समीकरण (8x+py=24) और (2x+3y=7) का अद्वितीय हल होने के लिए कौन-सी शर्त सही है?

Which condition is correct for (8x+py=24) and (2x+3y=7) to have a unique solution?

Explanation opens after your attempt
Correct Answer

B. \(p \ne 12\)

Step 1

Concept

For a unique solution, \(8/2 \ne p/3\) must hold. Therefore, \(p \ne 12\).

Step 2

Why this answer is correct

The correct answer is B. \(p \ne 12\). For a unique solution, \(8/2 \ne p/3\) must hold. Therefore, \(p \ne 12\).

Step 3

Exam Tip

अद्वितीय हल के लिए \(8/2 \ne p/3\) होना चाहिए। इसलिए \(p \ne 12\)।

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समीकरण (8x+py=24) और (2x+3y=7) का अद्वितीय हल होने के लिए कौन-सी शर्त सही है? / Which condition is correct for (8x+py=24) and (2x+3y=7) to have a unique solution?

Correct Answer: B. \(p \ne 12\). Explanation: अद्वितीय हल के लिए \(8/2 \ne p/3\) होना चाहिए। इसलिए \(p \ne 12\)। / For a unique solution, \(8/2 \ne p/3\) must hold. Therefore, \(p \ne 12\).

Which concept should I revise for this Mathematics MCQ?

For a unique solution, \(8/2 \ne p/3\) must hold. Therefore, \(p \ne 12\).

What exam hint can help solve this Mathematics question?

अद्वितीय हल के लिए \(8/2 \ne p/3\) होना चाहिए। इसलिए \(p \ne 12\)।