What is the (11)th term of the AP (200,180,160,140,\ldots)?
Answer and explanation
Correct answer: 0
For this AP, the first term is \(a=200\) and the common difference is \(d=180-200=-20\). The \(n\)th term is \(a_n=a+(n-1)d\). Therefore, \(a_{11}=200+(11-1)(-20)=200-200=0\). The value 20 is the 10th term, not the 11th term. Exam tip: use \(n-1\), not \(n\), in the nth-term formula.
Frequently asked questions
What is the correct answer to this question?
0
Why is this the correct answer?
For this AP, the first term is \(a=200\) and the common difference is \(d=180-200=-20\). The \(n\)th term is \(a_n=a+(n-1)d\). Therefore, \(a_{11}=200+(11-1)(-20)=200-200=0\). The value 20 is the 10th term, not the 11th term. Exam tip: use \(n-1\), not \(n\), in the nth-term formula.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Arithmetic Progressions (AP). Topic: Finding the $n$th term of an AP.
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