समीकरण (16x+4y=52) को (y=mx+c) रूप में लिखने पर ढाल और (y)-अवरोध क्या होंगे?
When (16x+4y=52) is written in (y=mx+c) form, what are the slope and (y)-intercept?
#standard_form
#slope_intercept
#rearrange
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A ढाल (-4), (y)-अवरोध (13) / Slope (-4), (y)-intercept (13)
B ढाल (4), (y)-अवरोध (13) / Slope (4), (y)-intercept (13)
C ढाल (-16), (y)-अवरोध (4) / Slope (-16), (y)-intercept (4)
D ढाल (16), (y)-अवरोध (-4) / Slope (16), (y)-intercept (-4)
Explanation opens after your attempt
Correct Answer
A. ढाल (-4), (y)-अवरोध (13) / Slope (-4), (y)-intercept (13)
Step 1
Concept
From (4y=-16x+52), we get (y=-4x+13). The coefficient is the slope and the constant term is the (y)-intercept.
Step 2
Why this answer is correct
The correct answer is A. ढाल (-4), (y)-अवरोध (13) / Slope (-4), (y)-intercept (13). From (4y=-16x+52), we get (y=-4x+13). The coefficient is the slope and the constant term is the (y)-intercept.
Step 3
Exam Tip
(4y=-16x+52) से (y=-4x+13) मिलता है। गुणांक ढाल और स्थिर पद (y)-अवरोध होता है।
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यदि रेखा (y=(2k+3)x-5) की ढाल (19) है, तो (k) क्या है?
If the line (y=(2k+3)x-5) has slope (19), what is (k)?
#parameter_slope
#linear_expression
#solve
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A (6)
B (8)
C (9)
D (11)
Explanation opens after your attempt
Step 1
Concept
The slope is (2k+3). From (2k+3=19), (k=8).
Step 2
Why this answer is correct
The correct answer is B. (8). The slope is (2k+3). From (2k+3=19), (k=8).
Step 3
Exam Tip
ढाल (2k+3) है। (2k+3=19) से (k=8) मिलता है।
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समीकरण (8y=24x-64) का (y)-अवरोध क्या है?
What is the (y)-intercept of (8y=24x-64)?
#y_intercept
#rearrange_equation
#constant_term
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A (24)
B (8)
C (-8)
D (-64)
Explanation opens after your attempt
Step 1
Concept
Dividing by (8) gives (y=3x-8). The constant term (-8) is the (y)-intercept.
Step 2
Why this answer is correct
The correct answer is C. (-8). Dividing by (8) gives (y=3x-8). The constant term (-8) is the (y)-intercept.
Step 3
Exam Tip
(8) से भाग देने पर (y=3x-8) मिलता है। स्थिर पद (-8) (y)-अवरोध है।
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रेखा (y=-7x+c) बिंदु ((4,-20)) से गुजरती है। इसका (y)-अवरोध क्या है?
The line (y=-7x+c) passes through ((4,-20)). What is its (y)-intercept?
#find_intercept
#point_given
#negative_slope
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A (6)
B (7)
C (9)
D (8)
Explanation opens after your attempt
Step 1
Concept
Substituting the point gives (-20=-7(4)+c). Therefore (c=8).
Step 2
Why this answer is correct
The correct answer is D. (8). Substituting the point gives (-20=-7(4)+c). Therefore (c=8).
Step 3
Exam Tip
बिंदु रखने पर (-20=-7(4)+c) मिलता है। इसलिए (c=8) है।
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रेखा (y=mx-13) बिंदु ((-5,12)) से गुजरती है। इसकी ढाल क्या है?
The line (y=mx-13) passes through ((-5,12)). What is its slope?
#find_slope
#point_given
#parameter
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A (5)
B (-5)
C (6)
D (-6)
Explanation opens after your attempt
Step 1
Concept
Substituting the point gives (12=-5m-13). Thus (-5m=25) and (m=-5).
Step 2
Why this answer is correct
The correct answer is B. (-5). Substituting the point gives (12=-5m-13). Thus (-5m=25) and (m=-5).
Step 3
Exam Tip
बिंदु रखने पर (12=-5m-13) मिलता है। इससे (-5m=25) और (m=-5) है।
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समीकरण (11x-5y=35) की ढाल क्या है?
What is the slope of (11x-5y=35)?
#standard_form
#fraction_slope
#rearrange
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A \(\frac{11}{5}\)
B \(-\frac{11}{5}\)
C (5)
D (35)
Explanation opens after your attempt
Correct Answer
A. \(\frac{11}{5}\)
Step 1
Concept
From (11x-5y=35), we get \(y=\frac{11}{5}x-7\). Therefore the slope is \(\frac{11}{5}\).
Step 2
Why this answer is correct
The correct answer is A. \(\frac{11}{5}\). From (11x-5y=35), we get \(y=\frac{11}{5}x-7\). Therefore the slope is \(\frac{11}{5}\).
Step 3
Exam Tip
(11x-5y=35) से \(y=\frac{11}{5}x-7\) मिलता है। इसलिए ढाल \(\frac{11}{5}\) है।
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यदि (ay=42x-70) की ढाल (7) है, तो (a) का मान क्या है?
If (ay=42x-70) has slope (7), what is the value of (a)?
#parameter_slope
#rearrange_equation
#expert
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A (5)
B (6)
C (7)
D (8)
Explanation opens after your attempt
Step 1
Concept
\(y=\frac{42}{a}x-\frac{70}{a}\). From \(\frac{42}{a}=7\), (a=6).
Step 2
Why this answer is correct
The correct answer is B. (6). \(y=\frac{42}{a}x-\frac{70}{a}\). From \(\frac{42}{a}=7\), (a=6).
Step 3
Exam Tip
\(y=\frac{42}{a}x-\frac{70}{a}\) होगा। \(\frac{42}{a}=7\) से (a=6) है।
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यदि (ky=36x-108) का (y)-अवरोध (-18) है, तो (k) क्या है?
If (ky=36x-108) has (y)-intercept (-18), what is (k)?
#parameter_intercept
#rearrange_equation
#expert
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A (4)
B (9)
C (6)
D (12)
Explanation opens after your attempt
Step 1
Concept
\(y=\frac{36}{k}x-\frac{108}{k}\). From \(-\frac{108}{k}=-18\), (k=6).
Step 2
Why this answer is correct
The correct answer is C. (6). \(y=\frac{36}{k}x-\frac{108}{k}\). From \(-\frac{108}{k}=-18\), (k=6).
Step 3
Exam Tip
\(y=\frac{36}{k}x-\frac{108}{k}\) होगा। \(-\frac{108}{k}=-18\) से (k=6) है।
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रेखा (y=(5p-2)x-7) की ढाल (38) है। (p) क्या होगा?
The line (y=(5p-2)x-7) has slope (38). What will (p) be?
#parameter_slope
#linear_polynomial
#solve
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A (6)
B (7)
C (9)
D (8)
Explanation opens after your attempt
Step 1
Concept
The slope is (5p-2). From (5p-2=38), (p=8).
Step 2
Why this answer is correct
The correct answer is D. (8). The slope is (5p-2). From (5p-2=38), (p=8).
Step 3
Exam Tip
ढाल (5p-2) है। (5p-2=38) से (p=8) मिलता है।
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यदि (y=(r+10)x+(r-6)) मूल बिंदु से गुजरती है, तो इसकी ढाल क्या होगी?
If (y=(r+10)x+(r-6)) passes through the origin, what will be its slope?
#origin
#parameter
#find_slope
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A (10)
B (16)
C (6)
D (4)
Explanation opens after your attempt
Step 1
Concept
To pass through the origin, (r-6=0). Thus (r=6) and the slope is (16).
Step 2
Why this answer is correct
The correct answer is B. (16). To pass through the origin, (r-6=0). Thus (r=6) and the slope is (16).
Step 3
Exam Tip
मूल बिंदु से गुजरने के लिए (r-6=0) होगा। इसलिए (r=6) और ढाल (16) है।
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समीकरण (20x+5y-85=0) में ढाल और (y)-अवरोध क्या हैं?
What are the slope and (y)-intercept in (20x+5y-85=0)?
#general_form
#slope_intercept
#rearrange
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A ढाल (-4), (y)-अवरोध (17) / Slope (-4), (y)-intercept (17)
B ढाल (4), (y)-अवरोध (17) / Slope (4), (y)-intercept (17)
C ढाल (-20), (y)-अवरोध (5) / Slope (-20), (y)-intercept (5)
D ढाल (20), (y)-अवरोध (-5) / Slope (20), (y)-intercept (-5)
Explanation opens after your attempt
Correct Answer
A. ढाल (-4), (y)-अवरोध (17) / Slope (-4), (y)-intercept (17)
Step 1
Concept
From (5y=-20x+85), (y=-4x+17). So the slope is (-4) and the (y)-intercept is (17).
Step 2
Why this answer is correct
The correct answer is A. ढाल (-4), (y)-अवरोध (17) / Slope (-4), (y)-intercept (17). From (5y=-20x+85), (y=-4x+17). So the slope is (-4) and the (y)-intercept is (17).
Step 3
Exam Tip
(5y=-20x+85) से (y=-4x+17) मिलता है। इसलिए ढाल (-4) और (y)-अवरोध (17) है।
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समीकरण (12x-6y+30=0) का (y)-अवरोध क्या है?
What is the (y)-intercept of (12x-6y+30=0)?
#general_form
#y_intercept
#substitution
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A (5)
B (-5)
C (12)
D (30)
Explanation opens after your attempt
Step 1
Concept
Putting (x=0) gives (-6y+30=0). Thus (y=5).
Step 2
Why this answer is correct
The correct answer is A. (5). Putting (x=0) gives (-6y+30=0). Thus (y=5).
Step 3
Exam Tip
(x=0) रखने पर (-6y+30=0) मिलता है। इससे (y=5) है।
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यदि दो रेखाएं (y=(q-9)x+14) और (y=12x-6) समान ढाल रखती हैं, तो (q) क्या है?
If the two lines (y=(q-9)x+14) and (y=12x-6) have the same slope, what is (q)?
#compare_slopes
#parameter
#parallel_lines
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A (18)
B (20)
C (21)
D (24)
Explanation opens after your attempt
Step 1
Concept
For equal slopes, (q-9=12). This gives (q=21).
Step 2
Why this answer is correct
The correct answer is C. (21). For equal slopes, (q-9=12). This gives (q=21).
Step 3
Exam Tip
समान ढाल के लिए (q-9=12) होना चाहिए। इससे (q=21) मिलता है।
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यदि (y=-10x+s) और (y=7x-19) का (y)-अवरोध समान है, तो (s) क्या होगा?
If (y=-10x+s) and (y=7x-19) have the same (y)-intercept, what will (s) be?
#compare_intercepts
#parameter
#constant_term
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A (-19)
B (-10)
C (7)
D (19)
Explanation opens after your attempt
Step 1
Concept
The first line has (y)-intercept (s) and the second has (-19). If equal, (s=-19).
Step 2
Why this answer is correct
The correct answer is A. (-19). The first line has (y)-intercept (s) and the second has (-19). If equal, (s=-19).
Step 3
Exam Tip
पहली रेखा का (y)-अवरोध (s) और दूसरी का (-19) है। समान होने पर (s=-19) होगा।
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यदि (y=(a+8)x+a) में ढाल और (y)-अवरोध का अंतर (8) है, तो कौन सा कथन सही है?
If in (y=(a+8)x+a), the difference between slope and (y)-intercept is (8), which statement is correct?
#parameter_condition
#slope_intercept
#identity
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A यह हर (a) के लिए सही है / It is true for every (a)
B केवल (a=8) के लिए सही है / It is true only for (a=8)
C कोई (a) संभव नहीं / No (a) is possible
D केवल (a=0) के लिए सही है / It is true only for (a=0)
Explanation opens after your attempt
Correct Answer
A. यह हर (a) के लिए सही है / It is true for every (a)
Step 1
Concept
The slope is (a+8) and the (y)-intercept is (a). The difference ((a+8)-a=8) holds for every (a).
Step 2
Why this answer is correct
The correct answer is A. यह हर (a) के लिए सही है / It is true for every (a). The slope is (a+8) and the (y)-intercept is (a). The difference ((a+8)-a=8) holds for every (a).
Step 3
Exam Tip
ढाल (a+8) और (y)-अवरोध (a) है। अंतर ((a+8)-a=8) हर (a) के लिए है।
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रेखा (y=7x+b) बिंदुओं ((2,23)) और ((5,44)) से गुजरती है। (b) क्या है?
The line (y=7x+b) passes through ((2,23)) and ((5,44)). What is (b)?
#two_points
#intercept_given_slope
#verify
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A (7)
B (8)
C (9)
D (11)
Explanation opens after your attempt
Step 1
Concept
From the first point, (23=7(2)+b). So (b=9) and the second point also fits.
Step 2
Why this answer is correct
The correct answer is C. (9). From the first point, (23=7(2)+b). So (b=9) and the second point also fits.
Step 3
Exam Tip
पहले बिंदु से (23=7(2)+b) मिलता है। इसलिए (b=9) है और दूसरा बिंदु भी सही है।
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रेखा (y=mx+4) बिंदुओं ((3,25)) और ((6,46)) से गुजरती है। (m) क्या है?
The line (y=mx+4) passes through ((3,25)) and ((6,46)). What is (m)?
#two_points
#slope
#linear_form
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A (5)
B (6)
C (7)
D (8)
Explanation opens after your attempt
Step 1
Concept
The slope from the two points is \(\frac{46-25}{6-3}=7\). Therefore (m=7).
Step 2
Why this answer is correct
The correct answer is C. (7). The slope from the two points is \(\frac{46-25}{6-3}=7\). Therefore (m=7).
Step 3
Exam Tip
दोनों बिंदुओं से ढाल \(\frac{46-25}{6-3}=7\) है। इसलिए (m=7) है।
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यदि (y=(k-10)x+13) और (y=6x+(k-3)) की ढालें समान हैं, तो (k) क्या है?
If (y=(k-10)x+13) and (y=6x+(k-3)) have equal slopes, what is (k)?
#compare_slopes
#parameter
#hard
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A (14)
B (15)
C (16)
D (17)
Explanation opens after your attempt
Step 1
Concept
For equal slopes, (k-10=6). This gives (k=16).
Step 2
Why this answer is correct
The correct answer is C. (16). For equal slopes, (k-10=6). This gives (k=16).
Step 3
Exam Tip
समान ढाल के लिए (k-10=6) होगा। इससे (k=16) मिलता है।
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यदि (y=(m+3)x-9) और (y=11x+(m-14 )) का (y)-अवरोध समान है, तो (m) क्या है?
If (y=(m+3)x-9) and (y=11x+(m-14 )) have the same (y)-intercept, what is (m)?
#compare_intercepts
#parameter
#hard
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A (3)
B (4)
C (5)
D (6)
Explanation opens after your attempt
Step 1
Concept
For equal (y)-intercepts, (-9=m-14 ). This gives (m=5).
Step 2
Why this answer is correct
The correct answer is C. (5). For equal (y)-intercepts, (-9=m-14 ). This gives (m=5).
Step 3
Exam Tip
समान (y)-अवरोध के लिए (-9=m-14 ) होगा। इससे (m=5) मिलता है।
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रेखा (y=-8x+30) में (x) कितने बढ़ाने पर (y) (64) घटेगा?
In the line (y=-8x+30), by how much must (x) increase for (y) to decrease by (64)?
#negative_slope
#change_in_x
#total_change
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A (6)
B (7)
C (8)
D (9)
Explanation opens after your attempt
Step 1
Concept
The slope is (-8), so the decrease is \(8\Delta x\). From \(8\Delta x=64\), \(\Delta x=8\).
Step 2
Why this answer is correct
The correct answer is C. (8). The slope is (-8), so the decrease is \(8\Delta x\). From \(8\Delta x=64\), \(\Delta x=8\).
Step 3
Exam Tip
ढाल (-8) है, इसलिए कमी \(8\Delta x\) होगी। \(8\Delta x=64\) से \(\Delta x=8\) है।
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रेखा \(y=\frac{9}{4}x-15\) में (y) को (36) बढ़ाने के लिए (x) कितना बढ़ना चाहिए?
In the line \(y=\frac{9}{4}x-15\), how much should (x) increase to increase (y) by (36)?
#fraction_slope
#change_in_x
#rate
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A (12)
B (14)
C (16)
D (18)
Explanation opens after your attempt
Step 1
Concept
The change is \(\frac{9}{4}\Delta x=36\). This gives \(\Delta x=16\).
Step 2
Why this answer is correct
The correct answer is C. (16). The change is \(\frac{9}{4}\Delta x=36\). This gives \(\Delta x=16\).
Step 3
Exam Tip
परिवर्तन \(\frac{9}{4}\Delta x=36\) होगा। इससे \(\Delta x=16\) मिलता है।
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यदि (y=px+q) में (p=-9) और (q=14), तो सही कथन कौन सा है?
If (p=-9) and (q=14) in (y=px+q), which statement is correct?
#sign_analysis
#graph_behavior
#slope_intercept
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A रेखा बढ़ती है और (y)-अवरोध ऋणात्मक है / The line increases and the (y)-intercept is negative
B रेखा घटती है और (y)-अवरोध धनात्मक है / The line decreases and the (y)-intercept is positive
C रेखा क्षैतिज है और मूल से गुजरती है / The line is horizontal and passes through origin
D रेखा बढ़ती है और मूल से गुजरती है / The line increases and passes through origin
Explanation opens after your attempt
Correct Answer
B. रेखा घटती है और (y)-अवरोध धनात्मक है / The line decreases and the (y)-intercept is positive
Step 1
Concept
(p=-9) gives a negative slope and (q=14) gives a positive (y)-intercept. So the line decreases.
Step 2
Why this answer is correct
The correct answer is B. रेखा घटती है और (y)-अवरोध धनात्मक है / The line decreases and the (y)-intercept is positive. (p=-9) gives a negative slope and (q=14) gives a positive (y)-intercept. So the line decreases.
Step 3
Exam Tip
(p=-9) ऋणात्मक ढाल देता है और (q=14) धनात्मक (y)-अवरोध देता है। इसलिए रेखा घटती है।
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यदि (6x+ay=54) का (y)-अवरोध (9) है, तो (a) क्या है?
If (6x+ay=54) has (y)-intercept (9), what is (a)?
#parameter_intercept
#standard_form
#substitution
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A (4)
B (5)
C (6)
D (9)
Explanation opens after your attempt
Step 1
Concept
Putting (x=0) gives (ay=54) and \(y=\frac{54}{a}\). From \(\frac{54}{a}=9\), (a=6).
Step 2
Why this answer is correct
The correct answer is C. (6). Putting (x=0) gives (ay=54) and \(y=\frac{54}{a}\). From \(\frac{54}{a}=9\), (a=6).
Step 3
Exam Tip
(x=0) रखने पर (ay=54) और \(y=\frac{54}{a}\) मिलता है। \(\frac{54}{a}=9\) से (a=6) है।
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यदि (bx+12y=96) की ढाल (-4) है, तो (b) क्या है?
If (bx+12y=96) has slope (-4), what is (b)?
#parameter_slope
#standard_form
#hard
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A (24)
B (36)
C (48)
D (60)
Explanation opens after your attempt
Step 1
Concept
From (12y=-bx+96), the slope is \(-\frac{b}{12}\). From \(-\frac{b}{12}=-4\), (b=48).
Step 2
Why this answer is correct
The correct answer is C. (48). From (12y=-bx+96), the slope is \(-\frac{b}{12}\). From \(-\frac{b}{12}=-4\), (b=48).
Step 3
Exam Tip
(12y=-bx+96) से ढाल \(-\frac{b}{12}\) है। \(-\frac{b}{12}=-4\) से (b=48) है।
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रेखा (y=(n-9)x+(5n-7)) का (y)-अवरोध (38) है। इसकी ढाल क्या है?
The line (y=(n-9)x+(5n-7)) has (y)-intercept (38). What is its slope?
#parameter_intercept
#find_slope
#zero_slope
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A (0)
B (1)
C (2)
D (3)
Explanation opens after your attempt
Step 1
Concept
From (5n-7=38), (n=9). The slope is (n-9=0).
Step 2
Why this answer is correct
The correct answer is A. (0). From (5n-7=38), (n=9). The slope is (n-9=0).
Step 3
Exam Tip
(5n-7=38) से (n=9) मिलता है। ढाल (n-9=0) है।
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रेखा (y=(t-12)x+(4t-3)) की ढाल (6) है। इसका (y)-अवरोध क्या है?
The line (y=(t-12)x+(4t-3)) has slope (6). What is its (y)-intercept?
#parameter_slope
#find_intercept
#hard
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A (67)
B (68)
C (69)
D (70)
Explanation opens after your attempt
Step 1
Concept
From (t-12=6), (t=18). The (y)-intercept is (4t-3=69).
Step 2
Why this answer is correct
The correct answer is C. (69). From (t-12=6), (t=18). The (y)-intercept is (4t-3=69).
Step 3
Exam Tip
(t-12=6) से (t=18) मिलता है। (y)-अवरोध (4t-3=69) है।
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कौन सी रेखा ((0,-16)) पर (y)-अक्ष काटती है और (x) के (7) बढ़ने पर (y) (70) बढ़ाती है?
Which line cuts the (y)-axis at ((0,-16)) and increases (y) by (70) when (x) increases by (7)?
#equation_from_rate
#intercept
#hard
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A (y=10x-16)
B (y=70x-16)
C (y=-10x-16)
D (y=10x+16)
Explanation opens after your attempt
Correct Answer
A. (y=10x-16)
Step 1
Concept
The slope is \(\frac{70}{7}=10\) and the (y)-intercept is (-16). So the line is (y=10x-16).
Step 2
Why this answer is correct
The correct answer is A. (y=10x-16). The slope is \(\frac{70}{7}=10\) and the (y)-intercept is (-16). So the line is (y=10x-16).
Step 3
Exam Tip
ढाल \(\frac{70}{7}=10\) है और (y)-अवरोध (-16) है। इसलिए रेखा (y=10x-16) है।
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कौन सी रेखा ((0,20)) पर (y)-अक्ष काटती है और (x) के (8) बढ़ने पर (y) (72) घटाती है?
Which line cuts the (y)-axis at ((0,20)) and decreases (y) by (72) when (x) increases by (8)?
#equation_from_rate
#negative_slope
#intercept
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A (y=9x+20)
B (y=-9x+20)
C (y=-72x+20)
D (y=-9x-20)
Explanation opens after your attempt
Correct Answer
B. (y=-9x+20)
Step 1
Concept
The slope is \(-\frac{72}{8}=-9\) and the (y)-intercept is (20). So (y=-9x+20) is correct.
Step 2
Why this answer is correct
The correct answer is B. (y=-9x+20). The slope is \(-\frac{72}{8}=-9\) and the (y)-intercept is (20). So (y=-9x+20) is correct.
Step 3
Exam Tip
ढाल \(-\frac{72}{8}=-9\) है और (y)-अवरोध (20) है। इसलिए (y=-9x+20) सही है।
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यदि (y=(a+11)x+(a-18)) मूल बिंदु से गुजरती है, तो इसकी ढाल क्या होगी?
If (y=(a+11)x+(a-18)) passes through the origin, what will be its slope?
#origin
#parameter
#find_slope
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A (27)
B (28)
C (29)
D (30)
Explanation opens after your attempt
Step 1
Concept
To pass through the origin, (a-18=0). Thus (a=18) and the slope is (29).
Step 2
Why this answer is correct
The correct answer is C. (29). To pass through the origin, (a-18=0). Thus (a=18) and the slope is (29).
Step 3
Exam Tip
मूल बिंदु से गुजरने के लिए (a-18=0) होगा। इसलिए (a=18) और ढाल (29) है।
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यदि (y=(4u-3)x+(u+7)) का (y)-अवरोध (19) है, तो ढाल क्या है?
If (y=(4u-3)x+(u+7)) has (y)-intercept (19), what is the slope?
#parameter_intercept
#find_slope
#linear_form
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A (43)
B (45)
C (47)
D (49)
Explanation opens after your attempt
Step 1
Concept
From (u+7=19), (u=12). The slope is (4u-3=45).
Step 2
Why this answer is correct
The correct answer is B. (45). From (u+7=19), (u=12). The slope is (4u-3=45).
Step 3
Exam Tip
(u+7=19) से (u=12) मिलता है। ढाल (4u-3=45) है।
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समीकरण (12x+5y-65=0) में (y)-अवरोध और ढाल कौन से हैं?
What are the (y)-intercept and slope in (12x+5y-65=0)?
#general_form
#fraction_slope
#y_intercept
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A (y)-अवरोध (13), ढाल \(-\frac{12}{5}\) / (y)-intercept (13), slope \(-\frac{12}{5}\)
B (y)-अवरोध (-13), ढाल \(\frac{12}{5}\) / (y)-intercept (-13), slope \(\frac{12}{5}\)
C (y)-अवरोध (65), ढाल (-12) / (y)-intercept (65), slope (-12)
D (y)-अवरोध (12), ढाल (5) / (y)-intercept (12), slope (5)
Explanation opens after your attempt
Correct Answer
A. (y)-अवरोध (13), ढाल \(-\frac{12}{5}\) / (y)-intercept (13), slope \(-\frac{12}{5}\)
Step 1
Concept
From (5y=-12x+65), \(y=-\frac{12}{5}x+13\). So the (y)-intercept is (13) and slope is \(-\frac{12}{5}\).
Step 2
Why this answer is correct
The correct answer is A. (y)-अवरोध (13), ढाल \(-\frac{12}{5}\) / (y)-intercept (13), slope \(-\frac{12}{5}\). From (5y=-12x+65), \(y=-\frac{12}{5}x+13\). So the (y)-intercept is (13) and slope is \(-\frac{12}{5}\).
Step 3
Exam Tip
(5y=-12x+65) से \(y=-\frac{12}{5}x+13\) मिलता है। इसलिए (y)-अवरोध (13) और ढाल \(-\frac{12}{5}\) है।
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यदि (y=9x+b) और (y=-7x+15) (y)-अक्ष पर एक ही बिंदु काटती हैं, तो (b) क्या है?
If (y=9x+b) and (y=-7x+15) cut the (y)-axis at the same point, what is (b)?
#same_y_intercept
#parameter
#comparison
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A (7)
B (9)
C (15)
D (16)
Explanation opens after your attempt
Step 1
Concept
The same (y)-axis point means equal (y)-intercepts. Therefore (b=15).
Step 2
Why this answer is correct
The correct answer is C. (15). The same (y)-axis point means equal (y)-intercepts. Therefore (b=15).
Step 3
Exam Tip
एक ही (y)-अक्ष बिंदु का अर्थ समान (y)-अवरोध है। इसलिए (b=15) है।
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यदि (y=ax-14) और (y=11x+6) की ढालें समान हैं, तो (x=3) पर पहली रेखा का (y) क्या होगा?
If (y=ax-14) and (y=11x+6) have equal slopes, what is (y) on the first line at (x=3)?
#compare_slopes
#evaluate_line
#parameter
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A (17)
B (19)
C (21)
D (23)
Explanation opens after your attempt
Step 1
Concept
Equal slopes give (a=11). Putting (x=3), (y=11(3)-14=19).
Step 2
Why this answer is correct
The correct answer is B. (19). Equal slopes give (a=11). Putting (x=3), (y=11(3)-14=19).
Step 3
Exam Tip
समान ढाल से (a=11) है। (x=3) रखने पर (y=11(3)-14=19) है।
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रेखा (y=-12x+c) का (y)-अवरोध (9) है। (x=-4) पर (y) क्या होगा?
The line (y=-12x+c) has (y)-intercept (9). What will (y) be at (x=-4)?
#evaluate_line
#negative_x
#intercept_given
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A (48)
B (55)
C (57)
D (60)
Explanation opens after your attempt
Step 1
Concept
The (y)-intercept (9) gives (c=9). Putting (x=-4), (y=-12(-4)+9=57).
Step 2
Why this answer is correct
The correct answer is C. (57). The (y)-intercept (9) gives (c=9). Putting (x=-4), (y=-12(-4)+9=57).
Step 3
Exam Tip
(y)-अवरोध (9) से (c=9) है। (x=-4) रखने पर (y=-12(-4)+9=57) है।
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यदि रेखा (y=(k-6)x+5) (x) के (9) बढ़ने पर (y) (108) बढ़ाती है, तो (k) क्या है?
If the line (y=(k-6)x+5) increases (y) by (108) when (x) increases by (9), what is (k)?
#parameter_slope
#total_change
#hard
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A (16)
B (17)
C (18)
D (19)
Explanation opens after your attempt
Step 1
Concept
The slope is (k-6) and (9(k-6)=108). Therefore (k-6=12) and (k=18).
Step 2
Why this answer is correct
The correct answer is C. (18). The slope is (k-6) and (9(k-6)=108). Therefore (k-6=12) and (k=18).
Step 3
Exam Tip
ढाल (k-6) है और (9(k-6)=108)। इसलिए (k-6=12) और (k=18) है।
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यदि रेखा (y=-(p+5)x+24) (x) के (6) बढ़ने पर (y) (72) घटाती है, तो (p) क्या है?
If the line (y=-(p+5)x+24) decreases (y) by (72) when (x) increases by (6), what is (p)?
#parameter_slope
#negative_slope
#total_change
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A (5)
B (6)
C (7)
D (8)
Explanation opens after your attempt
Step 1
Concept
The slope is (-(p+5)), and the decrease is (6(p+5)=72). So (p+5=12) and (p=7).
Step 2
Why this answer is correct
The correct answer is C. (7). The slope is (-(p+5)), and the decrease is (6(p+5)=72). So (p+5=12) and (p=7).
Step 3
Exam Tip
ढाल (-(p+5)) है और कमी (6(p+5)=72) होगी। इसलिए (p+5=12) और (p=7) है।
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समीकरण (10y-9x=60) में (x=0) पर (y) का मान और ढाल क्या हैं?
In (10y-9x=60), what are the value of (y) at (x=0) and the slope?
#rearrange_equation
#value_at_zero
#slope
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A (y=6), ढाल \(\frac{9}{10}\) / (y=6), slope \(\frac{9}{10}\)
B (y=-6), ढाल \(-\frac{9}{10}\) / (y=-6), slope \(-\frac{9}{10}\)
C (y=60), ढाल (9) / (y=60), slope (9)
D (y=10), ढाल (-9) / (y=10), slope (-9)
Explanation opens after your attempt
Correct Answer
A. (y=6), ढाल \(\frac{9}{10}\) / (y=6), slope \(\frac{9}{10}\)
Step 1
Concept
From (10y=9x+60), \(y=\frac{9}{10}x+6\). So at (x=0), (y=6) and the slope is \(\frac{9}{10}\).
Step 2
Why this answer is correct
The correct answer is A. (y=6), ढाल \(\frac{9}{10}\) / (y=6), slope \(\frac{9}{10}\). From (10y=9x+60), \(y=\frac{9}{10}x+6\). So at (x=0), (y=6) and the slope is \(\frac{9}{10}\).
Step 3
Exam Tip
(10y=9x+60) से \(y=\frac{9}{10}x+6\) मिलता है। इसलिए (x=0) पर (y=6) और ढाल \(\frac{9}{10}\) है।
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यदि (y=mx+c) में (m+c=24) और (c=9), तो ढाल क्या है?
If (m+c=24) and (c=9) in (y=mx+c), what is the slope?
#slope_intercept_relation
#parameter
#hard
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A (9)
B (12)
C (15)
D (24)
Explanation opens after your attempt
Step 1
Concept
Putting (c=9) gives (m+9=24). Therefore (m=15).
Step 2
Why this answer is correct
The correct answer is C. (15). Putting (c=9) gives (m+9=24). Therefore (m=15).
Step 3
Exam Tip
(c=9) रखने पर (m+9=24) मिलता है। इसलिए (m=15) है।
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यदि (y=mx+c) में ढाल (-8) है और (m+c=6), तो (y)-अवरोध क्या है?
If the slope is (-8) and (m+c=6) in (y=mx+c), what is the (y)-intercept?
#slope_intercept_relation
#find_intercept
#hard
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A (8)
B (12)
C (14)
D (-14)
Explanation opens after your attempt
Step 1
Concept
Slope (-8) gives (m=-8). From (-8+c=6), (c=14).
Step 2
Why this answer is correct
The correct answer is C. (14). Slope (-8) gives (m=-8). From (-8+c=6), (c=14).
Step 3
Exam Tip
ढाल (-8) से (m=-8) है। (-8+c=6) से (c=14) है।
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रेखा \(y=\frac{7}{8}x+c\) बिंदु ((16,25)) से गुजरती है। (c) क्या है?
The line \(y=\frac{7}{8}x+c\) passes through ((16,25)). What is (c)?
#fraction_slope
#find_intercept
#point_given
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A (9)
B (10)
C (11)
D (12)
Explanation opens after your attempt
Step 1
Concept
Substituting the point gives (25=\frac{7}{8}(16)+c). So (25=14+c) and (c=11).
Step 2
Why this answer is correct
The correct answer is C. (11). Substituting the point gives (25=\frac{7}{8}(16)+c). So (25=14+c) and (c=11).
Step 3
Exam Tip
बिंदु रखने पर (25=\frac{7}{8}(16)+c) मिलता है। इसलिए (25=14+c) और (c=11) है।
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रेखा (y=mx-9) बिंदु ((18,0)) से गुजरती है। (m) क्या है?
The line (y=mx-9) passes through ((18,0)). What is (m)?
#find_slope
#point_given
#fraction_slope
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A \(\frac{1}{2}\)
B \(\frac{1}{3}\)
C \(\frac{2}{3}\)
D \(\frac{3}{2}\)
Explanation opens after your attempt
Correct Answer
A. \(\frac{1}{2}\)
Step 1
Concept
Substituting the point gives (0=18m-9). Thus (18m=9) and \(m=\frac{1}{2}\).
Step 2
Why this answer is correct
The correct answer is A. \(\frac{1}{2}\). Substituting the point gives (0=18m-9). Thus (18m=9) and \(m=\frac{1}{2}\).
Step 3
Exam Tip
बिंदु रखने पर (0=18m-9) मिलता है। इससे (18m=9) और \(m=\frac{1}{2}\) है।
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यदि (y=(7a-6)x+(a+5)) का (y)-अवरोध (17) है, तो ढाल क्या है?
If (y=(7a-6)x+(a+5)) has (y)-intercept (17), what is the slope?
#parameter_intercept
#find_slope
#linear_form
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A (76)
B (78)
C (80)
D (82)
Explanation opens after your attempt
Step 1
Concept
From (a+5=17), (a=12). The slope is (7a-6=78).
Step 2
Why this answer is correct
The correct answer is B. (78). From (a+5=17), (a=12). The slope is (7a-6=78).
Step 3
Exam Tip
(a+5=17) से (a=12) मिलता है। ढाल (7a-6=78) है।
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यदि (y=(b-15)x+(4b+2)) की ढाल (5) है, तो (y)-अवरोध क्या है?
If (y=(b-15)x+(4b+2)) has slope (5), what is the (y)-intercept?
#parameter_slope
#find_intercept
#linear_form
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A (80)
B (81)
C (82)
D (83)
Explanation opens after your attempt
Step 1
Concept
From (b-15=5), (b=20). The (y)-intercept is (4b+2=82).
Step 2
Why this answer is correct
The correct answer is C. (82). From (b-15=5), (b=20). The (y)-intercept is (4b+2=82).
Step 3
Exam Tip
(b-15=5) से (b=20) मिलता है। (y)-अवरोध (4b+2=82) है।
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समीकरण (9x-10y+30=0) की ढाल और (y)-अवरोध क्या हैं?
What are the slope and (y)-intercept of (9x-10y+30=0)?
#general_form
#fraction_slope
#rearrange
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A ढाल \(\frac{9}{10}\), (y)-अवरोध (3) / Slope \(\frac{9}{10}\), (y)-intercept (3)
B ढाल \(-\frac{9}{10}\), (y)-अवरोध (-3) / Slope \(-\frac{9}{10}\), (y)-intercept (-3)
C ढाल (10), (y)-अवरोध \(\frac{9}{10}\) / Slope (10), (y)-intercept \(\frac{9}{10}\)
D ढाल (9), (y)-अवरोध (-30) / Slope (9), (y)-intercept (-30)
Explanation opens after your attempt
Correct Answer
A. ढाल \(\frac{9}{10}\), (y)-अवरोध (3) / Slope \(\frac{9}{10}\), (y)-intercept (3)
Step 1
Concept
From (-10y=-9x-30), \(y=\frac{9}{10}x+3\). So the slope is \(\frac{9}{10}\) and the (y)-intercept is (3).
Step 2
Why this answer is correct
The correct answer is A. ढाल \(\frac{9}{10}\), (y)-अवरोध (3) / Slope \(\frac{9}{10}\), (y)-intercept (3). From (-10y=-9x-30), \(y=\frac{9}{10}x+3\). So the slope is \(\frac{9}{10}\) and the (y)-intercept is (3).
Step 3
Exam Tip
(-10y=-9x-30) से \(y=\frac{9}{10}x+3\) मिलता है। इसलिए ढाल \(\frac{9}{10}\) और (y)-अवरोध (3) है।
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यदि (y=(t+6)x-10) और (y=16x+(2t-9)) की ढालें समान हैं, तो दूसरी रेखा का (y)-अवरोध क्या है?
If (y=(t+6)x-10) and (y=16x+(2t-9)) have equal slopes, what is the (y)-intercept of the second line?
#compare_slopes
#find_intercept
#parameter
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A (9)
B (11)
C (13)
D (15)
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Step 1
Concept
Equal slopes give (t+6=16) and (t=10). The second line's (y)-intercept is (2t-9=11).
Step 2
Why this answer is correct
The correct answer is B. (11). Equal slopes give (t+6=16) and (t=10). The second line's (y)-intercept is (2t-9=11).
Step 3
Exam Tip
समान ढाल से (t+6=16) और (t=10) है। दूसरी रेखा का (y)-अवरोध (2t-9=11) है।
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यदि (y=6x+(v-11)) और (y=(v+5)x+10) का (y)-अवरोध समान है, तो दूसरी रेखा की ढाल क्या है?
If (y=6x+(v-11)) and (y=(v+5)x+10) have the same (y)-intercept, what is the slope of the second line?
#compare_intercepts
#find_slope
#parameter
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A (24)
B (25)
C (26)
D (27)
Explanation opens after your attempt
Step 1
Concept
Equal (y)-intercepts give (v-11=10) and (v=21). The slope of the second line is (v+5=26).
Step 2
Why this answer is correct
The correct answer is C. (26). Equal (y)-intercepts give (v-11=10) and (v=21). The slope of the second line is (v+5=26).
Step 3
Exam Tip
समान (y)-अवरोध से (v-11=10) और (v=21) है। दूसरी रेखा की ढाल (v+5=26) है।
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रेखा \(y=-\frac{9}{5}x+22\) में (y) को (54) घटाने के लिए (x) कितना बढ़ना चाहिए?
In the line \(y=-\frac{9}{5}x+22\), how much should (x) increase to decrease (y) by (54)?
#negative_fraction_slope
#change_in_x
#rate
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A (25)
B (28)
C (30)
D (35)
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Step 1
Concept
The decrease is \(\frac{9}{5}\Delta x\). From \(\frac{9}{5}\Delta x=54\), \(\Delta x=30\).
Step 2
Why this answer is correct
The correct answer is C. (30). The decrease is \(\frac{9}{5}\Delta x\). From \(\frac{9}{5}\Delta x=54\), \(\Delta x=30\).
Step 3
Exam Tip
कमी \(\frac{9}{5}\Delta x\) होगी। \(\frac{9}{5}\Delta x=54\) से \(\Delta x=30\) मिलता है।
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यदि (y=(k+8)x+3) (x) के (6) बढ़ने पर (y) (96) बढ़ाती है, तो (k) क्या है?
If (y=(k+8)x+3) increases (y) by (96) when (x) increases by (6), what is (k)?
#parameter_slope
#total_change
#solve
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A (6)
B (7)
C (8)
D (9)
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Step 1
Concept
The slope is (k+8) and (6(k+8)=96). Therefore (k+8=16) and (k=8).
Step 2
Why this answer is correct
The correct answer is C. (8). The slope is (k+8) and (6(k+8)=96). Therefore (k+8=16) and (k=8).
Step 3
Exam Tip
ढाल (k+8) है और (6(k+8)=96)। इसलिए (k+8=16) और (k=8) है।
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यदि (y=mx+c) में (c=-18) और (m-c=31), तो ढाल क्या है?
If (c=-18) and (m-c=31) in (y=mx+c), what is the slope?
#slope_intercept_relation
#parameter
#hard
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A (11)
B (12)
C (13)
D (14)
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Step 1
Concept
Putting (c=-18) gives (m-(-18)=31). Therefore (m=13).
Step 2
Why this answer is correct
The correct answer is C. (13). Putting (c=-18) gives (m-(-18)=31). Therefore (m=13).
Step 3
Exam Tip
(c=-18) रखने पर (m-(-18)=31) मिलता है। इसलिए (m=13) है।
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यदि (y=mx+c) में (m=-6) और (4c+m=42), तो (y)-अवरोध क्या है?
If (m=-6) and (4c+m=42) in (y=mx+c), what is the (y)-intercept?
#slope_intercept_relation
#find_intercept
#hard
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A (10)
B (11)
C (12)
D (13)
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Step 1
Concept
Putting (m=-6) gives (4c-6=42). Thus (4c=48) and (c=12).
Step 2
Why this answer is correct
The correct answer is C. (12). Putting (m=-6) gives (4c-6=42). Thus (4c=48) and (c=12).
Step 3
Exam Tip
(m=-6) रखने पर (4c-6=42) मिलता है। इससे (4c=48) और (c=12) है।
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