समीकरण (3x+qy=11) और (7x+14y=26) का अद्वितीय हल होने के लिए कौन-सी शर्त सही है?

Which condition is correct for (3x+qy=11) and (7x+14y=26) to have a unique solution?

Explanation opens after your attempt
Correct Answer

B. \(q \ne 6\)

Step 1

Concept

For a unique solution, \(3/7 \ne q/14\) must hold. Therefore, \(q \ne 6\) is correct.

Step 2

Why this answer is correct

The correct answer is B. \(q \ne 6\). For a unique solution, \(3/7 \ne q/14\) must hold. Therefore, \(q \ne 6\) is correct.

Step 3

Exam Tip

अद्वितीय हल के लिए \(3/7 \ne q/14\) होना चाहिए। इसलिए \(q \ne 6\) सही है।

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समीकरण (3x+qy=11) और (7x+14y=26) का अद्वितीय हल होने के लिए कौन-सी शर्त सही है? / Which condition is correct for (3x+qy=11) and (7x+14y=26) to have a unique solution?

Correct Answer: B. \(q \ne 6\). Explanation: अद्वितीय हल के लिए \(3/7 \ne q/14\) होना चाहिए। इसलिए \(q \ne 6\) सही है। / For a unique solution, \(3/7 \ne q/14\) must hold. Therefore, \(q \ne 6\) is correct.

Which concept should I revise for this Mathematics MCQ?

For a unique solution, \(3/7 \ne q/14\) must hold. Therefore, \(q \ne 6\) is correct.

What exam hint can help solve this Mathematics question?

अद्वितीय हल के लिए \(3/7 \ne q/14\) होना चाहिए। इसलिए \(q \ne 6\) सही है।