Concept-wise Practice

parameter MCQ Questions for Class 10

parameter se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

737 questions tagged with parameter.

यदि (p(x)=3x-2+bx-10) में (x=2) एक शून्य है, तो (b) का मान क्या होगा?

If (x=2) is a zero of (p(x)=3x-2+bx-10), what will be the value of (b)?

Explanation opens after your attempt
Correct Answer

A. (-1)

Step 1

Concept

(p(2)=12+2b-10=0), so (2b=-2) and (b=-1). When a zero is given, set the polynomial value equal to (0).

Step 2

Why this answer is correct

The correct answer is A. (-1). (p(2)=12+2b-10=0), so (2b=-2) and (b=-1). When a zero is given, set the polynomial value equal to (0).

Step 3

Exam Tip

(p(2)=12+2b-10=0), इसलिए (2b=-2) और (b=-1)। शून्य दिए होने पर बहुपद का मान (0) रखें।

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यदि (p(x)=kx-2+6x+9) और (p(-3)=0), तो (k) क्या है?

If (p(x)=kx-2+6x+9) and (p(-3)=0), what is (k)?

Explanation opens after your attempt
Correct Answer

A. (1)

Step 1

Concept

(p(-3)=9k-18+9=0), so (9k-9=0) and (k=1). Substitute the given zero to find the unknown coefficient.

Step 2

Why this answer is correct

The correct answer is A. (1). (p(-3)=9k-18+9=0), so (9k-9=0) and (k=1). Substitute the given zero to find the unknown coefficient.

Step 3

Exam Tip

(p(-3)=9k-18+9=0), इसलिए (9k-9=0) और (k=1)। दिए गए शून्य को रखकर अज्ञात गुणांक निकालें।

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यदि (p(x)=(m-2)x-3+4x-2-7) की घात (2) है, तो (m) का मान क्या होगा?

If the degree of (p(x)=(m-2)x-3+4x-2-7) is (2), what will be the value of (m)?

Explanation opens after your attempt
Correct Answer

B. (2)

Step 1

Concept

For the degree to be (2), the coefficient of \(x^3\) must be (0), so (m-2=0) and (m=2). In exams, check the coefficient of the highest power first.

Step 2

Why this answer is correct

The correct answer is B. (2). For the degree to be (2), the coefficient of \(x^3\) must be (0), so (m-2=0) and (m=2). In exams, check the coefficient of the highest power first.

Step 3

Exam Tip

घात (2) होने के लिए \(x^3\) का गुणांक (0) होना चाहिए, इसलिए (m-2=0) और (m=2)। परीक्षा में सबसे ऊंची घात के गुणांक को पहले देखें।

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किस मान के लिए \(x^2-4x+m\) में (x=1) शून्य होगा?

For what value of (m) will (x=1) be a zero of \(x^2-4x+m\)?

Explanation opens after your attempt
Correct Answer

C. (3)

Step 1

Concept

(1-4+m=0), so (m=3). When a zero is given, set the polynomial value equal to (0).

Step 2

Why this answer is correct

The correct answer is C. (3). (1-4+m=0), so (m=3). When a zero is given, set the polynomial value equal to (0).

Step 3

Exam Tip

(1-4+m=0), इसलिए (m=3)। शून्य मिलने पर बहुपद का मान (0) रखें।

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यदि (p(x)=x-2-ax+10) और (p(5)=0), तो (a) का मान क्या है?

If (p(x)=x-2-ax+10) and (p(5)=0), what is the value of (a)?

Explanation opens after your attempt
Correct Answer

B. (7)

Step 1

Concept

(p(5)=25-5a+10=0), so (35=5a) and (a=7). Use the given zero.

Step 2

Why this answer is correct

The correct answer is B. (7). (p(5)=25-5a+10=0), so (35=5a) and (a=7). Use the given zero.

Step 3

Exam Tip

(p(5)=25-5a+10=0), इसलिए (35=5a) और (a=7)। दिए गए शून्य का उपयोग करें।

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यदि (p(x)=x-2+kx+6) और (p(2)=0), तो (k) क्या है?

If (p(x)=x-2+kx+6) and (p(2)=0), what is (k)?

Explanation opens after your attempt
Correct Answer

A. (-5)

Step 1

Concept

(p(2)=4+2k+6=0), so (2k=-10) and (k=-5). Substitute the zero and form an equation.

Step 2

Why this answer is correct

The correct answer is A. (-5). (p(2)=4+2k+6=0), so (2k=-10) and (k=-5). Substitute the zero and form an equation.

Step 3

Exam Tip

(p(2)=4+2k+6=0), इसलिए (2k=-10) और (k=-5)। शून्य की शर्त में मान रखकर समीकरण बनाएं।

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(p(x)=2x-2+kx+8) में (x) का गुणांक (5) हो तो (k) क्या है?

If the coefficient of (x) in (p(x)=2x-2+kx+8) is (5), what is (k)?

Explanation opens after your attempt
Correct Answer

B. (5)

Step 1

Concept

In (kx), the coefficient of (x) is (k). It is given that (k=5).

Step 2

Why this answer is correct

The correct answer is B. (5). In (kx), the coefficient of (x) is (k). It is given that (k=5).

Step 3

Exam Tip

(kx) में (x) का गुणांक (k) है। दिया है (k=5)।

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यदि (p(x)=x-2+ax+4) का स्थिर पद (4) है, तो स्थिर पद कौन-सा है?

If the constant term of (p(x)=x-2+ax+4) is (4), which term is the constant term?

Explanation opens after your attempt
Correct Answer

C. (4)

Step 1

Concept

The constant term does not contain (x). So (4) is the constant term.

Step 2

Why this answer is correct

The correct answer is C. (4). The constant term does not contain (x). So (4) is the constant term.

Step 3

Exam Tip

स्थिर पद में (x) नहीं होता। इसलिए (4) स्थिर पद है।

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यदि (p(x)=2x-2+kx+3) में (x) का गुणांक (5) है, तो (k) का मान क्या है?

If the coefficient of (x) in (p(x)=2x-2+kx+3) is (5), what is the value of (k)?

Explanation opens after your attempt
Correct Answer

C. (5)

Step 1

Concept

In (kx), the coefficient of (x) is (k). Therefore (k=5).

Step 2

Why this answer is correct

The correct answer is C. (5). In (kx), the coefficient of (x) is (k). Therefore (k=5).

Step 3

Exam Tip

(kx) में (x) का गुणांक (k) है। इसलिए (k=5) होगा।

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यदि (x-2-2(a+1)x+\(a^2+4a+5\)=0) के कोई वास्तविक मूल नहीं हों, तो (a) पर कौन सी शर्त सही है?

If (x-2-2(a+1)x+\(a^2+4a+5\)=0) has no real roots, which condition on (a) is correct?

Explanation opens after your attempt
Correct Answer

A. (a>-2)

Step 1

Concept

Here (D=4(a+1)2-4\(a^2+4a+5\)=-8(a+2)). For no real roots (D<0), so (a>-2).

Step 2

Why this answer is correct

The correct answer is A. (a>-2). Here (D=4(a+1)2-4\(a^2+4a+5\)=-8(a+2)). For no real roots (D<0), so (a>-2).

Step 3

Exam Tip

यहाँ (D=4(a+1)2-4\(a^2+4a+5\)=-8(a+2)) है। कोई वास्तविक मूल न होने के लिए (D<0), इसलिए (a>-2)।

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यदि (x-2-(a+b+1)x+ab+a+b=0) हो, तो (a) और (b) के लिए मूलों की प्रकृति किस पर निर्भर करेगी?

If (x-2-(a+b+1)x+ab+a+b=0), on what will the nature of roots depend for (a) and (b)?

Explanation opens after your attempt
Correct Answer

A. (D=(a-b)2+1-2(a+b))

Step 1

Concept

Here (D=(a+b+1)2-4(ab+a+b)). On simplification the correct discriminant is ( (a-b)2+1-2(a+b) ).

Step 2

Why this answer is correct

The correct answer is A. (D=(a-b)2+1-2(a+b)). Here (D=(a+b+1)2-4(ab+a+b)). On simplification the correct discriminant is ( (a-b)2+1-2(a+b) ).

Step 3

Exam Tip

यहाँ (D=(a+b+1)2-4(ab+a+b)) है। सरल करने पर सही विविक्तकर ( (a-b)2+1-2(a+b) ) मिलता है।

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कथन: (x-2-2(a-3b)x+(a+3b)2=0) में यदि (ab<0), तो मूल वास्तविक और असमान हैं। कारण: इसका (D=-48ab) है। सही विकल्प चुनिए।

Assertion: In (x-2-2(a-3b)x+(a+3b)2=0), if (ab<0), the roots are real and distinct. Reason: Its (D=-48ab). Choose the correct option.

Explanation opens after your attempt
Correct Answer

A. कथन और कारण दोनों सही हैंBoth assertion and reason are correct

Step 1

Concept

The discriminant is (D=-48ab). If (ab<0), then (D>0), so roots are real and distinct.

Step 2

Why this answer is correct

The correct answer is A. कथन और कारण दोनों सही हैं / Both assertion and reason are correct. The discriminant is (D=-48ab). If (ab<0), then (D>0), so roots are real and distinct.

Step 3

Exam Tip

विविक्तकर (D=-48ab) है। (ab<0) होने पर (D>0), इसलिए मूल वास्तविक असमान होंगे।

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समीकरण (4x-2-2(5k-1)x+(k+2)2=0) के समान मूलों के लिए सही समीकरण कौन सा है?

Which equation is correct for equal roots of (4x-2-2(5k-1)x+(k+2)2=0)?

Explanation opens after your attempt
Correct Answer

A. \(21k^2-18k-15=0\)

Step 1

Concept

Here (D=4(5k-1)2-16(k+2)2=4\(21k^2-18k-15\)). For equal roots the inner part becomes (0).

Step 2

Why this answer is correct

The correct answer is A. \(21k^2-18k-15=0\). Here (D=4(5k-1)2-16(k+2)2=4\(21k^2-18k-15\)). For equal roots the inner part becomes (0).

Step 3

Exam Tip

यहाँ (D=4(5k-1)2-16(k+2)2=4\(21k^2-18k-15\)) है। समान मूलों के लिए अंदर वाला भाग (0) होगा।

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यदि (x-2+2(m-5)x+\(m^2-9m+24\)=0) के कोई वास्तविक मूल नहीं हों, तो (m) पर कौन सी शर्त सही है?

If (x-2+2(m-5)x+\(m^2-9m+24\)=0) has no real roots, which condition on (m) is correct?

Explanation opens after your attempt
Correct Answer

A. (m>2)

Step 1

Concept

In this equation (D=4(2-m)). For no real roots (D<0), so (m>2).

Step 2

Why this answer is correct

The correct answer is A. (m>2). In this equation (D=4(2-m)). For no real roots (D<0), so (m>2).

Step 3

Exam Tip

इसी समीकरण में (D=4(2-m)) है। कोई वास्तविक मूल नहीं के लिए (D<0), इसलिए (m>2)।

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यदि (x-2+2(m-5)x+\(m^2-9m+24\)=0) के समान मूल हों, तो (m) का मान क्या होगा?

If (x-2+2(m-5)x+\(m^2-9m+24\)=0) has equal roots, what is the value of (m)?

Explanation opens after your attempt
Correct Answer

A. (2)

Step 1

Concept

Here (D=4(m-5)2-4\(m^2-9m+24\)=4(2-m)). From (D=0), (m=2).

Step 2

Why this answer is correct

The correct answer is A. (2). Here (D=4(m-5)2-4\(m^2-9m+24\)=4(2-m)). From (D=0), (m=2).

Step 3

Exam Tip

यहाँ (D=4(m-5)2-4\(m^2-9m+24\)=4(2-m)) है। (D=0) से (m=2)।

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समीकरण \(x^2-2\theta x+3\theta=0\) के समान मूलों के लिए \(\theta\) के मान कौन से होंगे?

What are the values of \(\theta\) for equal roots of \(x^2-2\theta x+3\theta=0\)?

Explanation opens after your attempt
Correct Answer

A. \(\theta=0\) या \(\theta=3\)\(\theta=0\) or \(\theta=3\)

Step 1

Concept

For equal roots (D=4\theta\(\theta-3\)=0). Hence \(\theta=0\) or \(\theta=3\).

Step 2

Why this answer is correct

The correct answer is A. \(\theta=0\) या \(\theta=3\) / \(\theta=0\) or \(\theta=3\). For equal roots (D=4\theta\(\theta-3\)=0). Hence \(\theta=0\) or \(\theta=3\).

Step 3

Exam Tip

समान मूलों के लिए (D=4\theta\(\theta-3\)=0) है। अतः \(\theta=0\) या \(\theta=3\)।

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समीकरण ((q+3)x-2-2(q-2)x+q=0) में समान मूलों के लिए (q) का सही मान क्या है, जबकि \(q\neq-3\)?

What is the correct value of (q) for equal roots in ((q+3)x-2-2(q-2)x+q=0), where \(q\neq-3\)?

Explanation opens after your attempt
Correct Answer

A. \(q=\frac{4}{7}\)

Step 1

Concept

Here (D=4(q-2)2-4q(q+3)=4(4-7q)). From (D=0), \(q=\frac{4}{7}\).

Step 2

Why this answer is correct

The correct answer is A. \(q=\frac{4}{7}\). Here (D=4(q-2)2-4q(q+3)=4(4-7q)). From (D=0), \(q=\frac{4}{7}\).

Step 3

Exam Tip

यहाँ (D=4(q-2)2-4q(q+3)=4(4-7q)) है। (D=0) से \(q=\frac{4}{7}\)।

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समीकरण (x-2-(u+6)x+6u=0) में समान मूलों के लिए (u) का मान क्या होगा?

What is the value of (u) for equal roots in (x-2-(u+6)x+6u=0)?

Explanation opens after your attempt
Correct Answer

A. (u=6)

Step 1

Concept

Here (D=(u+6)2-24u=(u-6)2). From (D=0), (u=6).

Step 2

Why this answer is correct

The correct answer is A. (u=6). Here (D=(u+6)2-24u=(u-6)2). From (D=0), (u=6).

Step 3

Exam Tip

यहाँ (D=(u+6)2-24u=(u-6)2) है। (D=0) से (u=6) मिलता है।

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समीकरण (x-2-(t+7)x+7t=0) के दो वास्तविक और असमान मूलों के लिए कौन सी शर्त सही है?

Which condition is correct for two real and distinct roots of (x-2-(t+7)x+7t=0)?

Explanation opens after your attempt
Correct Answer

A. \(t\neq7\)

Step 1

Concept

Here (D=(t+7)2-28t=(t-7)2). For two distinct roots (D>0), so \(t\neq7\).

Step 2

Why this answer is correct

The correct answer is A. \(t\neq7\). Here (D=(t+7)2-28t=(t-7)2). For two distinct roots (D>0), so \(t\neq7\).

Step 3

Exam Tip

यहाँ (D=(t+7)2-28t=(t-7)2) है। दो असमान मूलों के लिए (D>0), इसलिए \(t\neq7\)।

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यदि (x-2-2(k-4)x+\(k^2-10k+27\)=0) के कोई वास्तविक मूल नहीं हों, तो (k) पर कौन सी शर्त सही है?

If (x-2-2(k-4)x+\(k^2-10k+27\)=0) has no real roots, which condition on (k) is correct?

Explanation opens after your attempt
Correct Answer

A. \(k<\frac{11}{2}\)

Step 1

Concept

Here (D=4(k-4)2-4\(k^2-10k+27\)=4(2k-11)). For no real roots (D<0), so \(k<\frac{11}{2}\).

Step 2

Why this answer is correct

The correct answer is A. \(k<\frac{11}{2}\). Here (D=4(k-4)2-4\(k^2-10k+27\)=4(2k-11)). For no real roots (D<0), so \(k<\frac{11}{2}\).

Step 3

Exam Tip

यहाँ (D=4(k-4)2-4\(k^2-10k+27\)=4(2k-11)) है। कोई वास्तविक मूल नहीं के लिए (D<0), इसलिए \(k<\frac{11}{2}\)।

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यदि (x-2-2(a+2)x+\(a^2+6a+8\)=0) के कोई वास्तविक मूल नहीं हों, तो (a) पर कौन सी शर्त सही है?

If (x-2-2(a+2)x+\(a^2+6a+8\)=0) has no real roots, which condition on (a) is correct?

Explanation opens after your attempt
Correct Answer

A. (a>-2)

Step 1

Concept

Here (D=4(a+2)2-4\(a^2+6a+8\)=-8(a+2)). For no real roots (D<0), so (a>-2).

Step 2

Why this answer is correct

The correct answer is A. (a>-2). Here (D=4(a+2)2-4\(a^2+6a+8\)=-8(a+2)). For no real roots (D<0), so (a>-2).

Step 3

Exam Tip

यहाँ (D=4(a+2)2-4\(a^2+6a+8\)=-8(a+2)) है। कोई वास्तविक मूल न होने के लिए (D<0), इसलिए (a>-2)।

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कथन: (x-2-2(a-b)x+(a+b)2=0) में यदि (ab<0), तो मूल वास्तविक और असमान हैं। कारण: इसका (D=-16ab) है। सही विकल्प चुनिए।

Assertion: In (x-2-2(a-b)x+(a+b)2=0), if (ab<0), the roots are real and distinct. Reason: Its (D=-16ab). Choose the correct option.

Explanation opens after your attempt
Correct Answer

A. कथन और कारण दोनों सही हैंBoth assertion and reason are correct

Step 1

Concept

The discriminant is (D=-16ab). If (ab<0), then (D>0), so roots are real and distinct.

Step 2

Why this answer is correct

The correct answer is A. कथन और कारण दोनों सही हैं / Both assertion and reason are correct. The discriminant is (D=-16ab). If (ab<0), then (D>0), so roots are real and distinct.

Step 3

Exam Tip

विविक्तकर (D=-16ab) है। यदि (ab<0), तो (D>0) और मूल वास्तविक असमान होंगे।

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समीकरण (2x-2-2(3k-1)x+(k+1)2=0) के समान मूलों के लिए सही समीकरण कौन सा है?

Which equation is correct for equal roots of (2x-2-2(3k-1)x+(k+1)2=0)?

Explanation opens after your attempt
Correct Answer

A. \(7k^2-10k-1=0\)

Step 1

Concept

Here (D=4(3k-1)2-8(k+1)2=4\(7k^2-10k-1\)). For equal roots set it equal to (0).

Step 2

Why this answer is correct

The correct answer is A. \(7k^2-10k-1=0\). Here (D=4(3k-1)2-8(k+1)2=4\(7k^2-10k-1\)). For equal roots set it equal to (0).

Step 3

Exam Tip

यहाँ (D=4(3k-1)2-8(k+1)2=4\(7k^2-10k-1\)) है। समान मूलों के लिए इसे (0) के बराबर रखें।

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समीकरण (2x-2-2(3k-1)x+(k+1)2=0) में समान मूलों के लिए (k) के मान क्या होंगे?

For equal roots in (2x-2-2(3k-1)x+(k+1)2=0), what are the values of (k)?

Explanation opens after your attempt
Correct Answer

A. (k=1) या (k=-3)(k=1) or (k=-3)

Step 1

Concept

Here (D=4(3k-1)2-8(k+1)2). For equal roots, solve (D=0) directly and avoid mental shortcuts.

Step 2

Why this answer is correct

The correct answer is A. (k=1) या (k=-3) / (k=1) or (k=-3). Here (D=4(3k-1)2-8(k+1)2). For equal roots, solve (D=0) directly and avoid mental shortcuts.

Step 3

Exam Tip

यहाँ (D=4(3k-1)2-8(k+1)2=4\(7k^2-10k-1\)) नहीं, यह विकल्प जाँचने योग्य है। सही समान मूल के लिए सीधे (D=0) हल करें।

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यदि (x-2+2(m-4)x+\(m^2-7m+14\)=0) के वास्तविक मूल हों, तो (m) पर कौन सी शर्त सही है?

If (x-2+2(m-4)x+\(m^2-7m+14\)=0) has real roots, which condition on (m) is correct?

Explanation opens after your attempt
Correct Answer

A. \(m\leq2\)

Step 1

Concept

From the discriminant, (D=4(2-m)). For real roots \(D\geq0\), so \(m\leq2\).

Step 2

Why this answer is correct

The correct answer is A. \(m\leq2\). From the discriminant, (D=4(2-m)). For real roots \(D\geq0\), so \(m\leq2\).

Step 3

Exam Tip

पिछले विविक्तकर से (D=4(2-m)) है। वास्तविक मूलों के लिए \(D\geq0\), इसलिए \(m\leq2\)।

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यदि (x-2+2(m-4)x+\(m^2-7m+14\)=0) के समान मूल हों, तो (m) का मान क्या होगा?

If (x-2+2(m-4)x+\(m^2-7m+14\)=0) has equal roots, what is the value of (m)?

Explanation opens after your attempt
Correct Answer

A. (2)

Step 1

Concept

Here (D=4(m-4)2-4\(m^2-7m+14\)=4(2-m)). From (D=0), (m=2).

Step 2

Why this answer is correct

The correct answer is A. (2). Here (D=4(m-4)2-4\(m^2-7m+14\)=4(2-m)). From (D=0), (m=2).

Step 3

Exam Tip

यहाँ (D=4(m-4)2-4\(m^2-7m+14\)=4(2-m)) है। (D=0) से (m=2) मिलता है।

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समीकरण \(x^2-2\mu x+2\mu=0\) के समान मूलों के लिए \(\mu\) के मान कौन से होंगे?

What are the values of \(\mu\) for equal roots of \(x^2-2\mu x+2\mu=0\)?

Explanation opens after your attempt
Correct Answer

A. \(\mu=0\) या \(\mu=2\)\(\mu=0\) or \(\mu=2\)

Step 1

Concept

For equal roots (D=4\mu\(\mu-2\)=0). Therefore \(\mu=0\) or \(\mu=2\).

Step 2

Why this answer is correct

The correct answer is A. \(\mu=0\) या \(\mu=2\) / \(\mu=0\) or \(\mu=2\). For equal roots (D=4\mu\(\mu-2\)=0). Therefore \(\mu=0\) or \(\mu=2\).

Step 3

Exam Tip

समान मूलों के लिए (D=4\mu\(\mu-2\)=0) है। इसलिए \(\mu=0\) या \(\mu=2\)।

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समीकरण ((q+2)x-2-2(q-1)x+q=0) में समान मूलों के लिए सही (q) कौन सा है, यदि \(q\neq-2\)?

Which value of (q) gives equal roots in ((q+2)x-2-2(q-1)x+q=0), if \(q\neq-2\)?

Explanation opens after your attempt
Correct Answer

A. \(q=\frac{1}{4}\)

Step 1

Concept

Here (D=4(q-1)2-4q(q+2)=4(1-4q)). For equal roots (D=0), so \(q=\frac{1}{4}\).

Step 2

Why this answer is correct

The correct answer is A. \(q=\frac{1}{4}\). Here (D=4(q-1)2-4q(q+2)=4(1-4q)). For equal roots (D=0), so \(q=\frac{1}{4}\).

Step 3

Exam Tip

यहाँ (D=4(q-1)2-4q(q+2)=4(1-4q)) है। समान मूलों के लिए (D=0), इसलिए \(q=\frac{1}{4}\)।

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समीकरण ((q+2)x-2-2(q-1)x+q=0) में \(q\neq-2\) हो, तो समान मूलों के लिए (q) का मान क्या है?

In ((q+2)x-2-2(q-1)x+q=0), with \(q\neq-2\), what is the value of (q) for equal roots?

Explanation opens after your attempt
Correct Answer

A. \(\frac{1}{2}\)

Step 1

Concept

Here (D=4(q-1)2-4q(q+2)=4(1-4q)). Setting (D=0) gives \(q=\frac{1}{4}\), so calculate carefully.

Step 2

Why this answer is correct

The correct answer is A. \(\frac{1}{2}\). Here (D=4(q-1)2-4q(q+2)=4(1-4q)). Setting (D=0) gives \(q=\frac{1}{4}\), so calculate carefully.

Step 3

Exam Tip

यहाँ (D=4(q-1)2-4q(q+2)=4(1-4q)) है। (D=0) से \(q=\frac{1}{4}\) नहीं, सही गणना जाँचें।

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समीकरण (x-2-(s+4)x+4s=0) में समान मूलों के लिए (s) का मान क्या होगा?

What is the value of (s) for equal roots in (x-2-(s+4)x+4s=0)?

Explanation opens after your attempt
Correct Answer

A. (s=4)

Step 1

Concept

Here (D=(s+4)2-16s=(s-4)2). For equal roots (D=0), so (s=4).

Step 2

Why this answer is correct

The correct answer is A. (s=4). Here (D=(s+4)2-16s=(s-4)2). For equal roots (D=0), so (s=4).

Step 3

Exam Tip

यहाँ (D=(s+4)2-16s=(s-4)2) है। समान मूलों के लिए (D=0), इसलिए (s=4)।

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