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parameter MCQ Questions for Class 10

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737 questions tagged with parameter.

Question 91/737 Hard Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 58

समीकरणों (ax+4y=10) और (6x+8y=25) का कोई हल न होने के लिए (a) का मान क्या होगा?

What is the value of (a) for the equations (ax+4y=10) and (6x+8y=25) to have no solution?

Explanation opens after your attempt
Correct Answer

B. (3)

Step 1

Concept

For no solution, (a/6=4/8) and (10/25) must be different. This gives (a=3).

Step 2

Why this answer is correct

The correct answer is B. (3). For no solution, (a/6=4/8) and (10/25) must be different. This gives (a=3).

Step 3

Exam Tip

कोई हल नहीं के लिए (a/6=4/8) और (10/25) अलग होना चाहिए। इससे (a=3) मिलता है।

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Question 92/737 Hard Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 58

समीकरणों (3x+ky=12) और (9x+15y=36) के अनंत हल होने के लिए (k) का मान क्या होगा?

What is the value of (k) for the equations (3x+ky=12) and (9x+15y=36) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (5)

Step 1

Concept

For infinitely many solutions, (3/9=k/15=12/36) must hold. Therefore, (k=5) is correct.

Step 2

Why this answer is correct

The correct answer is C. (5). For infinitely many solutions, (3/9=k/15=12/36) must hold. Therefore, (k=5) is correct.

Step 3

Exam Tip

अनंत हल के लिए (3/9=k/15=12/36) होना चाहिए। इसलिए (k=5) सही है।

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Question 93/737 Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

समीकरण (5x+2y=18) और (15x+ky=54) का अद्वितीय हल होने के लिए कौन-सी शर्त सही है?

Which condition is correct for (5x+2y=18) and (15x+ky=54) to have a unique solution?

Explanation opens after your attempt
Correct Answer

B. \(k \ne 6\)

Step 1

Concept

For a unique solution \(5/15 \ne 2/k\) must hold. Therefore \(k \ne 6\) is the correct condition.

Step 2

Why this answer is correct

The correct answer is B. \(k \ne 6\). For a unique solution \(5/15 \ne 2/k\) must hold. Therefore \(k \ne 6\) is the correct condition.

Step 3

Exam Tip

अद्वितीय हल के लिए \(5/15 \ne 2/k\) होना चाहिए। इसलिए \(k \ne 6\) सही शर्त है।

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Question 94/737 Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

समीकरण (4x+ay=36) और (12x+21y=108) के अनंत हल होने के लिए (a) का मान क्या होगा?

What will be the value of (a) for (4x+ay=36) and (12x+21y=108) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (7)

Step 1

Concept

For infinitely many solutions (4/12=a/21=36/108) must hold. Therefore (a=7).

Step 2

Why this answer is correct

The correct answer is C. (7). For infinitely many solutions (4/12=a/21=36/108) must hold. Therefore (a=7).

Step 3

Exam Tip

अनंत हल के लिए (4/12=a/21=36/108) होना चाहिए। इसलिए (a=7) मिलता है।

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Question 95/737 Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

समीकरण (3x+4y=22) और (9x+12y=t) के असंगत होने के लिए (t) के लिए सही शर्त क्या है?

What is the correct condition on (t) for (3x+4y=22) and (9x+12y=t) to be inconsistent?

Explanation opens after your attempt
Correct Answer

B. \(t \ne 66\)

Step 1

Concept

The first two ratios are equal so the constant ratio must be different for inconsistency. Hence \(t \ne 66\) is correct.

Step 2

Why this answer is correct

The correct answer is B. \(t \ne 66\). The first two ratios are equal so the constant ratio must be different for inconsistency. Hence \(t \ne 66\) is correct.

Step 3

Exam Tip

पहले दो अनुपात बराबर हैं इसलिए असंगत होने के लिए स्थिर पद का अनुपात अलग होना चाहिए। अतः \(t \ne 66\) सही है।

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Question 96/737 Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

यदि (lx+11y=44) और (10x+22y=91) का कोई हल नहीं है तो (l) का मान क्या होगा?

If (lx+11y=44) and (10x+22y=91) have no solution then what will be the value of (l)?

Explanation opens after your attempt
Correct Answer

C. (5)

Step 1

Concept

For no solution (l/10=11/22) and (44/91) must be different. Hence (l=5).

Step 2

Why this answer is correct

The correct answer is C. (5). For no solution (l/10=11/22) and (44/91) must be different. Hence (l=5).

Step 3

Exam Tip

कोई हल नहीं के लिए (l/10=11/22) और (44/91) अलग होना चाहिए। इसलिए (l=5)।

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Question 97/737 Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

समीकरण (8x+ky=72) और (2x+7y=18) के अनंत हल होने के लिए (k) क्या होगा?

What will (k) be for (8x+ky=72) and (2x+7y=18) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (28)

Step 1

Concept

The first equation must be (4) times the second. Therefore (k=28).

Step 2

Why this answer is correct

The correct answer is C. (28). The first equation must be (4) times the second. Therefore (k=28).

Step 3

Exam Tip

पहला समीकरण दूसरे का (4) गुना होना चाहिए। इसलिए (k=28) है।

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Question 98/737 Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

समीकरण (5x+3y=14) और (10x+ay=33) का कोई हल न होने के लिए (a) क्या होगा?

What will (a) be for (5x+3y=14) and (10x+ay=33) to have no solution?

Explanation opens after your attempt
Correct Answer

C. (6)

Step 1

Concept

For no solution (5/10=3/a) and (14/33) must be different. This gives (a=6).

Step 2

Why this answer is correct

The correct answer is C. (6). For no solution (5/10=3/a) and (14/33) must be different. This gives (a=6).

Step 3

Exam Tip

कोई हल नहीं के लिए (5/10=3/a) और (14/33) अलग होना चाहिए। इससे (a=6) मिलता है।

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Question 99/737 Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

समीकरण (6x+7y=31) और (12x+14y=r) के असंगत होने के लिए कौन-सी शर्त सही है?

Which condition is correct for (6x+7y=31) and (12x+14y=r) to be inconsistent?

Explanation opens after your attempt
Correct Answer

B. \(r \ne 62\)

Step 1

Concept

The first two ratios are equal so the constant ratio must be different for inconsistency. Hence \(r \ne 62\).

Step 2

Why this answer is correct

The correct answer is B. \(r \ne 62\). The first two ratios are equal so the constant ratio must be different for inconsistency. Hence \(r \ne 62\).

Step 3

Exam Tip

पहले दो अनुपात बराबर हैं इसलिए असंगत होने के लिए स्थिर पद का अनुपात अलग होना चाहिए। अतः \(r \ne 62\)।

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Question 100/737 Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

समीकरण (4x+5y=29) और (8x+10y=s) के संगत और आश्रित होने के लिए (s) क्या होगा?

What should (s) be for (4x+5y=29) and (8x+10y=s) to be consistent and dependent?

Explanation opens after your attempt
Correct Answer

C. (58)

Step 1

Concept

To be consistent and dependent the second equation must be (2) times the first. Hence (s=58).

Step 2

Why this answer is correct

The correct answer is C. (58). To be consistent and dependent the second equation must be (2) times the first. Hence (s=58).

Step 3

Exam Tip

संगत और आश्रित होने के लिए दूसरा समीकरण पहले का (2) गुना होना चाहिए। अतः (s=58)।

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Question 101/737 Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

यदि (10x-5y=30) और (2x-y=t) असंगत हैं तो (t) के लिए सही शर्त क्या है?

If (10x-5y=30) and (2x-y=t) are inconsistent then what is the correct condition for (t)?

Explanation opens after your attempt
Correct Answer

B. \(t \ne 6\)

Step 1

Concept

The first two ratios are equal so (30/t) must be different for inconsistency. Hence \(t \ne 6\).

Step 2

Why this answer is correct

The correct answer is B. \(t \ne 6\). The first two ratios are equal so (30/t) must be different for inconsistency. Hence \(t \ne 6\).

Step 3

Exam Tip

पहले दो अनुपात बराबर हैं इसलिए असंगत होने के लिए (30/t) अलग होना चाहिए। अतः \(t \ne 6\)।

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Question 102/737 Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

यदि (7x+4y=37) और (21x+12y=n) के अनंत हल हैं तो (n) कितना होगा?

If (7x+4y=37) and (21x+12y=n) have infinitely many solutions then what is (n)?

Explanation opens after your attempt
Correct Answer

C. (111)

Step 1

Concept

The second equation must be (3) times the first. Therefore (n=111).

Step 2

Why this answer is correct

The correct answer is C. (111). The second equation must be (3) times the first. Therefore (n=111).

Step 3

Exam Tip

दूसरा समीकरण पहले का (3) गुना होना चाहिए। इसलिए (n=111) होगा।

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Question 103/737 Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

समीकरण (11x+py=33) और (4x+2y=15) का अद्वितीय हल होने के लिए कौन-सी शर्त सही है?

Which condition is correct for (11x+py=33) and (4x+2y=15) to have a unique solution?

Explanation opens after your attempt
Correct Answer

B. (p \ne 112)

Step 1

Concept

For a unique solution \(11/4 \ne p/2\) must hold. Therefore \(p \ne 11/2\) is the correct condition.

Step 2

Why this answer is correct

The correct answer is B. \(p \ne 11 / 2\). For a unique solution \(11/4 \ne p/2\) must hold. Therefore \(p \ne 11/2\) is the correct condition.

Step 3

Exam Tip

अद्वितीय हल के लिए \(11/4 \ne p/2\) होना चाहिए। इसलिए \(p \ne 11/2\) सही शर्त है।

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Question 104/737 Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

समीकरण (3x+by=24) और (12x+20y=96) के अनंत हल होने के लिए (b) का मान क्या है?

What is the value of (b) for (3x+by=24) and (12x+20y=96) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (5)

Step 1

Concept

For infinitely many solutions (3/12=b/20=24/96) must hold. Therefore (b=5).

Step 2

Why this answer is correct

The correct answer is C. (5). For infinitely many solutions (3/12=b/20=24/96) must hold. Therefore (b=5).

Step 3

Exam Tip

अनंत हल के लिए (3/12=b/20=24/96) होना चाहिए। इसलिए (b=5)।

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Question 105/737 Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

यदि (ax+9y=27) और (14x+21y=64) का कोई हल नहीं है तो (a) क्या होगा?

If (ax+9y=27) and (14x+21y=64) have no solution then what will (a) be?

Explanation opens after your attempt
Correct Answer

C. (6)

Step 1

Concept

For no solution (a/14=9/21) and (27/64) must be different. Therefore (a=6).

Step 2

Why this answer is correct

The correct answer is C. (6). For no solution (a/14=9/21) and (27/64) must be different. Therefore (a=6).

Step 3

Exam Tip

कोई हल नहीं के लिए (a/14=9/21) और (27/64) अलग होना चाहिए। इसलिए (a=6)।

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Question 106/737 Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

समीकरण (bx+8y=32) और (12x+24y=71) का कोई हल न होने के लिए (b) क्या होगा?

What will (b) be for (bx+8y=32) and (12x+24y=71) to have no solution?

Explanation opens after your attempt
Correct Answer

B. (4)

Step 1

Concept

For no solution (b/12=8/24) and (32/71) must be different. Hence (b=4).

Step 2

Why this answer is correct

The correct answer is B. (4). For no solution (b/12=8/24) and (32/71) must be different. Hence (b=4).

Step 3

Exam Tip

कोई हल नहीं के लिए (b/12=8/24) और (32/71) अलग होना चाहिए। इसलिए (b=4)।

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Question 107/737 Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

समीकरण (5x+ay=35) और (15x+18y=105) के अनंत हल होने के लिए (a) क्या होगा?

What will (a) be for (5x+ay=35) and (15x+18y=105) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (6)

Step 1

Concept

For infinitely many solutions (5/15=a/18=35/105) must hold. This gives (a=6).

Step 2

Why this answer is correct

The correct answer is C. (6). For infinitely many solutions (5/15=a/18=35/105) must hold. This gives (a=6).

Step 3

Exam Tip

अनंत हल के लिए (5/15=a/18=35/105) होना चाहिए। इससे (a=6) मिलता है।

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Question 108/737 Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

समीकरण (6x+ky=24) और (3x+5y=17) का अद्वितीय हल होने के लिए कौन-सी शर्त सही है?

Which condition is correct for (6x+ky=24) and (3x+5y=17) to have a unique solution?

Explanation opens after your attempt
Correct Answer

B. \(k \ne 10\)

Step 1

Concept

For a unique solution \(6/3 \ne k/5\) must hold. Therefore \(k \ne 10\) is the correct condition.

Step 2

Why this answer is correct

The correct answer is B. \(k \ne 10\). For a unique solution \(6/3 \ne k/5\) must hold. Therefore \(k \ne 10\) is the correct condition.

Step 3

Exam Tip

अद्वितीय हल के लिए \(6/3 \ne k/5\) होना चाहिए। इसलिए \(k \ne 10\) सही शर्त है।

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Question 109/737 Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

समीकरण (7x+qy=29) और (14x+10y=58) के अनंत हल होने के लिए (q) क्या होगा?

What will (q) be for (7x+qy=29) and (14x+10y=58) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (5)

Step 1

Concept

The second equation is (2) times the first so (q/10=1/2) must hold. Hence (q=5).

Step 2

Why this answer is correct

The correct answer is C. (5). The second equation is (2) times the first so (q/10=1/2) must hold. Hence (q=5).

Step 3

Exam Tip

दूसरा समीकरण पहले का (2) गुना है इसलिए (q/10=1/2) होना चाहिए। अतः (q=5)।

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Question 110/737 Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

समीकरण (px+6y=18) और (10x+15y=45) के अनंत हल होने के लिए (p) का मान क्या होगा?

What is the value of (p) for (px+6y=18) and (10x+15y=45) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

B. (3)

Step 1

Concept

For infinitely many solutions (p/10=6/15=18/45) must hold. Therefore (p=3).

Step 2

Why this answer is correct

The correct answer is B. (3). For infinitely many solutions (p/10=6/15=18/45) must hold. Therefore (p=3).

Step 3

Exam Tip

अनंत हल के लिए (p/10=6/15=18/45) होना चाहिए। इसलिए (p=3)।

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Question 111/737 Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

समीकरण (ax+4y=20) और (9x+12y=61) का कोई हल न होने के लिए (a) का मान क्या होगा?

What is the value of (a) for (ax+4y=20) and (9x+12y=61) to have no solution?

Explanation opens after your attempt
Correct Answer

B. (3)

Step 1

Concept

For no solution (a/9=4/12) and (20/61) must be different. This gives (a=3).

Step 2

Why this answer is correct

The correct answer is B. (3). For no solution (a/9=4/12) and (20/61) must be different. This gives (a=3).

Step 3

Exam Tip

कोई हल नहीं के लिए (a/9=4/12) और (20/61) अलग होना चाहिए। इससे (a=3) मिलता है।

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Question 112/737 Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 60

समीकरण (2x+5y=16) और (6x+15y=k) के अनंत हल होने के लिए (k) का मान क्या होगा?

What is the value of (k) for (2x+5y=16) and (6x+15y=k) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

B. (48)

Step 1

Concept

The second equation must be (3) times the first so (k=48). For infinitely many solutions all ratios must be equal.

Step 2

Why this answer is correct

The correct answer is B. (48). The second equation must be (3) times the first so (k=48). For infinitely many solutions all ratios must be equal.

Step 3

Exam Tip

दूसरा समीकरण पहले का (3) गुना होना चाहिए इसलिए (k=48)। अनंत हल के लिए सभी अनुपात बराबर होने चाहिए।

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Question 113/737 Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 59

समीकरण (3x+my=24) और (12x+28y=96) के अनंत हल होने के लिए (m) का मान क्या होगा?

What will be the value of (m) for (3x+my=24) and (12x+28y=96) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. (7)

Step 1

Concept

For infinitely many solutions, (3/12=m/28=24/96) must hold. Therefore, (m=7) is correct.

Step 2

Why this answer is correct

The correct answer is C. (7). For infinitely many solutions, (3/12=m/28=24/96) must hold. Therefore, (m=7) is correct.

Step 3

Exam Tip

अनंत हल के लिए (3/12=m/28=24/96) होना चाहिए। इसलिए (m=7) सही है।

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Question 114/737 Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 59

यदि (lx+9y=27) और (8x+18y=55) का कोई हल नहीं है, तो (l) का मान क्या होगा?

If (lx+9y=27) and (8x+18y=55) have no solution, what will be the value of (l)?

Explanation opens after your attempt
Correct Answer

C. (4)

Step 1

Concept

For no solution, (l/8=9/18) and (27/55) must be different. Hence, (l=4).

Step 2

Why this answer is correct

The correct answer is C. (4). For no solution, (l/8=9/18) and (27/55) must be different. Hence, (l=4).

Step 3

Exam Tip

कोई हल नहीं के लिए (l/8=9/18) और (27/55) अलग होना चाहिए। इसलिए (l=4)।

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Question 115/737 Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 59

समीकरण (6x+ky=42) और (2x+5y=14) के अनंत हल होने के लिए (k) क्या होगा?

What will (k) be for (6x+ky=42) and (2x+5y=14) to have infinitely many solutions?

Explanation opens after your attempt
Correct Answer

B. (15)

Step 1

Concept

The first equation must be (3) times the second. Therefore, (k=15).

Step 2

Why this answer is correct

The correct answer is B. (15). The first equation must be (3) times the second. Therefore, (k=15).

Step 3

Exam Tip

पहला समीकरण दूसरे का (3) गुना होना चाहिए। इसलिए (k=15) है।

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Question 116/737 Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 59

समीकरण (3x+4y=10) और (6x+ay=25) का कोई हल न होने के लिए (a) क्या होगा?

What will (a) be for (3x+4y=10) and (6x+ay=25) to have no solution?

Explanation opens after your attempt
Correct Answer

C. (8)

Step 1

Concept

For no solution, (3/6=4/a) and (10/25) must be different. This gives (a=8).

Step 2

Why this answer is correct

The correct answer is C. (8). For no solution, (3/6=4/a) and (10/25) must be different. This gives (a=8).

Step 3

Exam Tip

कोई हल नहीं के लिए (3/6=4/a) और (10/25) अलग होना चाहिए। इससे (a=8) मिलता है।

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Question 117/737 Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 59

समीकरण (5x+6y=29) और (10x+12y=r) के असंगत होने के लिए कौन-सी शर्त सही है?

Which condition is correct for (5x+6y=29) and (10x+12y=r) to be inconsistent?

Explanation opens after your attempt
Correct Answer

B. \(r \ne 58\)

Step 1

Concept

The first two ratios are equal, so for inconsistency the constant ratio must be different. Hence, \(r \ne 58\).

Step 2

Why this answer is correct

The correct answer is B. \(r \ne 58\). The first two ratios are equal, so for inconsistency the constant ratio must be different. Hence, \(r \ne 58\).

Step 3

Exam Tip

पहले दो अनुपात बराबर हैं, इसलिए असंगत होने के लिए स्थिर पद का अनुपात अलग होना चाहिए। अतः \(r \ne 58\)।

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Question 118/737 Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 59

समीकरण (2x+5y=17) और (4x+10y=s) के संगत और आश्रित होने के लिए (s) क्या होगा?

What should (s) be for (2x+5y=17) and (4x+10y=s) to be consistent and dependent?

Explanation opens after your attempt
Correct Answer

C. (34)

Step 1

Concept

To be consistent and dependent, the second equation must be (2) times the first. Hence, (s=34).

Step 2

Why this answer is correct

The correct answer is C. (34). To be consistent and dependent, the second equation must be (2) times the first. Hence, (s=34).

Step 3

Exam Tip

संगत और आश्रित होने के लिए दूसरा समीकरण पहले का (2) गुना होना चाहिए। अतः (s=34)।

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Question 119/737 Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 59

यदि (8x-4y=24) और (2x-y=t) असंगत हैं, तो (t) के लिए सही शर्त क्या है?

If (8x-4y=24) and (2x-y=t) are inconsistent, what is the correct condition for (t)?

Explanation opens after your attempt
Correct Answer

B. \(t \ne 6\)

Step 1

Concept

The first two ratios are equal, so for inconsistency (24/t) must be different. Hence, \(t \ne 6\).

Step 2

Why this answer is correct

The correct answer is B. \(t \ne 6\). The first two ratios are equal, so for inconsistency (24/t) must be different. Hence, \(t \ne 6\).

Step 3

Exam Tip

पहले दो अनुपात बराबर हैं, इसलिए असंगत होने के लिए (24/t) अलग होना चाहिए। अतः \(t \ne 6\)।

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Question 120/737 Medium Mathematics Pair of Linear Equations in Two Variables Conditions for solvability Class 10 Level 59

यदि (6x+5y=31) और (12x+10y=n) के अनंत हल हैं, तो (n) कितना होगा?

If (6x+5y=31) and (12x+10y=n) have infinitely many solutions, what is (n)?

Explanation opens after your attempt
Correct Answer

C. (62)

Step 1

Concept

The second equation must be (2) times the first. Therefore, (n=62).

Step 2

Why this answer is correct

The correct answer is C. (62). The second equation must be (2) times the first. Therefore, (n=62).

Step 3

Exam Tip

दूसरा समीकरण पहले का (2) गुना होना चाहिए। इसलिए (n=62) होगा।

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