समीकरण (3x+qy=11) और (7x+14y=26) का अद्वितीय हल होने के लिए कौन-सी शर्त सही है?
Which condition is correct for (3x+qy=11) and (7x+14y=26) to have a unique solution?
Explanation opens after your attempt
B. \(q \ne 6\)
Concept
For a unique solution, \(3/7 \ne q/14\) must hold. Therefore, \(q \ne 6\) is correct.
Why this answer is correct
The correct answer is B. \(q \ne 6\). For a unique solution, \(3/7 \ne q/14\) must hold. Therefore, \(q \ne 6\) is correct.
Exam Tip
अद्वितीय हल के लिए \(3/7 \ne q/14\) होना चाहिए। इसलिए \(q \ne 6\) सही है।
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