यदि (ax+6y=18) और (10x+15y=47) का कोई हल नहीं है, तो (a) क्या होगा?
If (ax+6y=18) and (10x+15y=47) have no solution, what will (a) be?
Explanation opens after your attempt
C. (4)
Concept
For no solution, (a/10=6/15) and (18/47) must be different. Therefore, (a=4).
Why this answer is correct
The correct answer is C. (4). For no solution, (a/10=6/15) and (18/47) must be different. Therefore, (a=4).
Exam Tip
कोई हल नहीं के लिए (a/10=6/15) और (18/47) अलग होना चाहिए। इसलिए (a=4) है।
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