In the AP (128,119,110,\ldots), which is the last term greater than (30)?
Answer and explanation
Correct answer: 38
The first term of the AP is 128 and the common difference is \(d=-9\). The term after 38 is \(38-9=29\). Since \(38>30\) but \(29<30\), 38 is the last term greater than 30. Option 29 is a close distractor, but it is not greater than 30. Exam tip: In a decreasing AP, check the next term to confirm that it crosses the given limit.
Frequently asked questions
What is the correct answer to this question?
38
Why is this the correct answer?
The first term of the AP is 128 and the common difference is \(d=-9\). The term after 38 is \(38-9=29\). Since \(38>30\) but \(29<30\), 38 is the last term greater than 30. Option 29 is a close distractor, but it is not greater than 30. Exam tip: In a decreasing AP, check the next term to confirm that it crosses the given limit.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Arithmetic Progressions (AP). Topic: Finding the $n$th term of an AP.
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