समीकरण (9x+py=27) और (3x+5y=11) का अद्वितीय हल होने के लिए कौन-सी शर्त सही है?

Which condition is correct for (9x+py=27) and (3x+5y=11) to have a unique solution?

Explanation opens after your attempt
Correct Answer

B. \(p \ne 15\)

Step 1

Concept

For a unique solution, \(9/3 \ne p/5\) must hold. Therefore, \(p \ne 15\) is the correct condition.

Step 2

Why this answer is correct

The correct answer is B. \(p \ne 15\). For a unique solution, \(9/3 \ne p/5\) must hold. Therefore, \(p \ne 15\) is the correct condition.

Step 3

Exam Tip

अद्वितीय हल के लिए \(9/3 \ne p/5\) होना चाहिए। इसलिए \(p \ne 15\) सही शर्त है।

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समीकरण (9x+py=27) और (3x+5y=11) का अद्वितीय हल होने के लिए कौन-सी शर्त सही है? / Which condition is correct for (9x+py=27) and (3x+5y=11) to have a unique solution?

Correct Answer: B. \(p \ne 15\). Explanation: अद्वितीय हल के लिए \(9/3 \ne p/5\) होना चाहिए। इसलिए \(p \ne 15\) सही शर्त है। / For a unique solution, \(9/3 \ne p/5\) must hold. Therefore, \(p \ne 15\) is the correct condition.

Which concept should I revise for this Mathematics MCQ?

For a unique solution, \(9/3 \ne p/5\) must hold. Therefore, \(p \ne 15\) is the correct condition.

What exam hint can help solve this Mathematics question?

अद्वितीय हल के लिए \(9/3 \ne p/5\) होना चाहिए। इसलिए \(p \ne 15\) सही शर्त है।