समीकरण (9x+py=27) और (3x+5y=11) का अद्वितीय हल होने के लिए कौन-सी शर्त सही है?
Which condition is correct for (9x+py=27) and (3x+5y=11) to have a unique solution?
Explanation opens after your attempt
Correct Answer
B. \(p \ne 15\)
Step 1
Concept
For a unique solution, \(9/3 \ne p/5\) must hold. Therefore, \(p \ne 15\) is the correct condition.
Step 2
Why this answer is correct
The correct answer is B. \(p \ne 15\). For a unique solution, \(9/3 \ne p/5\) must hold. Therefore, \(p \ne 15\) is the correct condition.
Step 3
Exam Tip
अद्वितीय हल के लिए \(9/3 \ne p/5\) होना चाहिए। इसलिए \(p \ne 15\) सही शर्त है।
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समीकरण (4x+by=28) और (12x+21y=84) के अनंत हल होने के लिए (b) का मान क्या है?
What is the value of (b) for (4x+by=28) and (12x+21y=84) to have infinitely many solutions?
Explanation opens after your attempt
Step 1
Concept
For infinitely many solutions, (4/12=b/21=28/84) must hold. Therefore, (b=7).
Step 2
Why this answer is correct
The correct answer is C. (7). For infinitely many solutions, (4/12=b/21=28/84) must hold. Therefore, (b=7).
Step 3
Exam Tip
अनंत हल के लिए (4/12=b/21=28/84) होना चाहिए। इसलिए (b=7) होगा।
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यदि (ax+6y=18) और (10x+15y=47) का कोई हल नहीं है, तो (a) क्या होगा?
If (ax+6y=18) and (10x+15y=47) have no solution, what will (a) be?
Explanation opens after your attempt
Step 1
Concept
For no solution, (a/10=6/15) and (18/47) must be different. Therefore, (a=4).
Step 2
Why this answer is correct
The correct answer is C. (4). For no solution, (a/10=6/15) and (18/47) must be different. Therefore, (a=4).
Step 3
Exam Tip
कोई हल नहीं के लिए (a/10=6/15) और (18/47) अलग होना चाहिए। इसलिए (a=4) है।
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समीकरण (8x+ay=40) और (2x+6y=13) का कोई हल न होने के लिए (a) क्या होगा?
What will (a) be for (8x+ay=40) and (2x+6y=13) to have no solution?
Explanation opens after your attempt
Step 1
Concept
For no solution, (8/2=a/6) and (40/13) must be different. Therefore, (a=24).
Step 2
Why this answer is correct
The correct answer is D. (24). For no solution, (8/2=a/6) and (40/13) must be different. Therefore, (a=24).
Step 3
Exam Tip
कोई हल नहीं के लिए (8/2=a/6) और (40/13) अलग होना चाहिए। इसलिए (a=24) है।
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समीकरण (5x+ky=35) और (x+4y=7) के अनंत हल होने के लिए (k) का मान क्या होगा?
What is the value of (k) for (5x+ky=35) and (x+4y=7) to have infinitely many solutions?
Explanation opens after your attempt
Step 1
Concept
The first equation must be (5) times the second, so (k=20). A common multiplier makes both lines coincident.
Step 2
Why this answer is correct
The correct answer is C. (20). The first equation must be (5) times the second, so (k=20). A common multiplier makes both lines coincident.
Step 3
Exam Tip
पहला समीकरण दूसरे का (5) गुना होना चाहिए, इसलिए (k=20)। समान गुणक से दोनों रेखाएं संपाती होती हैं।
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समीकरण (3x+qy=11) और (7x+14y=26) का अद्वितीय हल होने के लिए कौन-सी शर्त सही है?
Which condition is correct for (3x+qy=11) and (7x+14y=26) to have a unique solution?
Explanation opens after your attempt
Correct Answer
B. \(q \ne 6\)
Step 1
Concept
For a unique solution, \(3/7 \ne q/14\) must hold. Therefore, \(q \ne 6\) is correct.
Step 2
Why this answer is correct
The correct answer is B. \(q \ne 6\). For a unique solution, \(3/7 \ne q/14\) must hold. Therefore, \(q \ne 6\) is correct.
Step 3
Exam Tip
अद्वितीय हल के लिए \(3/7 \ne q/14\) होना चाहिए। इसलिए \(q \ne 6\) सही है।
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समीकरण (px+3y=15) और (12x+6y=30) के अनंत हल होने के लिए (p) क्या होगा?
What will (p) be for (px+3y=15) and (12x+6y=30) to have infinitely many solutions?
Explanation opens after your attempt
Step 1
Concept
For infinitely many solutions, (p/12=3/6=15/30) must hold. Therefore, (p=6).
Step 2
Why this answer is correct
The correct answer is C. (6). For infinitely many solutions, (p/12=3/6=15/30) must hold. Therefore, (p=6).
Step 3
Exam Tip
अनंत हल के लिए (p/12=3/6=15/30) होना चाहिए। इसलिए (p=6) है।
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समीकरण (kx+7y=28) और (8x+14y=60) का कोई हल न होने के लिए (k) का मान क्या होगा?
What value of (k) makes (kx+7y=28) and (8x+14y=60) have no solution?
Explanation opens after your attempt
Step 1
Concept
For no solution, (k/8=7/14) and (28/60) must be different. This gives (k=4).
Step 2
Why this answer is correct
The correct answer is C. (4). For no solution, (k/8=7/14) and (28/60) must be different. This gives (k=4).
Step 3
Exam Tip
कोई हल नहीं के लिए (k/8=7/14) और (28/60) अलग होना चाहिए। इससे (k=4) मिलता है।
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समीकरण (5x+4y=18) और (10x+8y=k) के अनंत हल होने के लिए (k) का मान क्या होगा?
What is the value of (k) for (5x+4y=18) and (10x+8y=k) to have infinitely many solutions?
Explanation opens after your attempt
Step 1
Concept
The second equation must be (2) times the first, so (k=36). For infinitely many solutions, keep all three ratios equal.
Step 2
Why this answer is correct
The correct answer is B. (36). The second equation must be (2) times the first, so (k=36). For infinitely many solutions, keep all three ratios equal.
Step 3
Exam Tip
दूसरा समीकरण पहले का (2) गुना होना चाहिए, इसलिए (k=36)। अनंत हल के लिए तीनों अनुपात बराबर रखें।
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समीकरण (2x+my=14) और (8x+20y=56) के अनंत हल होने के लिए (m) का मान क्या होगा?
What will be the value of (m) for (2x+my=14) and (8x+20y=56) to have infinitely many solutions?
Explanation opens after your attempt
Step 1
Concept
For infinitely many solutions, (2/8=m/20=14/56) must hold. Therefore, (m=5).
Step 2
Why this answer is correct
The correct answer is A. (5). For infinitely many solutions, (2/8=m/20=14/56) must hold. Therefore, (m=5).
Step 3
Exam Tip
अनंत हल के लिए (2/8=m/20=14/56) होना चाहिए। इसलिए (m=5) है।
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यदि (lx+7y=21) और (6x+14y=40) का कोई हल नहीं है, तो (l) का मान क्या होगा?
If (lx+7y=21) and (6x+14y=40) have no solution, what will be the value of (l)?
Explanation opens after your attempt
Step 1
Concept
For no solution, (l/6=7/14) and (21/40) must be different. Hence (l=3).
Step 2
Why this answer is correct
The correct answer is C. (3). For no solution, (l/6=7/14) and (21/40) must be different. Hence (l=3).
Step 3
Exam Tip
कोई हल नहीं के लिए (l/6=7/14) और (21/40) अलग होना चाहिए। इसलिए (l=3)।
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समीकरण (5x+ky=25) और (x+3y=5) के अनंत हल होने के लिए (k) क्या होगा?
What will (k) be for (5x+ky=25) and (x+3y=5) to have infinitely many solutions?
Explanation opens after your attempt
Step 1
Concept
The first equation must be (5) times the second. Therefore, (k=15).
Step 2
Why this answer is correct
The correct answer is B. (15). The first equation must be (5) times the second. Therefore, (k=15).
Step 3
Exam Tip
पहला समीकरण दूसरे का (5) गुना होना चाहिए। इसलिए (k=15)।
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समीकरण (2x+3y=5) और (4x+ay=11) का कोई हल न होने के लिए (a) क्या होगा?
What will (a) be for (2x+3y=5) and (4x+ay=11) to have no solution?
Explanation opens after your attempt
Step 1
Concept
For no solution, (2/4=3/a) and (5/11) must be different. This gives (a=6).
Step 2
Why this answer is correct
The correct answer is C. (6). For no solution, (2/4=3/a) and (5/11) must be different. This gives (a=6).
Step 3
Exam Tip
कोई हल नहीं के लिए (2/4=3/a) और (5/11) अलग होना चाहिए। इससे (a=6) मिलता है।
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समीकरण (3x+5y=14) और (6x+10y=r) के असंगत होने के लिए कौन-सी शर्त सही है?
Which condition is correct for (3x+5y=14) and (6x+10y=r) to be inconsistent?
Explanation opens after your attempt
Correct Answer
B. \(r \ne 28\)
Step 1
Concept
The first two ratios are equal, so for inconsistency the constant ratio must be different. Hence \(r \ne 28\).
Step 2
Why this answer is correct
The correct answer is B. \(r \ne 28\). The first two ratios are equal, so for inconsistency the constant ratio must be different. Hence \(r \ne 28\).
Step 3
Exam Tip
पहले दो अनुपात बराबर हैं, इसलिए असंगत होने के लिए स्थिर पद का अनुपात अलग होना चाहिए। अतः \(r \ne 28\)।
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समीकरण (x+4y=9) और (2x+8y=s) के संगत और आश्रित होने के लिए (s) क्या होगा?
What should (s) be for (x+4y=9) and (2x+8y=s) to be consistent and dependent?
Explanation opens after your attempt
Step 1
Concept
To be consistent and dependent, the second equation must be (2) times the first. Hence, (s=18).
Step 2
Why this answer is correct
The correct answer is C. (18). To be consistent and dependent, the second equation must be (2) times the first. Hence, (s=18).
Step 3
Exam Tip
संगत और आश्रित होने के लिए दूसरा समीकरण पहले का (2) गुना होना चाहिए। अतः (s=18)।
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यदि (6x-2y=18) और (3x-y=t) असंगत हों, तो (t) के लिए सही शर्त क्या है?
If (6x-2y=18) and (3x-y=t) are inconsistent, what is the correct condition for (t)?
Explanation opens after your attempt
Correct Answer
B. \(t \ne 9\)
Step 1
Concept
The first two ratios are equal, so for inconsistency (18/t) must be different. Hence \(t \ne 9\).
Step 2
Why this answer is correct
The correct answer is B. \(t \ne 9\). The first two ratios are equal, so for inconsistency (18/t) must be different. Hence \(t \ne 9\).
Step 3
Exam Tip
पहले दो अनुपात बराबर हैं, इसलिए असंगत होने के लिए (18/t) अलग होना चाहिए। अतः \(t \ne 9\)।
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यदि (5x+2y=16) और (10x+4y=n) के अनंत हल हैं, तो (n) कितना होगा?
If (5x+2y=16) and (10x+4y=n) have infinitely many solutions, what is (n)?
Explanation opens after your attempt
Step 1
Concept
The second equation must be (2) times the first. Therefore, (n=32).
Step 2
Why this answer is correct
The correct answer is D. (32). The second equation must be (2) times the first. Therefore, (n=32).
Step 3
Exam Tip
दूसरा समीकरण पहले का (2) गुना होना चाहिए। इसलिए (n=32) होगा।
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समीकरण (8x+py=24) और (2x+3y=7) का अद्वितीय हल होने के लिए कौन-सी शर्त सही है?
Which condition is correct for (8x+py=24) and (2x+3y=7) to have a unique solution?
Explanation opens after your attempt
Correct Answer
B. \(p \ne 12\)
Step 1
Concept
For a unique solution, \(8/2 \ne p/3\) must hold. Therefore, \(p \ne 12\).
Step 2
Why this answer is correct
The correct answer is B. \(p \ne 12\). For a unique solution, \(8/2 \ne p/3\) must hold. Therefore, \(p \ne 12\).
Step 3
Exam Tip
अद्वितीय हल के लिए \(8/2 \ne p/3\) होना चाहिए। इसलिए \(p \ne 12\)।
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समीकरण (3x+by=15) और (9x+12y=45) के अनंत हल होने के लिए (b) क्या होगा?
What will (b) be for (3x+by=15) and (9x+12y=45) to have infinitely many solutions?
Explanation opens after your attempt
Step 1
Concept
For infinitely many solutions, (3/9=b/12=15/45) must hold. Therefore, (b=4).
Step 2
Why this answer is correct
The correct answer is C. (4). For infinitely many solutions, (3/9=b/12=15/45) must hold. Therefore, (b=4).
Step 3
Exam Tip
अनंत हल के लिए (3/9=b/12=15/45) होना चाहिए। इसलिए (b=4) है।
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यदि समीकरण (ax+4y=10) और (6x+8y=25) का कोई हल नहीं है, तो (a) का मान क्या है?
If the equations (ax+4y=10) and (6x+8y=25) have no solution, what is the value of (a)?
Explanation opens after your attempt
Step 1
Concept
For no solution, (a/6=4/8) and (10/25) must be different. Hence (a=3).
Step 2
Why this answer is correct
The correct answer is B. (3). For no solution, (a/6=4/8) and (10/25) must be different. Hence (a=3).
Step 3
Exam Tip
कोई हल नहीं के लिए (a/6=4/8) और (10/25) अलग होना चाहिए। इसलिए (a=3)।
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समीकरण (6x+ay=30) और (2x+5y=11) का कोई हल न होने के लिए (a) का मान क्या है?
What is the value of (a) for (6x+ay=30) and (2x+5y=11) to have no solution?
Explanation opens after your attempt
Step 1
Concept
For no solution, (6/2=a/5) and (30/11) must be different. This gives (a=15).
Step 2
Why this answer is correct
The correct answer is D. (15). For no solution, (6/2=a/5) and (30/11) must be different. This gives (a=15).
Step 3
Exam Tip
कोई हल नहीं के लिए (6/2=a/5) और (30/11) अलग होना चाहिए। इससे (a=15) मिलता है।
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समीकरण (4x+ky=16) और (x+3y=4) के अनंत हल होने के लिए (k) क्या होगा?
What will (k) be for (4x+ky=16) and (x+3y=4) to have infinitely many solutions?
Explanation opens after your attempt
Step 1
Concept
The first equation must be (4) times the second, so (k=12). A common multiplier makes the lines coincident.
Step 2
Why this answer is correct
The correct answer is C. (12). The first equation must be (4) times the second, so (k=12). A common multiplier makes the lines coincident.
Step 3
Exam Tip
पहला समीकरण दूसरे का (4) गुना होना चाहिए, इसलिए (k=12)। समान गुणक से रेखाएं संपाती बनती हैं।
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समीकरण (2x+qy=8) और (5x+10y=21) का अद्वितीय हल होने के लिए कौन-सी शर्त सही है?
Which condition is correct for (2x+qy=8) and (5x+10y=21) to have a unique solution?
Explanation opens after your attempt
Correct Answer
B. \(q \ne 4\)
Step 1
Concept
For a unique solution, \(2/5 \ne q/10\) must hold. Therefore, \(q \ne 4\) is the correct condition.
Step 2
Why this answer is correct
The correct answer is B. \(q \ne 4\). For a unique solution, \(2/5 \ne q/10\) must hold. Therefore, \(q \ne 4\) is the correct condition.
Step 3
Exam Tip
अद्वितीय हल के लिए \(2/5 \ne q/10\) होना चाहिए। इसलिए \(q \ne 4\) सही शर्त है।
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समीकरण (px+2y=6) और (9x+6y=18) के अनंत हल होने के लिए (p) का मान क्या है?
What is the value of (p) for (px+2y=6) and (9x+6y=18) to have infinitely many solutions?
Explanation opens after your attempt
Step 1
Concept
For infinitely many solutions, (p/9=2/6=6/18), so (p=3). All three ratios must be equal.
Step 2
Why this answer is correct
The correct answer is C. (3). For infinitely many solutions, (p/9=2/6=6/18), so (p=3). All three ratios must be equal.
Step 3
Exam Tip
अनंत हल के लिए (p/9=2/6=6/18), इसलिए (p=3)। तीनों अनुपात बराबर होने चाहिए।
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समीकरण (kx+5y=20) और (6x+10y=45) का कोई हल न होने के लिए (k) क्या होगा?
What should (k) be for (kx+5y=20) and (6x+10y=45) to have no solution?
Explanation opens after your attempt
Step 1
Concept
For no solution, (k/6=5/10) and (20/45) must be different. This gives (k=3).
Step 2
Why this answer is correct
The correct answer is B. (3). For no solution, (k/6=5/10) and (20/45) must be different. This gives (k=3).
Step 3
Exam Tip
कोई हल नहीं के लिए (k/6=5/10) और (20/45) अलग होना चाहिए। इससे (k=3) मिलता है।
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यदि समीकरण (4x+6y=18) और (2x+3y=k) के अनंत हल हों, तो (k) का मान क्या होगा?
If the equations (4x+6y=18) and (2x+3y=k) have infinitely many solutions, what is the value of (k)?
Explanation opens after your attempt
Step 1
Concept
The first equation must be (2) times the second, so (k=9). For infinitely many solutions, keep all three ratios equal.
Step 2
Why this answer is correct
The correct answer is C. (9). The first equation must be (2) times the second, so (k=9). For infinitely many solutions, keep all three ratios equal.
Step 3
Exam Tip
पहला समीकरण दूसरे का (2) गुना होना चाहिए, इसलिए (k=9)। परीक्षा में अनंत हल के लिए तीनों अनुपात बराबर रखें।
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समीकरण (3x+2y=11) और (6x+4y=t) का कोई हल न होने के लिए (t) क्या नहीं होना चाहिए?
What should (t) not be for (3x+2y=11) and (6x+4y=t) to have no solution?
Explanation opens after your attempt
Step 1
Concept
For no solution \(3/6=2/4 \ne 11/t\) must hold. If (t=22) the pair will have infinitely many solutions.
Step 2
Why this answer is correct
The correct answer is C. (22). For no solution \(3/6=2/4 \ne 11/t\) must hold. If (t=22) the pair will have infinitely many solutions.
Step 3
Exam Tip
कोई हल नहीं के लिए \(3/6=2/4 \ne 11/t\) होना चाहिए। यदि (t=22) हो तो अनंत हल हो जाएंगे।
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समीकरण (2x+3y=9) और (4x+ky=18) के अनंत हल होने के लिए (k) क्या होगा?
What will (k) be for (2x+3y=9) and (4x+ky=18) to have infinitely many solutions?
Explanation opens after your attempt
Step 1
Concept
For infinitely many solutions (2/4=3/k=9/18) must hold. This gives (k=6).
Step 2
Why this answer is correct
The correct answer is C. (6). For infinitely many solutions (2/4=3/k=9/18) must hold. This gives (k=6).
Step 3
Exam Tip
अनंत हल के लिए (2/4=3/k=9/18) होना चाहिए। इससे (k=6) मिलता है।
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समीकरण (qx+6y=18) और (5x+3y=12) का अद्वितीय हल होने के लिए कौन-सी शर्त सही है?
Which condition is correct for (qx+6y=18) and (5x+3y=12) to have a unique solution?
Explanation opens after your attempt
Correct Answer
B. \(q \ne 10\)
Step 1
Concept
For a unique solution \(q/5 \ne 6/3\) must hold. Therefore \(q \ne 10\) is the correct condition.
Step 2
Why this answer is correct
The correct answer is B. \(q \ne 10\). For a unique solution \(q/5 \ne 6/3\) must hold. Therefore \(q \ne 10\) is the correct condition.
Step 3
Exam Tip
अद्वितीय हल के लिए \(q/5 \ne 6/3\) होना चाहिए। इसलिए \(q \ne 10\) सही शर्त है।
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समीकरण (ax+3y=12) और (8x+6y=25) का कोई हल न होने के लिए (a) क्या होगा?
What will (a) be for (ax+3y=12) and (8x+6y=25) to have no solution?
Explanation opens after your attempt
Step 1
Concept
For no solution (a/8=3/6) and (12/25) must be different. This gives (a=4).
Step 2
Why this answer is correct
The correct answer is C. (4). For no solution (a/8=3/6) and (12/25) must be different. This gives (a=4).
Step 3
Exam Tip
कोई हल नहीं के लिए (a/8=3/6) और (12/25) अलग होना चाहिए। इससे (a=4) मिलता है।
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