Concept-wise Practice

linear form MCQ Questions for Class 10

linear form se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

4 questions tagged with linear form.

यदि \(a_n=An+B\), \(a_2=11\) और \(a_5=26\), तो सामान्य अंतर क्या है?

If \(a_n=An+B\), \(a_2=11\) and \(a_5=26\), what is the common difference?

Explanation opens after your attempt
Correct Answer

C. (5)

Step 1

Concept

\(a_5-a_2=3d=15\), so (d=5). In exams, even for a linear form, (d) can be found from term differences.

Step 2

Why this answer is correct

The correct answer is C. (5). \(a_5-a_2=3d=15\), so (d=5). In exams, even for a linear form, (d) can be found from term differences.

Step 3

Exam Tip

\(a_5-a_2=3d=15\), इसलिए (d=5)। परीक्षा में रैखिक रूप में भी पदों के अंतर से (d) निकाला जा सकता है।

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(p(x)=ax+b) में यदि \(a\ne0\) है, तो इसकी घात क्या होती है?

In (p(x)=ax+b), if \(a\ne0\), what is its degree?

Explanation opens after your attempt
Correct Answer

B. (1)

Step 1

Concept

When \(a\ne0\), the (x)-term exists, so the degree is (1). This is the form of a linear polynomial.

Step 2

Why this answer is correct

The correct answer is B. (1). When \(a\ne0\), the (x)-term exists, so the degree is (1). This is the form of a linear polynomial.

Step 3

Exam Tip

\(a\ne0\) होने पर (x) वाला पद मौजूद है, इसलिए घात (1) है। यही रैखिक बहुपद का रूप है।

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यदि (p(x)=ax+b) और \(a\neq0\), तो (p(x)) की घात क्या है?

If (p(x)=ax+b) and \(a\neq0\), what is the degree of (p(x))?

Explanation opens after your attempt
Correct Answer

B. (1)

Step 1

Concept

Since \(a\neq0\), the (x)-term is present. Therefore the degree of the polynomial is (1).

Step 2

Why this answer is correct

The correct answer is B. (1). Since \(a\neq0\), the (x)-term is present. Therefore the degree of the polynomial is (1).

Step 3

Exam Tip

\(a\neq0\) होने से (x) वाला पद मौजूद है। इसलिए बहुपद की घात (1) है।

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यदि \(a+b\sqrt{2}=0\) है जहां (a) और (b) परिमेय हैं तथा \(b\neq 0\) है तो क्या निष्कर्ष निकलेगा?

If \(a+b\sqrt{2}=0\) where (a) and (b) are rational and \(b\neq 0\) then what conclusion follows?

Explanation opens after your attempt
Correct Answer

A. \(\sqrt{2}=-\frac{a}{b}\) परिमेय होगा जो असंभव है\(\sqrt{2}=-\frac{a}{b}\) would be rational which is impossible

Step 1

Concept

The equation gives \(\sqrt{2}=-\frac{a}{b}\).

Step 2

Why this answer is correct

\(-\frac{a}{b}\) is rational but \(\sqrt{2}\) is irrational.

Step 3

Exam Tip

Such questions use irrationality to create a contradiction. चरण 1: समीकरण से \(\sqrt{2}=-\frac{a}{b}\) मिलेगा। चरण 2: \(-\frac{a}{b}\) परिमेय है लेकिन \(\sqrt{2}\) अपरिमेय है। चरण 3: ऐसे प्रश्नों में अपरिमेयता से विरोधाभास बनता है।

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