find_intercept se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.
46 questions tagged with find_intercept.
If (m=-6) and (4c+m=42) in (y=mx+c), what is the (y)-intercept?
C. (12)
(m=-6) रखने पर (4c-6=42) मिलता है। इससे (4c=48) और (c=12) है। / Putting (m=-6) gives (4c-6=42). Thus (4c=48) and (c=12).
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If (y=(t+6)x-10) and (y=16x+(2t-9)) have equal slopes, what is the (y)-intercept of the second line?
B. (11)
समान ढाल से (t+6=16) और (t=10) है। दूसरी रेखा का (y)-अवरोध (2t-9=11) है। / Equal slopes give (t+6=16) and (t=10). The second line's (y)-intercept is (2t-9=11).
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If (y=(b-15)x+(4b+2)) has slope (5), what is the (y)-intercept?
C. (82)
(b-15=5) से (b=20) मिलता है। (y)-अवरोध (4b+2=82) है। / From (b-15=5), (b=20). The (y)-intercept is (4b+2=82).
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The line \(y=\frac{7}{8}x+c\) passes through ((16,25)). What is (c)?
C. (11)
बिंदु रखने पर (25=\frac{7}{8}(16)+c) मिलता है। इसलिए (25=14+c) और (c=11) है। / Substituting the point gives (25=\frac{7}{8}(16)+c). So (25=14+c) and (c=11).
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If the slope is (-8) and (m+c=6) in (y=mx+c), what is the (y)-intercept?
C. (14)
ढाल (-8) से (m=-8) है। (-8+c=6) से (c=14) है। / Slope (-8) gives (m=-8). From (-8+c=6), (c=14).
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The line (y=(t-12)x+(4t-3)) has slope (6). What is its (y)-intercept?
C. (69)
(t-12=6) से (t=18) मिलता है। (y)-अवरोध (4t-3=69) है। / From (t-12=6), (t=18). The (y)-intercept is (4t-3=69).
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The line (y=-7x+c) passes through ((4,-20)). What is its (y)-intercept?
D. (8)
बिंदु रखने पर (-20=-7(4)+c) मिलता है। इसलिए (c=8) है। / Substituting the point gives (-20=-7(4)+c). Therefore (c=8).
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If (m=-5) and (3c+m=31) in (y=mx+c), what is the (y)-intercept?
C. (12)
(m=-5) रखने पर (3c-5=31) मिलता है। इससे (3c=36) और (c=12) है। / Putting (m=-5) gives (3c-5=31). Thus (3c=36) and (c=12).
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If (y=(t+5)x-9) and (y=14x+(2t-7)) have equal slopes, what is the (y)-intercept of the second line?
B. (11)
समान ढाल से (t+5=14) और (t=9) है। दूसरी रेखा का (y)-अवरोध (2t-7=11) है। / Equal slopes give (t+5=14) and (t=9). The second line's (y)-intercept is (2t-7=11).
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If (y=(b-13)x+(3b+1)) has slope (4), what is the (y)-intercept?
B. (52)
(b-13=4) से (b=17) मिलता है। (y)-अवरोध (3b+1=52) है। / From (b-13=4), (b=17). The (y)-intercept is (3b+1=52).
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The line \(y=\frac{5}{6}x+c\) passes through ((12,19)). What is (c)?
B. (9)
बिंदु रखने पर (19=\frac{5}{6}(12)+c) मिलता है। इसलिए (19=10+c) और (c=9) है। / Substituting the point gives (19=\frac{5}{6}(12)+c). So (19=10+c) and (c=9).
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If the slope is (-7) and (m+c=5) in (y=mx+c), what is the (y)-intercept?
C. (12)
ढाल (-7) से (m=-7) है। (-7+c=5) से (c=12) है। / Slope (-7) gives (m=-7). From (-7+c=5), (c=12).
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The line (y=(t-10)x+(3t-1)) has slope (5). What is its (y)-intercept?
B. (44)
(t-10=5) से (t=15) मिलता है। (y)-अवरोध (3t-1=44) है। / From (t-10=5), (t=15). The (y)-intercept is (3t-1=44).
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The line (y=-6x+c) passes through ((5,-18)). What is its (y)-intercept?
D. (12)
बिंदु रखने पर (-18=-6(5)+c) मिलता है। इसलिए (c=12) है। / Substituting the point gives (-18=-6(5)+c). Therefore (c=12).
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If (m=-4) and (2c+m=18) in (y=mx+c), what is the (y)-intercept?
C. (11)
(m=-4) रखने पर (2c-4=18) मिलता है। इससे (2c=22) और (c=11) है। / Putting (m=-4) gives (2c-4=18). Thus (2c=22) and (c=11).
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If (y=(t+4)x-8) and (y=12x+(2t-5)) have equal slopes, what is the (y)-intercept of the second line?
A. (11)
समान ढाल से (t+4=12) और (t=8) है। दूसरी रेखा का (y)-अवरोध (2t-5=11) है। / Equal slopes give (t+4=12) and (t=8). The second line's (y)-intercept is (2t-5=11).
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If (y=(b-11)x+(2b+5)) has slope (2), what is the (y)-intercept?
A. (29)
(b-11=2) से (b=13) मिलता है। (y)-अवरोध (2b+5=31) नहीं, (31) है। / From (b-11=2), (b=13). The (y)-intercept is (2b+5=31), so option (C) is correct.
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The line \(y=\frac{4}{5}x+c\) passes through ( (10,15) ). What is (c)?
C. (7)
बिंदु रखने पर (15=\frac{4}{5}(10)+c) मिलता है। इसलिए (15=8+c) और (c=7) है। / Substituting the point gives (15=\frac{4}{5}(10)+c). So (15=8+c) and (c=7).
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If the slope is (-6) and (m+c=4) in (y=mx+c), what is the (y)-intercept?
C. (10)
ढाल (-6) से (m=-6) है। (-6+c=4) से (c=10), जो (y)-अवरोध है। / Slope (-6) gives (m=-6). From (-6+c=4), (c=10), which is the (y)-intercept.
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The line (y=(t-9)x+(2t+1)) has slope (3). What is its (y)-intercept?
C. (25)
(t-9=3) से (t=12) मिलता है। (y)-अवरोध (2t+1=25) है। / From (t-9=3), (t=12). The (y)-intercept is (2t+1=25).
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The line (y=-5x+c) passes through ( (4,-11) ). What is its (y)-intercept?
C. (9)
बिंदु रखने पर (-11=-5(4)+c) मिलता है। इसलिए (c=9), जो (y)-अवरोध है। / Substituting the point gives (-11=-5(4)+c). Therefore (c=9), which is the (y)-intercept.
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If (m=-3) and (3c+m=18) in (y=mx+c), what is the (y)-intercept?
C. (7)
(m=-3) रखने पर (3c-3=18) मिलता है। इससे (3c=21) और (c=7) है। / Putting (m=-3) gives (3c-3=18). Thus (3c=21) and (c=7).
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If (y=(t+2)x-6) and (y=9x+(2t-1)) have equal slopes, what is the (y)-intercept of the second line?
B. (13)
समान ढाल से (t+2=9) और (t=7) है। दूसरी रेखा का (y)-अवरोध (2t-1=13) है। / Equal slopes give (t+2=9) and (t=7). The second line's (y)-intercept is (2t-1=13).
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If (y=(b-9)x+(3b-2)) has slope (1), what is the (y)-intercept?
B. (28)
(b-9=1) से (b=10) मिलता है। (y)-अवरोध (3b-2=28) है। / From (b-9=1), (b=10). The (y)-intercept is (3b-2=28).
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The line \(y=\frac{3}{4}x+c\) passes through ( (8,10) ). What is (c)?
C. (4)
बिंदु रखने पर (10=\frac{3}{4}(8)+c) मिलता है। इसलिए (10=6+c) और (c=4) है। / Substituting the point gives (10=\frac{3}{4}(8)+c). So (10=6+c) and (c=4).
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If the slope is (-5) and (m+c=2) in (y=mx+c), what is the (y)-intercept?
C. (7)
ढाल (-5) से (m=-5) है। (-5+c=2) से (c=7), जो (y)-अवरोध है। / Slope (-5) gives (m=-5). From (-5+c=2), (c=7), which is the (y)-intercept.
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The line (y=(t-8)x+(t+5)) has slope (6). What is its (y)-intercept?
D. (19)
(t-8=6) से (t=14) मिलता है। (y)-अवरोध (t+5=19) है। / From (t-8=6), (t=14). The (y)-intercept is (t+5=19).
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The line (y=-4x+c) passes through ( (3,-5) ). What is its (y)-intercept?
B. (7)
बिंदु रखने पर (-5=-4(3)+c) मिलता है। इसलिए (c=7), जो (y)-अवरोध है। / Substituting the point gives (-5=-4(3)+c). Therefore (c=7), the (y)-intercept.
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If (m=-2) and (2c+m=10) in (y=mx+c), what is the (y)-intercept?
C. (6)
(m=-2) रखने पर (2c-2=10) मिलता है। इससे (2c=12) और (c=6) है। / Putting (m=-2) gives (2c-2=10). Thus (2c=12) and (c=6).
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If (y=(t+1)x-4) and (y=8x+(2t-3)) have equal slopes, what is the (y)-intercept of the second line?
C. (13)
समान ढाल से (t+1=8) और (t=7) है। दूसरी रेखा का (y)-अवरोध (2t-3=11) नहीं बल्कि (11) है। / Equal slopes give (t+1=8) and (t=7). The second line's (y)-intercept is (2t-3=11), so option (A) is correct.
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