समीकरण (12x+5y-65=0) में (y)-अवरोध और ढाल कौन से हैं?
What are the (y)-intercept and slope in (12x+5y-65=0)?
Explanation opens after your attempt
A. (y)-अवरोध (13), ढाल \(-\frac{12}{5}\)(y)-intercept (13), slope \(-\frac{12}{5}\)
Concept
From (5y=-12x+65), \(y=-\frac{12}{5}x+13\). So the (y)-intercept is (13) and slope is \(-\frac{12}{5}\).
Why this answer is correct
The correct answer is A. (y)-अवरोध (13), ढाल \(-\frac{12}{5}\) / (y)-intercept (13), slope \(-\frac{12}{5}\). From (5y=-12x+65), \(y=-\frac{12}{5}x+13\). So the (y)-intercept is (13) and slope is \(-\frac{12}{5}\).
Exam Tip
(5y=-12x+65) से \(y=-\frac{12}{5}x+13\) मिलता है। इसलिए (y)-अवरोध (13) और ढाल \(-\frac{12}{5}\) है।
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