समीकरण (16x+4y=52) को (y=mx+c) रूप में लिखने पर ढाल और (y)-अवरोध क्या होंगे?
When (16x+4y=52) is written in (y=mx+c) form, what are the slope and (y)-intercept?
Explanation opens after your attempt
A. ढाल (-4), (y)-अवरोध (13)Slope (-4), (y)-intercept (13)
Concept
From (4y=-16x+52), we get (y=-4x+13). The coefficient is the slope and the constant term is the (y)-intercept.
Why this answer is correct
The correct answer is A. ढाल (-4), (y)-अवरोध (13) / Slope (-4), (y)-intercept (13). From (4y=-16x+52), we get (y=-4x+13). The coefficient is the slope and the constant term is the (y)-intercept.
Exam Tip
(4y=-16x+52) से (y=-4x+13) मिलता है। गुणांक ढाल और स्थिर पद (y)-अवरोध होता है।
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