यदि (p(x)=3x-2 +bx-10) में (x=2) एक शून्य है, तो (b) का मान क्या होगा?
If (x=2) is a zero of (p(x)=3x-2 +bx-10), what will be the value of (b)?
#zero
#parameter
#quadratic polynomial
A (-1)
B (-2)
C (1)
D (2)
Explanation opens after your attempt
Step 1
Concept
(p(2)=12+2b-10=0), so (2b=-2) and (b=-1). When a zero is given, set the polynomial value equal to (0).
Step 2
Why this answer is correct
The correct answer is A. (-1). (p(2)=12+2b-10=0), so (2b=-2) and (b=-1). When a zero is given, set the polynomial value equal to (0).
Step 3
Exam Tip
(p(2)=12+2b-10=0), इसलिए (2b=-2) और (b=-1)। शून्य दिए होने पर बहुपद का मान (0) रखें।
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यदि (p(x)=kx-2 +6x+9) और (p(-3)=0), तो (k) क्या है?
If (p(x)=kx-2 +6x+9) and (p(-3)=0), what is (k)?
#parameter
#zero condition
#quadratic polynomial
A (1)
B (2)
C (3)
D (4)
Explanation opens after your attempt
Step 1
Concept
(p(-3)=9k-18+9=0), so (9k-9=0) and (k=1). Substitute the given zero to find the unknown coefficient.
Step 2
Why this answer is correct
The correct answer is A. (1). (p(-3)=9k-18+9=0), so (9k-9=0) and (k=1). Substitute the given zero to find the unknown coefficient.
Step 3
Exam Tip
(p(-3)=9k-18+9=0), इसलिए (9k-9=0) और (k=1)। दिए गए शून्य को रखकर अज्ञात गुणांक निकालें।
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यदि (p(x)=(m-2 )x-3 +4x-2 -7) की घात (2) है, तो (m) का मान क्या होगा?
If the degree of (p(x)=(m-2 )x-3 +4x-2 -7) is (2), what will be the value of (m)?
#degree
#parameter
#polynomial
A (0)
B (2)
C (4)
D (6)
Explanation opens after your attempt
Step 1
Concept
For the degree to be (2), the coefficient of \(x^3\) must be (0), so (m-2 =0) and (m=2). In exams, check the coefficient of the highest power first.
Step 2
Why this answer is correct
The correct answer is B. (2). For the degree to be (2), the coefficient of \(x^3\) must be (0), so (m-2 =0) and (m=2). In exams, check the coefficient of the highest power first.
Step 3
Exam Tip
घात (2) होने के लिए \(x^3\) का गुणांक (0) होना चाहिए, इसलिए (m-2 =0) और (m=2)। परीक्षा में सबसे ऊंची घात के गुणांक को पहले देखें।
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किस मान के लिए \(x^2-4x+m\) में (x=1) शून्य होगा?
For what value of (m) will (x=1) be a zero of \(x^2-4x+m\)?
#zero
#parameter
#quadratic
A (1)
B (2)
C (3)
D (4)
Explanation opens after your attempt
Step 1
Concept
(1-4+m=0), so (m=3). When a zero is given, set the polynomial value equal to (0).
Step 2
Why this answer is correct
The correct answer is C. (3). (1-4+m=0), so (m=3). When a zero is given, set the polynomial value equal to (0).
Step 3
Exam Tip
(1-4+m=0), इसलिए (m=3)। शून्य मिलने पर बहुपद का मान (0) रखें।
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यदि (p(x)=x-2 -ax+10) और (p(5)=0), तो (a) का मान क्या है?
If (p(x)=x-2 -ax+10) and (p(5)=0), what is the value of (a)?
#parameter
#evaluation
#quadratic polynomial
A (5)
B (7)
C (10)
D (15)
Explanation opens after your attempt
Step 1
Concept
(p(5)=25-5a+10=0), so (35=5a) and (a=7). Use the given zero.
Step 2
Why this answer is correct
The correct answer is B. (7). (p(5)=25-5a+10=0), so (35=5a) and (a=7). Use the given zero.
Step 3
Exam Tip
(p(5)=25-5a+10=0), इसलिए (35=5a) और (a=7)। दिए गए शून्य का उपयोग करें।
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यदि (p(x)=x-2 +kx+6) और (p(2)=0), तो (k) क्या है?
If (p(x)=x-2 +kx+6) and (p(2)=0), what is (k)?
#parameter
#zero condition
#polynomial
A (-5)
B (-4)
C (4)
D (5)
Explanation opens after your attempt
Step 1
Concept
(p(2)=4+2k+6=0), so (2k=-10) and (k=-5). Substitute the zero and form an equation.
Step 2
Why this answer is correct
The correct answer is A. (-5). (p(2)=4+2k+6=0), so (2k=-10) and (k=-5). Substitute the zero and form an equation.
Step 3
Exam Tip
(p(2)=4+2k+6=0), इसलिए (2k=-10) और (k=-5)। शून्य की शर्त में मान रखकर समीकरण बनाएं।
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(p(x)=2x-2 +kx+8) में (x) का गुणांक (5) हो तो (k) क्या है?
If the coefficient of (x) in (p(x)=2x-2 +kx+8) is (5), what is (k)?
#coefficient
#parameter
#polynomial
A (2)
B (5)
C (8)
D (10)
Explanation opens after your attempt
Step 1
Concept
In (kx), the coefficient of (x) is (k). It is given that (k=5).
Step 2
Why this answer is correct
The correct answer is B. (5). In (kx), the coefficient of (x) is (k). It is given that (k=5).
Step 3
Exam Tip
(kx) में (x) का गुणांक (k) है। दिया है (k=5)।
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यदि (p(x)=x-2 +ax+4) का स्थिर पद (4) है, तो स्थिर पद कौन-सा है?
If the constant term of (p(x)=x-2 +ax+4) is (4), which term is the constant term?
#constant_term
#parameter
#polynomials
A \(x^2\)
B (ax)
C (4)
D (a)
Explanation opens after your attempt
Step 1
Concept
The constant term does not contain (x). So (4) is the constant term.
Step 2
Why this answer is correct
The correct answer is C. (4). The constant term does not contain (x). So (4) is the constant term.
Step 3
Exam Tip
स्थिर पद में (x) नहीं होता। इसलिए (4) स्थिर पद है।
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यदि (p(x)=2x-2 +kx+3) में (x) का गुणांक (5) है, तो (k) का मान क्या है?
If the coefficient of (x) in (p(x)=2x-2 +kx+3) is (5), what is the value of (k)?
#coefficient
#parameter
#polynomials
A (2)
B (3)
C (5)
D (8)
Explanation opens after your attempt
Step 1
Concept
In (kx), the coefficient of (x) is (k). Therefore (k=5).
Step 2
Why this answer is correct
The correct answer is C. (5). In (kx), the coefficient of (x) is (k). Therefore (k=5).
Step 3
Exam Tip
(kx) में (x) का गुणांक (k) है। इसलिए (k=5) होगा।
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यदि (x-2 -2(a+1)x+\(a^2+4a+5\)=0) के कोई वास्तविक मूल नहीं हों, तो (a) पर कौन सी शर्त सही है?
If (x-2 -2(a+1)x+\(a^2+4a+5\)=0) has no real roots, which condition on (a) is correct?
#quadratic-equations
#no-real-roots
#parameter
A (a>-2)
B (a=-2)
C (a<-2)
D हर वास्तविक (a) / Every real (a)
Explanation opens after your attempt
Step 1
Concept
Here (D=4(a+1)2 -4\(a^2+4a+5\)=-8(a+2)). For no real roots (D<0), so (a>-2).
Step 2
Why this answer is correct
The correct answer is A. (a>-2). Here (D=4(a+1)2 -4\(a^2+4a+5\)=-8(a+2)). For no real roots (D<0), so (a>-2).
Step 3
Exam Tip
यहाँ (D=4(a+1)2 -4\(a^2+4a+5\)=-8(a+2)) है। कोई वास्तविक मूल न होने के लिए (D<0), इसलिए (a>-2)।
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यदि (x-2 -(a+b+1)x+ab+a+b=0) हो, तो (a) और (b) के लिए मूलों की प्रकृति किस पर निर्भर करेगी?
If (x-2 -(a+b+1)x+ab+a+b=0), on what will the nature of roots depend for (a) and (b)?
#quadratic-equations
#advanced-discriminant
#parameter
A (D=(a-b)2 +1-2(a+b))
B (D=(a+b)2 )
C (D=0) हमेशा / (D=0) always
D (D=-1) हमेशा / (D=-1) always
Explanation opens after your attempt
Correct Answer
A. (D=(a-b)2 +1-2(a+b))
Step 1
Concept
Here (D=(a+b+1)2 -4(ab+a+b)). On simplification the correct discriminant is ( (a-b)2 +1-2(a+b) ).
Step 2
Why this answer is correct
The correct answer is A. (D=(a-b)2 +1-2(a+b)). Here (D=(a+b+1)2 -4(ab+a+b)). On simplification the correct discriminant is ( (a-b)2 +1-2(a+b) ).
Step 3
Exam Tip
यहाँ (D=(a+b+1)2 -4(ab+a+b)) है। सरल करने पर सही विविक्तकर ( (a-b)2 +1-2(a+b) ) मिलता है।
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कथन: (x-2 -2(a-3b)x+(a+3b)2 =0) में यदि (ab<0), तो मूल वास्तविक और असमान हैं। कारण: इसका (D=-48ab) है। सही विकल्प चुनिए।
Assertion: In (x-2 -2(a-3b)x+(a+3b)2 =0), if (ab<0), the roots are real and distinct. Reason: Its (D=-48ab). Choose the correct option.
#quadratic-equations
#assertion-reason
#parameter
A कथन और कारण दोनों सही हैं / Both assertion and reason are correct
B कथन सही है, कारण गलत है / Assertion is correct, reason is wrong
C कथन गलत है, कारण सही है / Assertion is wrong, reason is correct
D कथन और कारण दोनों गलत हैं / Both assertion and reason are wrong
Explanation opens after your attempt
Correct Answer
A. कथन और कारण दोनों सही हैं / Both assertion and reason are correct
Step 1
Concept
The discriminant is (D=-48ab). If (ab<0), then (D>0), so roots are real and distinct.
Step 2
Why this answer is correct
The correct answer is A. कथन और कारण दोनों सही हैं / Both assertion and reason are correct. The discriminant is (D=-48ab). If (ab<0), then (D>0), so roots are real and distinct.
Step 3
Exam Tip
विविक्तकर (D=-48ab) है। (ab<0) होने पर (D>0), इसलिए मूल वास्तविक असमान होंगे।
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समीकरण (4x-2 -2(5k-1)x+(k+2)2 =0) के समान मूलों के लिए सही समीकरण कौन सा है?
Which equation is correct for equal roots of (4x-2 -2(5k-1)x+(k+2)2 =0)?
#quadratic-equations
#parameter
#discriminant-equation
A \(21k^2-18k-15=0\)
B \(k^2-2k+1=0\)
C \(5k^2-k+2=0\)
D \(k^2+18k+21=0\)
Explanation opens after your attempt
Correct Answer
A. \(21k^2-18k-15=0\)
Step 1
Concept
Here (D=4(5k-1)2 -16(k+2)2 =4\(21k^2-18k-15\)). For equal roots the inner part becomes (0).
Step 2
Why this answer is correct
The correct answer is A. \(21k^2-18k-15=0\). Here (D=4(5k-1)2 -16(k+2)2 =4\(21k^2-18k-15\)). For equal roots the inner part becomes (0).
Step 3
Exam Tip
यहाँ (D=4(5k-1)2 -16(k+2)2 =4\(21k^2-18k-15\)) है। समान मूलों के लिए अंदर वाला भाग (0) होगा।
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यदि (x-2 +2(m-5 )x+\(m^2-9m+24\)=0) के कोई वास्तविक मूल नहीं हों, तो (m) पर कौन सी शर्त सही है?
If (x-2 +2(m-5 )x+\(m^2-9m+24\)=0) has no real roots, which condition on (m) is correct?
#quadratic-equations
#no-real-roots
#parameter
A (m>2)
B (m=2)
C (m<2)
D हर (m) / Every (m)
Explanation opens after your attempt
Step 1
Concept
In this equation (D=4(2-m)). For no real roots (D<0), so (m>2).
Step 2
Why this answer is correct
The correct answer is A. (m>2). In this equation (D=4(2-m)). For no real roots (D<0), so (m>2).
Step 3
Exam Tip
इसी समीकरण में (D=4(2-m)) है। कोई वास्तविक मूल नहीं के लिए (D<0), इसलिए (m>2)।
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यदि (x-2 +2(m-5 )x+\(m^2-9m+24\)=0) के समान मूल हों, तो (m) का मान क्या होगा?
If (x-2 +2(m-5 )x+\(m^2-9m+24\)=0) has equal roots, what is the value of (m)?
#quadratic-equations
#equal-roots
#parameter
A (2)
B (5)
C (9)
D (24)
Explanation opens after your attempt
Step 1
Concept
Here (D=4(m-5 )2 -4\(m^2-9m+24\)=4(2-m)). From (D=0), (m=2).
Step 2
Why this answer is correct
The correct answer is A. (2). Here (D=4(m-5 )2 -4\(m^2-9m+24\)=4(2-m)). From (D=0), (m=2).
Step 3
Exam Tip
यहाँ (D=4(m-5 )2 -4\(m^2-9m+24\)=4(2-m)) है। (D=0) से (m=2)।
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समीकरण \(x^2-2\theta x+3\theta=0\) के समान मूलों के लिए \(\theta\) के मान कौन से होंगे?
What are the values of \(\theta\) for equal roots of \(x^2-2\theta x+3\theta=0\)?
#quadratic-equations
#equal-roots
#parameter
A \(\theta=0\) या \(\theta=3\) / \(\theta=0\) or \(\theta=3\)
B केवल \(\theta=3\) / Only \(\theta=3\)
C केवल \(\theta=0\) / Only \(\theta=0\)
D \(\theta=-3\) या \(\theta=3\) / \(\theta=-3\) or \(\theta=3\)
Explanation opens after your attempt
Correct Answer
A. \(\theta=0\) या \(\theta=3\) / \(\theta=0\) or \(\theta=3\)
Step 1
Concept
For equal roots (D=4\theta\(\theta-3\)=0). Hence \(\theta=0\) or \(\theta=3\).
Step 2
Why this answer is correct
The correct answer is A. \(\theta=0\) या \(\theta=3\) / \(\theta=0\) or \(\theta=3\). For equal roots (D=4\theta\(\theta-3\)=0). Hence \(\theta=0\) or \(\theta=3\).
Step 3
Exam Tip
समान मूलों के लिए (D=4\theta\(\theta-3\)=0) है। अतः \(\theta=0\) या \(\theta=3\)।
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समीकरण ((q+3)x-2 -2(q-2)x+q=0) में समान मूलों के लिए (q) का सही मान क्या है, जबकि \(q\neq-3\)?
What is the correct value of (q) for equal roots in ((q+3)x-2 -2(q-2)x+q=0), where \(q\neq-3\)?
#quadratic-equations
#parameter
#equal-roots
A \(q=\frac{4}{7}\)
B \(q=\frac{7}{4}\)
C (q=4)
D (q=-3)
Explanation opens after your attempt
Correct Answer
A. \(q=\frac{4}{7}\)
Step 1
Concept
Here (D=4(q-2)2 -4q(q+3)=4(4-7q)). From (D=0), \(q=\frac{4}{7}\).
Step 2
Why this answer is correct
The correct answer is A. \(q=\frac{4}{7}\). Here (D=4(q-2)2 -4q(q+3)=4(4-7q)). From (D=0), \(q=\frac{4}{7}\).
Step 3
Exam Tip
यहाँ (D=4(q-2)2 -4q(q+3)=4(4-7q)) है। (D=0) से \(q=\frac{4}{7}\)।
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समीकरण (x-2 -(u+6)x+6u=0) में समान मूलों के लिए (u) का मान क्या होगा?
What is the value of (u) for equal roots in (x-2 -(u+6)x+6u=0)?
#quadratic-equations
#equal-roots
#parameter
A (u=6)
B (u=-6)
C (u=0)
D (u=12)
Explanation opens after your attempt
Step 1
Concept
Here (D=(u+6)2 -24u=(u-6)2 ). From (D=0), (u=6).
Step 2
Why this answer is correct
The correct answer is A. (u=6). Here (D=(u+6)2 -24u=(u-6)2 ). From (D=0), (u=6).
Step 3
Exam Tip
यहाँ (D=(u+6)2 -24u=(u-6)2 ) है। (D=0) से (u=6) मिलता है।
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समीकरण (x-2 -(t+7)x+7t=0) के दो वास्तविक और असमान मूलों के लिए कौन सी शर्त सही है?
Which condition is correct for two real and distinct roots of (x-2 -(t+7)x+7t=0)?
#quadratic-equations
#parameter
#distinct-roots
A \(t\neq7\)
B (t=7)
C (t>7) मात्र / Only (t>7)
D (t<7) मात्र / Only (t<7)
Explanation opens after your attempt
Correct Answer
A. \(t\neq7\)
Step 1
Concept
Here (D=(t+7)2 -28t=(t-7)2 ). For two distinct roots (D>0), so \(t\neq7\).
Step 2
Why this answer is correct
The correct answer is A. \(t\neq7\). Here (D=(t+7)2 -28t=(t-7)2 ). For two distinct roots (D>0), so \(t\neq7\).
Step 3
Exam Tip
यहाँ (D=(t+7)2 -28t=(t-7)2 ) है। दो असमान मूलों के लिए (D>0), इसलिए \(t\neq7\)।
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यदि (x-2 -2(k-4)x+\(k^2-10k+27\)=0) के कोई वास्तविक मूल नहीं हों, तो (k) पर कौन सी शर्त सही है?
If (x-2 -2(k-4)x+\(k^2-10k+27\)=0) has no real roots, which condition on (k) is correct?
#quadratic-equations
#no-real-roots
#parameter
A \(k<\frac{11}{2}\)
B \(k=\frac{11}{2}\)
C \(k>\frac{11}{2}\)
D हर (k) / Every (k)
Explanation opens after your attempt
Correct Answer
A. \(k<\frac{11}{2}\)
Step 1
Concept
Here (D=4(k-4)2 -4\(k^2-10k+27\)=4(2k-11)). For no real roots (D<0), so \(k<\frac{11}{2}\).
Step 2
Why this answer is correct
The correct answer is A. \(k<\frac{11}{2}\). Here (D=4(k-4)2 -4\(k^2-10k+27\)=4(2k-11)). For no real roots (D<0), so \(k<\frac{11}{2}\).
Step 3
Exam Tip
यहाँ (D=4(k-4)2 -4\(k^2-10k+27\)=4(2k-11)) है। कोई वास्तविक मूल नहीं के लिए (D<0), इसलिए \(k<\frac{11}{2}\)।
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यदि (x-2 -2(a+2)x+\(a^2+6a+8\)=0) के कोई वास्तविक मूल नहीं हों, तो (a) पर कौन सी शर्त सही है?
If (x-2 -2(a+2)x+\(a^2+6a+8\)=0) has no real roots, which condition on (a) is correct?
#quadratic-equations
#no-real-roots
#parameter
A (a>-2)
B (a=-2)
C (a<-2)
D हर वास्तविक (a) / Every real (a)
Explanation opens after your attempt
Step 1
Concept
Here (D=4(a+2)2 -4\(a^2+6a+8\)=-8(a+2)). For no real roots (D<0), so (a>-2).
Step 2
Why this answer is correct
The correct answer is A. (a>-2). Here (D=4(a+2)2 -4\(a^2+6a+8\)=-8(a+2)). For no real roots (D<0), so (a>-2).
Step 3
Exam Tip
यहाँ (D=4(a+2)2 -4\(a^2+6a+8\)=-8(a+2)) है। कोई वास्तविक मूल न होने के लिए (D<0), इसलिए (a>-2)।
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कथन: (x-2 -2(a-b)x+(a+b)2 =0) में यदि (ab<0), तो मूल वास्तविक और असमान हैं। कारण: इसका (D=-16ab) है। सही विकल्प चुनिए।
Assertion: In (x-2 -2(a-b)x+(a+b)2 =0), if (ab<0), the roots are real and distinct. Reason: Its (D=-16ab). Choose the correct option.
#quadratic-equations
#assertion-reason
#parameter
A कथन और कारण दोनों सही हैं / Both assertion and reason are correct
B कथन सही है, कारण गलत है / Assertion is correct, reason is wrong
C कथन गलत है, कारण सही है / Assertion is wrong, reason is correct
D कथन और कारण दोनों गलत हैं / Both assertion and reason are wrong
Explanation opens after your attempt
Correct Answer
A. कथन और कारण दोनों सही हैं / Both assertion and reason are correct
Step 1
Concept
The discriminant is (D=-16ab). If (ab<0), then (D>0), so roots are real and distinct.
Step 2
Why this answer is correct
The correct answer is A. कथन और कारण दोनों सही हैं / Both assertion and reason are correct. The discriminant is (D=-16ab). If (ab<0), then (D>0), so roots are real and distinct.
Step 3
Exam Tip
विविक्तकर (D=-16ab) है। यदि (ab<0), तो (D>0) और मूल वास्तविक असमान होंगे।
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समीकरण (2x-2 -2(3k-1)x+(k+1)2 =0) के समान मूलों के लिए सही समीकरण कौन सा है?
Which equation is correct for equal roots of (2x-2 -2(3k-1)x+(k+1)2 =0)?
#quadratic-equations
#parameter
#discriminant-equation
A \(7k^2-10k-1=0\)
B \(k^2-2k+1=0\)
C \(3k^2-k+1=0\)
D \(k^2+10k+7=0\)
Explanation opens after your attempt
Correct Answer
A. \(7k^2-10k-1=0\)
Step 1
Concept
Here (D=4(3k-1)2 -8(k+1)2 =4\(7k^2-10k-1\)). For equal roots set it equal to (0).
Step 2
Why this answer is correct
The correct answer is A. \(7k^2-10k-1=0\). Here (D=4(3k-1)2 -8(k+1)2 =4\(7k^2-10k-1\)). For equal roots set it equal to (0).
Step 3
Exam Tip
यहाँ (D=4(3k-1)2 -8(k+1)2 =4\(7k^2-10k-1\)) है। समान मूलों के लिए इसे (0) के बराबर रखें।
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समीकरण (2x-2 -2(3k-1)x+(k+1)2 =0) में समान मूलों के लिए (k) के मान क्या होंगे?
For equal roots in (2x-2 -2(3k-1)x+(k+1)2 =0), what are the values of (k)?
#quadratic-equations
#equal-roots
#parameter
A (k=1) या (k=-3) / (k=1) or (k=-3)
B (k=3) या (k=-1) / (k=3) or (k=-1)
C (k=0) या (k=-2) / (k=0) or (k=-2)
D (k=2) या (k=-3) / (k=2) or (k=-3)
Explanation opens after your attempt
Correct Answer
A. (k=1) या (k=-3) / (k=1) or (k=-3)
Step 1
Concept
Here (D=4(3k-1)2 -8(k+1)2 ). For equal roots, solve (D=0) directly and avoid mental shortcuts.
Step 2
Why this answer is correct
The correct answer is A. (k=1) या (k=-3) / (k=1) or (k=-3). Here (D=4(3k-1)2 -8(k+1)2 ). For equal roots, solve (D=0) directly and avoid mental shortcuts.
Step 3
Exam Tip
यहाँ (D=4(3k-1)2 -8(k+1)2 =4\(7k^2-10k-1\)) नहीं, यह विकल्प जाँचने योग्य है। सही समान मूल के लिए सीधे (D=0) हल करें।
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यदि (x-2 +2(m-4 )x+\(m^2-7m+14\)=0) के वास्तविक मूल हों, तो (m) पर कौन सी शर्त सही है?
If (x-2 +2(m-4 )x+\(m^2-7m+14\)=0) has real roots, which condition on (m) is correct?
#quadratic-equations
#real-roots
#parameter
A \(m\leq2\)
B (m>2)
C (m=4)
D हर (m) / Every (m)
Explanation opens after your attempt
Correct Answer
A. \(m\leq2\)
Step 1
Concept
From the discriminant, (D=4(2-m)). For real roots \(D\geq0\), so \(m\leq2\).
Step 2
Why this answer is correct
The correct answer is A. \(m\leq2\). From the discriminant, (D=4(2-m)). For real roots \(D\geq0\), so \(m\leq2\).
Step 3
Exam Tip
पिछले विविक्तकर से (D=4(2-m)) है। वास्तविक मूलों के लिए \(D\geq0\), इसलिए \(m\leq2\)।
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यदि (x-2 +2(m-4 )x+\(m^2-7m+14\)=0) के समान मूल हों, तो (m) का मान क्या होगा?
If (x-2 +2(m-4 )x+\(m^2-7m+14\)=0) has equal roots, what is the value of (m)?
#quadratic-equations
#equal-roots
#parameter
A (2)
B (4)
C (7)
D (14)
Explanation opens after your attempt
Step 1
Concept
Here (D=4(m-4 )2 -4\(m^2-7m+14\)=4(2-m)). From (D=0), (m=2).
Step 2
Why this answer is correct
The correct answer is A. (2). Here (D=4(m-4 )2 -4\(m^2-7m+14\)=4(2-m)). From (D=0), (m=2).
Step 3
Exam Tip
यहाँ (D=4(m-4 )2 -4\(m^2-7m+14\)=4(2-m)) है। (D=0) से (m=2) मिलता है।
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समीकरण \(x^2-2\mu x+2\mu=0\) के समान मूलों के लिए \(\mu\) के मान कौन से होंगे?
What are the values of \(\mu\) for equal roots of \(x^2-2\mu x+2\mu=0\)?
#quadratic-equations
#equal-roots
#parameter
A \(\mu=0\) या \(\mu=2\) / \(\mu=0\) or \(\mu=2\)
B केवल \(\mu=2\) / Only \(\mu=2\)
C केवल \(\mu=0\) / Only \(\mu=0\)
D \(\mu=-2\) या \(\mu=2\) / \(\mu=-2\) or \(\mu=2\)
Explanation opens after your attempt
Correct Answer
A. \(\mu=0\) या \(\mu=2\) / \(\mu=0\) or \(\mu=2\)
Step 1
Concept
For equal roots (D=4\mu\(\mu-2\)=0). Therefore \(\mu=0\) or \(\mu=2\).
Step 2
Why this answer is correct
The correct answer is A. \(\mu=0\) या \(\mu=2\) / \(\mu=0\) or \(\mu=2\). For equal roots (D=4\mu\(\mu-2\)=0). Therefore \(\mu=0\) or \(\mu=2\).
Step 3
Exam Tip
समान मूलों के लिए (D=4\mu\(\mu-2\)=0) है। इसलिए \(\mu=0\) या \(\mu=2\)।
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समीकरण ((q+2)x-2 -2(q-1)x+q=0) में समान मूलों के लिए सही (q) कौन सा है, यदि \(q\neq-2\)?
Which value of (q) gives equal roots in ((q+2)x-2 -2(q-1)x+q=0), if \(q\neq-2\)?
#quadratic-equations
#parameter
#equal-roots
A \(q=\frac{1}{4}\)
B \(q=\frac{1}{2}\)
C (q=1)
D (q=-2)
Explanation opens after your attempt
Correct Answer
A. \(q=\frac{1}{4}\)
Step 1
Concept
Here (D=4(q-1)2 -4q(q+2)=4(1-4q)). For equal roots (D=0), so \(q=\frac{1}{4}\).
Step 2
Why this answer is correct
The correct answer is A. \(q=\frac{1}{4}\). Here (D=4(q-1)2 -4q(q+2)=4(1-4q)). For equal roots (D=0), so \(q=\frac{1}{4}\).
Step 3
Exam Tip
यहाँ (D=4(q-1)2 -4q(q+2)=4(1-4q)) है। समान मूलों के लिए (D=0), इसलिए \(q=\frac{1}{4}\)।
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समीकरण ((q+2)x-2 -2(q-1)x+q=0) में \(q\neq-2\) हो, तो समान मूलों के लिए (q) का मान क्या है?
In ((q+2)x-2 -2(q-1)x+q=0), with \(q\neq-2\), what is the value of (q) for equal roots?
#quadratic-equations
#equal-roots
#parameter
A \(\frac{1}{2}\)
B (2)
C \(-\frac{1}{2}\)
D (0)
Explanation opens after your attempt
Correct Answer
A. \(\frac{1}{2}\)
Step 1
Concept
Here (D=4(q-1)2 -4q(q+2)=4(1-4q)). Setting (D=0) gives \(q=\frac{1}{4}\), so calculate carefully.
Step 2
Why this answer is correct
The correct answer is A. \(\frac{1}{2}\). Here (D=4(q-1)2 -4q(q+2)=4(1-4q)). Setting (D=0) gives \(q=\frac{1}{4}\), so calculate carefully.
Step 3
Exam Tip
यहाँ (D=4(q-1)2 -4q(q+2)=4(1-4q)) है। (D=0) से \(q=\frac{1}{4}\) नहीं, सही गणना जाँचें।
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समीकरण (x-2 -(s+4)x+4s=0) में समान मूलों के लिए (s) का मान क्या होगा?
What is the value of (s) for equal roots in (x-2 -(s+4)x+4s=0)?
#quadratic-equations
#equal-roots
#parameter
A (s=4)
B (s=-4)
C (s=0)
D (s=8)
Explanation opens after your attempt
Step 1
Concept
Here (D=(s+4)2 -16s=(s-4 )2 ). For equal roots (D=0), so (s=4).
Step 2
Why this answer is correct
The correct answer is A. (s=4). Here (D=(s+4)2 -16s=(s-4 )2 ). For equal roots (D=0), so (s=4).
Step 3
Exam Tip
यहाँ (D=(s+4)2 -16s=(s-4 )2 ) है। समान मूलों के लिए (D=0), इसलिए (s=4)।
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