\times6=x+181\)। / (12d=72), so (d=6). \(a_{35}=x+91+15\times6=x+181\).
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B. (x+188)
(11d=77) से (d=7)। \(a_{32}=a_{18}+14d=x+90+98=x+188\)। / From (11d=77), (d=7). \(a_{32}=a_{18}+14d=x+90+98=x+188\).
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B. (x+137)
(9d=54) से (d=6)। \(a_{27}=a_{15}+12d=x+65+72=x+137\)। / From (9d=54), (d=6). \(a_{27}=a_{15}+12d=x+65+72=x+137\).
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The (12)th term of an AP is (71) and the common difference is (5). What is the first term?
D. (16)
\(71=a+11\times5\) से (a=16)। ज्ञात पद से पहले पद तक जाने के लिए (11d) घटाएं। / From \(71=a+11\times5\), (a=16). To move from the known term to the first term subtract (11d).
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The (9)th term of an AP is (47) and the common difference is (4). What is the first term?
D. (15)
\(47=a+8\times4\) से (a=15)। ज्ञात पद से पहले पद तक जाने के लिए (8d) घटाएं। / From \(47=a+8\times4\), (a=15). To move from the known term to the first term, subtract (8d).
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The (6)th term of an AP is (23) and the common difference is (5). What is the first term?
D. (-2)
(23=a+5d=a+25), इसलिए (a=-2)। दिए गए पद से पीछे जाते समय (5d) घटाया जाता है। / (23=a+5d=a+25), so (a=-2). When moving backward from a given term, subtract (5d).
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The general term of an AP is \(a_n=7n+2\). Find the (11)th term.
C. (79)
\(a_{11}=7\times11+2=79\)। सामान्य पद में सही पद संख्या रखना ही मुख्य कदम है। / \(a_{11}=7\times11+2=79\). The main step is substituting the correct term number in the general term.
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In the AP \(50,47,44,\ldots\), what is the sum from the (6)th term to the (20)th term?
C. (210)
आवश्यक योग \(S_{20}-S_5=210\) है। घटती श्रेढ़ी में भी आंशिक योग का वही तरीका लागू होता है। / The required sum is \(S_{20}-S_5=210\). The same partial-sum method works for a decreasing AP.
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In the AP \(240,222,204,\ldots\), which is the last term greater than (-150)?
B. (-144)
(d=-18) है। (-144) के बाद (-162) आता है इसलिए (-150) से बड़ा अंतिम पद (-144) है। / (d=-18). After (-144), (-162) comes, so the last term greater than (-150) is (-144).
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In the AP \(310,291,272,\ldots\), what is the first term less than (75)?
B. (63)
यहां (d=-19) है। (82) के बाद (63) आता है इसलिए (75) से छोटा पहला पद (63) है। / Here (d=-19). After (82), (63) comes, so the first term less than (75) is (63).
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In the AP \(156,142,128,\ldots\), which is the last term greater than (-120)?
B. (-112)
(d=-14) है। (-110) इस श्रेणी में नहीं है, जबकि (-112) के बाद (-126) आता है। / (d=-14). (-110) is not in this AP, while after (-112), (-126) comes.
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In the AP \(221,204,187,\ldots\), what is the first term less than (50)?
B. (34)
यहां (d=-17) है। (51) के बाद (34) आता है, इसलिए (50) से छोटा पहला पद (34) है। / Here (d=-17). After (51), (34) comes, so the first term less than (50) is (34).
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In the AP \(121,109,97,\ldots\), which is the last term greater than (-75)?
A. (-71)
(d=-12) है। (-71) के बाद (-83) आता है, इसलिए (-75) से बड़ा अंतिम पद (-71) है। / (d=-12). After (-71), the next term is (-83), so the last term greater than (-75) is (-71).
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In the AP \(169,154,139,\ldots\), what is the first term less than (40)?
B. (34)
यहां (d=-15) है। (49) के बाद (34) आता है, इसलिए (40) से छोटा पहला पद (34) है। / Here (d=-15). After (49), the next term is (34), so the first term less than (40) is (34).
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In the AP \(104,95,86,\ldots\), which is the last term greater than (-50)?
A. (-41)
(d=-9) है। (-50) से बड़ा अंतिम पद (-40) नहीं बल्कि (-40) श्रेणी में नहीं आता इसलिए (-40) से पहले सही पद (-40) जांचना चाहिए। / (d=-9). The last term greater than (-50) is (-40) if it appears, so always verify actual terms before choosing.
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In the AP \(143,130,117,\ldots\), what is the first term less than (25)?
A. (13)
इस AP में (d=-13) है। (26) के बाद (13) आता है इसलिए (25) से छोटा पहला पद (13) है। / In this AP, (d=-13). After (26), the next term is (13), so the first term less than (25) is (13).
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In the AP \(85,77,69,\ldots\), which is the last term greater than (-35)?
C. (-31)
(d=-8) है। (-35) से बड़ा अंतिम पद (-27) है क्योंकि अगला पद (-35) है। / (d=-8). The last term greater than (-35) is (-27) because the next term is (-35).
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In the AP \(112,101,90,\ldots\), what is the first term less than (15)?
A. (13)
इस AP में (d=-11) है। (24) के बाद (13) आता है इसलिए (15) से छोटा पहला पद (13) है। / In this AP, (d=-11). After (24), the next term is (13), so the first term less than (15) is (13).
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In the AP \(64,57,50,\ldots\), which is the last term greater than (-20)?
A. (-13)
(d=-7) है। (-20) से बड़ा अंतिम पद (-13) है क्योंकि अगला पद (-20) है। / (d=-7). The last term greater than (-20) is (-13) because the next term is (-20).
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In the AP \(97,88,79,\ldots\), what is the first term less than (20)?
A. (16)
इस AP में (d=-9)। पद (25) के बाद (16) आता है इसलिए (20) से छोटा पहला पद (16) है। / In this AP, (d=-9). After the term (25), the next term is (16), so the first term less than (20) is (16).
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If \(a_n=95-5n\), what will be the (26)th term?
A. (-35)
\(a_{26}=95-5\times26=-35\)। घटते सूत्र में घटाव के बाद चिन्ह जांचें। / \(a_{26}=95-5\times26=-35\). In a decreasing formula check the sign after subtraction.
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If \(a_n=82-4n\), what will be the (23)rd term of the AP?
A. (-10)
\(a_{23}=82-4\times23=-10\)। घटते प्रत्यक्ष सूत्र में घटाव को ध्यान से करें। / \(a_{23}=82-4\times23=-10\). Do subtraction carefully in a decreasing direct formula.
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In the sequence \(35,30,25,20,\ldots\), how much less is each term than the previous term?
C. (5)
हर अगला पद पिछले पद से (5) कम है। इसका सार्व अंतर (-5) होगा। / Each next term is (5) less than the previous term. Its common difference will be (-5).
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In the sequence \(50,45,40,35,\ldots\), how much less is each term than the previous term?
C. (5)
हर अगला पद पिछले पद से (5) कम है। इसका सार्व अंतर (-5) होगा। / Each next term is (5) less than the previous term. Its common difference will be (-5).
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B. (1485)
शर्त से (6+13d=3(6+3d)), इसलिए (d=3) और \(S_{30}=1485\) है। पदों की शर्त को पहले समीकरण में बदलें। / The condition gives (6+13d=3(6+3d)), so (d=3) and \(S_{30}=1485\). Convert the term condition into an equation first.
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A. (1050)
शर्त से (5+11d=4(5+2d)), इसलिए (d=5) और \(S_{20}=1050\) है। पदों की शर्त को पहले समीकरण में बदलें। / The condition gives (5+11d=4(5+2d)), so (d=5) and \(S_{20}=1050\). Convert the term condition into an equation first.
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C. (1050)
शर्त से (6+8d=2(6+3d)), इसलिए (d=3) और \(S_{25}=1050\) है। पदों की शर्त को पहले समीकरण में बदलें। / The condition gives (6+8d=2(6+3d)), so (d=3) and \(S_{25}=1050\). Convert the term condition into an equation first.
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C. (576)
शर्त से (4+7d=3(4+2d)), इसलिए (d=8) और \(S_{12}=576\)। पदों की शर्त को पहले समीकरण में बदलें। / The condition gives (4+7d=3(4+2d)), so (d=8) and \(S_{12}=576\). Convert the term condition into an equation first.
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The (n)th-term formula of the AP \(23,31,39,\ldots\) is \(a_n=8n+15\). What is the (36)th term?
C. (303)
\(a_{36}=8\times36+15=303\)। बने हुए सूत्र में (n=36) रखकर सीधे उत्तर पाएं। / \(a_{36}=8\times36+15=303\). Put (n=36) in the formed formula to get the answer directly.
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If the (r)th term of an AP is (3r-2) and (d=4), what is the ((r+6))th term?
C. (3r+22)
((r+6))वां पद (r)वें पद से (6d) आगे है इसलिए (3r-2+24=3r+22)। प्रतीकात्मक प्रश्न में स्थान अंतर देखें। / The ((r+6))th term is (6d) ahead of the (r)th term so (3r-2+24=3r+22). In symbolic questions look at the position gap.
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The (n)th-term formula of the AP \(19,26,33,\ldots\) is \(a_n=7n+12\). What is the (41)st term?
D. (299)
\(a_{41}=7\times41+12=299\)। बने हुए सूत्र में केवल (n=41) रखें। / \(a_{41}=7\times41+12=299\). Put only (n=41) in the formed formula.
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If the (m)th term of an AP is (2m+3) and (d=2), what is the ((m+5))th term?
D. (2m+13)
((m+5))वां पद (m)वें पद से (5d) आगे है इसलिए (2m+3+10=2m+13)। प्रतीकात्मक पदों में भी स्थान अंतर देखें। / The ((m+5))th term is (5d) ahead of the (m)th term, so (2m+3+10=2m+13). In symbolic terms, look at the position gap.
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The first term of an AP is (25) and the (18)th term is (93). What is the common difference?
C. (4)
(93=25+17d) से (68=17d) इसलिए (d=4)। (18)वें पद के लिए गुणक (17) होता है। / From (93=25+17d), (68=17d) so (d=4). For the (18)th term, the multiplier is (17).
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The (n)th term of the AP \(11,17,23,\ldots\) is \(a_n=6n+5\). What is its (32)nd term?
B. (197)
\(a_{32}=6\times32+5=197\)। बनाए गए सूत्र में (n) का सही मान रखें। / \(a_{32}=6\times32+5=197\). Substitute the correct value of (n) in the formed formula.
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The first term of an AP is (18) and the (16)th term is (93). What is the common difference?
A. (5)
(93=18+15d), इसलिए (75=15d) और (d=5)। (16)वें पद के लिए गुणक (15) होगा। / (93=18+15d), so (75=15d) and (d=5). For the (16)th term, the multiplier is (15).
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If the (10)th term of an AP is (41) and the (20)th term is (81), what is its common difference?
C. (4)
दो पदों का अंतर (81-41=40) है और पद संख्या का अंतर (10), इसलिए (d=4)। \(दो ज्ञात पदों में (d=\frac{\)पदों का अंतर}{स्थान का अंतर}) लगाएं। \(/ The difference of terms is (81-41=40) and the difference of positions is (10), so (d=4). Use (d=\frac{\)difference of terms}{difference of positions}).
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If the first term of an AP is (7) and the common difference is (4), what is its (18)th term?
A. (75)
सूत्र (a_n=a+(n-1)d) लगाने पर \(7+17\times4=75\)। परीक्षा में (n-1) को भूलना नहीं चाहिए। / Using (a_n=a+(n-1)d), \(7+17\times4=75\). Exam tip: do not forget (n-1).
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If the (4)th term of an AP is (21) and (d=6), what is the (10)th term?
C. (57)
(10)वाँ पद (4)थे पद से (6d) आगे है इसलिए (21+36=57)। पद संख्या का अंतर सीधे उपयोग करें। / The (10)th term is (6d) after the (4)th term, so (21+36=57). Use the difference in term numbers directly.
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If the first term of an AP is (-12) and the common difference is (5), what is the (16)th term?
B. (63)
\(a_{16}=-12+15\times5=63\)। पहले (15d) निकालें फिर प्रथम पद जोड़ें। / \(a_{16}=-12+15\times5=63\). First calculate (15d), then add the first term.
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If the first term of an AP is (9) and the common difference is (10), what is the (7)th term?
B. (69)
\(a_7=9+6\times10=69\)। (7)वें पद के लिए (6d) जोड़ना होता है। / \(a_7=9+6\times10=69\). For the (7)th term, (6d) is added.
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If the (3)rd term of an AP is (14) and (d=5), what is the (7)th term?
C. (34)
(7)वाँ पद (3)रे पद से (4d) आगे है इसलिए (14+20=34)। बीच के पदों की संख्या सही गिनें। / The (7)th term is (4d) after the (3)rd term, so (14+20=34). Count the gap between terms correctly.
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If the first term of an AP is (-2) and the common difference is (6), what is the (12)th term?
B. (64)
\(a_{12}=-2+11\times6=64\)। पहले गुणा करें फिर (-2) जोड़ें। / \(a_{12}=-2+11\times6=64\). Multiply first and then add (-2).
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If the (5)th term of an AP is (22) and (d=6), what is the (8)th term?
D. (40)
(8)वाँ पद (5)वें पद से (3d) आगे है इसलिए (22+18=40)। पदों का अंतर गिनना आसान तरीका है। / The (8)th term is (3d) after the (5)th term, so (22+18=40). Counting the gap between terms is an easy method.
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If the (7)th term of an AP is (31) and (d=4), what is the (10)th term?
C. (43)
(10)वाँ पद (7)वें पद से (3d) आगे है इसलिए \(31+3\times4=43\)। पास के पदों के लिए अंतर विधि तेज होती है। / The (10)th term is (3d) after the (7)th term, so \(31+3\times4=43\). The difference method is quick for nearby terms.
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If the first term of an AP is (15) and the common difference is (-4), what is the (8)th term?
A. (-13)
(a_8=15+7(-4)=-13)। ऋणात्मक (d) को कोष्ठक में लिखना उपयोगी है। / (a_8=15+7(-4)=-13). Writing negative (d) in brackets is useful.
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If the first term of an AP is (5) and common difference is (3), what is the (8)th term?
C. (26)
सूत्र (a_n=a+(n-1)d) लगाएं तो \(5+7\times3=26\)। परीक्षा में (n-1) लेना न भूलें। / Using (a_n=a+(n-1)d), \(5+7\times3=26\). In exams, do not forget (n-1).
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The (n)th term of an AP is \(a_n=2n+3\). What will be the (18)th term?
A. (39)
(n=18) रखने पर \(a_{18}=2\times18+3=39\)। दिए गए \(a_n\) में सीधे पद संख्या रखें। / Putting (n=18), \(a_{18}=2\times18+3=39\). Substitute the term number directly in the given \(a_n\).
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The first term of an AP is (25) and the common difference is (4). What will be the (21)st term?
B. (105)
\(a_{21}=25+20\times4=105\)। पद संख्या से (1) घटाना न भूलें। / \(a_{21}=25+20\times4=105\). Do not forget to subtract (1) from the term number.
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If the first term of an AP is (6) and the common difference is (7), what is the (11)th term?
D. (76)
\(a_{11}=6+10\times7=76\)। (11)वें पद तक (10) बार अंतर जुड़ता है। / \(a_{11}=6+10\times7=76\). Up to the (11)th term, the difference is added (10) times.
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In an AP, first term (a=4) and common difference (d=3). What is the (10)th term?
A. (31)
सूत्र (a_n=a+(n-1)d) लगाने पर \(a_{10}=4+9\times3=31\)। परीक्षा में (n-1) को ध्यान से लिखें। / Using (a_n=a+(n-1)d), \(a_{10}=4+9\times3=31\). Exam tip: write (n-1) carefully.
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Which option shows a decreasing AP?
C. \(20,17,14,11,\ldots\)
यहां सामान्य अंतर (-3) है, इसलिए पद घट रहे हैं। परीक्षा में घटती समांतर श्रेणी का (d) ऋणात्मक होता है। / Here the common difference is (-3), so the terms are decreasing. In exams, a decreasing AP has negative (d).
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A. (96) लीटर(96) litres
यह घटती AP है जिसमें (a=240) और (d=-18) है। (a_9=240+8(-18)=96) लीटर। / This is a decreasing AP with (a=240) and (d=-18). (a_9=240+8(-18)=96) litres.
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C. (₹585)
शुल्क घट रहा है इसलिए (d=-35)। (a_{10}=900+9(-35)=585)। / The fee is decreasing so (d=-35). (a_{10}=900+9(-35)=585).
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A. (60) लीटर(60) litres
यह घटती समान्तर श्रेणी है जिसमें (a=180) और (d=-12) है। (a_{11}=180+10(-12)=60) लीटर। / This is a decreasing AP with (a=180) and (d=-12). (a_{11}=180+10(-12)=60) litres.
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A. (240)
यहां (a=500), (d=-20), इसलिए (a_{14}=500+13(-20)=240)। घटते शब्द-प्रश्न में (d) ऋणात्मक लें। / Here (a=500), (d=-20), so (a_{14}=500+13(-20)=240). In decreasing word problems, take (d) as negative.
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What is the third term in the sequence \(9,7,5,3,\ldots\)?
D. (5)
पद क्रम से (9,7,5,3) हैं इसलिए तीसरा पद (5) है। पद संख्या गिनने में जल्दबाजी न करें। / The terms are (9,7,5,3), so the third term is (5). Do not rush while counting term positions.
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How can divide and rule policy be linked with both short term control and long term crisis?
A. इससे तत्काल विरोध कमजोर हो सकता था लेकिन सामाजिक अविश्वास बचता थाIt could weaken immediate resistance but leave social distrust
यह नीति नियंत्रण के लिए विभाजन का उपयोग करती थी। परीक्षा में इसकी विरासत भी लिखें। / This policy used division for control. For exams also write its legacy.
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C. (3000)
\(a_{21}+a_{40}=a_1+a_{60}=300\), इसलिए (20) पदों का योग (3000) है। सममित पदों का योग बराबर होता है। / \(a_{21}+a_{40}=a_1+a_{60}=300\), so the sum of (20) terms is (3000). Sums of symmetric terms are equal in an AP.
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B. (2100)
\(a_{11}+a_{30}=a_1+a_{40}=210\), इसलिए (20) पदों का योग (2100) है। सममित पदों का योग बराबर होता है। / \(a_{11}+a_{30}=a_1+a_{40}=210\), so the sum of (20) terms is (2100). Sums of symmetric terms are equal in an AP.
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B. (14)
(740=10(a+60)) से (a=14) मिलता है। जब (n)वाँ पद दिया हो तो उसे अंतिम पद की तरह इस्तेमाल करें। / From (740=10(a+60)), (a=14). When the (n)th term is given, use it as the last term for the first (n) terms.
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What is the last term among the positive multiples of (13) less than (600)?
B. (598)
(13n<600) में सबसे बड़ा (n=46) है इसलिए पद \(13\times46=598\)। सीमा से कम सबसे बड़ा पूर्णांक लें। / In (13n<600), the greatest (n=46) so the term is \(13\times46=598\). Take the greatest integer below the limit.
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The (n)th term of the AP \(73,68,63,\ldots\) is (-12). What is (n)?
C. (18)
(-12=73+(n-1)(-5)) से (85=5(n-1)) इसलिए (n=18)। घटती AP में ऋणात्मक लक्ष्य तक चिन्ह सही रखें। / From (-12=73+(n-1)(-5)), (85=5(n-1)) so (n=18). In a decreasing AP keep signs correct up to the negative target.
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If the (19)th term of the AP \(z,z+5,z+10,\ldots\) is (112), what is (z)?
C. (22)
\(112=z+18\times5\) से (z=22)। चर वाले पहले पद को (a) मानकर सूत्र लगाएं। / From \(112=z+18\times5\), (z=22). Treat the variable first term as (a) and apply the formula.
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In the AP \(7,12,17,\ldots\), what is the last term less than (180)?
C. (177)
पद (7+5(n-1)) हैं। (180) से कम अंतिम पद (177) है क्योंकि अगला पद (182) होगा। / The terms are (7+5(n-1)). The last term less than (180) is (177) because the next term will be (182).
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In an AP (a=63) and (d=-4). Which term will be (-1)?
C. (17)वां(17)th
(-1=63+(n-1)(-4)) से (64=4(n-1)) इसलिए (n=17)। ऋणात्मक लक्ष्य पद में चिन्हों को ध्यान से संभालें। / From (-1=63+(n-1)(-4)), (64=4(n-1)) so (n=17). Handle signs carefully with a negative target term.
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Which is the first negative term of the AP \(105,98,91,\ldots\)?
C. (17)वां(17)th
(a_n=105+(n-1)(-7)=112-7n)। \(a_n<0\) से (n>16) इसलिए पहला ऋणात्मक पद (17)वां है। / (a_n=105+(n-1)(-7)=112-7n). From \(a_n<0\), (n>16) so the first negative term is the (17)th.
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Which term of the AP \(26,35,44,\ldots\) is (206)?
C. (21)वां(21)st
(206=26+(n-1)9) से (180=9(n-1)) इसलिए (n=21)। पद और पहले पद का अंतर (d) से भाग दें। / From (206=26+(n-1)9), (180=9(n-1)) so (n=21). Divide the difference between the term and first term by (d).
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The (14)th term of an AP is (92) and (d=7). What is \(a_1\)?
A. (1)
\(92=a+13\times7\) से (a=1)। (14)वें पद से पहले पद तक (13d) घटता है। / From \(92=a+13\times7\), (a=1). From the (14)th term to the first term (13d) is subtracted.
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Which term of the AP \(9,17,25,\ldots\) is (201)?
C. (25)वां(25)th
(201=9+(n-1)8) से (192=8(n-1)) और (n=25)। पद संख्या पूर्णांक आए तो उत्तर सही दिशा में है। / From (201=9+(n-1)8), (192=8(n-1)) and (n=25). If the term number is an integer the answer is on the right track.
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What is the last term among the positive multiples of (11) less than (500)?
B. (495)
(11n<500) में सबसे बड़ा (n=45) है इसलिए पद \(11\times45=495\)। सीमा से कम सबसे बड़ा पूर्णांक लें। / In (11n<500), the greatest (n=45), so the term is \(11\times45=495\). Take the greatest integer below the limit.
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The (n)th term of the AP \(55,51,47,\ldots\) is (-17). What is (n)?
C. (19)
(-17=55+(n-1)(-4)) से (72=4(n-1)) इसलिए (n=19)। ऋणात्मक पद तक जाते समय चिन्ह सही रखें। / From (-17=55+(n-1)(-4)), (72=4(n-1)) so (n=19). Keep signs correct while reaching a negative term.
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If the (12)th term of the AP \(y,y+6,y+12,\ldots\) is (89), what is the value of (y)?
D. (23)
\(89=y+11\times6\) से (y=23)। चर वाले पहले पद को सीधे (a) मानें। / From \(89=y+11\times6\), (y=23). Treat the variable first term directly as (a).
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In the AP \(2,6,10,\ldots\), what is the last term less than (75)?
A. (74)
इस श्रेणी के पद (2+4(n-1)) हैं। (75) से कम अंतिम पद (74) है। / The terms of this sequence are (2+4(n-1)). The last term less than (75) is (74).
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In an AP, (a=48) and (d=-3). Which term will be (0)?
C. (17)वां(17)th
(0=48+(n-1)(-3)) से (3(n-1)=48) इसलिए (n=17)। शून्य पद के लिए भी सामान्य सूत्र लगाएं। / From (0=48+(n-1)(-3)), (3(n-1)=48) so (n=17). Use the usual formula even for the zero term.
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Which is the first negative term of the AP \(72,66,60,\ldots\)?
B. (14)वां(14)th
(a_n=72+(n-1)(-6)=78-6n)। \(a_n<0\) से (n>13) इसलिए पहला ऋणात्मक पद (14)वां है। / (a_n=72+(n-1)(-6)=78-6n). From \(a_n<0\), (n>13) so the first negative term is the (14)th.
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