समीकरण (12x+5y-65=0) में (y)-अवरोध और ढाल कौन से हैं?

What are the (y)-intercept and slope in (12x+5y-65=0)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. (y)-अवरोध (13), ढाल \(-\frac{12}{5}\)(y)-intercept (13), slope \(-\frac{12}{5}\)

Step 1

Concept

From (5y=-12x+65), \(y=-\frac{12}{5}x+13\). So the (y)-intercept is (13) and slope is \(-\frac{12}{5}\).

Step 2

Why this answer is correct

The correct answer is A. (y)-अवरोध (13), ढाल \(-\frac{12}{5}\) / (y)-intercept (13), slope \(-\frac{12}{5}\). From (5y=-12x+65), \(y=-\frac{12}{5}x+13\). So the (y)-intercept is (13) and slope is \(-\frac{12}{5}\).

Step 3

Exam Tip

(5y=-12x+65) से \(y=-\frac{12}{5}x+13\) मिलता है। इसलिए (y)-अवरोध (13) और ढाल \(-\frac{12}{5}\) है।

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Mathematics Answer, Explanation and Revision Hints

समीकरण (12x+5y-65=0) में (y)-अवरोध और ढाल कौन से हैं? / What are the (y)-intercept and slope in (12x+5y-65=0)?

Correct Answer: A. (y)-अवरोध (13), ढाल \(-\frac{12}{5}\) / (y)-intercept (13), slope \(-\frac{12}{5}\). Explanation: (5y=-12x+65) से \(y=-\frac{12}{5}x+13\) मिलता है। इसलिए (y)-अवरोध (13) और ढाल \(-\frac{12}{5}\) है। / From (5y=-12x+65), \(y=-\frac{12}{5}x+13\). So the (y)-intercept is (13) and slope is \(-\frac{12}{5}\).

Which concept should I revise for this Mathematics MCQ?

From (5y=-12x+65), \(y=-\frac{12}{5}x+13\). So the (y)-intercept is (13) and slope is \(-\frac{12}{5}\).

What exam hint can help solve this Mathematics question?

(5y=-12x+65) से \(y=-\frac{12}{5}x+13\) मिलता है। इसलिए (y)-अवरोध (13) और ढाल \(-\frac{12}{5}\) है।